Answer:
12
Step-by-step explanation:
let x be the number of men
4:7 = x:21
4/7 = x/21
7x = 84
x = 12
In ΔDEF, the measure of ∠F=90°, the measure of ∠E=41°, and FD = 79 feet. Find the length of DE to the nearest tenth of a foot.
Answer:
120.4ft
Step-by-step explanation:
Find the diagram in the attachment.
The triangle shown is a right angled triangle with the side DE as the hypotenuse, EF is adjacent side while DF is the opposite side.
To get DE, we will use the SOH CAH TOA trigonometry identity
Using CAH which is defined as:
Cos(theta) = Adjacent/Hypotenuse
Cos 79°= 23/Hypotenuse
Hypotenuse = 23/cos79°
Hypotenuse = 23/0.191
Hypotenuse = 120.4feet
DE = 120.4feet (to nearest tenth)
The safety officers of a mining company take an SRS of 500500500 employees and finds that 15\, percent of the sampled employees wear contact lenses. The safety officers may take several more samples like this. Suppose it is really 12\, percent of the approximately 34{,}00034,00034, comma, 000 employees in the company who wear contact lenses. What are the mean and standard deviation of the sampling distribution of the proportion of employees who wear contact lenses
Answer:
The mean of the sampling distribution of the proportion of employees who wear contact lenses is 0.12 and the standard deviation is 0.0145.
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
12% of the employees wear contact lenses.
This means that [tex]p = 0.12[/tex]
Samples of 500:
This means that [tex]n = 500[/tex]
What are the mean and standard deviation of the sampling distribution of the proportion of employees who wear contact lenses?
Mean:
[tex]\mu = p = 0.12[/tex]
Standard deviation:
[tex]s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.12*0.88}{500}} = 0.0145[/tex]
The mean of the sampling distribution of the proportion of employees who wear contact lenses is 0.12 and the standard deviation is 0.0145.
Luis wants to buy a skateboard that usually sells for $79.91. All merchandise is discounted by %12. What is the total cost of the skateboard if Luis has to pay a state sales tax of 8.25%. Round your intermediate calculations and answer to the nearest cent.
Answer:
Luis' skateboard will cost $76.32.
Step-by-step explanation:
Divide 79.91 by 100, this is what one percent is worth, .7991.
Multiply this by 12, giving you 12 percent, 9.59 (rounded to the nearest 10th).
Now subtract 9.59 from 79.91, 70.32. That is the price BEFORE tax.
Than divide 70.32 by 100, .7032.
Multiply this by 8.25, 5.80, this is tax.
Now add the price before tax, 70.32, to the tax, 5.80.
This creates 76.12. This means that the total price of the skateboard is $76.32.
Answer:
saving $10.38
tax $5.80
total pay $76.12
Step-by-step explanation:
79.91*0.12=9.59
79.91-9.59=70.32
70.32*0.0825=5.80
70.32+5.80=76.12
Pls answer ASAP it’s due tomorrow
Answer:
729
Step-by-step explanation:
Find the distance between (-5,6)and (3,2).
Answer:
[tex]\displaystyle d = 4\sqrt{5}[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
Coordinates (x, y)Algebra II
Distance Formula: [tex]\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]Step-by-step explanation:
Step 1: Define
Point (-5, 6) → x₁ = -5, y₁ = 6
Point (3, 2) → x₂ = 3, y₂ = 2
Step 2: Find distance d
Simply plug in the 2 coordinates into the distance formula to find distance d
Substitute in points [Distance Formulas]: [tex]\displaystyle d = \sqrt{(3+5)^2+(2-6)^2}[/tex][Distance] [√Radical] (Parenthesis) Add/Subtract: [tex]\displaystyle d = \sqrt{(8)^2+(-4)^2}[/tex][Distance] [√Radical] Evaluate exponents: [tex]\displaystyle d = \sqrt{64+16}[/tex][Distance] [√Radical] Add: [tex]\displaystyle d = \sqrt{80}[/tex][Distance] [√Radical] Simplify: [tex]\displaystyle d = 4\sqrt{5}[/tex]Artificial grass sells for $10.98 per square yard final cost to buy and install 69.2 square yards if the seller charges $5.15 per square yard for labor round to the nearest cent
Answer:
$1,116.19.
