The thermite reaction occurs when iron(III) oxide reacts with solid
aluminum. The reaction is so hot that molten iron forms as a product.
>
Fe2O3(s) + Al(s) → Fe(C) + Al2O3(s)
What mass of aluminum should be used in order to completely
consume 10.0 g Fe2O3(s)? If the reaction described produces 5.3 g
Al2O3(s), what is the percent yield?

Answers

Answer 1

Answer:

[tex]m_{Al}=3.38gAl[/tex]

[tex]Y=83.1\%[/tex]

Explanation:

Hello.

In this case, for the given balanced reaction:

[tex]Fe_2O_3(s) + 2Al(s)\rightarrow 2Fe(s) + Al_2O_3(s)[/tex]

For 10.0 g of iron (III) oxide (molar mass = 160 g/mol), based on the 1:2 mole ratio with Al (atomic mass = 27 g/mol), the required mass is then:

[tex]m_{Al}=10.0gFe_2O_3*\frac{1molFe_2O_3}{160gFe_2O_3} *\frac{2molAl}{1molFe_2O_3} *\frac{27gAl}{1molAl} \\\\m_{Al}=3.38gAl[/tex]

Moreover, as 5.3 g of aluminum oxide are actually yielded, from the 10.0 g of iron (III) oxide, we can compute the theoretical mass of aluminum oxide (molar mass = 102 g/mol) via their 1:1 mole ratio:

[tex]m_{Al_2O_3}=10.0gFe_2O_3*\frac{1molFe_2O_3}{160gFe_2O_3} *\frac{1molAl_2O_3}{1molFe_2O_3} *\frac{102gAl_2O_3}{1molAl_2O_3} \\\\m_{Al_2O_3}=6.38gAl_2O_3[/tex]

Thus, the percent yield (actual/theoretical*100%) turns out:

[tex]Y=\frac{5.3 g}{6.38 g}* 100\%\\\\Y=83.1\%[/tex]

Best regards.


Related Questions

2. The new element Odessium (Od) was discovered in 2020 by Mr. Green. It has three isotopes: Od-284
(34.60%), Od-285 (21.20%), and Od-288 (44.20%). What is its average atomic mass?|

Answers

Answer:

Odessium (Od) has an average atomic mass of 284.45

Explanation:

Average mass is calculated from the isotopes of an element weighted by their relative abundance.

To calculate the relative average mass, you need to find the % of each isotope and use these to calculate the relative average mass

(34.60 %)/100 x 284=96.73(21.20 %)/100 x 285=60.42(44.20 %)/ 100 x 288=127.296

Add all 3 answers to get the relative average mass

96.73 + 60.42 + 127.296= 284.45

2. Using the following data, calculate the average atomic mass of magnesium (give your answer to the nearest
.01 ) : Show all work!
Isotope: Mg Percent abundance: 78.70%
24
Isotope: 'Mg Percent abundance: 10.13%
25
Isotope:
Mg Percent abundance: 11.17%
26

Answers

Answer:

24.32

Explanation:

From the question given above, the following data were obtained:

Isotope A:

Mass of A = 24

Abundance (A%) = 78.70%

Isotope B

Mass of B = 25

Abundance (B%) = 10.13%

Isotope C:

Mass of C = 26

Abundance (C%) = 11.17%

Average atomic mass of Mg =..?

The average atomic mass of Mg can be obtained as illustrated below:

Average atomic mass = [(Mass of A × A%)/100] + [(Mass of B × B%)/100] + [(Mass of C × C%)/100]

Average atomic mass = [(24 × 78.70)/100] + [(25 × 10.13)/100] + [(26 × 11.17)/100]

= 18.888 + 2.5325 + 2.9042

= 24.3247 ≈ 24.32

Therefore, the average atomic mass of magnesium (Mg) is 24.32

why is soaking necessary for seed germination

Answers

Answer:

Explanation:

well it needs water like us to stay alive

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Answers

Answer:

The balloon’s volume to decrease

Explanation:

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Answer:

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Explanation:

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RE
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Answers

Answer:

An atom is the smallest particle of an element that still has the properties of that element. Atoms, in turn, are composed of subatomic particles, including negative electrons, positive protons, and neutral neutrons. The number of protons in an atom determines the element it represent

Explanation:

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Answers

Answer:

I'm pretty sure k

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I'm not for sure I'm trying to help

Answer:

Potassium

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Answers

Answer:

cool

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Answers

Answer:

Energy is used when someone is climbing while energy is not used when someone is going down the slope

A pizza is an example of a heterogeneous mixture. Explain why it is classified as such?​

Answers

Answer:

Hi!

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Answers

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Write
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Answer:

b

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Answers

Answer:

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Explanation:

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Answers

Answer:

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Explanation:

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c ...The number of filled electron shells increases.
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Answers

Answer:

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Answers

Answer:

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(B) becomes a positive ion
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Answers

Answer:

(C) releases energy

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(C) releases energy

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Answers

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Explanation:

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An antacid tablet contains 640.0 mg of magnesium oxide per tablet.
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Answers

Answer:

317.6 mL

Explanation:

Step 1: Write the balanced neutralization equation

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Step 2: Calculate the mass corresponding to 640.0 mg of MgO

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Answers

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Answers

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0.00004

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Answer:

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