The skin is approximately how much percentage of our total body wieght? 0−5%
5−10%
10−15%
15−20%

Answers

Answer 1

The skin makes up approximately 15-20% of our total body weight.

The skin is the largest organ in the human body and serves several important functions. It acts as a protective barrier against external factors, helps regulate body temperature, and plays a crucial role in sensory perception.

The percentage of body weight attributed to the skin can vary depending on factors such as age, overall body composition, and individual characteristics. However, the commonly accepted range is around 15-20%. It is important to note that this percentage includes not only the outermost layer of the skin (epidermis) but also the underlying layers (dermis and subcutaneous tissue).

While the skin may not seem heavy compared to other organs like the heart or liver, its large surface area contributes to its overall weight. This percentage estimate underscores the significance of the skin as a vital organ and emphasizes the importance of proper skincare and protection to maintain its health and functionality.

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suppose you treat a culture of human cells with mutagenic ultraviolet (UV) radiation and you want to determine how many cells have initiated apoptosis and how many have not. Which of the following features would be present in the normal (non-apoptotic cells? a. phosphatidylserine will be found in the cytoplasm b. phosphatidylserine will be found in mitochondria c. cytochrome c will be found in mitochondria d.cytochrome c will be found in the cytoplasm e. cytochrome c will be found in the outer leaflet of the plasma membrane

Answers

The correct answer is (e) cytochrome c will be found in the outer leaflet of the plasma membrane. A feature that would be present in normal (non-apoptotic) cells is cytochrome c will be found in the outer leaflet of the plasma membrane.

Cytochrome c is a soluble electron carrier protein that plays a key role in the cell's energy-generating process called oxidative phosphorylation. It is also involved in the initiation of apoptosis, or programmed cell death. In the process of apoptosis, cytochrome c is released from the mitochondria into the cytoplasm, where it activates a series of caspase enzymes that lead to the breakdown of the cell. Therefore, cytochrome c will not be found in the cytoplasm in normal (non-apoptotic) cells. It will be found in the outer leaflet of the plasma membrane. Option e.

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You have been asked to work as an undergraduate researcher on a project studying the effects of pollution on reproduction. Which of the following is NOT a characteristic that you should be looking for in a model organism? a) Low cost. b) Short generation times. c) Well-known life history. d) Unique anatomy.

Answers

The characteristic that you should NOT be looking for in a model organism for studying the effects of pollution on reproduction is Unique anatomy. The correct option is D

When working as an undergraduate researcher on a project studying the effects of pollution on reproduction, it is important to select an appropriate model organism. Model organisms are chosen based on specific characteristics that make them suitable for scientific research.

Options a) Low cost, b) Short generation times, and c) Well-known life history are all desirable characteristics in a model organism for this type of study. A low-cost organism allows for larger sample sizes and cost-effective experimentation.  

A well-known life history ensures that comprehensive knowledge about the organism's reproductive biology and behavior is available, aiding in experimental design and data interpretation.

On the other hand, option d) Unique anatomy is not a characteristic sought after in this context. Unique anatomy can complicate the study of reproductive effects, as it may introduce additional variables or make it difficult to generalize findings to other species.

Ideally, researchers aim to choose a model organism with a representative anatomy, which allows for broader extrapolation of results and enhances the study's relevance to other species or ecological contexts.

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Which of the following is NOT likely to be a mechanism employed by repressor proteins to decrease transcription of a specific gene? The repressor associates with a promoter element blocking RNA polymerase from binding promoter element The repressor binds to the activation domain of an activator, eliminating its ability to increase transcription The repressor binds to DNA-binding domain of an activator, eliminating its ability to associate with enhancer. The repressor binds to a DNA sequence in an enhancer, eliminating access to sequence by activator. The repressor binds to RNA polymerase II, blocking its ability to associate with promoter element.

Answers

Out of the given options, the mechanism that is NOT likely to be employed by repressor proteins to decrease transcription of a specific gene is that the repressor binds to RNA polymerase II, blocking its ability to associate with promoter element.

Transcription is a process in which the genetic information is passed from DNA to RNA. It is regulated by the proteins known as transcription factors, which either increase or decrease the transcription of a specific gene. These transcription factors can be of two types, i.e., activators and repressors.

Activators promote the transcription of a gene, while repressors suppress it.The repressor proteins decrease transcription by blocking the RNA polymerase from binding to the promoter element. Repressors can also bind with activators and prevent them from promoting transcription. They can also bind with DNA sequences in an enhancer, thus eliminating access to the sequence by activator and decreasing the transcription of a specific gene.

The mechanism that is NOT likely to be employed by repressor proteins to decrease transcription of a specific gene is that the repressor binds to RNA polymerase II, blocking its ability to associate with the promoter element.

The repressor binds to RNA polymerase II, blocking its ability to associate with the promoter element is the correct option.

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Visual accommodation contracts which extraocular eye muscle in the right eye? (do not use spaces

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The extraocular eye muscle responsible for visual accommodation in the right eye is the ciliary muscle.

