Answer:
254 x 10^5
Step-by-step explanation:
Hope this helps :)
If anything is misunderstood plz comment and I will change to the answer which you give me thank you very much :)
Answer:
2.54 x 10^5
hope this answer helps u ._.
10 - 2x, when x = 3
Answer:
4
Step-by-step explanation:
Plug in 3 as x in the expression:
10 - 2x
10 - 2(3)
10 - 6
= 4
Answer:
4
Step-by-step explanation:
10 - 2x
Let x =3
10 -2(3)
10 -6
4
Can some help with the answer please it’s very much needed and apprIeciated
Answer:
A
Step-by-step explanation:
The degree of the Polynomial is 3
The parallelogram to be a square,x=?
Answer:
7°
Step-by-step explanation:
for this paralellogram to be a square, the sides should be perpendicular.
Woch means that 4x+17° = 45°
● 4x +17° = 45°
Substract 17 from both sides.
● 4x +17°-17° = 45°-17°
● 4x = 28°
Divide both sides by 4
● 4x/4 = 28°/ 4
● x = 7°
The bowling scores for six people are:
27, 142, 145, 146, 154, 162
What is the most appropriate measure of center?
O A. The standard deviation
O B. The range
O C. The median
O D. The mean
Answer: Option D. will be the answer.
Explanation: The bowling scores for six persons have been given as 27, 142, 145, 146, 154, 162.
The most appropriate measure of the center of these scores will be the median.
Here median will be mean of 146 and 146 because number of persons are 6 which is an even number.
So there are two center scores those are 145 and 146 and median =
Option D. will be the answer.
M is the midpoint of HA. The coordinate of His
(3x + 5,3y) and the coordinate of A is (x-1, -y). What is
the coordinate of M?
Step-by-step explanation:
ANSWER:(2x+2,y)
You have 9kg of oats and cup scales that gears of 50g and 200g. How − in three weighings− can you measure 2kg of the oats?
Answer: You will need 8 cup scales
Step-by-step explanation:
kg=1000 grams
2000/250=8
In 8 cups it is possible to measure the 2kg or 2000 grams but in three weighs it is not possible to measure the 2kg or 2000 grams.
What is a fraction?Fraction number consists of two parts, one is the top of the fraction number which is called the numerator and the second is the bottom of the fraction number which is called the denominator.
It is given that:
You have 9kg of oats and cup scales that gears of 50g and 200g.
Total oats need to measure = 9kg
As we know in 1 kg there are 1000 grams.
1 kg = 1000 grams
9kg = 9000 grams
2kg = 2000 grams
Cup scales that gears: 50g and 200g
The number of cups if consider one cup is of 250 grams( = 200 + 50)
Number of cups = 2000/250
Number of cups = 8
In three weighs it is not possible to measure the 2kg or 2000 grams.
Thus, in 8 cups it is possible to measure the 2kg or 2000 grams but in three weighs it is not possible to measure the 2kg or 2000 grams.
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1. Find the length of the side indicated.
6
9.1
?
Answer:
10.9
Step-by-step explanation:
[tex]a^2+b^2=c^2[/tex]
[tex]9.1^2+6^2=c^2[/tex]
[tex]82.81+36=c^2[/tex]
[tex]c^2=118.81[/tex]
[tex]c=\sqrt{118.81} =10.9[/tex]
I need help please help me!
Answer:
36ft³
Step-by-step explanation:
Bottom rectangular prism: 2x2x6=24
Top rectangular prism: 2x2x3=12
24+12=36ft³
Answer:
[tex]\boxed{36ft^3}[/tex]
Step-by-step explanation:
Hey there!
Well to solve for V we need to find the volume of the 2 rectangular prism's given.
Rec#1: 2•3•2 = 12
Rec#2: 6•2•2 = 24
Rec#1 + Rec#2 = V
12 + 24 = 36ft³
Hope this helps :)
3/4 + 20 (2/5 x 4/7)
Answer:
i believe the answer is 5.3
Which of the following theorems verifies that AABC - ASTU?
