The whole numbers are the set of what numbers and zero ?

We need to multiply the 80mph by the 1.6 to make it KPH

When done correctly we get the answer of 128KPH

The limit is 128kph

HOPE THIS HELPED. DONT FORGET TO MARK THIS AS THE BRAINLIEST ANSWER AND GIVE IT A 5 STAR SO OTHER PEOPLE CAN BE HELPED BY THIS ANSWER!! HAVE A NICE DAY!

Answer:13

Step-by-step explanation:

13^2

Answer:

28.64632

also if you can can you please help me with my question

Answer:

not gonna lie

Step-by-step explanation:

28.64632 km

Answer:

9 dimes and 17 quarters

Step-by-step explanation:

9+17=26 coins

9 dimes = 90 cents

17 = 425 cents

90+425= 515 cents or $5.15

Hope this helps! :)

Answer:

9cm

Step-by-step explanation: i think. ah

Answer:

3 cm³

Step-by-step explanation:

Formula a =√(A/6)

a = edge

A = Surface Area

a = √(54/6) = 3

Answer:

D

Step-by-step explanation:

Answer:

1. -5

2. 1/3 (1 third)

3. -3

4. -1\2 (negative one and a half)

5.-4

6. 1.66666

Step-by-step explanation:

1.  Let's solve your equation step-by-step. ( x + 5 ) ( x − 2 ) = 0 Step 1: Simplify both sides of the equation. x 2 + 3 x − 10 = 0 Step 2: Factor left side of equation. ( x − 2 ) ( x + 5 ) = 0 Step 3: Set factors equal to 0. x − 2 = 0 or x + 5 = 0 x = 2 or x = − 5.        <—— this is for the first explanation

2. Step 1: Simplify both sides of the equation. 6 x 2 + 13 x − 5 = 0 Step 2: Factor left side of equation. ( 3 x − 1 ) ( 2 x + 5 ) = 0 Step 3: Set factors equal to 0. 3 x − 1 = 0 or 2 x + 5 = 0 x = 1 3 or x = − 5 2 Answer: x = 1 3 or x = − 5 2

<———— this is for the second explanation

3.Step 1: Factor left side of equation. ( x + 1 ) ( x − 4 ) = 0 Step 2: Set factors equal to 0. x + 1 = 0 or x − 4 = 0 x = − 1 or x      

<———- this is for the third explanation

4.Step 1: Factor left side of equation. ( 2 x + 1 ) ( x − 3 ) = 0 Step 2: Set factors equal to 0. 2 x + 1 = 0 or x − 3 = 0 x = − 1 2 or x = 3

<—————- this is for the fourth explanation

5. Step 1: Add 16 to both sides. x 2 − 16 + 16 = 0 + 16 x 2 = 16 Step 2: Take square root. x = ± 16 x = 4 or x = − 4

<—————- this is for the fith explanation

6. Step 1: Add 25 to both sides. 9 x 2 − 25 + 25 = 0 + 25 9 x 2 = 25 Step 2: Divide both sides by 9. 9 x 2 9 = 25 9 x 2 = 25 9 Step 3: Take square root. x = ± 25 9 x = 1.666667 , − 1.666667

<—————- this is for the sixth explanation

Hope this helps :)

Answer:

Step-by-step explanation:

This is actually a word problem

step one:

let the maximum number be  x  

18+4x<30

4x<30-18

4x<12

divide both sides by 4 we have

4x<12

x<3

step two:

From this analysis, we can see that all possible numbers are real numbers less than 3 that is 2,1,0,-1,-2,..............etc

Answer:

35

Step-by-step explanation:

Steps to solve:

4 + (m - n)^4 when m = 7 and n = 5

~Substitute

4 + (7 - 5)^4

~Simplify

4 + 2^4

~Simplify

4 + 16

~Add

20

Best of Luck!

Answer:

4¹⁰

Step-by-step explanation:

4³ × 4⁷ = 4³⁺⁷ = 4¹⁰

Answer:

It depends.

Step-by-step explanation:

If it is two straight lines, then no, there is no way for the lines to intersect in more than one place. If the line is a parabola, then the lines would intersect in 2 places. It depends on what type of line you have.  

Answer:

IT'S A BELIEVE PLZZZZZZZz

Step-by-step explanation:

Answer:

The cost at Store A is $2.00 greater than at Store B.

Step-by-step explanation:

i had the same quiz this was correct

Answer:  9 1/10      91/10

Step-by-step explanation:

Answer:

9 1/10 and 91/10

Step-by-step explanation:

hope it helps :)

brainliest pls? have a good day/night

Think about the rule when multiplying powers together.

When multiplying two powers that have the

same base, simply add their exponents.

In this problem, each power has a base

of a and our exponents are m and n.

So adding these exponents together, we have a^m + n.

Answer:

A, D, E

Step-by-step explanation:

like with division if you multiply the same thing on both sides it is still equal

The  ratios are equivalent to 8 : 12 are A 4 : 6 , D 24 : 36 and E 56 : 84.

