the schwarzschild radius of a black hole depends on

Answers

Answer 1

Answer:

The mass of the object.

Explanation:

Happy Thanksgiving!

Answer 2

The Schwarzschild radius of a black hole depends solely on its mass. The Schwarzschild radius is a concept in general relativity that defines the boundary known as the event horizon.

The formula for the Schwarzschild radius is given by:

r_s = 2GM / c²

Where: r_s is the Schwarzschild radius

As the mass of the black hole increases, its Schwarzschild radius also increases. This means that a more massive black hole has a larger event horizon and a stronger gravitational pull.

The mass of the black hole is the primary factor determining the size of the Schwarzschild radius, while other properties, such as spin or charge, can also affect the structure and behavior of the black hole but do not directly impact the Schwarzschild radius.

Therefore,The Schwarzschild radius of a black hole depends solely on its mass.

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Related Questions

As a speaker, I should know my purpose and method of delivery before giving my speech so...​

Answers

Explanation:

I will prepare my speech first and then I will give a speech on it.

What nation recently blew up one of its own satellites as part of a missile test, triggering a warning from the u.s. over a potentially dangerous debris field?

Answers

Answer:

Russia

Explanation:

my answer was deleted for no reason. apparently i was violating community guidelines when i wasnt. anyways, the answer is russia...

A wooden block moves at a constant speed on a rough horizontal surface. Draw a free-body diagram
clearly showing all the forces applied to the block; compare their magnitudes and directions.

Answers

The weight of the block and normal reaction are equal in magnitude but opposite in direction. Also, the frictional force and applied force are equal in magnitude but opposite in direction.

The forces acting on the wooden block moving at a constant speed include the following;

weight of block acting downwards, Wnormal reaction on the block acting upwards, Napplied force on the block acting towards positive x-direction, Ffrictional force acting towards negative x-direction, [tex]F_f[/tex]

The free-body diagram is presented below;

                                         

                                              N

                                              ↑

                               [tex]F_f[/tex]      ←  ⊕  →   F

                                              ↓

                                              W

The block is moving at a constant speed, we will have the following;

[tex]W = N \\\\F = F_f[/tex]

Thus, we can conclude that the weight of the block and normal reaction are equal in magnitude but opposite in direction. Also, the frictional force and applied force are equal in magnitude but opposite in direction.

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A 1,000 kg truck is traveling at 3 m/s. Suddenly, the driver sees a herd of cows on the road ahead and applies the brakes. The truck's tires could fail after doing 5,000 J of work to slow the vehicle. Can the truck stop before the tires fail?


A. Yes, the total KE the tires need to transfer out of the system is less than 5,000 J.


B. Yes, the tires do not do any work, it is only the brakes that do work.


C. No, the truck had to stop suddenly and the quick change in KE will cause the tires to fail.


D. No, the total KE the tires need to transfer out of the system is more than 5,000 J.

Answers

This question involves the concepts of the law of conservation of energy and kinetic energy.

The correct option is "A. Yes, the total KE the tires need to transfer out of the system is less than 5,000 J".

According to the law of conservation of energy:

Loss in Kinetic Energy = Work done by the tires

[tex]\frac{1}{2}mv^2=W[/tex]

where,

W = work done by tires = ?

m = mass of the truck = 1000 kg

v = speed of the truck = 3 m/s

Therefore,

[tex]W=\frac{1}{2}(1000\ kg)(3\ m/s)^2[/tex]

W = 4500 J

Since the failure limit of work done by the tire is 5000 J, which is greater than the actual work done by the tire in this scenario. Hence, the tire will not fail in this case.

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The attached picture explains the law of conservation of energy.

Is a football tackle an elastic or inelastic collision and why?

A: elastic, because momentum is conserved

B: inelastic, because kinetic energy is conserved

C: inelastic, because momentum is not conserved

D: inelastic, because kinetic energy is not conserved

Answers

If the kinetic energy of an object changes, then the collision is considered inelastic. This is regardless of whether the objects sticks together or not.

My best answer for this question would be D) inelastic, because kinetic energy is not conserved.

We can tell from the collision that it is not elastic.

Momentum is is conserved, it transfers to the other player.

Kinetic energy is not conserved, at it turns into internal friction.

I hope this helps! :)

A football tackle is an inelastic collision , because kinetic energy is not conserved.

What is collision?

When two bodies or particles move towards enough to interact with each other it is called the particles or the bodies are colliding.

What are the types of collision?Elastic collisioninelastic collisionWhat is an elastic collision?In this type of collision , there is no loss of kinetic energy.The momentum and kinetic energy both are conserved.What is an inelastic collision?in this type of collision , there is a loss of kinetic energy.The momentum of the system is conserved but the kinetic energy is not conserved .

So, when the football tackles it's kinetic energy changes.

Thus, A football tackle is an inelastic collision , because kinetic energy is not conserved.

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A car starts from rest and for 15.0 s its wheels has a constant linear acceleration of 0.800 m/s^2 to the right. What is the angle through which each wheel rotated in 20.0 s interval if the radius of the tires is 0.330 m?

Answers

237.375 rad. …………………

What do scientists call a substance that contains atoms from two or more different elements that are chemically bonded?

Atom
Compound
Element
Molecule

Answers

Answer is b compound is a substance that contains two or more elements chemically combined in a fixed proportion. The elements carbon and hydrogen combine to form many different compounds.

A 68 g plastic ball is moving to the left at 17 m/s . How much work must be done on the ball to cause it to move to the right at 17 m/s ?

Answers

Answer:

KE = 19.652 J to the right

Explanation:

KE = J or N*m

KE = (1/2)m*v²

KE = kinetic energy

m = mass(kg)

v = velocity (m/s)

KE = .5*0.068kg*(17m/s)²

KE = 9.826 J to the left

So double it to the right to get 17m/s.

KE = 19.652 J to the right

J = Joules or can be expressed as N*m which is Newton-meters.

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