A. AA
B. HL
C. HA
D. LL
Answer:
AA
Step-by-step explanation:
See In Triangle ABC and Triangle STU
[tex]\because\begin{cases}\sf \angle A=\angle S=90° \\ \sf \angle B=\angle T=31°\end{cases}[/tex]
Hence
[tex]\sf \Delta ABC~\Delta STU(Angle-Angle)[/tex]
By AA similarity triangle ABC is similar to triangle SUT. Therefore, option A is the correct answer.
What are similar triangles?Two triangles are similar if the angles are the same size or the corresponding sides are in the same ratio. Either of these conditions will prove two triangles are similar.
In the given triangle ABC, ∠C=180°-90°-31°
∠C=59°
In the given triangle SUT, ∠U=180°-90°-31°
∠U=59°
Here, ∠B=∠T (Given)
∠C=∠U (Obtained using angle sum property of a triangle)
So, by AA similarity ΔABC is similar to ΔSUT.
Therefore, option A is the correct answer.
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Write a few sentences to describe the picture below. Can you use the words “slide”, “flip”or “turn”in your description?
Answer:
Turn
Step-by-step explanation:
you could say that, "No matter which way you turn the image, it stays the same".
hope this helps :D
Help please, I’m confused about this question.
Answer:
The order, least to greatest, is:
Lemon, Cherry, Grape.
Step-by-step explanation:
Adding all these values up, we get to 1. This means that the smallest values will be the least likely and the highest values will be the most likely.
With the numbers 0.2, 0.16, and 0.64, we can sort these by value.
0.16 is the smallest.
0.2 is the next biggest
and 0.64 is the largest number.
So, the order is Lemon, Cherry, Grape.
Hope this helped!
According the the U.S. Department of Education, full-time graduate students receive an average salary of $15,000 with a standard deviation of $1,200. The dean of graduate studies at a large state university in PA claims that his graduate students earn more than this. He surveys 100 randomly selected students and finds their average salary is $16,000. Use a significance level of 0.05 to test if there is evidence that the dean's claim is correct. What are the hypotheses
Answer:
Step-by-step explanation:
Given that :
population Mean = 15000
standard deviation= 1200
sample size n = 100
sample mean = 16000
The null and the alternative hypothesis can be computed as follows:
[tex]\mathtt{H_o : \mu = 15000 }\\ \\ \mathtt{H_1 : \mu > 15000}[/tex]
Using the standard normal z statistics
[tex]z = \dfrac{\overline X - \mu}{\dfrac{\sigma }{\sqrt{n}}}[/tex]
[tex]z = \dfrac{16000 -15000}{\dfrac{1200 }{\sqrt{100}}}[/tex]
[tex]z = \dfrac{1000}{\dfrac{1200 }{10}}[/tex]
[tex]z = \dfrac{1000\times 10}{1200}[/tex]
z = 8.333
degree of freedom = n - 1 = 100 - 1 = 99
level of significance ∝ = 0.05
P - value from the z score = 0.00003
Decision Rule: since the p value is lesser than the level of significance, we reject the null hypothesis
Conclusion: There is sufficient evidence that the Dean claim for his graduate students earn more than average salary of $15,000
Dean's Claim of Average Salary = 16000, ie greater than 15000 : is correct
Null Hypothesis [ H0 ] : Average Salary = 15000
Alternate Hypothesis [ H1 ] : Average Salary > 15000
Hypothesis is tested using t statistic.
t = ( x - u ) / ( s / √ n ) ; where -
x = sample mean , u = population mean , s = standard deviation, n = sample size
t = ( 16000 - 15000 ) / ( 1200 / √100 )
= 1000 / 120
t {Calculated} = 8.33,
Degrees of Freedom = n - 1 = 100 = 1 = 99
Tabulated t 0.05 (one tail) , at degrees of freedom 99 = 1.664
As Calculated t value 8.33 > Tabulated t value 1.664 , So we reject the Null Hypothesis in favour of Alternate Hypothesis.
