Answer:
a. endothermic
Explanation:
The reaction shown is an endothermic reaction. In such reaction, they require an input of energy.
Endothermic changes involves absorption of heat from the surrounding. The surrounding becomes colder at the end of the reaction. When heat is on the reactant side, it suggests a reaction that requires a considerable input of energy.A man exerts a force on a large couch by pushing on it. Which of the following must be a true statement about the couch after he begins pushing?
A. The couch will maintain a constant acceleration due to the man's push.
B. The couch will remain at rest.
C. The couch will remain at rest if the push does not overcome the force of friction.
D. The couch will accelerate and then remain at a constant velocity.
Answer: the answer is c
Explanation:
Which term best explains why you hear an echo?
Answer:
reflection
Explanation:
Answer:
reflection
Explanation:
A p e x
What fonts do you use to create color coded lyrics
100 POINTS!!! :D
Write a scientific explanation that describes the interaction between the two skaters caused by the forces that they apply to each other.
Explanation:
... in every interaction, there is a pair of forces acting on the two interacting objects. The size of the force on the first object equals the size of the force on the second object. The direction of the force on the first object is opposite to the direction of the force on the second object. Forces always come in pairs - equal and opposite action-reaction force pairs.
A 1800 kg car moves along a horizontal road at speed v₀ = 18.4 m/s. The road is wet, so the static friction coefficient between the tires and the road is only µ static = 0.188 and the kinetic friction coefficient is even lower, µ kinetic = 0.1316. The acceleration of gravity is 9.8 m/s². What is the shortest possible stopping distance for the car under such conditions? (neglect the reaction time of the driver and round your answer to 4 decimal places)
Answer:
The shortest possible distance is [tex]|s| = 91.9 \ m[/tex]
Explanation:
From the question we are told that
The mass of the car is [tex]m = 1800 \ kg[/tex]
The speed along the horizontal road is [tex]v_o =u = 18.4 \ m/s[/tex]
The static friction coefficient is [tex]\mu_s = 0.188[/tex]
The kinetic friction coefficient is [tex]\mu_k = 0.1316[/tex]
Generally the static frictional force acting on the car is mathematically represented as
[tex]F_f = m * g * \mu_s[/tex]
Generally the force propelling the car is mathematically represented as
[tex]F = m * a[/tex]
Here a is the maximum acceleration
at the point which the car stops ,
[tex]F = F_f[/tex]
=> [tex]m * g * \mu_s = ma[/tex]
=> [tex]g * \mu_s =a[/tex]
=> [tex]a = 9.8 * 0.188[/tex]
=> [tex]a = 1.8424 \ m/s^2[/tex]
Generally from kinematic equation
[tex]v^2 = u^2 + 2as[/tex]
Here v is the final velocity of the car and the value is zero given that the car comes to rest
So
[tex]0^2 = 18.4^2 + 2* 1.8424 s[/tex]
=> [tex]s = - \frac{18.4^2}{2 * 1.8424}[/tex]
=> [tex]|s| = 91.9 \ m[/tex]
Conduction In Everyday Life Examples
at least 5 plz help
1. Heat transfer from a hot burner on the stove into a pot or pan
2. A metal spoon that gets hot from the boiling water
3. Chocolate candy in your hand that melts because of the heat
4. The wires in your house that conduct electricity
5. Roasting marshmallows, the heat will soften the marshmallow
Answer:
the engine heat from a car you just turned on.
a heater
a pad warmer
a hot pot
using a campfire to roast hot dogs
Where does digestion begin?
Answer:
Digestion begins in the mouth, when you chew.
A rescue plane wants to drop supplies to isolated mountain climbers on a rocky ridge 235m below. If the plane is traveling horizontally with a speed of 250 km/h (69.4m/s), (a) how far in advance of the recipients ( horizontal distance) must the goods be dropped. (b) Suppose, instead that the plane release the supplies a horizontal distance of 425m in advance of the mountain climbers. What vertical velocity (up or down) should the supplies be given so that they arrive precisely at the climber's position? (c) with what speed do the supplies land in the latter case
Answer:
Explanation:
For vertical displacement of food-supply
if time taken to reach the ground be t
235 = 1/2 g t² , initial velocity downwards is zero.
t = 6.92 s
Horizontal displacement of food during this period
= 6.92 x 69.4 m
= 480.25 m .
b )
time required to cover horizontal distance of 425 m
= 425 / 69.4 = 6.124 s
This time period will be the time of vertical fall of 235 m . Let initial vertical velocity required be u
h = ut + 1/2 gt²
235 = u x 6.124 + .5 x 9.8 x 6.124²
235 = u x 6.124 + 183.76
u = 8.36 m /s
c )
v = u + gt
= 8.36 + 9.8 x 6.124
= 68.37 m /s
This will be vertical component of velocity .
horizontal velocity = 69.4 m /s
resultant velocity = √ ( 68.37² + 69.4²)
= √(4674.45 +4816.36)
= 97.42 m /s
A model rocket Was built last weekend. We launched it in a nearby field. The rocket took off Straight up with an initial velocity 62.3 m/s. If it accelerates upward at 4.30 m/s2 until the engines stop 3.73 s later: (a) What is the maximum height the rocket reaches? (b) How long is the rocket in the air? (c) What is the velocity of the rocket as it hits the ground?
Answer:
a) y_total = 575.4 m , b) t_total = 22.56 s , c) v = 106.20 m
Explanation:
a) We can solve this exercise using the scientific relations
Let's find the height reached while the engines are running
v₁ = v₀ + a t
v₁ = 62.3 + 4.30 3.73
v₁ = 78.339 m / s
in this time it rose
y₁ = v₀ t₁ + ½ a t₁²
y₁ = 62.3 3.73 + ½ 4.30 3.73²
y₁ = 262.29 m
At this moment the engines are turned off and the rocket continues in a vertical launch, suppose that the acceleration of gravity is constant in this path
v₂ = v₁ 2 - 2 g y₂
at maximum height the velocity is zero (v₂ = 0)
y₂ = v₁ 2 / 2g
y₂ = 78.339 2/2 9.8
y₂ = 313.11 m
the total height is
y_total = y₁ + y₂
y_total = 262.29 + 313.11
y_total = 575.4 m
b) the time the rocket is in the air is
t_total = t₁ + t₂
where t₂ is the time after the engines have shut down
y = y₁ + v₁ t₂ - ½ g t₂²
y = 0
0 = 262.29 + 78.339 t₂ - ½ 9.8 t₂²
t₂² - 15.99 t₂ - 53.53 = 0
t₂ = [15.99 ±√ (15.99² +4 53.53)] / 2
t₂ = [15.99 ± 21.67] / 2
t₂´ = 18.83 s
t₂´´ = -2.84 s
since the time must be a positive quantity the correct result is t2 = 18.83 s, the total time in the air is
t_total = 3.73 + 18.83
t_total = 22.56 s
c) the speed when it hits the ground
We can perform this calculation starting with the maximum height y = 575.4 m where it has zero initial velocity (vo = 0)
v² = v₀² + 2 g y
v = √ 2gy
v = √ (2 9.8 575.4)
v = 106.20 m
Which step of mitosis involves the chromosomes lining up in the center of the cell?
Answer:
Metaphase
Explanation:
During metaphase,chromosome line up in the middle of the cell.
pls answer quick & an accurate answer will get brainliest
Answer:
3.766 kg or 3.7 kg
Explanation:
F= M*A equation