Answer:
18 kids
Step-by-step explanation:
ANSWER THIS ASAP DONT SEND A FILE AT ALL !! I NEED THE QUICK ONLY ANSWER IF YOU REALY KNOW !!
Answer: 90% of people marry there 7th grade love. since u have read this, u will be told good news tonight. if u don't pass this on nine comments your worst week starts now this isn't fake. apparently if u copy and paste this on ten comments in the next ten minutes you will have the best day of your life tomorrow. you will either get kissed or asked out in the next 53 minutes someone will say i love you.
Step-by-step explanation:
HELP!!! WILL GIVE BRAINLIEST +LIKE AND 5 STARS ANSWER THE QUESTION IN THE PICTURE
Answer:
omg lol look at the picture are u that guy
Step-by-step explanation:
its me from web2.0 :KOBE2482
D its D
22. Using the graph, state the approximate
x-intercept of the function?
a. (0, -1)
b. (0.5, 0)
C. (-1,-1.75)
d. (1, 2)
Answer:
I believe Awnser B.. (0.5, 0)
Step-by-step explanation:
Is the equation a linear function?
y = -x + 3 +
What is the value of x
Answer:
awnser is 36
Step-by-step explanation:
Answer: x = 37
Step-by-step explanation:
you can use the pythagorean theorem to solve this:
[tex]a^{2} + b^{2} = c^{2}[/tex]
'a' and 'b' in the equation is referring to the legs of the right triangle, or the sides adjacent to the hypotenuse (which is the side opposite the right angle)
plug in the legs into the equation and you get :
[tex]12^{2} + 35^{2} = x^{2}[/tex]
now to solve that we just square 12 and 35 and you get
144 + 1225 = [tex]x^{2}[/tex]
1369 = [tex]x^{2}[/tex]
x = [tex]\sqrt{1369}[/tex]
x= 37
:))
HELP!! I WILL give Brainly!! LINKS WILL BE REPORTED. THANK YOU!!
Answer:
E
Step-by-step explanation:
We can see that the graph is shifted up 3 units
to do this you need to add 3 to the equaton
it's E
two thousand twelve and thirty-two thousandths in standard form
Answer:
2012.032
Step-by-step explanation:
2012.032
The following is a linear programming formulation of a labor planning problem. There are four overlapping shifts, and management must decide how many employees to schedule to start work on each shift. The objective is to minimize the total number of employees required while the constraints stipulate how many employees are required at each time of day. The variables X1 - X4 represent the number of employees starting work on each shift (shift 1 through shift 4).
MIN X1 + X2 + X3 + X4
s.t. X1 + X4 ≥ 12 ........(on duty during shift 1)
X1 + X2 ≥ 15 ........(on duty during shift 2)
X2 + X3 ≥ 16 ........(on duty during shift 3)
X3 + X4 ≥ 14 ........(on duty during shift 4)
X1, X2, X3, and X4 ≥ 0
Given the optimal solution: X1* = 13, X2* = 2, X3* = 14, X4* = 0, how many workers would be assigned to shift 2?
a. 13
b. 12
c. 14
d. 15
e. 2
Answer:
d. 15
Step-by-step explanation:
Putting the values in the shift 2 function
X1 + X2 ≥ 15
where x1= 13, and x2=2
13+12≥ 15
15≥ 15
At least 15 workers must be assigned to the shift 2.
The LP model questions require that the constraints are satisfied.
The constraint for the shift 2 is that the number of workers must be equal or greater than 15
This can be solved using other constraint functions e.g
Putting X4= 0 in
X1 + X4 ≥ 12
gives
X1 ≥ 12
Now Putting the value X1 ≥ 12 in shift 2 constraint
X1 + X2 ≥ 15
12+ 2≥ 15
14 ≥ 15
this does not satisfy the condition so this is wrong.
Now from
X2 + X3 ≥ 16
Putting X3= 14
X2 + 14 ≥ 16
gives
X2 ≥ 2
Putting these in the shift 2
X1 + X2 ≥ 15
13+2 ≥ 15
15 ≥ 15
Which gives the same result as above.