So, conclusion : Average Salary > 15000
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A box contains12 balls in which 4 are white,3 blue and 5 are red.3 balls are drawn at random from the box.Find the chance that all three balls are of sifferent color.(answer in three decimal places)
[tex]|\Omega|=_{12}C_3=\dfrac{12!}{3!9!}=\dfrac{10\cdot11\cdot12}{2\cdot3}=220\\|A|=4\cdot3\cdot5=60\\\\P(A)=\dfrac{60}{220}=\dfrac{3}{11}\approx0,273[/tex]
Answer:
0.273
Step-by-step explanation:
Total number of balls is 4+3+5 = 12
There are 6 ways to draw 3 different colors (WBR, WRB, BWR, BRW, RWB, RBW) each with a chance of 4/12 · 3/11 · 5/10 = 1/22
So the total chance is 6 · 1/22 = 6/22 = 3/11 ≈ 0.273
In the diagram below, ΔABC ≅ ΔDEF. Complete the statement AB¯¯¯¯¯¯¯¯≅ __
A. BC
B. DF
C. FE
D. DE
Answer:
The answer would be D. DE
Step-by-step explanation:
same prob
Congruent triangles are exact same triangles, but they might be placed at different positions. The correct option is D.
What are congruent triangles?Suppose it is given that two triangles ΔABC ≅ ΔDEF
Then that means ΔABC and ΔDEF are congruent. Congruent triangles are exact same triangles, but they might be placed at different positions.
The order in which the congruency is written matters.
For ΔABC ≅ ΔDEF, we have all of their corresponding elements like angle and sides congruent.
Thus, we get:
[tex]\rm m\angle A = m\angle D \: or \: \: \angle A \cong \angle D \angle B = \angle E\\\\\rm m\angle B = m\angle E \: or \: \: \angle B \cong \angle E \\\\\rm m\angle C = m\angle F \: or \: \: \angle C \cong \angle F \\\\\rm |AB| = |DE| \: \: or \: \: AB \cong DE\\\\\rm |AC| = |DF| \: \: or \: \: AC \cong DF\\\\\rm |BC| = |EF| \: \: or \: \: BC \cong EF[/tex]
(|AB| denotes the length of line segment AB, and so on for others).
Given that ΔABC ≅ ΔDEF. Therefore, the given sentence can be completed as AB ≅ ΔDE.
Hence, the side AB ≅ ΔDE
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Stuck on this problem
9514 1404 393
Answer:
-8,257,536·u^5·v^10
Step-by-step explanation:
The expansion of (a +b)^n is ...
(c0)a^nb^0 +(c1)a^(n-1)b^1 +(c2)a^(n-2)b^2 +... +(ck)a^(n-k)b^k +... +(cn)a^0b^n
Then the k-th term is (ck)a^(n-k)b^k, where k is counted from 0 to n.
The value of ck can be found using Pascal's triangle, or by the formula ...
ck = n!/(k!(n-k)!) . . . . where x! is the factorial of x, the product of all positive integers less than or equal to x.
This expansion has 11 terms, so the middle one is the one for k=5. That term will be ...
5th term = (10!/(5!(10-5)!)(2u)^(10-5)(-4v^2)^5
= (252)(32u^5)(-1024v^10) = -8,257,536·u^5·v^10
Convert the polar equation to an equivalent rectangular equation:
Answer:
The correct answer will be option b
Step-by-step explanation:
We know that x = rcos( θ ), and y = rsin( θ ), so let's rewrite this polar equation.
r = 4( x / r ) + 2( y / r ),
r = 4x / r + 2y / r,
r = 4x + 2y / r,
r / 1 = 4x + 2y / r ( Cross - Multiply )
4x + 2y = r²
We also know that r² = x² + y², so let's substitute.
x² + y² = 4x + 2y,
x² - 4x - 2y + y² = 0,
Circle Equation : ( x - 2 )² + ( y - 1 )² = ( √5 )²,
Solution : ( x - 2 )² + ( y - 1 )² = 5
A car is traveling 40 kilometers per hour. What is the speed of that car in meters per second?
