the third period element with the largest number of electrons

Answer:

the answer to this question is A H202

Answer:

mH₂O = 6.4116 g

Explanation:

Let's write the given reaction:

2H₂ + O₂ -------> 2H₂O

The problem states that 5.7 g of oxygen reacts with excess hydrogen, hence, the limiting reagent is the oxygen. With this mass of oxygen, we can determine the moles, and then, the moles of water with the mole ratio:

moles = mass / atomic weight        AW of O₂ = 16 g/mol

Replacing we have:

moles O₂ = 5.70 / (16 * 2)

moles O₂ = 0.1781 moles

According to the balanced reaction, 1 mole of Oxygen produces 2 moles of water, so we have a mole ratio 1:2, therefore the moles of water would be twice the moles of oxygen:

moles H₂O = 0.1781 * 2 = 0.3562 moles

Finally the mass of water can be calculated solving for the mass from the expression of moles, and using molecular mass of water:

m = moles * MM          MM H₂O = 18 g/mol

m = 0.3562 * 18

Hope this helps

Answer:

Yes water is a pure, Water, H2O, is a pure substance, a compound made of hydrogen and oxygen. Although water is the most abundant substance on earth, it is rarely found naturally in its pure form. Most of the time, pure water has to be created. Pure water is called distilled water or deionized water.

Oxygen is a chemical element – a substance that contains only one type of atom. Its official chemical symbol is O, and its atomic number is 8, which means that an oxygen atom has eight protons in its nucleus. Oxygen is a gas at room temperature and has no colour, smell or taste

Usually by pure substances we mean either pure elements (all one type of atom), regular crystals (atoms arranged in a repeating pattern), or things made of only one type of molecule (a tightly bound structure of one or more types of atoms). So copper is a pure substance in any form (only copper atoms).

Answer:

The volume required for the titration is 20.49mL.

Explanation:

In a titration of an acid, you must fill the burette until a particular volume (In the problem, the burette is filled until 2.49mL).

Then, when the titration is ran, the final volume helps to find the volume required to the titration as follows:

Volume of titration = Final Volume - Initial volume

Volume of titration = 22.98mL - 2.49mL = 20.49mL

Answer:

option B is correct answer of this question

it is. Evaporation

Answer:

It's filtration!

Explanation:

Filtration is a physical chemical operation that separates solid matter and fluid from a mixture!

Answer:

37.7 atm

Explanation:

Using the relation;

(P + an^2/V^2) (V - nb) = nRT

(P + an^2/V^2) = nRT/(V - nb)

a = 0.0341 atm dm^2 Mol^2

b = 0.0237 dm/mol

P = nRT/(V - nb) - an^2/V^2

P = [4.3 * 0.082 * 325 / (3.6 - (4.3 * 0.0237))] - (0.0341 * (4.3^2))/(3.6^2)

P = 114.595/(3.498) - 0.0487

P = 37.7 atm

Answer: The molecular formula will be [tex]H_{16}NOCl[/tex]

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of H = 5.80 g

Mass of N = 20.16 g

Mass of O = 23.02 g

Mass of Cl = 51.02 g

Step 1 : convert given masses into moles.

Moles of H =[tex]\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{5.80g}{1g/mole}=5.80moles[/tex]

Moles of N =[tex]\frac{\text{ given mass of N}}{\text{ molar mass of N}}= \frac{20.16g}{14g/mole}=1.44moles[/tex]

Moles of O =[tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{23.02g}{16g/mole}=1.44moles[/tex]

Moles of Cl =[tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{51.02g}{35.5g/mole}=1.44moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For H = [tex]\frac{5.80}{1.44}=4[/tex]

For N = [tex]\frac{1.44}{1.44}=1[/tex]

For O = [tex]\frac{1.44}{1.44}=1[/tex]

For Cl = [tex]\frac{1.44}{1.44}=1[/tex]

The ratio of H: N: O: Cl= 4: 1: 1: 1

Hence the empirical formula is [tex]H_4NOCl[/tex]

The empirical weight of [tex]H_4NOCl[/tex] = 4(1)+1(14)+ 1(16) + 1(35.5)= 69.5 g.

The molecular weight = 278 g/mole

Now we have to calculate the molecular formula.

[tex]n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{278}{69.5}=4[/tex]

The molecular formula will be=[tex]4\times H_4NOCl=H_{16}NOCl[/tex]

Answer:

Soap is a mixture of sodium salts of various naturally occurring fatty acids. ... Soap is produced by a saponification or basic hydrolysis reaction of a fat or oil. Currently, sodium carbonate or sodium hydroxide is used to neutralize the fatty acid and convert it to the salt.