A journal article reports that a sample of size was used as a basis for calculating a CI for the true average natural frequency (Hz) of delaminated beams of a certain type. The resulting interval was . You decide that a confidence level of is more appropriate than the level used. What are the limits of the interval
Answer:
The limit of the (228.533, 234.735)
Step-by-step explanation:
The values are missing in the given question. Therefore, in order to attempt this question, we will make assumptions.
So, let's assume that:
sample size of the journal article that was reported = 5
which is applied for determining a 95% CI
Also, assuming that the resulting interval = (229.764, 233.504)
However, if we are to use a 99% CI which we deemed to be more appropriate;
Then, our objective is to find the limits of this particular interval in question.
To do that:
We need to first find the sample mean at 95% CI by using the formula:
[tex]\Big ( \bar {x} - t_{\alpha/2, df} \ \dfrac{s}{\sqrt{n}}}, \bar x + t_{\alpha/2, df} \ \dfrac{s}{\sqrt{n}}} \Big) = (229.764,233.504)[/tex]
Since; df = n - 1
df = 5 - 1
df = 4
Then;
[tex]\Big ( \bar {x} - t_{\alpha/2, 4} \ \dfrac{s}{\sqrt{n}}}, \bar x + t_{\alpha/2, 4} \ \dfrac{s}{\sqrt{n}}} \Big) = (233.504+229.764)[/tex]
[tex]2 \bar {x} = (463.268)[/tex]
[tex]\bar {x} =\dfrac{463.268}{2 }[/tex]
[tex]\bar {x} =231.634[/tex]
Sample mean = 231.634
Using the same formula to determine the standard deviation, we have:
[tex]\Big ( \bar {x} - t_{\alpha/2, df} \ \dfrac{s}{\sqrt{n}}}, \bar x + t_{\alpha/2, df} \ \dfrac{s}{\sqrt{n}}} \Big) = (229.764,233.504)[/tex]
[tex]\Big ( \bar {x} - t_{\alpha/2, 4} \ \dfrac{s}{\sqrt{n}}}, \bar x + t_{\alpha/2, 4} \ \dfrac{s}{\sqrt{n}}} \Big) = (233.504-229.764)[/tex]
[tex]\Big ( (\bar x + t_{\alpha/2, 4} \ \dfrac{s}{\sqrt{n}}} )- (\bar {x} - t_{\alpha/2, 4} \ \dfrac{s}{\sqrt{n}}}) \Big) = (233.504-229.764)[/tex]
[tex]\Big ( (\bar x + t_{0.05/2, 4} \ \dfrac{s}{\sqrt{4}}} )- (\bar {x} - t_{0.05/2, 4} \ \dfrac{s}{\sqrt{5}}}) \Big) = (233.504-229.764)[/tex]
At t = 0.025 and df = 4; = 2.776
[tex]2\times 2.776 \dfrac{s}{\sqrt{5}}= 3.74[/tex]
[tex]5.552 \dfrac{s}{\sqrt{5}}= 3.74[/tex]
[tex]\dfrac{s}{\sqrt{5}}= \dfrac{ 3.74}{5.552}[/tex]
[tex]\dfrac{s}{\sqrt{5}}= 0.6736[/tex]
[tex]s = 0.6736 \times \sqrt{5}[/tex]
s = 1.5063
The 99% CI is:
[tex]\implies \Big(\bar x \pm t_{\alpha/2,4} \dfrac{s}{\sqrt{n}} \Big)[/tex]
At t =0.005 and df =4; = 4.604
[tex]\implies \Big(231.634 \pm 4.604 \dfrac{1.5063}{\sqrt{5}} \Big)[/tex]
[tex]\implies \Big(231.634 \pm 4.604 (0.67364) \Big)[/tex]
[tex]\implies \Big(231.634 \pm 3.1014 \Big)[/tex]
[tex]\implies \Big((231.634 - 3.1014), (231.634 + 3.1014) \Big)[/tex]
[tex]\implies \Big( 228.533, 234.735 \Big)[/tex]
brainliest for answer
Answer:
im not gonna help u~ but i can talk to u~ <3
Step-by-step explanation:
Find the area of each circle. Round to the nearest tenth. Use 3.14 for π.