We have to convert it to m/s
[tex]\boxed{\sf 1km/h=\dfrac{5}{18}m/s}[/tex]
[tex]\\ \sf\longmapsto 40km/h[/tex]
[tex]\\ \sf\longmapsto 40\times \dfrac{5}{18}[/tex]
[tex]\\ \sf\longmapsto \dfrac{200}{18}[/tex]
[tex]\\ \sf\longmapsto 11.1m/s[/tex]
km/h > m/s
when converting km/h to m/s all you need to do is divide by 3.6
and vise versa when converting m/s to km/h multiply by 3.6
so therefore,
40km/h > m/s
= 40 / 3.6
= 11.11 m/s (4sf)
Circle O has a circumference of approximately 28.3 cm. Circle O with radius r is shown. What is the approximate length of the radius, r? 4.5 cm 9.0 cm 14.2 cm 28.3 cm
Answer:
4.5cm
Step-by-step explanation:
Circumference = 2[tex]\pi[/tex]r
28.3=2[tex]\pi[/tex]r
28.3/2[tex]\pi[/tex]=r
4.456
The radius of the circle O is 4.5 cm.
What is radius?A radius is a measure of distance from the center of any circular object to its outermost edge or boundary.
Given that, a circle having a circumference of approximately 28.3 cm, we need to find its radius,
So, Circumference = 2 π × radius
2 π × radius = 28.3
Radius = 28.3 / 2π
Radius = 28.3 / 6.28
Radius = 4.5
Hence, the radius of the circle O is 4.5 cm.
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Is this a function help
One car travels 390 miles in the same amount of time it takes a second car traveling 3 miles per hour slower than
the first to go 372 miles. What are the speeds of the cars?
The speed of the cars are
miles per hour.
PLEASE HELP
If a = -1, b = 2.5, and c = 3, then evaluate a+2[c^(2)-(b+c)].
Answer:
6
Step-by-step explanation:
Let a = -1, b = 2.5, and c = 3.
-1 + 2(3² - (2.5 + 3))
-1 + 2(9 - 5.5)
-1 + 2(3.5)
-1 + 7
6
1
1 point
mZABD = 79
D
C
V
(5x + 4)
(8x - 3)
В B.
A
x= type your answer...
2
1 point
Answer:
x = 6
Step-by-step explanation:
∠ DBC + ∠ ABC = ∠ ABD , substitute values
5x - 4 + 8x - 3 = 79
13x + 1 = 79 ( subtract 1 from both sides )
13x = 78 ( divide both sides by 13 )
x = 6
6x - 10 = 4(x + 3) x = ? x = 9 x = 10 x = 11 x = 12
Answer:
x=11
Step-by-step explanation:
Answer:
x = 11
Step-by-step explanation:
6x - 10 = 4(x+3)
6x - 10 = 4*x + 4*3
6x - 10 = 4x + 12
6x - 4x = 12 + 10
2x = 22
x = 22/2
x = 11
check:
6*11 - 10 = 4(11+3)
66 - 10 = 4*14 = 56
A pharmacy has purchased 550 products over a period of 3 months. If their average inventory was 235 products in a 3 month period what was their inventory turnover rate for this period
Answer:
2.34
Step-by-step explanation:
A pharmacy purchased 550 products over a period of 3 months
The average inventory was 235 products during the period of 3 months
Therefore, the inventory turnover rate for this period can be calculated as follows
= 550/235
= 2.34
Hence the inventory turnover rate for this period is 2.34
Given the exponential function f(x) = 16(0.75)", classify the function as exponential growth or decay and determine the percent rate of growth or decay.
Exponential growth, 75% increase
O Exponential decay, 75% decrease
O Exponential growth, 25% increase
Exponential decay, 25% decrease
Answer:
D
Step-by-step explanation:
To determine if a function is exponential decay or growth, simply look at the rate. If the rate is less than one, it is decay. It it's greater than one, it's growth.