Step-by-step explanation:
Given that artificial grass sells for $ 10.98 per square yard, to determine the final cost to buy and install 69.2 square yards if the seller charges $ 5.15 per square yard for labor, round to the nearest cent, the following calculation must be performed:
69.2 x (10.98 + 5.15) = X
69.2 x 16.13 = X
1,116,196 = X
Thus, the cost to purchase and install 69.2 square yards of artificial grass is $ 1,116.19.
Is 13:15 and 30:26 a pair of equivalent ratios and why?
Given:
The two ratios are 13:15 and 30:26.
To find:
Whether the given ratios are equivalent or not.
Solution:
Two ratios are equivalent if the values of the ratio are equal after simplification.
[tex]13:15=\dfrac{13}{15}[/tex]
And,
[tex]30:26=\dfrac{30}{26}[/tex]
[tex]30:26=\dfrac{15}{13}[/tex]
[tex]30:26=15:13[/tex]
The first ratio is 13:15 and the value of second ratio after simplification is 15:13 both ratios are different, so,
[tex]\dfrac{13}{15}\neq \dfrac{30}{26}[/tex]
Therefore, the required answer is "No", the given ratios are not a pair of equivalent ratios.
Verify that parallelogram ABCD with vertices A(-5, -1), B(-9, 6), C(-1, 5), and D(3, is a rhombus by showing that it is a parallelogram with perpendicular diagonals.
multiplication of the gradients of the two diagonals is equals to -1 if they are perpendicular
Little help ?please 5 points
Tawna and Donnie Milled cartons with bottles, Tawna put in 10 bottles and Bonnie put in a bottles, How many bottles does each carton hold?
Answer:
I Think E But Im Not Sure About It
In the year 2001, a person bought a new car for $15500. For each consecutive year after that, the value of the car depreciated by 5%. How much would the car be worth in the year 2005, to the nearest hundred dollars?
Answer:
$12,000.
Step-by-step explanation:
Given that in the year 2001, a person bought a new car for $ 15500, and for each consecutive year after that, the value of the car depreciated by 5%, to determine how much would the car be worth in the year 2005, to the nearest hundred dollars, the following calculation must be performed:
100-5 = 95
15,500 x 0.95 x 0.95 x 0.95 x 0.95 x 0.95 = X
14.725 x 0.95 x 0.95 x 0.95 x 0.95 = X
13,988.75 x 0.95 x 0.95 x 0.95 = X
13,289.3125 x 0.95 x 0.95 = X
12,624.846875 x 0.95 = X
11.993.60453125 = X
Thus, to the nearest hundred dollars, the cost of the car after 5 years will be $ 12,000.
Simplify the expression 1 + 4.25n + 3/2p -3 + (-2p) + 5/4n
Answer:
5.5n -2 -0.5p
Step-by-step explanation:
Make Everything to either decimals or fractions.
then simplify as shown
The sum of 3 and
twice the number n
Which one is prime 32,42,29,15
Answer:
29
Step-by-step explanation:
32 can be created from 4 x 8, so it is not.
42 can be created from 6 x 7, so it is not.
15 can be created from 5 x 3, so it is not.
29 cannot be created from any numbers multiplied.
What is the area of the fire pit? (Use 3.14 for pi.)
Answer:
[tex]Area = 65.94[/tex]
Step-by-step explanation:
I will assume that the shaded region is the fire pit
Given
[tex]R = 5[/tex]
[tex]r = 2[/tex]
Required
Determine the area of the fire pit
First, calculate the area of the big circle.
[tex]A_2 = \pi R^2[/tex]
Area of the small is:
[tex]A_1 = \pi r^2[/tex]
The area of the pit is:
[tex]Area = A_2 - A_1[/tex]
[tex]Area = \pi R^2 - \pi r^2[/tex]
[tex]Area = \pi (R^2 - r^2)[/tex]
[tex]Area = 3.14 (5^2 - 2^2)[/tex]
[tex]Area = 3.14 (25 - 4)[/tex]
[tex]Area = 3.14 * 21[/tex]
[tex]Area = 65.94[/tex]
Examine the steps used to solve the equation.
