there was a total of 400 oranges and mangoes at a fruit stall.3/8 of these fruits were mangoes.each orange was priced at 40 cents,and each mango was priced at 60 cents.how much would mr.mead make if he sold 2/3 of the mangoes and 4/5 of the oranges?

Answers

Answer 1

Answer:

First find the number of Mango and oranges. 400 divided by 8 = 50. We use 8 because it is the whole part of the percentage. Since, there is 3/8 mangoes, multiply 50* 3= 150 mangoes and 50*5= 250 oranges.

2/3 of 150=100 mangoes. You would find this by dividing 150/3=50 then multiply by 2.

4/5 of 250= 200 oranges. You would find this by dividing 250/5=50 then multiply by 4.

$.40*100= $40.00 mangoes

$.60*200= $120.00 oranges

Mr. Mead would make $160.00

Step-by-step explanation:


Related Questions

A research center project involved a survey of 851 Internet users. It provided a variety of statistics on Internet users. (a) The sample survey showed that 92% of respondents said the Internet has been a good thing for them personally. Develop a 95% confidence interval for the proportion of respondents who say the Internet has been a good thing for them personally. (Round your answers to four decimal places.)

Answers

Answer:

The answer is "(0.9193924 , 0.9206076)".

Step-by-step explanation:

[tex]\text{sample proportion}\ (SP) = 0.92\\\\\text{sample size}\ n = 851\\\\\text{Standard error} \ SE = \sqrt{\frac{(SP \times(1 - SP)}{n})}\\\\[/tex]

                              [tex]= \sqrt{\frac{(0.92 \times (0.08)}{851})}\\\\= \sqrt{\frac{0.0736}{851}}\\\\= \sqrt{8.648\times 10^{-5}}\\\\=0.00031[/tex]

[tex]\text{CI level is}\ 95\% \\\\\therefore\\\\ \alpha = 1 - 0.95 = 0.05\\\\\frac{\alpha}{2} = \frac{0.05}{2} = 0.025\\\\ Z_c = Z_{(\frac{\alpha}{2})} = 1.96[/tex]

Calculating the Margin of Error:

[tex]ME = z_{c} \times SE\\\\[/tex]

       [tex]= 1.96 \times 0.00031\\\\ = 0.0006076[/tex]

[tex]CI = (SP - z*SE, SP + z*SE)[/tex]

      [tex]= (0.92 - 1.96 * 0.00031 , 0.92 + 1.96 * 0.00031)\\\\ = (0.92 - 0.0006076 , 0.92 + 0.0006076)\\\\= (0.9193924 , 0.9206076)[/tex]

Ethan has collected 417 football cards. He shares them equally between himself and his two friends. How many will each person get

Answers

Answer:

139 cards

Step-by-step explanation:

This is basically just a division statement - we have 417 cards and want to split it with 3 people (two friends + himself = 3 people).

We can divide these using a calculator or long division, but either way you will get:

[tex]417\div3=139[/tex]

Hope this helped!

Answer: 139

Step-by-step explanation:

417 divided by 3 gives you 139.

I need help with these

Answers

Answer:

2. 20 oranges

3. 18 yellow tulips

4. 23 students

Subtract 750 -389 plzzz help

Answers

750 - 389 = 361
Therefore, 361

look at the image for the question

Answers

Answer:

3166.7

Step-by-step explanation:

V = πr²h

V = π * (12 km)² * 7 km

V ≈ 3166.7 km³

Hey there!

First, let's review the formula for finding a cylinder's volume.

Formula: [tex]\pi r^2h[/tex]

Our new equation would look like this: [tex]\pi[/tex] x [tex]12^{2}[/tex] x 7.

The original answer would be 3166.72539482, but the question states that it want it rounded to the nearest tenth. So, your answer would be 3166.7.

Hope this helps! Have a great day!

. A population is currently 6,000 and has been increasing by 1.2% each day. Write an exponential model for the population.

