The Sun is only an average sized star. Why does it appear so much brighter than any other star?

Explanation:

if the current is 1A

V=iR

V= 1 × 8

V = 8volts

Answer:

(a) a = 2.44 m/s²

(b) s = 63.24 m

Explanation:

(a)

We will use the second equation of motion here:

[tex]s = v_it+\frac{1}{2}at^2[/tex]

where,

s = distance covered = 47 m

vi = initial speed = 0 m/s

t = time taken = 6.2 s

a = acceleration = ?

Therefore,

[tex]47\ m = (0\ m/s)(6.2\ s)+\frac{1}{2}a(6.2\ s)^2\\\\a = \frac{2(47\ m)}{(6.2\ s)^2}[/tex]

a = 2.44 m/s²

(b)

Now, we will again use the second equation of motion for the complete length of the inclined plane:

[tex]s = v_it+\frac{1}{2}at^2[/tex]

where,

s = distance covered = ?

vi = initial speed = 0 m/s

t = time taken = 7.2 s

a = acceleration = 2.44 m/s²

Therefore,

[tex]s = (0\ m/s)(6.2\ s)+\frac{1}{2}(2.44\ m/s^2)(7.2\ s)^2\\\\[/tex]

s = 63.24 m

Answer:

Explanation:

Whats the entire question?

Answer:

Hello! Your answer would be, A) True

Explanation:

Hope I helped! Ask me anything if you have any questions. Brainiest plz!♥ Hope you make a 100%. Have a nice morning! -Amelia♥

Answer:

Explanation:

Dear Student, this question is incomplete, and to attempt this question, we have attached the complete copy of the question in the image below. Please, Kindly refer to it when going through the solution to the question.

To objective is to find the:

(i) required heat exchanger area.

(ii) flow rate to be maintained in the evaporator.

Given that:

water temperature = 300 K

At a reasonable depth, the water is cold and its temperature = 280 K

The power output W = 2 MW

Efficiency [tex]\zeta[/tex] = 3%

where;

[tex]\zeta = \dfrac{W_{out}}{Q_{supplied }}[/tex]

[tex]Q_{supplied } = \dfrac{2}{0.03} \ MW[/tex]

[tex]Q_{supplied } = 66.66 \ MW[/tex]

However, from the evaporator, the heat transfer Q can be determined by using the formula:

Q = UA(L MTD)

where;

[tex]LMTD = \dfrac{\Delta T_1 - \Delta T_2}{In (\dfrac{\Delta T_1}{\Delta T_2} )}[/tex]

Also;

[tex]\Delta T_1 = T_{h_{in}}- T_{c_{out}} \\ \\ \Delta T_1 = 300 -290 \\ \\ \Delta T_1 = 10 \ K[/tex]

[tex]\Delta T_2 = T_{h_{in}}- T_{c_{out}} \\ \\ \Delta T_2 = 292 -290 \\ \\ \Delta T_2 = 2\ K[/tex]

[tex]LMTD = \dfrac{10 -2}{In (\dfrac{10}{2} )}[/tex]

[tex]LMTD = \dfrac{8}{In (5)}[/tex]

LMTD = 4.97

Thus, the required heat exchanger area A is calculated by using the formula:

[tex]Q_H = UA (LMTD)[/tex]

where;

U = overall heat coefficient given as 1200 W/m².K

[tex]66.667 \times 10^6 = 1200 \times A \times 4.97 \\ \\ A= \dfrac{66.667 \times 10^6}{1200 \times 4.97} \\ \\ \mathbf{A = 11178.236 \ m^2}[/tex]

The mass flow rate:

[tex]Q_{H} = mC_p(T_{in} -T_{out} ) \\ \\ 66.667 \times 10^6= m \times 4.18 (300 -292) \\ \\ m = \dfrac{ 66.667 \times 10^6}{4.18 \times 8} \\ \\ \mathbf{m = 1993630.383 \ kg/s}[/tex]

Answer:

the maximum allowable current is 7302.967  amperl

Explanation:

The computation of the maximum allowable current is shown below;

Force F = mean ÷ 4π 2 I_1 I_2 ÷d  × ΔL

200 N = (10)^-7 (2I × I) ÷ 0.08 × 1.5

200 = 3.75 × 10^-6 I^2

I = √200 ÷ √ 3.75 × 10^-6

= 7302.967  amperl

Hence, the maximum allowable current is 7302.967  amperl

Basically we applied the above formula

Answer:

12558 J

Explanation:

Please do mark as brainliest. Hope this helps! :)

Answer:

B. evaluation

Explanation:

An employee can be defined as an individual who is employed by an employer of labor to perform specific tasks, duties or functions in an organization.