Visual accommodation is the process by which the eye adjusts its focus to see objects at different distances clearly. It involves the changing shape of the lens to bend light rays and focus them onto the retina. The primary muscle responsible for visual accommodation is the ciliary muscle. The ciliary muscle is located within the eye, specifically in the ciliary body, which is a ring-shaped structure behind the iris. When the ciliary muscle contracts, it causes the lens to become thicker and more curved, allowing it to focus on nearby objects. This process is known as accommodation. Conversely, when the ciliary muscle relaxes, the lens becomes thinner and less curved, enabling clear vision for objects in the distance. In the right eye, the ciliary muscle contracts or relaxes to adjust the lens for near or far vision, respectively, facilitating visual accommodation.

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The pattern of cell death that is characterized by the conversion of a single cell to an acidophilic body, usually with loss of the nucleus but with preservation of its shape to permit recognition of cell boundaries is termed:

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The pattern of cell death that is characterized by the conversion of a single cell to an acidophilic body, usually with loss of the nucleus but with preservation of its shape to permit recognition of cell boundaries is termed karyorrhexis.

Karyorrhexis is defined as a type of cell death that occurs when DNA in a nucleus of a cell undergoes fragmentation and the chromatin material breaks down.

Afterward, the chromatin collects into solid structures and leads to the dissolution of the cell.The nucleus of the cells undergoes karyorrhexis, which is characterized by the nucleus fragmenting into many small pieces.

These pieces are the same size and spread uniformly throughout the cell. In most instances, the chromatin is lost from the nucleus entirely as a result of karyorrhexis.

It is commonly seen in cells that have died as a result of various types of injuries, including inflammation, ischemia, and hypoxia. Acidophilic body is the residual structure that is left behind after karyorrhexis.

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In a cross between AaBbCcDdEe and AaBbccddEe, what proportion of the offspring would be expected to be A_bbCcD_ee? O 3/256 O 3/16 O 1/256 O 7/16 O 3/64

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In the given cross between AaBbCcDdEe and AaBbccddEe, the proportion of offspring expected to be A_bbCcD_ee is 3/256.

To determine the proportion of offspring with the genotype A_bbCcD_ee, we need to consider the inheritance pattern of each gene independently.

For each gene, the offspring has a 1/2 chance of receiving the lowercase allele (b) from one parent and a 1/2 chance of receiving the lowercase allele (b) from the other parent. This results in a 1/4 chance of having the genotype bb for the first gene (A).

Similarly, for the second gene (C), the offspring has a 1/4 chance of having the genotype Cc, as one parent is homozygous (Cc) and the other is homozygous recessive (cc).

For the third gene (D), the offspring has a 1/2 chance of having the genotype Dd, as both parents are heterozygous (Dd).

Lastly, for the fourth gene (E), the offspring has a 1/2 chance of having the genotype ee, as one parent is homozygous dominant (Ee) and the other is homozygous recessive (ee).

Multiplying these probabilities together, we get (1/4) * (1/4) * (1/2) * (1/2) = 1/256.

Therefore, the expected proportion of offspring with the genotype A_bbCcD_ee is 1/256, which is equivalent to 3/256 when simplified.

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D Question 50 3.3 pts Calcium concentration in your blood is regulated by your parathyroid gland. If it falls below 4.3 meq/I, the parathyroid gland recognizes it and signals to the signals to the kidney to prevent it from being released in urine as well as causes bone to break down and release calcium into the blood. If it gets above 5.3 meq/1, the kidneys excrete more calcium and your bone absorbs additional calcium. If the blood has too much calcium, what action might be taken? bone breaks down conserve calcium in bloodstream excrete calcium muscle tears D Question 51 3.3 pts Calcium concentration in your blood is regulated by your parathyroid gland. If it falls below 4.3 meg/l, the parathyroid gland recognizes it and signals to the signals to the kidney to prevent it from being released in urine as well as causes bone to break down and release calcium into the blood. If it gets above 5,3 meg/l, the kidneys excrete more calcium and your bone absorbs additional calcium. If the blood doesn't have enough calcium, what action might be taken? bone breaks down excrete calcium higher heart rate muscle spasm

Answers

If the blood doesn't have enough calcium, the action that might be taken is that the bone breaks down.

In response to low blood calcium levels, the parathyroid gland signals the bone to release calcium into the bloodstream through the process of bone resorption.  This allows calcium to be mobilized from the bone tissue and increase its concentration in the blood. The breakdown of bone helps to replenish the calcium levels and maintain homeostasis in the body. Therefore, when blood calcium is low, the body initiates the breakdown of bone as a mechanism to increase calcium availability in the bloodstream. Blood is a vital fluid in the human body that plays numerous essential roles in maintaining overall health and homeostasis. Here are some key points about blood: Composition: Blood is composed of various components, including red blood cells (erythrocytes), white blood cells (leukocytes), platelets (thrombocytes), and plasma. Plasma is the liquid portion of blood that carries cells, nutrients, hormones, waste products, and other substances. Functions: Oxygen Transport: Red blood cells contain hemoglobin, which binds to oxygen in the lungs and carries it to tissues throughout the body.

