The wavelength of yellow light in a spectrum is about 0.00002 inches. Which number best approximates this length as a power of 10? O A. 2x 10-5 O B. 2 x 105 O C. -2x 105 O D. 2 x 10-4 SUBMIT help me please fast ​

Answer:

48.1

Step-by-step explanation:

Seven rounds up.

Hope this helped! :)

Step-by-step explanation:

you have to be careful what you are typing.

the way you wrote the numbers Asia would be a tiny place with very few people.

but I think you meant to say :

area is 4.46 × 10⁷ km²

with 3.70 × 10⁹ people.

people / km² = 3.70/4.46 × 10⁹/10⁷ =

= 0.829596413... × 10² = 82.9596413... =

= 82.96 people/km²

The population density will be equal to 82.96 people/km2. The correct option is B.

Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

Given that the area is 4.46 × 10⁷ km² with 3.70 × 10⁹ people. The population density will be calculated as below:-

Density = people / km² = ( 3.70 × 10⁹ ) / ( 4.46 x 10⁷ )

Density = 0.829596413... × 10² = 82.9596413

Density = 82.96 people/km²

Therefore, the population density will be equal to 82.96 people/km2. The correct option is B.

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Answer:

[tex]\boxed{\tt \frac{40}{9}} \ \sf or \ \boxed{\tt 4 \frac{4}{9}}[/tex]

Step-by-step explanation:

[tex]\textsf{We are asked to solve for the sum of 2 fractions.}[/tex]

[tex]\large\underline{\textsf{What are Fractions?}}[/tex]

[tex]\textsf{Fractions are representations of rational numbers that can be represented as part}[/tex]

[tex]\textsf{of a whole number.}[/tex]

[tex]\underline{\textsf{What are the parts of a fraction?}}[/tex]

[tex]\textsf{Fractions have 2 parts, they're called the Numerator and the Denominator.}[/tex]

[tex]\frac{\sf Numerator}{\sf Denominator}[/tex]

[tex]\textsf{The Numerator represents the amount of equal parts a certain rational number}[/tex]

[tex]\textsf{has compared to the Denominator. The Denominator represents the total amount}[/tex]

[tex]\textsf{of parts that make a fraction equal to 1. If the Numerator is the same as the}[/tex]

[tex]\textsf{Denominator, then the fraction is just 1. If the Numerator is greater than 1, then}[/tex]

[tex]\textsf{this kind of fraction is considered an Improper Fraction, and improper fractions}[/tex]

[tex]\textsf{are fractions that are improper due to the Numerator being greater than the}[/tex]

[tex]\textsf{Denominator, which means these fractions shouldn't be represented as fractions,}[/tex]

[tex]\textsf{but there's nothing wrong with representing it as a fraction.}[/tex]

[tex]\textsf{Since we know what majority of fractions are, we may begin adding these fractions}[/tex]

[tex]\textsf{which are improper.}[/tex]

[tex]\large\underline{\textsf{How are we able to Add Fractions?}}[/tex]

[tex]\textsf{Adding Fractions is simply adding the Numerators together since the Denominator}[/tex]

[tex]\textsf{can't be changed, if so then the equation won't be equal.}[/tex]

[tex]\textsf{*Remember that when adding fractions we must have common denominators.}[/tex]

[tex]\textsf{This means that we should find the LCM (Least Common Multiple) of the}[/tex]

[tex]\textsf{Denominators.}[/tex]

[tex]\underline{\textsf{For our problem;}}[/tex]

[tex]\textsf{Since we already have Common Denominators, we are able to simply add the}[/tex]

[tex]\textsf{Numerators.}[/tex]

[tex]\large\underline{\textsf{Solving;}}[/tex]

[tex]\textsf{Add the Numerators together.}[/tex]

[tex]\tt \frac{\boxed{\tt 23}}{9} + \frac{\boxed{\tt 17}}{9} =\boxed{\tt \frac{40}9}[/tex]

[tex]\tt \frac{40}{9} \ \textsf{can be our final answer. However, since our sum is an Improper Fraction, it's}[/tex]

[tex]\textsf{greater than 1. Since 40 can divide into 9 about 4 times, our whole number will}[/tex]