Basically, an employee is saddled with the responsibility of providing specific services to the organization or company where he is currently employed while being paid a certain amount of money hourly, daily, weekly, or monthly depending on the contractual agreement between the two parties (employer and employee).

Hence, while an employer may be the owner of a business firm or company, an employee is a subordinate employed to provide unwavering services to the employer while also, being professional and diligent at all times.

Human resources management (HRM) can be defined as an art of managing, controlling and improving the number of people (employees or workers), functions, evaluation of employees, activities which are being used effectively and efficiently by an organization.

Hence, human resources managers are saddled with the responsibility of recruiting, evaluating, managing and improving the welfare and working conditions of the employees working in an organization.

Basically, the human resources manager carry out appraisals on the performance of the various employees working in an organization. These informations about employees are typically used for promotional purposes, allowances and other benefits or form of rewards.

Answer:

h = 3.5 m

Explanation:

First, we will calculate the final speed of the ball when it collides with a seesaw. Using the third equation of motion:

[tex]2gh = v_f^2 - v_i^2\\[/tex]

where,

g = acceleration due to gravity = 9.81 m/s²

h = height = 3.5 m

vf = final speed = ?

vi = initial speed = 0 m/s

Therefore,

[tex](2)(9.81\ m/s^2)(3.5\ m) = v_f^2 - (0\ m/s)^2\\v_f = \sqrt{68.67\ m^2/s^2}\\v_f = 8.3\ m/s[/tex]

Now, we will apply the law of conservation of momentum:

[tex]m_1v_1 = m_2v_2[/tex]

where,

m₁ = mass of colliding ball = 3.6 kg

m₂ = mass of ball on the other end = 3.6 kg

v₁ = vf = final velocity of ball while collision = 8.3 m/s

v₂ = vi = initial velocity of other end ball = ?

Therefore,

[tex](3.6\ kg)(8.3\ m/s)=(3.6\ kg)(v_i)\\v_i = 8.3\ m/s[/tex]

Now, we again use the third equation of motion for the upward motion of the ball:

[tex]2gh = v_f^2 - v_i^2\\[/tex]

where,

g = acceleration due to gravity = -9.81 m/s² (negative for upward motion)

h = height = ?

vf = final speed = 0 m/s

vi = initial speed = 8.3 m/s

Therefore,

[tex](2)(9.81\ m/s^2)h = (0\ m/s)^2-(8.3\ m/s)^2\\[/tex]

h = 3.5 m

Answer: Different types of telescopes usually don't take simultaneous readings. Space is a dynamic system, so an image taken at one time is not necessarily the precise equivalent of an image of the same phenomena taken at a later time. And often, there is barely enough time for one kind of telescope to observe extremely short-lived phenomena like gamma-ray bursts. By the time other telescopes point to the object, it has grown too faint to be detected.

Explanation: Trust me

Answer:

3.26mph

Explanation:

To calculate speed, use the formula distance/time. In this case, just divide 14.7  by 4.5.

The speed with which the cat runs towards its food bowl is 7.3 Miles per hour.

Given the data in the question

Speed of the cat; [tex]v = \ ?[/tex]

Speed is the time rate at which an object is moving along a path

Speed is the time rate at which an object is displaced.

Speed = Distance / Time

[tex]v = s / t[/tex]

We substitute our values into the equation

[tex]v = \frac{14.7m}{4.5s}\\\\v = 3.267 m/s\\\\v = 7.3mph[/tex]

Therefore, the speed with which the cat runs towards its food bowl is 7.3 Miles per hour.

Learn more: https://brainly.com/question/680492

Answer:

v = 2.82 m/s

Explanation:

For this exercise we can use the conservation of energy relations.

We place our reference system at the point where block 1 of m₁ = 4 kg

starting point. With the spring compressed

        Em₀ = K_e + U₂ = ½ k x² + m₂ g y₂

final point. When block 1 has descended y = - 0.400 m

        Em_f = K₂ + U₂ + U₁ = ½ m₂ v² + m₂ g y₂ + m₁ g y

as there is no friction, the energy is conserved

       Em₀ = Em_f

       ½ k x² + m₂ g y₂ = ½ m₂ v² + m₂ g y₂ + m₁ g y

       ½ k x² - m₁ g y = ½ m₂ v²

       v² = [tex]\frac{k}{m_2} x^2 - 2 \frac{m_1}{m_2} \ g y[/tex]

let's calculate

        v² = [tex]\frac{180}{6.00} \ 0.300^2 - 2 \ \frac{4.00}{6.00} \ 9.8 \ (- 0.400)[/tex]

        v² = 2.7 + 5.23

        v = √7.927

        v = 2,815 m / s

using of significant figures

        v = 2.82 m/s

Solution :