Answers

Answer: [tex]A=6000(1.012)^t[/tex]

Step-by-step explanation:

General exponential function:

[tex]A=P(1+r)^t[/tex]

, where P= current  population

r= rate of growth

t= time period

A= population after t years

As per given , we have P=6,000

r= 1.2% = 0.012

Then, the required exponential function:  [tex]A=6000(1+0.012)^t[/tex]

or [tex]A=6000(1.012)^t[/tex]


A restaurant is doing a special on burgers. If the home team get a sack, the next day, burgers will cost$1
Normally, they cost $3,99. If every fan who attended the game (86,047 people) buys a $1.00 burger, how™
money did the restaurant lose with this discount?

Answers

ans: 257,256.59

if it was sold for $3.99

it would have been 86,047 × $3.99 = 343,303.59 and it was sold for $1 instead so automatically it's $86,047

therefore

343, 303.59

-86, 047 which is equal to a loss of $257, 256.59

here is my question hope this works now

Answers

Answer:

[tex]\boxed{x=1}[/tex] and [tex]\boxed{x=7}[/tex]

Step-by-step explanation:

This quadratic is already factored down to its factors (x - 1) and (x - 7).

Set these equal to zero and solve for x by adding 1 or 7 to both sides of the equation.

[tex]x-1=0\\\\\boxed{x=1}[/tex]

[tex]x-7=0\\\\\boxed{x=7}[/tex]

Help me please answer this, this will be my first grade for freshman year. The picture of the question is down below.

Answers

Answer:

D

Step-by-step explanation:

-0.81 is a high negative correlation, which means the y is decreasing with x increasing, which means y(the number of broken glass) decreases when x(amount of paper used) increased. So we can say that the toilet paper is surely helping.

make me brainly if you find it correct

in the diagram, POS,QOT and UOR are straight lines. Find the value of y.​

Answers

Answer:

y = 15°

Step-by-step explanation:

Since ∠QOR and ∠UOT are vertical, they are congruent so ∠UOT = 5y. Since POS is a straight line (which has a measure of 180°) and ∠POS = ∠POU + ∠UOT + ∠TOS, we can write:

5y + 5y + 2y = 180

12y = 180

y = 15°

17. what is the value of x?

18. what is the value of z?

please help me fast!!

Answers

for x ,

8x + 10x = 180°

[sum of linear pair is equal to 180°]

or, 18x = 180°

or, x = 180/18

therefore, x = 10°……

for z,

10z =8x

[ being corresponding angles are equal ]

or, 10z = 8 × 10°

( replacing x by 10°)

or, 10z = 80°

or, z = 80/10

thus z = 8°…………

Fuller bought 4 cantaloupes at the grocery store. Each cantaloupe weighed between 4.5 and 6.3 pounds. Fuller estimates a reasonable weight of all the cantaloupes to be 21.2 pounds.

Answers

Answer:

Step-by-step explanation:

3w + 2c = 32

4w + 3c = 44

Multiply the 1st equation by 4 and 2nd equation by 3, we get:

12w + 8 c = 128

12w + 9 c = 132

Subtracting the top equation from the bottom equation, we get: c = 4

Substituting c = 4 in any one of the above equations and solving, we get: w = 8

Therefore, weight of 2w + 1c = 2(8) + 4 = 20 pounds (Answer)

If P is the midpoint of XY, XP = 8x - 2 and PY = 12x - 30, find the
value of x.

Answers

Answer:

x=7

Step-by-step explanation:

If P is the midpoint of XY, then XP = PY:

8x - 2 = 12x - 3012x -8x = 30 -24x = 28x= 28/4x= 7

Layla is going to drive from her house to City A without stopping. Layla plans to drive
at a speed of 30 miles per hour and her house is 240 miles from City A. Write an
equation for D, in terms of t, representing Layla's distance from City A t hours after
leaving her house.

Answers

Answer:

D = 240 - 30t

Step-by-step explanation:

If the equation represents her distance from City A, we need to include 240 in the equation to represent the distance to the city.

Then, we need to subtract 30t from 240 in the equation because 30t represents how far she will have traveled in t hours.

So, D = 240 - 30t is the equation that will represent Layla's distance from the city.