Explanation:

I hope this helps! ^^

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Answer:

Soap is a salt of a fatty acid used in a variety of cleansing and lubricating products. In a domestic setting, soaps are surfactants usually used for washing, bathing, and other types of housekeeping. In industrial settings, soaps are used as thickeners, components of some lubricants, and precursors to catalysts

Answer:

Speed is the time rate at which an object is moving along a path, while velocity is the rate and direction of an object's movement. Put another way, speed is a scalar value, while velocity is a vector.

Explanation:

Hope it is helpful.....

Answer: the electrostatic potential energy is -3.26 × 10⁻¹⁸ J

Explanation:

Given the data in the question;

I think the value of electrostatic potential energy of calcium sulfide CaS formed will be less(more negative) than KCl because the Ca2+ and S2- ions has more charge that is +2 and -2 respectively when compared to Kcl which has +1 and -1 charge.so it will be more negative.

radius = r[tex]_{ca+2}[/tex] + r[tex]_{s-2}[/tex] = 100 + 184 = 284 pm = 2.84 × 10⁻¹⁰ m

we know that; k = 2.31 × 10⁻²⁸ J

q1 = 2  ( charge on Ca⁺² )

q2 = -2( charge on S⁻²)

so

Ep = k × q1q2/r

so we substitute

Ep = 2.31 × 10⁻²⁸ × (+2×-2) / 2.84 × 10⁻¹⁰

Ep = (2.31 × 10⁻²⁸ × -4) / 2.84 × 10⁻¹⁰

Ep = -9.24 × 10⁻²⁸ / 2.84 × 10⁻¹⁰

Ep = -3.26 × 10⁻¹⁸ J

Therefore, the electrostatic potential energy is -3.26 × 10⁻¹⁸ J

Based on the data provided, the electrostatic potential energy is -3.26 × 10⁻¹⁸ J

The electrostatic potential energy is the work done in moving the charge from infinity to that point against the electric field.

The electrostatic potential energy between any two charges q1, q2 separated by distance r is derived from Coulomb’s law and mathematically given as:

where

From the data provided:

ionic radii of Ca2+ r1 = 100 pm

ionic radii of S2– = 184 pm.

Chargeon Ca2+ = +2

Charge on S2_ = -2

From the data above, it most likely that the value of electrostatic potential energy of calcium sulfide CaS formed will be less(more negative) than KCl because the Ca2+ and S2- ions has a greater charge of +2 and -2 respectively compared to Kcl which has +1 and -1 charge.

Calculating the electrostatic potential energy, Ep:

radius = r1 + r2 = 100 + 184 = 284 pm

r = 2.84 × 10⁻¹⁰ m

k = 2.31 × 10⁻²⁸ J

q1 = 2  ( charge on Ca⁺² )

q2 = -2( charge on S⁻²)

Then:

Ep = k × q1q2/r

Substituting the values above in the equation:

Ep = 2.31 × 10⁻²⁸ × (+2 ×-2) / 2.84 × 10⁻¹⁰

Ep = (2.31 × 10⁻²⁸ × -4) / 2.84 × 10⁻¹⁰

Ep = -9.24 × 10⁻²⁸ / 2.84 × 10⁻¹⁰

Ep = -3.26 × 10⁻¹⁸ J

Therefore, the electrostatic potential energy is -3.26 × 10⁻¹⁸ J.

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Answer:

[tex] \sqrt[.132 = ]{32 = ? = 1} = .82[/tex]

Answer:

693 j

Explanation:

weight =75 g * specific heat of copper = .385j/g * change in temp = 24

= 693

Answer:

0.389 M

Explanation:

From the question given above, the following data were obtained:

Mass of CuCl₂ = 78.5 g

Volume of solution = 1.50 L

Molarity of CuCl₂ =?

Next, we shall determine number of mole in 78.5 g of CuCl₂. This can be obtained as follow:

Molar mass of CuCl₂ = 63.5 + (35.5×2)

= 63.5 + 71

= 134.5 g/mol

Mass of CuCl₂ = 78.5 g

Number of mole of CuCl₂ =?

Mole = mass / Molar mass

Number of mole of CuCl₂ = 78.5 / 134.5

Number of mole of CuCl₂ = 0.584 mole

Finally, we shall determine the molarity of the solution. This can be obtained as follow:

Number of mole of CuCl₂ = 0.584 mole

Volume of solution = 1.50 L

Molarity of CuCl₂ =?