Those expressions who might look different but their simplified forms are same expressions are called equivalent expressions.

Suppose that we've got two quantities with measurements as 'a' and 'b'

Then, their ratio(ratio of a to b) a:b

We usually cancel out the common factors from both the numerator and the denominator of the fraction we obtained. Numerator is the upper quantity in the fraction and denominator is the lower quantity in the fraction).

Suppose that we've got a = 8, and b= 12,

[tex]a:b = 8 : 12\\\\ = \dfrac{8}{12} = \dfrac{2 \times 4}{2 \times 6} \\= \dfrac{2}{3} \\\\a : b = 2 : 3[/tex]

So, the  ratios are equivalent to 8 : 12

A 4 : 6

D 24 : 36

E 56 : 84

Remember that the ratio should always be taken of quantities with same unit of measurement. Also, ratio is a unitless(no units) quantity.

Learn more about ratio here:

brainly.com/question/186659

#SPJ2

Answer:

Its A

Step-by-step explanation:

Answer:

[tex]x<-8[/tex]

Step-by-step explanation:

So we have the inequality:

[tex]3x-1>4x+7[/tex]

Add 1 to both sides. The left side cancels:

[tex]3x>4x+8[/tex]

Subtract 4x from both sides. The right side cancels:

[tex]-x>8[/tex]

Divide both sides by -1. Since we're dividing by a negative, we flip the sign:

[tex]x<-8[/tex]

And we're done!

Our solution is all numbers less than -8.

Answer:

x = -8

Step-by-step explanation:

I will be the brainliest, its hard to explain on a document, i could make you avideo how to do these problems, im a math teacher.

Answer:

Step-by-step explanation:

Let the height (the dependent variable) be h.

Let the independent variable (x) be y

h = 8y + 10

So at birth, these creatures are 10 cm long. At each birthday, they are another 8 cm.

Take the fifth year which is where the table begins.

y= 8*5 + 10

y = 40 + 10

y = 50 cm which is exactly what you got.

[tex] \huge \purple {\tt {x + \frac{7}{6} = 2x - \frac{7}{6}}} [/tex]

[tex] \large {\tt {The \: answer \: in \: reduced}} [/tex]

[tex] \large {\tt { improper \: fraction \: form.}} [/tex]

[tex] \huge \pink {\tt {x + \frac{7}{6} = 2x - \frac{7}{6}}} [/tex]

[tex] \huge \blue {\tt {or, \: x - 2x = - \frac{7}{6} - \frac{7}{6}}} [/tex]

[tex] \huge \red {\tt {or, \: - x = \frac{ - 14}{6} = \frac{ - 7}{3}}} [/tex]

[tex] \huge \green {\tt {or, \: x = \frac{7}{3}}} [/tex]

[tex] \huge \orange {\tt {x = \frac{7}{3}}} [/tex]

The dimensions of this rectangle are 4 units by 3 units

4 units * 3 units = 12 sq units

Answer:

B) (-2,3)

Step-by-step explanation:

Graph all your points. No count the distance from point A to B. divide in half .

Answer:

Ray, Line, Transversal?, Plane, Segment

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

Answer:

see below

Step-by-step explanation:

 g(x) = 1/2 | x+2| -3

y = Cf(x)   0 < C < 1 compresses it in the y-direction

y = f(x + C)      C > 0 moves it left

y = f(x) + C C < 0 moves it down

1/2 compression in the y direction moved to the left 2 units and down 3 units

Given: g(x) = 1/2|x + 2| - 3

0 < c < 1 means at the y-axis and makes it smaller

y = cf(x)

1/2 compression

c > 0 means that you move it to the left

y = f(x + c)

2 units to the left

c < 0 means that you move it down

y = f(x) + c

3 units down

Best of Luck!

Answer:

m∠XAZ = 40°

Step-by-step explanation:

Since ∠YAU, ∠YAZ and ∠XAZ are the angles based at a point on a straight line, and the sum of the all angles on a line is 180°.

Therefore, m∠YAU + m∠YAZ + m∠XAZ = 180°

50° + 90° + m∠XAZ = 180°

m∠XAZ = 180° - 140°

             = 40°

Therefore, measure of angle XAZ is 40°.

Answer:

The answer is 1

Step-by-step explanation:

Answer:

11) 2nd option

12)2nd option

13)3rd option

Answer:  see proof below

Step-by-step explanation:

Given: A + B + C = π              → A + B = π - C

                                              → B + C = π - A

                                              → C + A = π - B

                                              → C = π - (B +  C)

Use Sum to Product Identity:  cos A + cos B = 2 cos [(A + B)/2] · cos [(A - B)/2]

Use the Sum/Difference Identity: cos (A - B) = cos A · cos B + sin A · sin B

Use the Double Angle Identity: sin 2A = 2 sin A · cos A

Use the Cofunction Identity: cos (π/2 - A) = sin A

Proof LHS → Middle:

[tex]\text{LHS:}\qquad \qquad \cos \bigg(\dfrac{A}{2}\bigg)+\cos \bigg(\dfrac{B}{2}\bigg)+\cos \bigg(\dfrac{C}{2}\bigg)[/tex]

[tex]\text{Sum to Product:}\qquad 2\cos \bigg(\dfrac{\frac{A}{2}+\frac{B}{2}}{2}\bigg)\cdot \cos \bigg(\dfrac{\frac{A}{2}-\frac{B}{2}}{2}\bigg)+\cos \bigg(\dfrac{C}{2}\bigg)\\\\\\.\qquad \qquad \qquad \qquad =2\cos \bigg(\dfrac{A+B}{4}\bigg)\cdot \cos \bigg(\dfrac{A-B}{4}\bigg)+\cos \bigg(\dfrac{C}{2}\bigg)[/tex]

[tex]\text{Given:}\qquad \quad =2\cos \bigg(\dfrac{A+B}{4}\bigg)\cdot \cos \bigg(\dfrac{A-B}{4}\bigg)+\cos \bigg(\dfrac{\pi -(A+B)}{2}\bigg)[/tex]

[tex]\text{Sum/Difference:}\quad =2\cos \bigg(\dfrac{A+B}{4}\bigg)\cdot \cos \bigg(\dfrac{A-B}{4}\bigg)+\sin \bigg(\dfrac{A+B}{2}\bigg)[/tex]

[tex]\text{Double Angle:}\quad =2\cos \bigg(\dfrac{A+B}{4}\bigg)\cdot \cos \bigg(\dfrac{A-B}{4}\bigg)+\sin \bigg(\dfrac{2(A+B)}{2(2)}\bigg)\\\\\\.\qquad \qquad \qquad =2\cos \bigg(\dfrac{A+B}{4}\bigg)\cdot \cos \bigg(\dfrac{A-B}{4}\bigg)+2\sin \bigg(\dfrac{A+B}{4}\bigg)\cdot \cos \bigg(\dfrac{A+B}{4}\bigg)[/tex]

[tex]\text{Factor:}\quad =2\cos \bigg(\dfrac{A+B}{4}\bigg)\bigg[ \cos \bigg(\dfrac{A-B}{4}\bigg)+\sin \bigg(\dfrac{A+B}{4}\bigg)\bigg][/tex]

[tex]\text{Cofunction:}\quad =2\cos \bigg(\dfrac{A+B}{4}\bigg)\bigg[ \cos \bigg(\dfrac{A-B}{4}\bigg)+\cos \bigg(\dfrac{\pi}{2}-\dfrac{A+B}{4}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad =2\cos \bigg(\dfrac{A+B}{4}\bigg)\cdot \cos \bigg(\dfrac{A-B}{4}\bigg)+\cos \bigg(\dfrac{2\pi-(A+B)}{4}\bigg)\bigg][/tex]

[tex]\text{Sum to Product:}\ 2\cos \bigg(\dfrac{A+B}{4}\bigg)\bigg[2 \cos \bigg(\dfrac{2\pi-2B}{2\cdot 4}\bigg)\cdot \cos \bigg(\dfrac{2A-2\pi}{2\cdot 4}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad =4\cos \bigg(\dfrac{A+B}{4}\bigg)\cdot \cos \bigg(\dfrac{\pi-B}{4}\bigg)\cdot \cos \bigg(\dfrac{\pi -A}{4}\bigg)[/tex]

[tex]\text{Given:}\qquad \qquad 4\cos \bigg(\dfrac{\pi -C}{4}\bigg)\cdot \cos \bigg(\dfrac{\pi-B}{4}\bigg)\cdot \cos \bigg(\dfrac{\pi -A}{4}\bigg)\\\\\\.\qquad \qquad \qquad =4\cos \bigg(\dfrac{\pi -A}{4}\bigg)\cdot \cos \bigg(\dfrac{\pi-B}{4}\bigg)\cdot \cos \bigg(\dfrac{\pi -C}{4}\bigg)[/tex]

LHS = Middle [tex]\checkmark[/tex]

Proof Middle → RHS:

[tex]\text{Middle:}\qquad 4\cos \bigg(\dfrac{\pi -A}{4}\bigg)\cdot \cos \bigg(\dfrac{\pi-B}{4}\bigg)\cdot \cos \bigg(\dfrac{\pi -C}{4}\bigg)\\\\\\\text{Given:}\qquad \qquad 4\cos \bigg(\dfrac{B+C}{4}\bigg)\cdot \cos \bigg(\dfrac{C+A}{4}\bigg)\cdot \cos \bigg(\dfrac{A+B}{4}\bigg)\\\\\\.\qquad \qquad \qquad =4\cos \bigg(\dfrac{A+B}{4}\bigg)\cdot \cos \bigg(\dfrac{B+C}{4}\bigg)\cdot \cos \bigg(\dfrac{C+A}{4}\bigg)[/tex]

Middle = RHS [tex]\checkmark[/tex]