[tex]\textsf{be 4, and the remainder will be our fraction.}[/tex]

[tex]\underline{\textsf{Explained in numerical;}}[/tex]

[tex]\tt \frac{40}{9} = \frac{9}{9} + \frac{9}{9} + \frac{9}{9} + \frac{9}{9} + \frac{4}{9} = \boxed{\tt 4 \frac{4}{9}}[/tex]

[tex]*\tt \frac{36}{9} = \frac{4}{1}[/tex]

[tex]\textsf{These are called Whole Number Fractions.}[/tex]

[tex]\large\underline{\textsf{Hence;}}[/tex]

[tex]\tt \frac{23}{9} + \frac{17}{9} = \boxed{\tt \frac{40}{9}} \ \sf or \ \boxed{\tt 4 \frac{4}{9}}[/tex]

[tex]\large\underline{\textsf{Learn more about Fractions;}}[/tex]

https://brainly.com/question/26180542

[tex]\textsf{This answer will give you a great review of how to turn word-form problems into}[/tex]

[tex]\textsf{fractions, and how to simpify those fractions.}[/tex]

Answer:

  82/63

Step-by-step explanation:

The sum can be found using the formula ...

  [tex]\dfrac{a}{b}+\dfrac{c}{d} =\dfrac{ad+bc}{bd}[/tex]

For the given fractions, the sum is ...

  [tex]\dfrac{6}{7}+\dfrac{4}{9} =\dfrac{6\cdot9+7\cdot4}{7\cdot9}=\dfrac{54+28}{63}=\boxed{\dfrac{82}{63}}[/tex]

_____

Additional comment

When the denominators have no common factor, the least common denominator is their product, as here.

Answer:

For this question, you can make the denominators the same to get the answer.

LCM of 7 and 9 = 63

[tex]\frac{6}{7} + \frac{4}{9} = \frac{54}{63} + \frac{28}{63} \\[/tex]

         = [tex]\frac{82}{63}[/tex]

         = 1[tex]\frac{19}{63}[/tex]

Step-by-step explanation:

(x-8)²+(y--8)²=(2)²

x²-16x+64+y²+16y+64=4

x²+y²-16x+16y+124=0

Answer:

new equation : 1.09t = new price

Step-by-step explanation:

1.09(15.99) = 17.4291

it's about $17

Answer: m>-50

x<=3 3/4

at point -2.1 3rd arrow

at 1.33 4th arrow

at 4 2nd arrow

Step-by-step explanation:

Answer:

6x sec2 (x2+5) the number to are in the top of x a c.

[tex]A = \dfrac 12 (b_1 + b_2)h\\\\\implies 2A = (b_1+b_2) h\\\\\implies h =\dfrac{2A}{b_1+b_2}[/tex]

Answer: -1 = (-3/3)

Step-by-step explanation

You go from one point to another, i started from 3,1 and went to 3,0. I got down -3 which is my rise and right 3 for the run. Tell me if this is correct

Answer:

[tex] \frac{2}{5} > \frac{1}{6} [/tex]

Answer: B. >

#CarryOnLearning

Mathew decided to have a picnic with his 4 friends. They were each assigned to bring 10 different foods. The food were to be brought in 15 bags total. How much food are there in each bag in total?

Answer:

5:1

Step-by-step explanation:

divide eatch side

Answer:

It's 1:5

Step-by-step explanation:

Answer:

0,0

Step-by-step explanation:

because it is in the centre of the graph

Answer:

4th on should be the correct

Answer:

[tex]b=-a^2-c[/tex]

Step-by-step explanation:

x = 27

Step-by-step explanation:

The two angles shown are called co-exterior angles and by definition, their sum is equal to 180° so we can write

[tex](3x - 3) + (4x - 6) = 180[/tex]

[tex]\Rightarrow 7x - 9 = 180[/tex]

Simplifying this further, we get

[tex]7x = 189 \Rightarrow x = 27[/tex]

Answer:

Step-by-step explanation:

Answer:

.6 miles

Step-by-step explanation:

Answer:

0.6 miles

Step-by-step explanation:

6 × t = 4 × (15 - t)

6t = 60 - 4t

6t + 4t = 60 - 4t + 4t

10t = 60

t = 6

6 × [tex]\frac{1}{10}[/tex] = 0.6

Answer:

This is not a linear function, as it isn't any function because 3 has two outputs.