Negative 3 y + two-thirds = 2 y minus 4. 1. Two-thirds = 5 y minus 4. 2. StartFraction 14 Over 3 EndFraction = 5 y. 3. (one-fifth) StartFraction 14 Over 3 EndFraction = (one-fifth) 5 y.
Evaluate the steps used to solve the equation, and then describe each step.
Step 1:
Step 2:
Step 3:
What is the solution to the equation?
y =
Answer:
can confirm guy or girl above me
Step-by-step explanation:
The solution to the equation is y=14/15.
The given equation is -3y+2/3=2y-4.
What is an equation?In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.
Now, transpose -3y to RHS and simplify.
That is, 2/3=5y-4
Transpose -4 to LHS and simplify.
That is, 14/3=5y
Multiply by 1/5 on both sides of the equation.
So, 14/3×1/5=5y×1/5
⇒y=14/15
Therefore, the solution to the equation is y=14/15.
To learn more about the equation visit:
https://brainly.com/question/10413253.
SPJ5
what is the volume of a cube with 2 1/4 inch sides
Answer:11.39
Step-by-step explanation:
Solve the equation: p2 - 4p + 4 = 0.
Perfect square trinomial
[tex] \boxed{ a^2 \pm 2ab+b^2 = (a \pm b)^2 } [/tex]
Using the perfect square trinomial
[tex] p^2 - 4p + 4 = 0 [/tex]
[tex] p^2 - 2(2p) + (2)^2 = 0 [/tex]
[tex] (p-2)^2 = 0 [/tex]
[tex] (p-2) = 0 [/tex]
[tex] p = 2 [/tex]
[tex]\huge\text{Hey there!}[/tex]
[tex]\bold{p^2-4p+4=0}[/tex]
[tex]\text{FACTOR the LEFT side of your equation}\\\bold{(p-2)(p-2)=0}[/tex]
[tex]\text{SET each of your FACTORS TO EQUAL to 0}\\\bold{p-2=0\ or\ p-2=0}[/tex]
[tex]\text{SIMPLIFY the equations\ above and you will have your answer}[/tex]
[tex]\boxed{\boxed{\bold{Answer: \large\text{\bf{p = 2}}}}}\huge\checkmark[/tex]
[tex]\textsf{Good luck on your assignment and enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
4. Marlie made her last monthly interest-only payment on December 1. Her next payment is due on
January 1. What will be the amount of that interest-only payment?
en
Answer:
ella tiene que pagar 10 por mes. lo siento si no es así, esa no es la respuesta correcta.
Step-by-step explanation:
Students at a major university are complaining of a serious housing crunch. Many of the university's students, they complain, have to commute too far to school because there is not enough housing near campus. The university officials respond with the following information:
The mean distance commuted to school by students is 17.1 miles, and the standard deviation of the distance commuted is 3.7 miles. Assuming that the university officials' information is correct, complete the following statements about the distribution of commute distances for students at this university.
1) According to Chebyshev's theorem, at least 36% of the commute distances lie between miles and miles. (Round your answer to 1 decimal place.)
2) According to Chebyshev's theorem, at least of the commute distances lie between 9.7 miles and 24.5 miles.
a) 56%
b) 75%
c) 84%
d) 89%
3) Suppose that the distribution is bell-shaped. According to the empirical rule, approximately of the commute distances lie between 9.7 miles and 24.5 miles.
a) 68%
b) 75%
c) 95%
d) 99.7%
4) Suppose that the distribution is bell-shaped. According to the empirical rule, approximately 68% of the commute distances lie between miles and miles.
Answer:
1) Between 12.5 miles and 21.7 miles.
2) b) 75%
3) c) 95%
4) Between 13.7 miles and 20.5 miles.
Step-by-step explanation:
Empirical Rule:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviations of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
Chebyshev Theorem:
The Chebyshev Theorem can also be applied to non-normal distribution. It states that:
At least 75% of the measures are within 2 standard deviations of the mean.