Immune Response: White blood cells play a crucial role in defending the body against infections and foreign invaders.

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What are some reasons for having multiple levels ( local, neural
and hormonal) of Homeostatic regulation?

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Homeostasis is the process by which the body maintains a stable internal environment. It does this by regulating various physiological processes such as temperature, blood pressure, and pH.

There are several reasons why the body has multiple levels of homeostatic regulation, including neural and hormonal regulation

Local regulation:Local regulation is the first level of homeostatic regulation. It involves the immediate response of the tissues or organs to changes in the environment. For example, when the body is exposed to a cold environment, the blood vessels in the skin constrict to conserve heat. This response is immediate and does not involve the brain or hormones

Neural regulation:Neural regulation is the second level of homeostatic regulation. It involves the central nervous system (CNS), which consists of the brain and spinal cord. The CNS is responsible for interpreting information from the environment and initiating the appropriate response. For example, when the body is exposed to a cold environment, the CNS signals the blood vessels in the skin to constrict, and also triggers shivering to generate heat.Hormonal regulation:

Hormonal regulation is the third level of homeostatic regulation. It involves the endocrine system, which is made up of glands that produce and secrete hormones. Hormones are chemical messengers that travel through the bloodstream and affect the activity of target cells. For example, when the body is exposed to stress, the endocrine system releases cortisol, which prepares the body for the "fight or flight" response. Cortisol increases blood sugar levels, heart rate, and blood pressure to provide the body with energy to deal with the stress.

Thus, multiple levels of homeostatic regulation are important for maintaining a stable internal environment. Local regulation is the quickest response, neural regulation is the intermediate response, and hormonal regulation is the slowest response.

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Suppose a nucleotide with a 3' OH in a DNA nick is instead replaced by a nucleotide with a 3' H. How will this affect the ligase mechanism? a) The 3'OH attacks the 5' phosphate b) The phosphodiester bond will be made c) The 3' Hattacks the 5' phosphate d) The AMP will not be released

Answers

The correct answer is 3' H attacks 5' phosphate. Ligase forms phosphodiester linkages to seal nicks in the DNA backbone during replication and repair. ATP hydrolysis powers Ligase.

During ligation, the nucleotide with a 3' OH group attacks the next nucleotide's 5' phosphate, forming a phosphodiester link. A DNA nick with a 3' H (hydrogen) instead of a 3' OH group will affect the ligase process. The 3' H group lacks hydroxyl activity to attack the neighbouring nucleotide's 5' phosphate nucleophilically. Thus, the phosphodiester bond will not form. The ligase mechanism cannot work without a 3' OH group to respond with nucleophilic assault. Thus, the ligase enzyme cannot catalyse the ligation step, preventing DNA backbone nick sealing.

In summary, the ligase mechanism is impacted if a nucleotide with a 3' H replaces one with a 3' OH group in a DNA nick. The 3' H cannot attack the 5' phosphate and produce a phosphodiester link.

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With regards to the development of the respiratory system, explain why a puppy born at 50 days' gestation (preterm) is having trouble breathing.[12 marks]

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:In the case of the respiratory system of puppies, the lungs are the primary organ affected by preterm birth. Because of the puppy's underdeveloped lungs, the ability to move oxygen and eliminate carbon dioxide is hampered, resulting in breathing difficulties. Puppies born early, like human infants, may have difficulty breathing because they may not yet have developed enough surfactant, a substance that allows the lungs to expand and deflate.

This is why respiratory distress syndrome is common in preterm infants. In puppies, the respiratory system begins to develop in the embryo stage, with alveolar sacs forming by day 38 of gestation. Surfactant production begins in the late fetal stage, at around day 47 of gestation, and it is critical for preventing alveolar collapse. As a result, a puppy born at 50 days' gestation will have difficulty breathing because its lungs have not yet fully formed and are not yet able to produce enough surfactant to function properly. In summary, the respiratory system of a puppy born at 50 days' gestation will have trouble breathing due to its underdeveloped lungs and inability to produce enough surfactant to function properly.

When a puppy is born prematurely, its respiratory system is not yet fully developed, making it difficult for the puppy to breathe. Preterm birth in puppies, as in human infants, affects primarily the lungs. Because of the puppy's immature lungs, their capacity to transport oxygen and expel carbon dioxide is impaired, resulting in respiratory distress. When puppies are born early, surfactant is a crucial substance that enables the lungs to expand and deflate. This is why respiratory distress syndrome is so common in premature babies.The respiratory system of puppies begins to develop during the embryonic stage, with alveolar sacs forming by day 38 of gestation. Surfactant production begins in the late fetal stage, around day 47 of gestation, and is crucial for preventing alveolar collapse. As a result, a puppy born at 50 days' gestation will experience difficulty breathing due to its immature lungs and insufficient production of surfactant.

