Answer:
Step-by-step explanation:
x-coordinate of the vertex is the time the baseball reaches maximum height.
Let f be differentiable such that f(-2)=3,f(3)=5, f'(-2)=4 and f'(3)=6. Let g be differentiable functions such that g(x)=f^-1 (x) for all x. What is the value of g'(3)
Answer:
[tex]g'(3)=\frac{1}{4}[/tex]
Step-by-step explanation:
There is a rule in calculus that tells us that:
[tex]g'[f(x)]=\frac{1}{f'(x)}[/tex]
In this case, we know that f(-2)=3, therefore:
g'(3)=g'(f(-2))
So, if we used the rule, we would get that:
[tex]g'[f(-2)]=\frac{1}{f'(-2)}[/tex]
we know that f'(-2)=4, so:
[tex]g'[f(-2)]=\frac{1}{4}[/tex]
or:
[tex]g'[3]=\frac{1}{4}[/tex]
help pls ok fast pls
Answer:
I would say the last one. If its wrong then its definitely option 9y/3
Sorry if its wrong :(
i'll pay someone to do my math <3
I would like to be paid, then xD