0.18 divided by 0.04

Answers

If you plug that into a calculator you get 4.5
0.45 is just a normal division

The heat evolved in calories per gram of a cement mixture is approximately normally distributed. The mean is thought to be 100, and the standard deviation is 2. You wish to test H0: μ = 100 versus H1: μ ≠ 100 with a sample of n = 9 specimens.
A. If the acceptance region is defined as 98.5 le x- 101.5, find the type I error probability alpha.
B. Find beta for the case where the true mean heat evolved is 103.
C. Find beta for the case where the true mean heat evolved is 105. This value of beta is smaller than the one found in part (b) above. Why?

Answers

Answer:

A.the type 1 error probability is [tex]\mathbf{\alpha = 0.0244 }[/tex]

B. β  = 0.0122

C. β  = 0.0000

Step-by-step explanation:

Given that:

Mean = 100

standard deviation = 2

sample size = 9

The null and the alternative hypothesis can be computed as follows:

[tex]\mathtt{H_o: \mu = 100}[/tex]

[tex]\mathtt{H_1: \mu \neq 100}[/tex]

A. If the acceptance region is defined as [tex]98.5 < \overline x > 101.5[/tex] , find the type I error probability [tex]\alpha[/tex] .

Assuming the critical region lies within [tex]\overline x < 98.5[/tex] or [tex]\overline x > 101.5[/tex], for a type 1 error to take place, then the sample average x will be within the critical region when the true mean heat evolved is [tex]\mu = 100[/tex]

[tex]\mathtt{\alpha = P( type \ 1 \ error ) = P( reject \ H_o)}[/tex]

[tex]\mathtt{\alpha = P( \overline x < 98.5 ) + P( \overline x > 101.5 )}[/tex]

when  [tex]\mu = 100[/tex]

[tex]\mathtt{\alpha = P \begin {pmatrix} \dfrac{\overline X - \mu}{\dfrac{\sigma}{\sqrt{n}}} < \dfrac{\overline 98.5 - 100}{\dfrac{2}{\sqrt{9}}} \end {pmatrix} + \begin {pmatrix}P(\dfrac{\overline X - \mu}{\dfrac{\sigma}{\sqrt{n}}} > \dfrac{101.5 - 100}{\dfrac{2}{\sqrt{9}}} \end {pmatrix} }[/tex]

[tex]\mathtt{\alpha = P ( Z < \dfrac{-1.5}{\dfrac{2}{3}} ) + P(Z > \dfrac{1.5}{\dfrac{2}{3}}) }[/tex]

[tex]\mathtt{\alpha = P ( Z <-2.25 ) + P(Z > 2.25) }[/tex]

[tex]\mathtt{\alpha = P ( Z <-2.25 ) +( 1- P(Z < 2.25) })[/tex]

From the standard normal distribution tables

[tex]\mathtt{\alpha = 0.0122+( 1- 0.9878) })[/tex]

[tex]\mathtt{\alpha = 0.0122+( 0.0122) })[/tex]

[tex]\mathbf{\alpha = 0.0244 }[/tex]

Thus, the type 1 error probability is [tex]\mathbf{\alpha = 0.0244 }[/tex]

B. Find beta for the case where the true mean heat evolved is 103.

The probability of type II error is represented by β. Type II error implies that we fail to reject null hypothesis [tex]\mathtt{H_o}[/tex]

Thus;

β = P( type II error) - P( fail to reject [tex]\mathtt{H_o}[/tex] )

[tex]\mathtt{\beta = P(98.5 \leq \overline x \leq 101.5) }[/tex]

Given that [tex]\mu = 103[/tex]

[tex]\mathtt{\beta = P( \dfrac{98.5 -103}{\dfrac{2}{\sqrt{9}}} \leq \dfrac{\overline X - \mu}{\dfrac{\sigma}{n}} \leq \dfrac{101.5-103}{\dfrac{2}{\sqrt{9}}}) }[/tex]

[tex]\mathtt{\beta = P( \dfrac{-4.5}{\dfrac{2}{3}} \leq Z \leq \dfrac{-1.5}{\dfrac{2}{3}}) }[/tex]

[tex]\mathtt{\beta = P(-6.75 \leq Z \leq -2.25) }[/tex]

[tex]\mathtt{\beta = P(z< -2.25) - P(z < -6.75 )}[/tex]

From standard normal distribution table

β  = 0.0122 - 0.0000

β  = 0.0122

C. Find beta for the case where the true mean heat evolved is 105. This value of beta is smaller than the one found in part (b) above. Why?