The rate in the given function is 0.75 or 75%. 0.75 is less than one so it's exponential decay.
To determine the percent decrease, simply subtract the rate into 1 or 100%. Thus:
[tex]1-0.75=0.25[/tex]
Therefore, it is a 0.25 or 25% decrease.
The answer is D.
Answer: D
Step-by-step explanation:
1-0.75=0.25
Therefore, it decreases Exponential decay,25 percent decrease
Suppose that X; Y have constant joint density on the triangle with corners at (4; 0), (0; 4), and the origin. a) Find P(X < 3; Y < 3). b) Are X and Y independent
The triangle (call it T ) has base and height 4, so its area is 1/2*4*4 = 8. Then the joint density function is
[tex]f_{X,Y}(x,y)=\begin{cases}\frac18&\text{for }(x,y)\in T\\0&\text{otherwise}\end{cases}[/tex]
where T is the set
[tex]T=\{(x,y)\mid 0\le x\le4\land0\le y\le4-x\}[/tex]
(a) I've attached an image of the integration region.
[tex]P(X<3,Y<3)=\displaystyle\int_0^1\int_0^3f_{X,Y}(x,y)\,\mathrm dy\,\mathrm dx+\int_1^3\int_0^{4-x}f_{X,Y}(x,y)\,\mathrm dy\,\mathrm dx=\frac12[/tex]
(b) X and Y are independent if the joint distribution is equal to the product of their marginal distributions.
Get the marginal distributions of one random variable by integrating the joint density over all values of the other variable:
[tex]f_X(x)=\displaystyle\int_{-\infty}^\infty f_{X,Y}(x,y)\,\mathrm dy=\int_0^{4-x}\frac{\mathrm dy}8=\begin{cases}\frac{4-x}8&\text{for }0\le x\le4\\0&\text{otherwise}\end{cases}[/tex]
[tex]f_Y(y)=\displaystyle\int_{-\infty}^\infty f_{X,Y}(x,y)\,\mathrm dx=\int_0^{4-y}\frac{\mathrm dx}8=\begin{cases}\frac{4-y}8&\text{for }0\le y\le4\\0&\text{otherwise}\end{cases}[/tex]
Clearly, [tex]f_{X,Y}(x,y)\neq f_X(x)f_Y(y)[/tex], so they are not independent.
A manufacturer of computer memory chips produces chips in lots of 1000. If nothing has gone wrong in the manufacturing process, at most 7 chips each lot would be defective, but if something does go wrong, there could be far more defective chips. If something goes wrong with a given lot, they discard the entire lot. It would be prohibitively expensive to test every chip in every lot, so they want to make the decision of whether or not to discard a given lot on the basis of the number of defective chips in a simple random sample. They decide they can afford to test 100 chips from each lot. You are hired as their statistician.
There is a tradeoff between the cost of eroneously discarding a good lot, and the cost of warranty claims if a bad lot is sold. The next few problems refer to this scenario.
Problem 8. (Continues previous problem.) A type I error occurs if (Q12)
Problem 9. (Continues previous problem.) A type II error occurs if (Q13)
Problem 10. (Continues previous problem.) Under the null hypothesis, the number of defective chips in a simple random sample of size 100 has a (Q14) distribution, with parameters (Q15)
Problem 11. (Continues previous problem.) To have a chance of at most 2% of discarding a lot given that the lot is good, the test should reject if the number of defectives in the sample of size 100 is greater than or equal to (Q16)
Problem 12. (Continues previous problem.) In that case, the chance of rejecting the lot if it really has 50 defective chips is (Q17)
Problem 13. (Continues previous problem.) In the long run, the fraction of lots with 7 defectives that will get discarded erroneously by this test is (Q18)
Problem 14. (Continues previous problem.) The smallest number of defectives in the lot for which this test has at least a 98% chance of correctly detecting that the lot was bad is (Q19)
(Continues previous problem.) Suppose that whether or not a lot is good is random, that the long-run fraction of lots that are good is 95%, and that whether each lot is good is independent of whether any other lot or lots are good. Assume that the sample drawn from a lot is independent of whether the lot is good or bad. To simplify the problem even more, assume that good lots contain exactly 7 defective chips, and that bad lots contain exactly 50 defective chips.
