Chemistry High School

THIS IS FOR SCIENCE PLS HELP ME WRITE MY PROMPT How does the human population and human activity affect Earth?

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Answer 1
both work together and the human activity is what population counts on and the activity is what effects the population

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a 5 g ice cube starts life at -1 C if 2182.5 j are added to it what will be the final temperature upon his demise ?

Answers

Answer:

Final Temp = 23.92°C

Explanation:

ΔH(total) = (m·c·ΔT)ice + (m·ΔH(f))melt'g + (m·c·ΔT)water

2182.5j = (5g)(2.092j/g·°C)(1°C) + (5g)(334.56j/g) + (5g)(4.184j/g·°C)(ΔT)

(2182.5 - 10.46 - 1672.8)j = 20.92j/°C·ΔT

ΔT = (2182.5 - 10.46 - 1672.8)j / 20.92j/°C = 23.92°C

Since the melting ice starts and ends at 0°C and is then warmed to 23.92°C then the temperature change is also the final temp of the water based upon given energy input values.

When this gas is burned what will happen to the surface of this type of star?

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Use the link above for the answer

Which statement describes particles of an ideal gas, based on the kinetic molecular theory?

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Answer:

There are 5 steps/rules of the ideal gases based on kinetic theory.

Explanation:

1. Particles in a gas are constant moving in random motion.

2. combined volume of the particles is negligible.

3. particles exert no forces on one another

4. any collisions between the particles are completely elastic

5. the average kinetic energy of particles is proportional to temperature in kelvins.

(I had help explaining steps from Sal Khan. I hope this helps! Have a great day!)

When 1 mol of Zn reacts with 0.8 mol of HCI, which of the following will be true?

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Answer:

Zn is the excess reagent

Explanation:

11) How many grams are in 2.3 moles of magnesium chloride, MgCl,?

Answers

Answer:

218.98 grams

Explanation:

Given that,

No. of moles, n = 2.3

The molar mass of magnesium chloride is 95.211 g/mol.

We need to find the mass of 2.3 moles of magnesium chloride.

We know that,

No. of moles = given mass/molar mass

Let m be the given mass. So,

[tex]m=n\times M\\\\=2.3\times 95.211 \\\\=218.98\ g[/tex]

So, the required mass is equal to 218.98 grams.

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