Answer:
1. 490.6 mm²
2. 14.1 ft²
Step-by-step explanation:
1. 3.14×(12.5)²= 3.14 × 156.25 =490.6mm²
2. ½×3.14×3²= 3.14×4.5= 14.1 ft²
If j ll k which could be one of the angle measures
A.25
B.37
C.60
D.84
Answer:
Hii friend
I am from India and u ??
Roshini here !!!!
Find sin S, sin R,cos S, and cos R.
Answer:
sin S = 9/13
sin R= 8/13
cos S= 8/13
cos R= 9/13
3. Which of the following is the solution for
the inequality below?
-3x+2<8
A x>-3
C x < -2
B x>-2
DX<-3
A fence is 8.5 feet tall. How many inches tall is it?
Answer:
The answer is 102, good luck<3
find value of x
3x (x+28)
Answer:
The value of x is 14.
Step-by-step explanation:
3x° = (x + 28)° [ vertically opposite angles
are equal]
3x = x + 28°
3x - x = 28°
2x = 28°
x = 28°/2
x = 14°
at party the pumpkin pie is cut into 14 slices and the cherry pies cut into seven slices if the host wants to serve identical plates that contained the same combination of pumpkin and Cherry sizes with no slices leftover what is the greatest number of plates the host can prepare
Answer:
The host can only prepare 7 plates
Step-by-step explanation:
7 plates, each will contain 1 slice of cherry pie and 2 slices of pumpkin pie. (14/7 = 2)
pls pls pls 4/1 68 The angle that is an alternate exterior angle with angle 2 is angle [?] 57 3/2 A. 3 B. 4 C. 5 D. 6
Answer:
B. 4
Step-by-step explanation:
∠4 is an alternate exterior angle with ∠2 because both angles are on the exterior of the lines, and lie on opposite ends on the transversal.
The angle that is an alternate exterior angle with angle 2 is angle 4.
What are Parallel lines?Parallel lines are those lines that are equidistance from each other and never intersect each other.
Given that;
The figure is shown in figure.
Now,
Since, ∠4 is an alternate exterior angle with ∠2 because both angles are on the exterior of the lines, and lie on opposite ends on the transversal.
Hence, ∠4 is an alternate exterior angle with angle 2.
Thus, The angle that is an alternate exterior angle with angle 2 is angle 4.
Learn more about the parallel lines visit:
https://brainly.com/question/26961508
#SPJ2
Write 0.000 376 in standard form.
Answer:
0.000376 in standard form
=3.76×10^-4
I’ll make brainly if the answer is right
Solve.
–51/2 + 63/4 + (-41/4)
Answer:
-20
Step-by-step explanation:
cause i did the math hope this helped :D
I used a calculator, the answer is
-20
Worth 10 please help
Answer:
b,c and A
Step-by-step explanation:
Answer:
Honestly I dont really know
Step-by-step explanation:
A Survey of 85 company employees shows that the mean length of the Christmas vacation was 4.5 days, with a standard deviation of 1.2 days. Construct a 95% confidence interval for the population's mean length of vacation. ( , ) Round your answer to two decimal digits Construct a 92% confidence interval for the population's mean length of vacation. ( , ) Round your answer to two decimal digits
Answer:
The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).
The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).
Step-by-step explanation:
We have the standard deviations for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 85 - 1 = 84
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 84 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 1.989.
The margin of error is:
[tex]M = T\frac{s}{\sqrt{n}} = 1.989\frac{1.2}{\sqrt{85}} = 0.26[/tex]
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.26 = 4.24 days
The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.26 = 4.76 days
The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).
92% confidence interval:
Following the sample logic, the critical value is 1.772. So
[tex]M = T\frac{s}{\sqrt{n}} = 1.772\frac{1.2}{\sqrt{85}} = 0.23[/tex]
The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.23 = 4.27 days
The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.23 = 4.73 days
The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).