[tex]\mathtt{\beta = P(98.5 \leq \overline x \leq 101.5) }[/tex]

Given that [tex]\mu = 105[/tex]

[tex]\mathtt{\beta = P( \dfrac{98.5 -105}{\dfrac{2}{\sqrt{9}}} \leq \dfrac{\overline X - \mu}{\dfrac{\sigma}{n}} \leq \dfrac{101.5-105}{\dfrac{2}{\sqrt{9}}}) }[/tex]

[tex]\mathtt{\beta = P( \dfrac{-6.5}{\dfrac{2}{3}} \leq Z \leq \dfrac{-3.5}{\dfrac{2}{3}}) }[/tex]

[tex]\mathtt{\beta = P(-9.75 \leq Z \leq -5.25) }[/tex]

[tex]\mathtt{\beta = P(z< -5.25) - P(z < -9.75 )}[/tex]

From standard normal distribution table

β  = 0.0000 - 0.0000

β  = 0.0000

The reason why the value of beta is smaller here is that since the difference between the value for the true mean and the hypothesized value increases, the probability of type II error decreases.

evaluate the expression for -c-12=

Answers

Answer:

-10

Step-by-step explanation:

We can substitute c into the equation as -2.

[tex]-(-2) - 12[/tex]

Two negatives make a positive:

[tex]2-12[/tex]

And [tex]2 - 12 = -10[/tex].

Hope this helped!

Which of the following correctly shows the quotient of 80 divided by 5 ?

Answers

Answer:16

Step-by-step explanation:

Just divide 80 by 5 or skip count by fives.

Complete the function table

Answers

The correct answer is A

6. A car dealership would like to estimate the mean mpg of its new model car with 90% confidence. The population is normally distributed; however we are taking a sample of 25 cars with a sample mean of 96.52 and a sample standard deviation of 10.70. Calculate a 90% confidence interval for the population mean using this sample data.

Answers

Answer:

92.9997<[tex]\mu[/tex]<99.5203

Step-by-step explanation:

Using the formula for calculating the confidence interval expressed as:

CI = xbar ± Z * S/√n where;

xbar is the sample mean

Z is the z-score at 90% confidence interval

S is the sample standard deviation

n is the sample size

Given parameters

xbar = 96.52

Z at 90% CI = 1.645

S = 10.70.

n = 25

Required

90% confidence interval for the population mean using the sample data.

Substituting the given parameters into the formula, we will have;

CI = 96.52 ± (1.645 * 10.70/√25)

CI = 96.52 ± (1.645 * 10.70/5)

CI = 96.52 ± (1.645 * 2.14)

CI = 96.52 ± (3.5203)

CI = (96.52-3.5203, 96.52+3.5203)

CI = (92.9997, 99.5203)

Hence a 90% confidence interval for the population mean using this sample data is 92.9997<[tex]\mu[/tex]<99.5203

Ashley, Milan, and Carlos sent a total of 131 text messages over their cell phones during the weekend. Carlos sent 7 times as many messages as Ashley. Ashley sent 4 more messages than Milan. How many messages did they each send?

Answers

Answer:

Ashley= 15

Milan= 11

Carlos= 105

Step-by-step explanation:

Let, A, M and C denotes Ashley, Milan and Carlos respectively.