Molarity = mole / Volume

Molarity of CuCl₂ = 0.584 / 1.50

Molarity of CuCl₂ = 0.389 M

The molarity of a solution that contains 78.5 g of copper(II) chloride in 1.50 L of solution is 0.389M.

The molarity of a solution can be calculated

From the question given above, the following data were obtained:

Next, we shall determine number of moles in 78.5g of CuCl₂. This can be obtained as follow:

Molar mass of CuCl₂ = 63.5 + (35.5×2)

= 63.5 + 71

= 134.5 g/mol

Mass of CuCl₂ = 78.5g

Number of mole of CuCl₂ = 78.5 / 134.5

Number of mole of CuCl₂ = 0.584 moles

The determine the molarity of the solution. This can be obtained as follow:

Molarity = mole / Volume

Molarity of CuCl₂ = 0.584 / 1.50

Molarity of CuCl₂ = 0.389M

Therefore, molarity of a solution that contains 78.5 g of copper(II) chloride in 1.50 L of solution is 0.389M.

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Answer:

The same instrument must be used to measure the unknown solution as was used to measure the known (standard) solutions that were used to create the calibration curve.

The analyte in the unknown solution must be the same analyte (or type of analyte) that is present in the known (standard) solutions that were used to create the calibration curve.

Domain and range restrictions must be observed.

Explanation:

Calibration curves are tools necessary in understanding the instrumental response for any analyte.

A calibration curve is obtained by preparing a set of  standard solutions with known concentrations of the analyte. The instrument response for each concentration is measured  and plotted against the concentration of the standard solution. The linear portion of this plot may be used to determine the unknown concentration of a sample of the analyte.  

The equation of the best-fit line is  used to determine the concentration of the unknown sample.

Answer and Explanation:

The introduced species is, literally, a species that was introduced into an environment by human action. In other words, an introduced species is one that is not native to a region, does not occur naturally, but has been taken by humans to that region.

An invasive species, on the other hand, is one that was introduced naturally in an environment, but multiplied in a harmful way, causing a strong imbalance in the region.

I'm certain the answer is D: All of the above, but please correct me if I'm wrong ^^

Answer:

1.25M

Explanation:

Answer:

Lead iodide (II) is an inorganic compound, lead salt and hydrogen acid, with the PbI2 formula.

Answer:

Within three molecules of Ethane, it would have 6 carbon, and 18 hydrogen atoms in it.

Explanation:

Answer:

The octet rule is only applicable to the main group elements. The molecules of the halogens, oxygen, nitrogen, and carbon are known to obey the octet rule. In general, the elements that obey this rule include the s-block elements and the p-block elements (except hydrogen, helium, and lithium).

Explanation:

I hope this helps and pls mark me brainliest :)

Answer:

93 kPa

Explanation:

Step 1: Given data

Step 2: Calculate the final pressure of carbon dioxide gas

If we assume carbon dioxide behaves as an ideal gas, we can calculate the final pressure of carbon dioxide gas using Boyle's law.

P₁ × V₁ = P₂ × V₂

P₂ = P₁ × V₁/V₂

P₂ = 155 kPa × 3.0 L/5.0 L = 93 kPa

Answer:

The mass of oxygen the container must have is 150.85 g.

Explanation:

Given;

mass of the oxygen, m₁ = 44.5 g

initial pressure of the gas, P₁ = 2.3 atm

final pressure of the gas, P₂ = 7.8 atm

Atomic mass of oxygen gas, = O₂ = 16 x 2 = 32 g

initial number of moles of oxygen in the container, n₁ = 44.5/32 = 1.39

let the final number of moles of oxygen = n₂

Apply ideal gas equation;

PV = nRT

[tex]\frac{PV}{Rn} = T\\\\since \ temperature\ T \ is \ constant;\\\\\frac{P_1V}{Rn_1} = \frac{P_2V}{Rn_2}\\\\\frac{P_1}{n_1} = \frac{P_2}{n_2} \\\\n_2 = \frac{n_1P_2}{P_1} \\\\n_2 = \frac{1.39 \times 7.8}{2.3} \\\\n_2 = 4.714 \ moles[/tex]

The mass of the oxygen in grams is calculated as;

m₂ = 4.714 x 32g

m₂ = 150.85 g

Therefore, the mass of oxygen the container must have is 150.85 g.