Problem 15. (Continues previous problem.) The number of lots the manufacturer has to produce to get one good lot that is not rejected by the test has a (Q20) distribution, with parameters (Q21)
Problem 16. (Continues previous problem.) The expected number of lots the manufacturer must make to get one good lot that is not rejected by the test is (Q22)
Problem 17. (Continues previous problem.) With this test and this mix of good and bad lots, among the lots that pass the test, the long-run fraction of lots that are actually bad is (Q23)
Step-by-step explanation:
A manufacturer of computer memory chips produces chips in lots of 1000. If nothing has gone wrong in the manufacturing process, at most 7 chips each lot would be defective, but if something does go wrong, there could be far more defective chips. If something goes wrong with a given lot, they discard the entire lot. It would be prohibitively expensive to test every chip in every lot, so they want to make the decision of whether or not to discard a given lot on the basis of the number of defective chips in a simple random sample. They decide they can afford to test 100 chips from each lot. You are hired as their statistician.
There is a tradeoff between the cost of eroneously discarding a good lot, and the cost of warranty claims if a bad lot is sold. The next few problems refer to this scenario.
Problem 8. (Continues previous problem.) A type I error occurs if (Q12)
Problem 9. (Continues previous problem.) A type II error occurs if (Q13)
Problem 10. (Continues previous problem.) Under the null hypothesis, the number of defective chips in a simple random sample of size 100 has a (Q14) distribution, with parameters (Q15)
Problem 11. (Continues previous problem.) To have a chance of at most 2% of discarding a lot given that the lot is good, the test should reject if the number of defectives in the sample of size 100 is greater than or equal to (Q16)
Problem 12. (Continues previous problem.) In that case, the chance of rejecting the lot if it really has 50 defective chips is (Q17)
Problem 13. (Continues previous problem.) In the long run, the fraction of lots with 7 defectives that will get discarded erroneously by this test is (Q18)
Problem 14. (Continues previous problem.) The smallest number of defectives in the lot for which this test has at least a 98% chance of correctly detecting that the lot was bad is (Q19)
(Continues previous problem.) Suppose that whether or not a lot is good is random, that the long-run fraction of lots that are good is 95%, and that whether each lot is good is independent of whether any other lot or lots are good. Assume that the sample drawn from a lot is independent of whether the lot is good or bad. To simplify the problem even more, assume that good lots contain exactly 7 defective chips, and that bad lots contain exactly 50 defective chips.
Problem 15. (Continues previous problem.) The number of lots the manufacturer has to produce to get one good lot that is not rejected by the test has a (Q20) distribution, with parameters (Q21)
Problem 16. (Continues previous problem.) The expected number of lots the manufacturer must make to get one good lot that is not rejected by the test is (Q22)
Problem 17. (Continues previous problem.) With this test and this mix of good and bad lots, among the lots that pass the test, the long-run fraction of lots that are actually bad is (Q23)
Solve the equation for y. Identify the slope and y- intercept. Then graph the equation. 2y-3x=10
Answer:
y=3/2x+5
The slope is 3/2 and the y-intercept is 5
Step-by-step explanation:
Solving for y will give us the slope and y-intercept
Isolate y
2y/2=10+3x/2
y=5+3/2x
The slope is 3/2 and the y-intercept is 5
Graph it by graphing (0,5) and using the slope (up 3 over 2) to put other points
Nathan saves 5 1/4% of his weekly salary. Naban earns $380.00 per week. How much
does he save per week?
.
A.$19.95
B.$20.52
C.$21.95
D.$25.20
Answer:
19.95
Step-by-step explanation:
Take the amount of his salary and multiply by 5 1/4 %
380 * .0525
19.95