The vertices of an ellipse are (0,-1) and (8,-1). The endpoints of the minor axis are (4,1) and (4,-3). Write the equation of the ellipse in general form

Answer:

x^2+4y^2-8x+8y+4=0

Step-by-step explanation:

The general form of the given ellipse is x² +4y² - 8x + 8y + 4 = 0.

An ellipse can be defined as a shape that looks like an oval circle.

The equation of an ellipse is

[tex]\dfrac{\left(x - h\right)^{2}}{a^{2}} + \dfrac{\left(y - k\right)^{2}}{b^{2}} = 1[/tex]

Where (h, k) is the center a and b are the lengths of the semi-major and the semi-minor axes.

The vertices of an ellipse are (0,-1) and (8,-1).

The endpoints of the minor axis are (4,1) and (4,-3).

The following equations take into account the different properties of an ellipse:

[tex]k = -1k=−1, h^{2} = a^{2}h 2 =a 2 , \left(h - 8\right)^{2} = a^{2}[/tex]

[tex]\begin{cases} b = 2 \\ k = -1 \\ h^{2} = a^{2} \\ \left(h - 8\right)^{2} = a^{2} \end{cases}[/tex]

We get that h = 4 k = -1, a = 4, and  b = 2

The standard form of the given ellipse is

[tex]\dfrac{\left(x - 4\right)^{2}}{4^{2}} + \dfrac{\left(y + 1\right)^{2}}{2^{2}} = 1[/tex]

So the general form will be as : x² +4y² - 8x + 8y + 4 = 0.

Thus, the general form of the given ellipse is x² +4y² - 8x + 8y + 4 = 0.

Learn more about ellipses here:

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