At least 89% of the measures are within 3 standard deviations of the mean.
An in general terms, the percentage of measures within k standard deviations of the mean is given by [tex]P = 100(1 - \frac{1}{k^{2}})[/tex].
1) According to Chebyshev's theorem, at least 36% of the commute distances lie between miles and miles.
Within k standard deviations of the mean, and k is found when [tex]P = 36[/tex]. So
[tex]P = 100(1 - \frac{1}{k^{2}})[/tex]
[tex]36 = 100 - \frac{100}{k^2}[/tex]
[tex]\frac{100}{k^2} = 64[/tex]
[tex]64k^2 = 100[/tex]
[tex]k^2 = \frac{100}{64}[/tex]
[tex]k = \sqrt{\frac{100}{64}}[/tex]
[tex]k = \frac{10}{8}[/tex]
[tex]k = 1.25[/tex]
Within 1.25 standard deviations of the mean.
1.25*3.7 = 4.6 miles
17.1 - 4.6 = 12.5 miles
17.1 + 4.6 = 21.7 miles
Between 12.5 miles and 21.7 miles.
2) According to Chebyshev's theorem, at least of the commute distances lie between 9.7 miles and 24.5 miles.
17.1 - 9.7 = 24.5 - 17.1 = 7.4 miles, so within 2 standard deviations of the mean, which is 75%, option B.
3) Suppose that the distribution is bell-shaped. According to the empirical rule, approximately of the commute distances lie between 9.7 miles and 24.5 miles.
Within 2 standard deviations of the mean, by the Empirical Rule, which is 95%, option c.
4) Suppose that the distribution is bell-shaped. According to the empirical rule, approximately 68% of the commute distances lie between miles and miles.
Within 1 standard deviation of the mean.
17.1 - 3.4 = 13.7
17.1 + 3.4 = 20.5
Between 13.7 miles and 20.5 miles.
1 1/3+2 3/4 simplified
Answer:
4 1/12
Step-by-step explanation:
Answer: 4 1/2
cause it is
Evaluate the expression: 16.2 x 2 + 1/2 x 8.5 x 12
Answer:
83.4
Step-by-step explanation:
16.2 x 2
=
32.4 +
1/2 x 8.5 x 12
=
51 + 32.4 = 83.4
Hope this helps!
f(x) = 2x² + 4x - 5
g(x) = 6x3 – 2x2 + 3
Find (f – g)(x).
A. (f – g)(x) = –6x3 + 4x2 + 4x – 2
B. (f - g)(x) = 6x + 4x – 2
C. (f - g)(x) b= 6x? – 4x² - 4x + 8
D. (f - g)(x) = –6x2 + 4x2 + 4x – 8
The required difference in the expression (f – g)(x) is - 6x³+ 4x² + 4x - 8
Given the following functions
f(x) = 2x² + 4x - 5
g(x) = 6x³ – 2x² + 3
In order to get the required function (f-g)(x), we will have to take the difference of the function as shown:
(f – g)(x) = f(x) - g(x)
Substitute the given parameters into the expression
(f – g)(x) = 2x² + 4x - 5 - (6x³ – 2x² + 3)
Expand
(f – g)(x) = 2x² + 4x - 5 - 6x³ + 2x² - 3
Collect the like terms
(f – g)(x) = 2x²+2x²- 6x³ + 4x -5 -3
(f – g)(x) = - 6x³+ 4x² + 4x -5 -3
(f – g)(x) = - 6x³+ 4x² + 4x - 8
Hence the required difference in the expression (f – g)(x) is - 6x³+ 4x² + 4x - 8
Learn more here: https://brainly.com/question/17431959
1) Find all the critical numbers of the given function
f(x) = X 1 - 4
-
3
Answer:
(0,-4)
Step-by-step explanation:
Given
[tex]f(x) = x^\frac{1}{3} - 4[/tex]
Required
Determine the critical numbers
[tex]f(x) = x^\frac{1}{3} - 4[/tex]
Differentiate:
[tex]f'(x) = \frac{1}{3}x^{\frac{1}{3} - 1}[/tex]