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Sometimes covalent modifications are added to proteins in order
to make them functional; what is the name of this process? Give 3
examples of such alterations

Answers

The process where covalent modifications are added to proteins in order to make them functional is known as post-translational modification. Three examples of such alterations include Phosphorylation, Glycosylation, and Methylation.

Three examples of such alterations are as follows:

Phosphorylation: It involves the addition of a phosphate group (-PO4) to a protein's serine, threonine, or tyrosine residue. This process is done by enzymes known as protein kinases. This type of covalent modification often changes the structure of the protein and how it interacts with other proteins and cellular components.

Glycosylation: This process involves the addition of carbohydrates, or sugar molecules, to proteins. In most cases, this process is carried out by enzymes in the endoplasmic reticulum and Golgi apparatus. The carbohydrates attached to proteins via glycosylation are involved in protein folding and stability, cell-to-cell adhesion, and protein-protein interactions.

Methylation: Methylation of proteins occurs when a methyl group (-CH3) is attached to a protein's arginine or lysine residues. The process is carried out by a specific group of enzymes called protein methyltransferases. Methylation can change how the protein interacts with DNA and other proteins, as well as altering gene expression.

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the life cycle of trematodes and cestodes require an intermediate host for its . stage. (choose adult or larval). this differs from nematodes. the intermediate host of the dog tapeworm is the .

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The life cycle of trematodes and cestodes requires an intermediate host for its larval stage. This differs from nematodes, as nematodes can have direct life cycles without an intermediate host.

In the case of the dog tapeworm (Dipylidium caninum), the intermediate host is the flea. The adult tapeworm resides in the small intestine of the definitive host, which in this case is the dog or other canids. The adult tapeworm produces proglottids that contain eggs, which are released through the feces of the definitive host.

The eggs of Dipylidium caninum are ingested by flea larvae, typically within the environment where the dog resides. Inside the flea larvae, the eggs hatch, and the released tapeworm larvae (cysticercoids) develop. When the flea larvae mature into adult fleas, they can then transmit the infective tapeworm larvae to the definitive host (dog) when the dog ingests the flea while grooming itself.

Thus, the intermediate host (flea) plays a crucial role in the life cycle of the dog tapeworm by facilitating the development and transmission of the larval stage of the parasite.

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Identify the FALSE statement describing cervical mucus: Select one: O a. at ovulation, mucus thins to help sperm enter the uterus b. mucus changes in consistency throughout the menstrual cycle C. Spinnbarkeit is the thick mass which forms to block movement of sperm

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Cervical mucus plays a crucial role in the female reproductive system and undergoes changes throughout the menstrual cycle. The FALSE statement describing cervical mucus is C. Spinnbarkeit is the thick mass that forms to block the movement of sperm.

During ovulation, which is the release of an egg from the ovary, the cervical mucus undergoes specific changes to create a more favorable environment for sperm. One of these changes is the thinning of the mucus, which allows sperm to swim more easily through the cervix and into the uterus.

The term "Spinnbarkeit" refers to the stretchiness and elasticity of cervical mucus. It describes the ability of the mucus to be stretched between the fingers without breaking. During ovulation, the cervical mucus exhibits higher Spinnbarkeit, indicating its optimal quality for sperm transport.

Spinnbarkeit refers to the stretchiness and elasticity of cervical mucus, which increases during ovulation to facilitate the movement and entry of sperm into the uterus. It does not refer to a thick mass that blocks the movement of sperm. Therefore, The FALSE statement describing cervical mucus is C. Spinnbarkeit is the thick mass that forms to block the movement of sperm.

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Bound hormones can readily leave a blood capillary and get to a target cell.

a. true

b. false

Answers

The statement "Bound hormones cannot readily leave a blood capillary and get to a target cell" is False.

When hormones are bound to a protein, they cannot cross a cell membrane and do not bind to their receptor, resulting in the hormone being inactive.

Hormones are molecules produced by endocrine glands, and they are involved in regulating and coordinating various physiological processes in the body.

They travel throughout the bloodstream and interact with cells in distant parts of the body via specific receptors on target cells.When hormones are in their unbound form, also known as free hormones, they are active and can readily leave a blood capillary and bind to receptors on a target cell.

Bound hormones are transported through the bloodstream attached to specific transport proteins, which help protect them from being broken down or excreted from the body. When the bound hormone reaches its target cell, it must first detach from the transport protein to become active and bind to the receptor.

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Question 6 Which cell types can cause tumours in the central
nervous system? Name three examples and describe their effects on
central nervous system function

Answers

There are several cell types that can cause tumours in the central nervous system (CNS), including astrocytes, oligodendrocytes, and ependymal cells. The effects of these tumours on CNS function can vary widely, depending on the location and size of the tumour.

Astrocytomas are the most common type of primary brain tumour. Astrocytes are star-shaped cells that provide structural support to neurons and help maintain the blood-brain barrier. When these cells become cancerous, they can form tumours that interfere with normal brain function.  