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Answer:

Plants use carbon dioxide for photosynthesis

Explanation:

They take it in, and chemically combined it with water to form glucose and oxygen

Answer:

a) the number-average molecular weight is 32,400 g/mol

b) the weight-average molecular weight is 36,320 g/mol

c) the degree of polymerization is 770

Explanation:

Given the data in the question;

Molecular                  Mean        Number      Weight      Number        Weight

weight                                                                             average         average

(g/mol)                    Mi(g/mol)         xi                wi          xiMi                  wiMi

8,000-16,000            12,000        0.07           0.03         840                360

16,000-24,000          20,000       0.15           0.09         3000              1800

24,000-32,000         28,000       0.26           0.21          7280              5880

32,000-40,000         36,000       0.27           0.27         9720               9720

40,000-48,000         44,000       0.18            0.28         7920              12320

48,000-56,000         52,000       0.07           0.12          3640              6240

∑                                                                                Mn=32,400     Mw=36,320

so;

a)  the number-average molecular weight

Mn = ∑Mixi

so from the table above; summation of Row Mixi

Mn = ∑Mixi = 32,400

Therefore, the number-average molecular weight is 32,400 g/mol

b) the weight-average molecular weight

Mw = ∑Miwi

so from the table above; summation of Row Miwi

Mw = ∑Miwi = 36,320

Therefore, the weight-average molecular weight is 36,320 g/mol

c) the degree of polymerization

the degree of polymerization of polypropylene can be determined using number-average molecular and repeat unit molecular weight.

now, for polypropylene { CH₂ = CH - CH₃ }

the repeat unit consist of 3 carbon atoms and 6 hydrogen atoms

given that;

Atomic weight of Carbon mC = 12.01 g/mol and

Atomic weight of  Hydrogen mH = 1.008 g/mol

now we find the repeat unit molecular weight of polypropylene

m = nCmC + nHmH

where n is the number of repeat of atoms

so we substitute

m = ( 3 × 12.01) + ( 6 × 1.008)

m = 36.03 + 6.048

m = 42.078 g/mol

now we calculate the degree of polymerization;

DP = Mn / m

so we substitute

DP = 32,400 / 42.078

DP = 769.9985 ≈ 770

Therefore,  the degree of polymerization is 770

Answer:

The solute that is most likely soluble in hexane is S₈

Explanation:

S₈ is a non-polar solute that exhibits the same characteristics and properties as hexane. Following the common principle "like dissolves like"; polar compounds will be soluble in polar solvents while non-polar compounds will be soluble in non-polar solvents. As such, since S₈ is non-polar, then it will be soluble in hexane.

Answer: 218.4 g of [tex]CaO[/tex] will be produced from 3.9 moles of [tex]CaCO_3[/tex]

Explanation:

The balanced chemical equation is:

[tex]CaCO_3\rightarrow CaO+CO_2[/tex]  

According to stoichiometry :

1 mole of [tex]CaCO_3[/tex] produce =  1 mole of [tex]CaO[/tex]

Thus 3.9 moles of [tex]CaCO_3[/tex] will produce=[tex]\frac{1}{1}\times 3.9=3.9moles[/tex] of [tex]CaO[/tex]

Mass of [tex]CaO=moles\times {\text {Molar mass}}=3.9moles\times 56g/mol=218.4g[/tex]

Thus 218.4 g of [tex]CaO[/tex] will be produced from 3.9 moles of [tex]CaCO_3[/tex]

218.4 grams of CaO is produced using 3.9 moles CaCO₃.

Moles of any substance will be define as:

n = W / M

Given chemical reaction is:

CaCO₃ → CaO + CO₂

From the above equation it is clear that according to the concept of stoichiometry 1 mole of CaCO₃ is producing 1 mole of CaO. By using above formula we calculate grams as follow:

W = n × M, where

n = no. of moles of CaO = 3.9 moles

M = molar mass of CaO = 56 g/mole

W = 3.9 × 56 = 218.4 g

Hence, 218.4 grams of CaO is produced.

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Answer:

See explanation

Explanation:

The reaction between tetraphenylcyclopentadienone and dimethyl acetylenedicarboxylate as well as the reaction of  tetraphenylcyclopentadienone and diphenylacetylene are  Diels Alder reactions. The former is performed in presence of a solvent while the former is performed neat.

The reaction of tetraphenylcyclopentadienone and dimethyl acetylenedicarboxylate leads to the formation of a more resonance-stabilized aromatic ring(lower energy product) compared to the reaction of  tetraphenylcyclopentadienone and diphenylacetylene.

Hence, the reaction between tetraphenylcyclopentadienone and dimethyl acetylenedicarboxylate can be conducted at relatively lower temperature compared to the reaction between tetraphenylcyclopentadienone and diphenylacetylene.