[tex]f'(x) = \frac{1}{3}x^{-\frac{2}{3}}[/tex]
Equate to 0
[tex]f'(x) = \frac{1}{3}x^{-\frac{2}{3}} = 0[/tex]
[tex]\frac{1}{3}x^{-\frac{2}{3}} = 0[/tex]
Multiply through by 3
[tex]3 * \frac{1}{3}x^{-\frac{2}{3}} = 0*3[/tex]
[tex]x^{-\frac{2}{3}} = 0[/tex]
[tex]x = 0[/tex]
Substitute 0 for x in [tex]f(x) = x^\frac{1}{3} - 4[/tex]
[tex]f(0) = 0^\frac{1}{3} - 4[/tex]
[tex]f(0) = 0- 4[/tex]
[tex]f(0) = - 4[/tex]
Hence, the critical point is: (0,-4)
1.5 x 2.5
Or 0.9 x 27
Answer:
what was the question I dont get it pls
Step-by-step explanation:
u can tell me
Doughnuts are sold in bag and cartons. A bag holds 4 doughnuts and a carton holds 10 doughnuts. Tome buys b bags of doughnuts and c cartons of doughnuts. He buys a total of t doughnuts. Write down the formula for t in terms of b and c
Answer:
[tex]t = 4b + 10c[/tex]
Step-by-step explanation:
Given
1 bag = 4 doughnuts
1 carton = 10 doughnuts
Required
Determine the amount of doughnuts in b bags and c cartons
If 1 bag contains 4 doughnuts, then b bags contain 4b doughnuts
If 1 carton contains 10 doughnuts, then c cartons contain 10b doughnuts
So, the total (t) is calculated by adding up the amount of doughnuts in the cartons and the bags:
i.e.
[tex]t = 4b + 10c[/tex]
Use the diagram below to find x and each missing angle.
Ms.Gallegos burns 236 calories
If there are 125 boxes of prescription bottle labels at the beginning of inventory cycle, and 25 3/4 remain ,how many boxes of labels remain?
Answer:
Rounded to the nearest integer, there are 32 boxes of labels left.
Step-by-step explanation:
Since there are 125 boxes of prescription bottle labels at the beginning of inventory cycle, and 25 3/4 remain, we can determine how many boxes of labels remain through the following mathematical operations:
3/4 = 0.75
100 = 125
25.75 = X
25.75 x 125/100 = X
3218.75 / 100 = X
32.1875 = X
Thus, rounded to the nearest integer, there are 32 boxes of labels left.
let f(x)=x^2 +2 and g(x)=1-3x. find each function value: (fg)(-1)
Answer:
12
Step-by-step explanation:
so basically
(x^2+2)*(1-3x)=-3x^3+x^2-6x+2
now plug in -1
-3(-1)^3+(-1)^2-6(-1)+2=12
hope this helped :)
The correct value of (fg)(-1) is "12". A further solution of the given query is provided below.
Given functions are:
[tex]f(x) = x^2+2[/tex]
[tex]g(x) = 1-3x[/tex]
Now,
⇒ [tex](fg) = (x^2+2)(1-3x)[/tex]
By applying multiplication, we get
[tex]=x^2+2-3x^3-6x[/tex]
[tex]=-3x^3+x^2-6x+2[/tex]...(equation 1)
By substituting the value "-1" in place of "x" in equation 1, we get
⇒ [tex](fg)(-1) = -3(-1)^3+(-1)^2-(6)(-1)+2[/tex]
[tex]=-3(-1)+1+6+2[/tex]
[tex]=3+1+6+2[/tex]
[tex]=12[/tex]
Thus the right answer is (fg)(-1) = 12.
Learn more:
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What is 23x56÷67-68?
Hurry plz
Me give brainliest
Thanks in advance
Answer:
-48.4328358209
Step-by-step explanation:
hope this helps!!!
Answer:
If you meant 68-67 then it would be 1288
But if you meant 67-68 it is -1288
(I really hope this isn't hard to understand).