A+M+C= 131 (according to the question)

Here,

C= 7A

A= M+ 4

So, M= A - 4

Now,

A+M+C = 131

or, A+ A-4+ 7A = 131 (putting the values)

or, 9A - 4 = 131 (adding like terms i.e. A + A + 7A)

or, 9A = 131 + 4

or, 9A = 135

or, A = 135 / 9

So, A = 15

C= 7A = 7×15= 105

M= A-4 = 15 - 4 = 11

f=((-1,1),(1,-2),(3,-4)) g=((5,0),(-3,4),(1,1),(-4,1)) find (fg)(1)

Answers

Answer:

f(g(1)) = - 2

Step-by-step explanation:

Find g(1) then use the value obtained to find f(x)

g(1) = 1 ← value of y when x = 1 (1, 1 ) , then

f(1) = - 2 ← value of y when x = 1 (1, - 2 )

Lillie is saving up for a trip she is taking with friends during her break from school. If Lillie's current monthly net pay is $560.00 and her monthly expenses are $347.49, what percent of her net pay is left for savings? (2 points)
19%
23%
38%

Answers

Answer:

38%

Step-by-step explanation:

First determine her savings

560-347.49

212.51

Then divide by the total amount

212.51/560

.379482143

Change to percent form

37.948%

Answer:

38%

Step-by-step explanation:

[tex]560.00-347.49=212.51\\212.51\div560.00==38[/tex]

PLS PLS PLS HELP QUICKKKK

Find the value of x in each case

Answers

Answer:

KI and HE are parallel

So we apply the law of exterior angles ;

3X=X + 180– 2X

3X +X = 180

4X= 180

X= 180/4

X= 45

I hope I helped you^_^

[tex]\int\limits^9_3 {\frac{1}{(x+21)\sqrt{x+22} } } \, dx[/tex]

Answers

Let y = x + 22 and dy = dx, so the integral becomes

[tex]\displaystyle \int_3^9 \frac{\mathrm dx}{(x+21)\sqrt{x+22}} = \int_{25}^{31} \frac{\mathrm dy}{(y-1)\sqrt{y}}[/tex]

Now let z = √y, so that z ² = y. Then 2z dz = dy, and the integral becomes

[tex]\displaystyle \int_3^9 \frac{\mathrm dx}{(x+21)\sqrt{x+22}} = \int_{\sqrt{25}}^{\sqrt{31}} \frac{2z}{(z^2-1)z} \\\\ = \int_5^{\sqrt{31}} \frac{2}{z^2-1}\,\mathrm dz[/tex]

Expand the integrand into partial fractions:

[tex]\dfrac{2}{z^2-1} = \dfrac1{z-1}-\dfrac1{z+1}[/tex]

Then we have

[tex]\displaystyle \int_3^9 \frac{\mathrm dx}{(x+21)\sqrt{x+22}} = \int_5^{\sqrt{31}}\left(\frac1{z-1}-\frac1{z+1}\right)\,\mathrm dz \\\\ = \left(\ln|z-1|-\ln|z+1|\right)\bigg|_5^{\sqrt{31}} \\\\ =\left[\ln\left|\frac{z-1}{z+1}\right|\right]\bigg|_5^{\sqrt{31}} \\\\ =\ln\left(\frac{\sqrt{31}-1}{\sqrt{31}+1}\right) - \ln\left(\frac{4}{6}\right) \\\\ =\ln\left(32-2\sqrt{31}\right) - \ln\left(\frac23\right) \\\\ =\boxed{\ln\left(48-3\sqrt{31}\right)}[/tex]

Determine the positive integer values of k for which the following polynomia
over the integers given: c^2 – 7c+ k

Answers

Answer: k = 10, 12, 6

Explanation:

c^2 - 7c + 10
= (c -5)(c-2)

c^2 - 7c + 12
= (c - 4)(c -3)

c^2 - 7c + 6
= (c - 1)(c - 6)

Players A and B play a basketball game in which they take turns shooting the ball, and the first player to make their shot wins. Player A has probability 2/3 of making each of her shots. Player B has probability 1/2 of making each of his shots. If Player A shoots first, what is the probability that she will win

Answers

Answer:

Player A has a probability 2/3 of making each of her shots, then she has a probability 1/3 of missing each shot.

Player B has a probability 1/2 of making each of his shots, then he also has a probability 1/2 of missing each shot.

Let's separate each case.

