The state of stress at a point is plane stress represented by the Mohr's circle shown. What is the largest principal stress at this point

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Answer 1

To find the largest principal stress at the given point, we need to analyze the Mohr's circle. Mohr's circle is a graphical method used to determine principal stresses and their orientations in a plane stress state.

From the given Mohr's circle, we can see that the largest principal stress occurs at the point where the circle intersects the x-axis. This point represents the maximum tensile stress.

To find the value of the largest principal stress, we need to read the corresponding value on the x-axis. Let's call this value σ1.

Therefore, the largest principal stress at this point is σ1.

Please note that without a visual representation of the Mohr's circle, it is not possible to provide a specific numerical value for σ1. However, by analyzing the circle, you can determine the largest principal stress based on its position relative to the x-axis.

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a voltage amplifier with an input resistance of 40 kn, an output resistance of i 00 n, and a gain of 300 v n is connected between a 10-kn source with an open-circuit voltage of to m v and a i 00-n load. for this situation:

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The current flowing through the circuit is approximately 0.4 μA.

To analyze the situation, we can use the voltage divider rule and the concept of load and source resistance to determine the voltage across the load and the current flowing through the circuit.

Given data:

Input resistance (Rin) = 40 kΩ

Output resistance (Rout) = 100 Ω

Gain (Av) = 300 V/V

Source resistance (Rsource) = 10 kΩ

Open-circuit voltage (Voc) = 20 mV

Load resistance (Rload) = 100 Ω

To calculate the voltage across the load (Vload), we can use the voltage divider rule:

Vload = Voc * (Rload / (Rsource + Rin + Rload))

Substituting the given values:

Vload = 20 mV * (100 Ω / (10 kΩ + 40 kΩ + 100 Ω))

Vload = 20 mV * (100 Ω / 50.1 kΩ)

Vload ≈ 0.04 mV

The voltage across the load is approximately 0.04 mV.

To calculate the current flowing through the circuit, we can use Ohm's Law:

I = Vload / Rload

Substituting the values:

I = 0.04 mV / 100 Ω

I = 0.4 μA

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