The symptoms of ependymomas can include headaches, nausea, vomiting, and changes in vision. In summary, there are several cell types that can cause tumours in the central nervous system (CNS), including astrocytes, are the oligodendrocytes, and ependymal cells. The effects of these tumours on CNS function can vary widely, depending on the location and size of the tumour. The three examples discussed above (astrocytomas, oligodendrogliomas, and ependymomas) can cause a range of symptoms, including headaches, seizures, cognitive impairment, and hydrocephalus.

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WRITE ABOUT A THEME: ORGANIZATION Natural selection has led to changes in the architecture of plants that enable them to photosynthesize more efficiently in the ecological niches they occupy. In a short essay (100-150 words), explain how shoot architecture enhances photosynthesis.

Answers

Natural selection has resulted in plant architecture adaptations that improve their photosynthesis efficiency in their natural environments. A plant's shoot architecture directly influences its capacity to photosynthesize. It is generally known that an increase in surface area exposed to sunlight causes an increase in the rate of photosynthesis. As a result, plants have evolved numerous strategies for maximizing the amount of light they get. The shoot architecture of a plant determines the efficiency of photosynthesis.

A plant's leaves contain photosynthetic pigments that aid in the conversion of light into energy. This means that plants have to guarantee that as much of their foliage is exposed to light as possible to maintain photosynthesis efficiency. Plant structures have evolved to enhance the amount of light absorbed by foliage, which contributes to increased photosynthesis. As an example, the canopy architecture of a tree is such that the uppermost branches are less dense and more exposed, while the lower branches are denser and shielded from the sun. As a result, more leaves are exposed to light, and photosynthesis rates are increased. This strategy is common in vegetation, particularly trees, where the upper leaves receive more sunlight, whereas lower leaves are less exposed to sunlight. This phenomenon is a product of plant adaptation, which is primarily driven by natural selection, where plant structures that increase the plant's chances of survival in their natural habitat are preferred.

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You have an unknown bacterium. You decide to plate it on an MSA plate. After 24 hours the plate turns from red to yellow. This means a. Your bacteria can ferment glucose to lactose The bacteria could be gram negative since it grew on MSA plates b. You do not need to test coagulase since it is not likely to be Gram positive c. Your bacteria can ferment mannitol d. Your bacteria can ferment galactose

Answers

The correct answer is the option C. Your bacteria can ferment mannitol. MSA (Mannitol Salt Agar) is a selective and differential medium used to identify pathogenic Staphylococcus bacterial species.

It is selective because it only permits the growth of halophilic bacteria (bacteria that can survive in a salt environment). It is also differential since it allows the differentiation of bacteria based on their capacity to ferment mannitol sugar.The MSA medium contains phenol red, mannitol, peptone, and salt. The phenol red functions as an indicator, changing color from red to yellow as the pH of the medium drops as a result of the fermentation of mannitol sugar. Therefore, the color shift from red to yellow indicates that the bacteria can ferment mannitol sugar.

To further determine the bacterial species, you can perform other tests such as the coagulase test to determine if the bacterium is coagulase-positive or coagulase-negative, or you can perform a Gram stain to determine if the bacterium is gram-positive or gram-negative. The growth of bacteria on the MSA plate does not indicate the bacterium's gram-staining or the ability to ferment lactose or galactose. Therefore, options A, B, and D are incorrect.

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Match the secretion with the cell or tissue that secretes it. Answers may be used more than once or not at all.
_______ Intrinsic factor
_______ Gastrin
_______ Stomach acid
_______ Pepsinogen
_______ Insulin
_______ Bile
_______ Secretin
_______ Saliva
A. small intestine
B. Enteroendocrine cell
C. Pancreas
D. Parotid, submandibular, and sublingual glands
E. Parietal cell
F. Pituitary gland
G. Chief cell
H. Spleen
I. Large intestine
J. Gallbladder/Liver

Answers

The secretion of the cell or tissue that secretes it are matched below:

______ Intrinsic factor: E. Parietal cell

_______ Gastrin: B. Enteroendocrine cell

_______ Stomach acid: E. Parietal cell

_______ Pepsinogen: G. Chief cell

_______ Insulin: C. Pancreas

_______ Bile: J. Gallbladder/Liver

_______ Secretin: A. small intestine

_______ Saliva: D. Parotid, submandibular, and sublingual glands

Note: The options H. Spleen and F. Pituitary gland do not match any of the secretions listed.

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**ANSWER BOTH PARTS FOR THIS QUESTION** A chronic alcoholic presents to the ER complaining of extreme abdominal pain and swelling, yellowing of skin, and worsening confusion. 1. Explain these three cl

Answers

Three clinical symptoms that a chronic alcoholic presents to the ER complaining of extreme abdominal pain and swelling, yellowing of skin, and worsening confusion chronic alcoholic presents to the ER with extreme abdominal pain and swelling, yellowing of skin, and worsening confusion.

These three clinical symptoms are the indication of alcoholic liver disease (ALD). ALD is a term used to describe a range of liver problems that are caused by alcohol misuse. ALD is a serious and potentially fatal condition. Extreme abdominal pain and swelling This is a symptom of cirrhosis, which is the last stage of ALD. Cirrhosis is a condition that develops over time and is characterized by scarring of the liver.