Given :

M = 0.35 kg

[tex]$m=\frac{M}{2}=0.175 \ kg$[/tex]

Total mechanical energy = constant

or [tex]$K.E._{top}+P.E._{top} = K.E._{bottom}+P.E._{bottom}$[/tex]

But [tex]$K.E._{top} = 0$[/tex] and [tex]$P.E._{bottom} = 0$[/tex]

Therefore, potential energy at the top = kinetic energy at the bottom

[tex]$\Rightarrow mgh = \frac{1}{2}mv^2$[/tex]

[tex]$\Rightarrow v = \sqrt{2gh}$[/tex]

      [tex]$=\sqrt{2 \times 9.8 \times 0.35}$[/tex]      (h = 35 cm = 0.35 m)

      = 2.62 m/s

It is the velocity of M just before collision of 'm' at the bottom.

We know that in elastic collision velocity after collision is given by :

[tex]$v_1=\frac{m_1-m_2}{m_1+m_2}v_1+ \frac{2m_2v_2}{m_1+m_2}$[/tex]

here, [tex]$m_1=M, m_2 = m, v_1 = 2.62 m/s, v_2 = 0$[/tex]

∴ [tex]$v_1=\frac{0.35-0.175}{0.5250}+\frac{2 \times 0.175 \times 0}{0.525}[/tex]

      [tex]$=\frac{0.175}{0.525}+0$[/tex]

     = 0.33 m/s

Therefore, velocity after the collision of mass M = 0.33 m/s

Answer: 4.94cm³

Explanation:

Data;

ρ = 1.59g/cm³

mass = 7.85g

volume = ?

density = mass / volume

ρ = m / v

v = m / ρ

v = 7.85 / 1.59

v = 4.94cm³

Explanation:

G. gamma rays because they are produced by the hottest and most energetic objects in the universe, such as neutron stars and pulsars, supernova explosions, and regions around black holes.

hope this helps you

have a nice day:)

Answer:

(a) Energy Density = 160.94 J/m³

(b) Energy Stored = 0.192 J

Explanation:

(a)

The energy density of the magnetic field inside the solenoid is given by the following formula:

[tex]Energy\ Denisty = \frac{B^2}{2\mu_o}\\[/tex]

where,

B = magnetic field strength of solenoid = [tex]\frac{\mu_oNI}{l}[/tex]

Therefore,

[tex]Energy\ Density = \frac{\mu_oN^2I^2}{2l^2}[/tex]

where,

μ₀ = permeability of free space = 4π x 10⁻⁷ N/A²

N = No. of turns = 1300

I = current = 8.15 A

L = length = 66.2 cm = 0.662 m

Therefore,

[tex]Energy\ Density = \frac{(4\pi\ x\ 10^{-7}\ N/A^2)(1300)^2(8.15\ A)^2}{2(0.662\ m)^2}[/tex]

Energy Density = 160.94 J/m³

(b)

Energy Stored = (Energy Density)(Volume)

Energy Stored = (Energy Density)(Area)(L)

Energy Stored = (160.94 J/m³)(0.0018 m²)(0.662 m)

Energy Stored = 0.192 J

Answer: 0.9

Explanation:

If frequency equals the amount of oscillations in one second then 20/18 = f = 1.11  and to find period (T) then we use the equation T= 1/f or in this case 1/1.11 = 0.9

Answer:

The answer is E., or "Plate Boundaries".

The word best describes the definition of the location of volcanoes is "plate boundaries". Therefore, option (E) is correct.

The lithosphere is broken into tectonic plates that undergo some large motions and the boundary regions between plates are called plate boundaries. Based on their motions there are three kinds of plate boundaries: divergent, convergent, and transform.

Divergent boundaries are moving away from one another and separate, they form a rift. As the gap widens, the underlying layer may be soft for molten lava underneath to push upward and resulting in the formation of volcanic islands.

Convergent boundaries move towards one another and collide, subduction usually takes place. The denser plate goes underneath the less dense one and the plate boundaries also experience buckling.

Transform boundaries slide alongside one another and are exposed to huge amounts of stress and strain and are momentarily held in place. The two plates succeed in moving with respect to one another and cause earthquakes.

Learn more about plate boundaries, here:

https://brainly.com/question/18256552

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Answer:

0.063 Kg

Explanation:

From the question given above, the following data were obtained:

Frequency (f) = 10 Hz

Spring constant (K) = 250 N/m

Mass (m) =?

Next, we shall determine the period of oscillation. This can be obtained as follow:

Frequency (f) = 10 Hz

Period (T) =?

