The water level at a local pier rises and falls with the tide. Yesterday, the maximum depth of the water at the pier was 8 feet, and the minimum depth was 4 feet. High tide occurred at 12:00 am and low tide occurred at 12:20 pm. Which function models the depth, in feet, of the water at the pier yesterday, as a function of the time t in minutes past high tide?

Answer: C, Bottom Left

Step-by-step explanation:

The  function that models the depth, in feet, of the water at the pier yesterday, as a function of the time t in minutes past high tide is: 2 cos(π/740t)+6.

Amplitude

A = 8 - 6

A = 2 ft

Average depth

A = (4 + 8)/2

A = 6 ft

Hence:

A+B=8

-A+B=4

1/2t=12×60×20=740

w=2π/t=π740

When t=0

d=2sin4+6=8

4=π/2

Hence:

d(t)=2 sin(π/740t + 4)+6

2 cos(π/740t)+6

Therefore the function that models the depth, in feet, of the water at the pier yesterday, as a function of the time t in minutes past high tide is: 2 cos(π/740t)+6.

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