This scarring disrupts the normal functioning of the liver, which can lead to a buildup of fluid in the abdomen and cause abdominal swelling and pain.  Yellowing of skin This is a symptom of jaundice, which is caused by an accumulation of bilirubin in the bloodstream. Bilirubin is a waste product produced by the liver when it breaks down old red blood cells. When the liver is damaged, it cannot process bilirubin properly, which leads to a buildup in the bloodstream and causes the skin and whites of the eyes to turn yellow.

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QUESTION 39 What do CDKs that are activated just before the end of G2 do to initiate the next phase of the cell cycle? a. They act as proteases to degrade proteins that inhibit mitosis b. They phosphorylate lipids needed for the cell to enter mitosis c. They ubiquitinate substrates needed for the cell to enter mitosis d. They phosphorylate substrates needed for the cell to enter mitosis e. They de-phosphorylate substrates needed for the cell to enter mitosis QUESTION 40 What has happened to your telomeres since you began taking Cell Biology? a. they are the same length in all of my cells b. they have gotten shorter in my cells. c. my cells don't have telomeres; they are only present in embryonic stem cells. d. they have gotten longer in my senescing cells e. they have gotten longer in my necrotic cells

Answers

39. CDKs that are activated just before the end of G2 phosphorylate to initiate the next phase of the cell cycle are they substrate that are needed for the cell to enter mitosis (Options C).

40. Telomeres have gotten shorter in the cells since you began taking Cell Biology (Option B).

CDKs (cyclin-dependent kinases) are activated just before the end of G2 phosphorylate substrates that are needed for the cell to enter mitosis. They initiate the next phase of the cell cycle by phosphorylating substrates, such as lamin, condensin, and the nuclear pore complex, which are involved in nuclear reorganization during mitosis. As a result, they promote the onset of mitosis, which is followed by chromosome segregation and cytokinesis.

In mitosis, CDK activity is regulated by phosphorylation, which is mediated by the phosphatase Cdc25. CDK activity is high during mitosis, but it declines during mitotic exit due to the action of the phosphatase PP1. This decline in CDK activity is required for the completion of cytokinesis and the return of the cell to G1.

Telomeres shorten with each cell division because DNA polymerase cannot replicate the ends of linear chromosomes effectively. This shortening can lead to senescence and apoptosis when telomeres become critically short.

Thus, the correct option is

39. C.

40. B.

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In this phylogenetic tree, which of the following statements are true? (This is a multiple response question; choose all that apply.) a) This tree was generated using molecular data rather than phenotypic characters. b) Taxa P is more closely related to taxa S than it is to taxa U. c) There is uncertainty in the relative timing of divergence (a polytomy) of taxa P,Q and R. d) Taxa R is more closely related to taxa S than to taxa T. e) There are no extinct taxa shown or implied on the tree.

Answers

Our task is to identify which of the following statements are true. The options are:a) This tree was generated using molecular data rather than phenotypic characters.b) Taxa P is more closely related to taxa S than it is to taxa U.

Option (a), (b), and (c) are true, and options (d) and (e) are false.

There is uncertainty in the relative timing of divergence (a polytomy) of taxa P,Q and R.d) Taxa R is more closely related to taxa S than to taxa T.e) There are no extinct taxa shown or implied on the tree.Now, let's see which options are true.a) This tree was generated using molecular data rather than phenotypic characters.Molecular data means the study of genes and proteins. Phenotypic characters mean the study of physical appearance. The phylogenetic tree is made by studying the molecular data rather than physical appearance. Hence, the statement is true. Option (a) is correct.b) Taxa P is more closely related to taxa S than it is to taxa U.To find out which species are closely related, we should look for the nearest branch.

Here, P and U share a common branch. However, the nearest branch to P is S. Therefore, the statement is true. Option (b) is correct.c) There is uncertainty in the relative timing of divergence (a polytomy) of taxa P, Q, and R.A polytomy is a node that implies an ancestral relationship among more than two lineages. Here, the polytomy between P, Q, and R indicates an uncertainty in the timing of divergence. Therefore, the statement is true. Option (c) is correct.d) Taxa R is more closely related to taxa S than to taxa T.Here, the nearest branch to R is T, not S. Therefore, the statement is false. Option (d) is incorrect.e) There are no extinct taxa shown or implied on the tree.No species is marked as extinct, nor any fossil is shown on the phylogenetic tree. Hence, the statement is true. Option (e) is correct. Therefore, options (a), (b), and (c) are true, and options (d) and (e) are false.

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Usually in cells, atp is hydrolyzed into adp, or ____________ , releasing a ____________ molecule and energy.

Answers

In cells, ATP is typically hydrolyzed into ADP, or adenosine diphosphate, releasing a phosphate molecule and energy.