Step-by-step explanation:

Explained above

Answer:

1,200

Step-by-step explanation

Multiply 720 and 100 = 72,000

Divide by 60 = 1,200

Answer:

The answer is 1,200

Step-by-step explanation:

First Multiply 720 and 100 which = 72,000

Then Divide 72,000 by 60 = 1,200

Answer:

151.5 cm = 1.515 m

151.5 cm = 1515/1000 m

The given triangles ΔDOA and ΔABC are right triangles that have a

common vertex at point A.

Reasons:

The given parameters are;

The diameter of the circle with center O = AB

DO ⊥ AB (DO is perpendicular to AB)

Required:

Prove that ∠AEC = ∠ODA

A two column proof is presented as follows;

Statement [tex]{}[/tex]                                                 Reason

1. AB is the diameter of circle     [tex]{}[/tex]                 1. Given

2. DO is perpendicular to AB [tex]{}[/tex]                     2. Given

3. ∠DOA = 90° [tex]{}[/tex]                                             3. Definition of DO ⊥ AB

4. ∠BCA = 90°   [tex]{}[/tex]                                             4. Thales theorem

5. ∠BCA ≅ ∠BCA [tex]{}[/tex]                                         5. Reflexive property

6. ΔDOA ~ ΔABC   [tex]{}[/tex]                                        6. AA similarity postulate

7. ∠ABC ≅ ∠ODA   [tex]{}[/tex]                                       7. CASTC

8. ∠ABC = ∠ODA   [tex]{}[/tex]                                        8. Definition of congruency

9. ∠AEC ≅ ∠ABC   [tex]{}[/tex]                                        9. Angles in the same segment

10. ∠AEC = ∠ABC   [tex]{}[/tex]                                       10. Definition of congruency

11. ∠AEC = ∠ODA   [tex]{}[/tex]                                        11. Transitive property of equality

In statement 6, ΔDOA is similar to ΔABC by Angle-Angle, AA, similarity

postulate, therefore, the three angles of ΔDOA are congruent to the three

angles of ΔABC.

Therefore ∠ABC ≅ ∠ODA by Corresponding Angles of Similar Triangles

are Congruent, CASTC.

Learn more about circle theorem here:

https://brainly.com/question/16879446

[tex]\mathfrak{ x ^ { 2 } + b x - 4 = 0} [/tex]

[tex]\mathfrak{bx-4=-x^{2} } [/tex]

[tex]\mathfrak{bx=-x^{2}+4 } [/tex]

[tex]\mathfrak{xb=4-x^{2} } [/tex]

[tex]\mathfrak{\frac{xb}{x}=\frac{4-x^{2}}{x} } [/tex]

[tex]\mathfrak{ b=\frac{4-x^{2}}{x} } [/tex]

[tex]\mathfrak{b=-x+\frac{4}{x} } [/tex]

AnSwEr

[tex]\boxed{\mathfrak{b=-x+\frac{4}{x},x\neq 0 } }[/tex]

 ღ ꪑ꠸᥅ꫀꪊ

Answer:

C

Step-by-step explanation:

There isnt rly a lot of information from this question but my best guess would be C.  It says "1 drop in each eye bid every 10 days", so assuming that 1 drop equals 1 ml and knowing we have to do it in "each eye bid" we could assume 2ml of eye drops would be used every 10 days.

Sorry if im wrong but i hope this helps have a great day and happy holidays (｢•-•)｢

Answer:

The domain corresponds to the values of the x and the range to the values of the y. So:

D: {-3, 0, 3}

R: {-6, 0, 6}

Answer:

[tex]\huge\boxed{A.}[/tex]

Step-by-step explanation:

Domain:

"Set of values on x-axis"

Domain = {-3,0,3}

Range:

"Set of values on y-axis"

Range = {-6,0,6}

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

Answer: x=10

Step-by-step explanation:To find the x-intercept, you have to set y=0.

4x-5y=40

4x-5(0)=40

4x-0=40

4x=40

Then divide both sides by 4 to get x=10

Hope this helps! :D