Find the zeros
[tex]x^3+8x^2-20x+48[/tex]
Answer:
Graph each side of the equation. The solution is the x-value of the point of intersection.
x≈−10.37392996
Step-by-step explanation:
Consider the following series.
1/4 + 1/8 + 1+12 + 1/16 + 1/20.....
Required:
Determine whether the geometric series is convergent or divergent.
Answer:
The series is convergent.
Step-by-step explanation:
1/4 + 1/8 + 1+12 + 1/16 + 1/20
In each term, the numerator stays 1, while the denominator is multiplied by 4. Thus, the series is given by:
[tex]\sum_{n=1}^{\infty} \frac{1}{4n}[/tex]
Convergence test:
We compare the sequence of this test, [tex]f_n = \frac{1}{4n}[/tex], with a sequence [tex]g_n = \frac{1}{n}[/tex].
If [tex]\lim_{n \rightarrow \infty} \frac{f_n}{g_n} \neq 0[/tex], the series is convergent. So
[tex]\lim_{n \rightarrow \infty} \frac{f_n}{g_n} = \lim_{n \rightarrow \infty} \frac{\frac{1}{4n}}{\frac{1}{n}} = \lim_{n \rightarrow \infty} \frac{n}{4n} = \lim_{n \rightarrow \infty} \frac{1}{4} = \frac{1}{4} \neq 0[/tex]
As the limit is different of zero, the series is convergent.
if you borrow 900 dollars for 6 years at an annual interest rate of 7% how much will you pay all together
Answer:
$963
Step-by-step explanation:
900 times 1.07=963
23 and 25
how do you do the work?
find the areas of each
9514 1404 393
Answer:
23) 35.77 in²
25) 48.19 cm²
Step-by-step explanation:
Use the appropriate area formula with the given information.
__
23) The area of a triangle is given by the formula ...
A = 1/2bh . . . . . base b, height h
A = 1/2(9.8 in)(7.3 in) = 35.77 in²
__
25) The area of a parallelogram is given by the formula ...
A = bh . . . . . . base b, height h
A = (7.9 cm)(6.1 cm) = 48.19 cm²
_____
The height in each figure is measured perpendicular to the base. This tells you that the length 10.6 cm of the diagonal side of the triangle is not relevant to finding the area.
Answer:
23) 35.77 in2
24) 48.19cm2
Aaliyah invested $350 in an account paying an interest rate of 4% compounded continuously. Assuming no deposits or withdrawals are made, how much money, to the nearest dollar, would be in the account after 20 years?
SsxcAnswer:
Step-by-step explanation:
4. Your best friend's birthday is tomorrow, and you would like to give her an ice cream cone
balloon. The spherical shaped ice cream on top of the cone has a radius of 6 inches. The cone
itself has a diameter of 12 inches and height of 24 inches. How many cubic inches of helium are
nded to fill the entire ice cream cone balloon? Use 3.14 for it.
Answer:
1808.64 IN^3
Step-by-step explanation:
Helium needed = volume of spherical shaped ice cream + volume of cone
Volume of a sphere = 4/3 x pi x r^3
4/3 x 3.14 x 6^3 = 904.32 ft^3
Volume of a cone 1/3 x (nr^2h)
n = 22/7
r = radius = 12/2 = 6
the diameter is the straight line that passes through the centre of a circle and touches the two edges of the circle.
h = height
1/3 x 3.14 x 6^2 x 24 = 904.32
helium needed = 2 x 904.32 = 1808.64 in^3
(Worth 10 points)
Please actually answer this question
Answer:
i belive the correct awnser is A
Step-by-step explanation:
9514 1404 393
Answer:
A figure 1
Step-by-step explanation:
The given equation is in slope-intercept form:
y = mx + b . . . . . . where m is the slope and b is the y-intercept
The slope and y-intercept in your equation are both 2. That means the graph crosses the y-axis at y=2 (above the x-axis), and has a positive slope (goes up to the right.
The two top graphs, figures 1 and 2, show lines with positive slope. Only figure 1 shows a graph with positive slope and a positive y-intercept.