T = 1/f

T = 1/10

T = 0.1 s

Finally, we shall determine the mass of the spring. This can be obtained as follow:

Spring constant (K) = 250 N/m

Period (T) = 0.1 s

Pi (π) = 3.14

Mass (m) =?

T = 2π√(m/K)

0.1 = 2 × 3.14 × √(m/250)

0.1 = 6.28 × √(m/250)

Divide both side by 6.28

0.1 / 6.28 = √(m/250)

Take the square of both side.

(0.1 / 6.28)² = m/250

Cross multiply

m = (0.1 / 6.28)² × 250

m = 0.063 Kg

Therefore, the mass of the spring is 0.063 Kg.

Answer:

hope u can understand the method

Solution :

Mass is varied keeping frequency constant.

Wavelength, λ  [tex]$=\frac{2l}{n}$[/tex]

where length of spring = l

           number of segments = n

Velocity, v = λ x f

                 = [tex]$\sqrt{\frac{T}{\mu}}$[/tex]

[tex]$\mu $[/tex] =  mass density, T = tension in string

[tex]$T=\frac{4 \mu l^2f^2}{n^2}$[/tex]

[tex]$T=mg = \frac{4 \mu l^2f^2}{n^2}$[/tex]  , n = 2

[tex]$T = (m-2.2)g = \frac{4 \mu l^2f^2}{n^2}, n = 5$[/tex]

[tex]$\Rightarrow \frac{m}{m-2.2}=\frac{25}{4}$[/tex]

[tex]$\Rightarrow m = 2.619\ kg$[/tex]

Therefore, μ = 0.002785 kg/ m

Frequency is varied keeping T constant

[tex]$T=\frac{4 \mu l^2f^2}{n^2}, f=60 , \ \ n = 2$[/tex]

[tex]$T=\frac{4 \mu l^2f^2}{n^2}, f=? , \ \ n = 7$[/tex]

[tex]$\Rightarrow \frac{60^2}{4}=\frac{f^2}{49}$[/tex]

f = 210 Hz

Explanation:

hope it helps.

Answer:

The Moment of a force is a measure of its tendency to cause a body to rotate about a specific point or axis.

Answer:

Torque

Explanation:

I serached it up sjdjbdjd

Answer:

0.4112 m

Explanation:

The mass of the 1st ball = 3.6 kg

The height of the 1st ball =3.5 m

The mass of the 2nd ball = 3.6 kg

Mass of the bar M = 9.9 kg

Length of the bar L = 4.2 m

The velocity of the ball when it dropped from the height is calculated by using the formula:

[tex]\dfrac{1}{2}mv_1^2 = mgh_1 \\ \\ v = \sqrt{2gh_1} \\ \\ v =\sqrt{2\times9.8 \times 3.5} \\ \\ v = 8.283 \ m/s\\\\[/tex]

Provided that the bar is pivoted at the center and the ball is placed at the two ends, the moment of inertia for the bar is:

[tex]I = \dfrac{1}{12}ML^2 + m_1 (\dfrac{L}{2})^2 + m_2(\dfrac{L}{2})^2 \\ \\ =\dfrac{1}{12}(9.9kg)(4.2m)^2 + [3.6 kg+3.6kg](\dfrac{4.2}{2 \ m})^2 \\ \\ = 46.305 \ kg.m^2[/tex]

The angular momentum of the system due to the ball can be determined by using the formula:

L = mvr

L = (3.6 kg) (8.283 m/s) (2.1 m)

L = 62.61948 kg. m²

Now, Using the law of conservation:

[tex]L_i = L_f \\ \\ 62.61948 \ kg.m^2/s = I \omega \\ \\[/tex]

[tex]\omega = \dfrac{62.6198 \ kg.m^2/s}{46.305 \ kg.m^2}[/tex]

[tex]\omega =1.352 \ rad/s[/tex]

The linear angular velocity is deduced to be:

[tex]v = r \omega \\ \\ v = (2.1 \ m) ( 1.352 \ rad/s) = 2.839 \ m/s[/tex]

∴

the height raised by the second ball is:

[tex]h_2 = \dfrac{v^2}{2g} \\ \\ h_2 = \dfrac{(2.839)^2}{2(9.8 \ m/s^2)} \\ \\ h_2 =0.4112 \ m[/tex]

Answer:

R = v^2 sin 2 theta / g

The range provides the distance a projectile can travel

R(max) = v^2 / g    if theta = 45 deg

R = 2.7^2 / 9.8 = .74 m

Answer:

Explanation:

The different types of government include a direct democracy, a representative democracy, socialism, communism, a monarchy, an oligarchy, and an autocracy

Answer:

C, Red has the longest one

c red

red has longest wavelength

amnh dot org

Answer:

m=29.6kg

Explanation:

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