ATP (adenosine triphosphate) is the primary energy currency in cells. It stores and releases energy during various cellular processes. When ATP is hydrolyzed, it undergoes a reaction where a water molecule is used to break the bond between the second and third phosphate groups. This hydrolysis reaction results in the formation of ADP (adenosine diphosphate) and an inorganic phosphate molecule (Pi). The released phosphate molecule can be used in other metabolic reactions or to phosphorylate other molecules, while the energy released during this process is used to drive cellular activities.

The hydrolysis of ATP into ADP and Pi is an exergonic reaction, meaning it releases energy. This energy is utilized by the cell to perform various functions such as muscle contraction, active transport of ions across cell membranes, synthesis of macromolecules, and other energy-requiring processes. The energy released from ATP hydrolysis is harnessed by coupling it with endergonic reactions that require energy. This coupling allows the transfer of energy from ATP to the target molecules, enabling them to perform their specific cellular tasks. Overall, the hydrolysis of ATP into ADP and Pi is a crucial process for cellular energy metabolism and maintaining the energy balance within the cell.

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What is the sequence of events in introducing mutations by
site-directed mutagenesis? What is the function of the DpnI
restriction enzyme?

Answers

Site-directed mutagenesis is a technique for introducing mutations into a DNA sequence that involves the use of synthetic oligonucleotides to replace specific segments of the DNA strand. The process involves several steps to achieve the desired mutation.

The sequence of events in introducing mutations by site-directed mutagenesis are as follows:1. Primer design: Two oligonucleotide primers are designed to anneal with the target DNA sequence. The primers should be complementary to the template DNA, except for the mutation that is to be introduced.2. PCR amplification: The target DNA sequence is amplified using the primers in a polymerase chain reaction (PCR). The amplification should generate a high yield of the DNA product.3. Annealing: The PCR product is annealed with a complementary strand to generate a double-stranded DNA molecule.4. Digestion:

The DNA is digested with a restriction enzyme to create a nick in the target DNA sequence.5. Ligation: The oligonucleotide primers are ligated to the nicked DNA strand, replacing the original DNA sequence with the mutated sequence.6. Transformation: The mutated DNA is introduced into a host cell, where it can be replicated and expressed.The function of the DpnI restriction enzyme is to selectively digest methylated DNA. This enzyme recognizes the sequence 5'-Gm6ATC-3' and cleaves the phosphodiester bond between the G and A nucleotides, leaving a blunt end. This enzyme is often used in site-directed mutagenesis to eliminate the original DNA template after PCR amplification

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If a student inhales as deeply as possible and then blows the aire out until he cannot exhale anymorethe amount of air he expels is his?

Answers

The amount of air a student exhales after inhaling as deeply as possible is called their vital capacity. Vital capacity is the maximum amount of air a person can exhale after taking the deepest breath possible.

Vital capacity refers to the maximum amount of air a person can forcefully exhale after taking a deep breath. It is a measure of lung function and is used to assess respiratory health and pulmonary capacity. Vital capacity is influenced by factors such as age, sex, height, weight, and overall lung health.

Here are some key points about vital capacity:

Measurement: Vital capacity is typically measured using a spirometer, which is a device that measures the volume of air exchanged during breathing. The person being tested takes a deep breath and then exhales as forcefully and completely as possible into the spirometer.

Components: Vital capacity is made up of three primary lung volumes: inspiratory reserve volume (IRV), tidal volume (TV), and expiratory reserve volume (ERV). It can be calculated as the sum of these volumes:

Vital Capacity = IRV + TV + ERV

Inspiratory Reserve Volume (IRV): The maximum amount of air that can be inhaled after a normal inhalation.

Tidal Volume (TV): The amount of air inhaled and exhaled during normal breathing at rest.

Expiratory Reserve Volume (ERV): The maximum amount of air that can be forcefully exhaled after a normal exhalation.

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As indicated by the section, Gender in Infancy in Chapter 4 of your textbook, from an anthropological
perspective:
© Someone's Sex is culturally defined.
O Studying to what degree gender "is naturally determined" in infants is difficult because culture may have an
effect on infants as early as their time in the womb.
O Gender, which is a purely biological concept, is fixed at birth.

Answers

As indicated by the section, Gender in Infancy in Chapter 4 of your textbook, from an anthropological perspective studying to what degree gender "is naturally determined" in infants is difficult because culture may have an effect on infants as early as their time in the womb.

Anthropology is the investigation of human behavior, values, and practices from a social, biological, and cultural standpoint. It's been said that someone's sex is culturally defined. Anthropologists are concerned in the study of gender and its connection to society, politics, and culture.The concept of gender is primarily defined as the societal norms and roles associated with sex categories. Despite the fact that gender and sex are often used interchangeably, gender is a social construct that goes beyond biological or physiological distinctions between male and female.

Gender is a social construct that has evolved over time, and its definition is culturally influenced. According to an anthropological perspective, gender is influenced by several factors, including economic, political, and social factors. Gender influences people's decisions, social norms, and roles in society. It is determined by cultural expectations rather than biological sex, according to anthropologists. Gender, which is a purely biological concept, is fixed at birth, but cultural expectations of gender vary by region and have varied over time. Gender is influenced by the society and the environment in which individuals live, learn, and socialize.