Let's define:

P(x) = probability of winning at the "x" shot.

Player A wins on the first shot.

Because she has a probability 2/3 of making each of her shots, the probability of winning at the first shot is

P(1) = 2/3

Now let's see the next case, player A wins at her second shot.

This means that first, she misses her first shot, with a probability of:

p₁ = 1/3

Player B must miss his shot, the probability is:

p₂ = 1/2

Now player A must make her shot, so the probability is:

p₃ = 2/3

The joint probability is the product of the individual probabilities, so we have:

P(2) = (1/3)*(1/2)*(2/3) = 1/9

Now we can see the pattern, for P(3) we have

A misses: p₁ = 1/3    (first shot of A)

B misses: p₂ = 1/2

A misses: p₃ = 1/3   (Second shot of A)

B misses: p₄ = 1/2

A makes the shot: p₅ = 2/3

P(3) =  (1/3)*(1/2)*(1/3)*(1/2)*(2/3) = 1/54

We already can see the pattern.

P(n) = (1/3)^(n - 1)*(1/2)*(n - 1)*(2/3)

Player A has a probability P of winning, and we can write P as:

P = P(1) + P(2) + P(3) + ...

Then we will have:

P = 2/3 + 1/9 + 1/54 + 1/324 + ... ≈ 0.8

It can be shown that the line with intercepts (a, 0) and (0, b) has the following equation:
x/a + y/b= 1, a ≠ 0, b ≠ 0.

Use this result to write an equation of the line.

Point on line:

(−2, 4)

x-intercept: (a, 0)

y-intercept: (0, a)

(a ≠ 0)

Answers

The equation of the straight line is [tex]x+y=2[/tex].

Given:

The line with intercepts (a,0) and (0,b) has the equation [tex]\frac{x}{a} +\frac{y}{b} =1, a\neq 0, b\neq 0[/tex] Point on the line: (-2, 4)x-intercept: (a, 0)y-intercept: (0, a)[tex]a\neq 0[/tex]

To find: The equation of this line

It is given that a line with intercepts (a,0) and (0,b) has the equation [tex]\frac{x}{a} +\frac{y}{b} =1, a\neq 0, b\neq 0[/tex]

Now, it is given that the referred line has intercepts (a, 0) and (0, a). Then, using the above statement, the equation of this line can be written as,

[tex]\frac{x}{a} +\frac{y}{a}=1[/tex]. It is already given that [tex]a\neq 0[/tex]. So, we need not mention it again.

It is also given that the point (-2, 4) lies on this line. Then, the coordinates of this point must satisfy the equation of the line.

This implies that,

[tex]\frac{-2}{a} +\frac{4}{a} =1[/tex]

[tex]\frac{2}{a} =1[/tex]

[tex]a=2[/tex]

Now, put [tex]a=2[/tex] in the equation of the line, [tex]\frac{x}{a} +\frac{y}{a}=1[/tex] to get,

[tex]\frac{x}{2} +\frac{y}{2} =1[/tex]

[tex]x+y=2[/tex]

So, the equation of the line is [tex]x+y=2[/tex].

Learn more about equations of straight lines here:

https://brainly.com/question/18879008

If f(x) = 3x-1 and g(x)= x+2 find (f-g) (x)

Answers

Answer:

2x-3

Step-by-step explanation:

f(x) = 3x-1

g(x)= x+2

(f-g) (x) = 3x-1 - (x+2)

Distribute the minus sign

             = 3x-1 -x-2

 Combine like terms

               = 3x-x -1-2

                =2x -3

what is the decimal equivalent of 7/20

Answers

7/20 x 5= 35/100
35/100= .35
Other Questions
If it is determined that your procurement scenario will not be conducted using full and open competition you are prohibited from purchasing a non-domestic product.A. TrueB. False A 80 kg bungee jumper is on a bridge that is 100 meters above a river. Attached to the jumper is a bungee cord that is 50 meters long. After jumping off of the bridge, the jumper reaches a position that is 10 meters above the river when the bungee cord is at its maximum stretch.Required:a. How much energy is stored in the bungee cord at that maximum stretch?b. What is the spring force constant of the bungee cord? Select the sentence that uses standard English to communicate the message:O Cant wait!O B there soonBest. Party. Evar.O I'm looking forward to the party. You have tickets to go to Jamaica over spring break. Just this week your best friend informs you that he (she) is getting married over spring break. Your friend would like you to stay back in the city and be the wedding attendant. The tickets to Jamaica are nonrefundable. Which of the following is a sunk cost relating to your decision of attending the wedding or going on the trip to Jamaica?a. The cost of wedding gift. b. The cost of the airline tickets to Jamaica. c. The cost of the clothing you will have to buy/rent to be in the wedding. d. The cost of the rent on your apartment for the month - Which of the following is the correct distance between the points (-5, 3) and (7,8)? How did growers in the South attempt to rebuild their cotton market?O Produced more cottonO Raised the price of cottonO Hired more laborersO Sold their land Cash Payback Method Lily Products Company is considering an investment in one of two new product lines. The investment required for either product line is $540,000. The net cash flows associated with each product are as follows: Year Liquid Soap Body Lotion 1 $170,000 $90,000 2 150,000 90,000 3 120,000 90,000 4 100,000 90,000 5 70,000 90,000 6 40,000 90,000 7 40,000 90,000 8 30,000 90,000 Total $720,000 $720,000 A. Recommend a product offering to Lily Products Company, based on the cash payback period for each product line. Payback period for liquid soap Payback period for body lotion B. The project with the_____net cash flows in the early years of the project life will be favored over the one with the______net cash flows in the initial years. 32. Identify all real and non-real zeros of the function f(x) = x^3 + 5x^2 + 3x + 15. options: A. x = 0, 5, 1.7i, 1.7i B. x = 0,5, 1.7i C. x = 5, 1.7i, 1.7i D. x = 0,3, 5 Kate wants to paddleher canoe across the lake. To determine how far she must paddle, she paced out a triangle,counting the number of strides, as shown.If Kate's strides average 3.5 ft, what is thelength of the longest side of the triangle?What distance must Kate paddle acrossthe lake? I've known1 my new neighbours.2 Anna for over ten years. On January 1, Year 2, Kincaid Company's Accounts Receivable and the Allowance for Doubtful Accounts carried balances of $71,000 and $2,900, respectively. During the year Kincaid reported $190,000 of credit sales. Kincaid wrote off $1,750 of receivables as uncollectible in Year 2. Cash collections of receivables amounted to $227,700. Kincaid estimates that it will be unable to collect one percent (1%) of credit sales. The net realizable value of receivables appearing on Kincaid's Year 2 balance sheet will amount to: a) $29,650. b) $28,500. c) $33,300. d) $31,550. Express the distance between the given numbers using absolute value. Then find the distance by evaluating the absolute value expression.-7.5 and 5.4 What similarities can you find in the life of Jesus, and your own life? in the 1500s, how did the church of England differ from the Catholic Church? The Federal Reserve Board foresees the probability of an overheated economy and the resumption of double-digit inflation. Therefore, the FRB takes actions to slow down the economy, including increasing the discount rate. Which of the following are likely effects of these moves?i An increase in the prime rate.ii An increase in bond yields and an accompanying decrease in bond prices.iii A slowdown in corporate growth.iv A decrease in corporate earnings.A) III and IV.B) I, II, III and IV.C) I and II.D) I, III and IV. Help me please An inequality is shown: np 4 2(c 3) Which of the following solves for n? What kind of suffering is worse in The Giverphysical or emotional? It takes a graphic designer 1.5h to make one page of a website. Using a new software, the designer could complete each page in 1.25h, but it takes 8h to learn the software. How many web pages would the designer have to make in order to save time using the new software? The four wheels of a car are connected to the car's body by spring assemblies that let the wheels move up and down over bumps and dips in the road. When a 68 kg (about 150 lb) person sits on the left front fender of a small car, this corner of the car dips by about 1.2 cm (about 1/2 in). If we treat the spring assembly as a single spring, what is the approximate spring constant? k= ____________