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Compare and contrast the elbow and knee joints. Considering the
bone and joint structures and their functions, what are the
similarities and differences?

Answers

The elbow's distinctive ability to contribute to the additional pronation and supination movement is the primary distinction between these two joints.

The right pleural cavity surrounds the right lung left lung trachea digestive organs Question 8 (1 point) is the study of tissues. Histology Cytology Anatomy Biology

Answers

Histology is the scientific discipline that focuses on the study of tissues. The correct answer is option a.

It involves examining the structure, organization, and functions of different types of tissues that make up organs and body systems. Histologists use specialized techniques, such as staining and microscopy, to analyze tissue samples and identify cellular components and their spatial relationships.

By studying tissues at a microscopic level, histology provides insights into the cellular composition, architecture, and physiological processes within organs and tissues. It plays a crucial role in understanding normal tissue structure and function, as well as the pathological changes that occur in various diseases.

Histological findings contribute to advancements in medical research, diagnostics, and treatment strategies, making it an essential field in biological and medical sciences.

The correct answer is option a.

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Complete question

The right pleural cavity surrounds the right lung left lung trachea digestive organs Question 8 (1 point) is the study of tissues.

a. Histology

b. Cytology

c. Anatomy

d. Biology

What sorts of things can cause a population to deviate away from Hardy Weinberg equilibrium? Mark all that applies. Don't just copy exactly what's in the powerpoint. Think hard about each one. Genetic drift Natural Selection Hybridization between species Random mating Mutations No change in allele frequencies from one generation to the next Gene flow

Answers

Several factors can cause a population to deviate away from Hardy-Weinberg equilibrium. The following factors can contribute to deviations from equilibrium:

1. Genetic drift: Genetic drift refers to random fluctuations in allele frequencies due to chance events, particularly in small populations. Genetic drift can lead to the loss or fixation of alleles and can cause deviations from Hardy-Weinberg equilibrium.

2. Natural selection: Natural selection acts on the variation in heritable traits within a population, favoring certain traits that confer a reproductive advantage. If a particular allele provides a selective advantage or disadvantage, it can result in changes in allele frequencies and deviations from Hardy-Weinberg equilibrium.

3. Hybridization between species: Hybridization occurs when individuals from different species mate and produce offspring. This can introduce new gene combinations and alter allele frequencies, leading to deviations from Hardy-Weinberg equilibrium.

4. Mutations: Mutations are the source of genetic variation in populations. New mutations can introduce new alleles, alter existing alleles, or result in the loss of alleles. If mutations occur, they can affect the allele frequencies and deviate the population from Hardy-Weinberg equilibrium.

5. No change in allele frequencies from one generation to the next: Hardy-Weinberg equilibrium assumes that there is no change in allele frequencies from one generation to the next. Any changes, such as genetic drift, natural selection, or mutations, can disrupt this equilibrium.

6. Gene flow: Gene flow occurs when individuals migrate between populations and bring their genetic material with them. Gene flow can introduce new alleles into a population or remove existing alleles, leading to deviations from Hardy-Weinberg equilibrium.

Therefore, the factors that can cause a population to deviate away from Hardy-Weinberg equilibrium include genetic drift, natural selection, hybridization between species, mutations, and gene flow.

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There are only 2,5000 genes encoded by human genome; however, more than 100,000 proteins have been identified by biological scientists. These findings suggest that the number of proteins is much larger than the number of genes. Please give a reasonable explanation for the findings ( 30 points)

Answers

The number of proteins in the human genome is greater than the number of genes. This has been observed by researchers who have identified more than 100,000 proteins.

However, the human genome only has 20,500-25,000 genes.What explains this finding is that a single gene can produce multiple proteins. This is because genes undergo modifications after they are transcribed into mRNA. This modification can occur at various stages like the translation of mRNA to proteins. During the translation stage, the mRNA sequence is read in triplets, which are called codons.

The codons specify the amino acid to be incorporated into the growing protein. This step is critical for the formation of proteins. After the translation, modifications like the removal of a part of the protein, can occur. The processed protein can be folded, modified, or form complexes with other proteins. These additional processes increase the number of proteins generated by a single gene. Consequently, even though there are only 20,500-25,000 genes, more than 100,000 proteins can be produced.

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accumulation of serous fluids in the abdominal cavity is called: group of answer choices bulimia. edema. ascites. anorexia. flatus.

Answers

The accumulation of serous fluids in the abdominal cavity is called ascites. Option C is the correct answer.

Ascites is a condition characterized by the buildup of serous fluid in the abdominal cavity. This fluid accumulation is often a result of liver disease, such as cirrhosis, which impairs the liver's ability to maintain fluid balance in the body. Ascites can also be caused by other conditions such as heart failure, kidney disease, or certain cancers.

It leads to abdominal swelling, discomfort, and increased abdominal girth. Treatment options for ascites include dietary changes, medications to reduce fluid retention, and, in severe cases, therapeutic procedures to remove the excess fluid. Option C is the correct answer.

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