The scatter plot shows the first-year income for 15 people, based on the number of years of school they each had after high school. A line of best fit
was drawn through the data. The equation for the line is y = 8x + 15.
Which statement describes the meaning of the y-intercept for the line of best fit?

Answer:

71

Step-by-step explanation:

ndndnrbrjen3n3nn3b2n2b2b

Answer:answer is 2.5v+5<5v A.k.a:A

Step-by-step explanation:

Answer:

37 inches

Step-by-step explanation:

to get 37 inches, you need to add 24 and 13. so 24+13 would equal 37.

Answer:

x=0, y=-2

Step-by-step explanation:

6x0=0

2(-2)=-4

so, -4=-4 so it is determined true

Then 0-2(-2), -2(-2)=4

subtract 0 from 4 which is 4

so, 4=4, so it is determined true

Answer:

i don't know that language sorry

Step-by-step explanation:

Answer:

Its A let me know if im wrong!

Answer:

Fourth option is most suitable here.

Answer:

[tex] \frac{108}{2 } = 54[/tex]

The value of y for the given circle will be 54°.

A circle is a geometrical figure which becomes by plotting a point around a fixed point by keeping a constant distance.

The diameter is the longest line that can be drawn inside a circle.

In our daily life, we always see circle objects for example our bike wheel.

Area of circle = πr² and the perimeter of circle = 2πr where r is the radius of the circle.

In the given question by the circle theorem that if a curve makes a 2x angle then the extreme point will make the angle on circle as x.

So angle y = half of angle 108°

∠Y = 108°/2 = 54°

Angle w will also same as 54° because it also satisfies the theorem of the circle.

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Answer:

The first ">" should be underlined in the equation.

..

The rules for solving inequalities are the same as those used for solving regular equations except for one important rule, that is, when you multiply both sides of an inequality by -1, the inequality sign reverses.

..

5-4x≥17

-4x≥12

-x≥3

Step-by-step explanation:

Answer:

hope it helps.

Answer:

What?

Step-by-step explanation:

G8ve me more info and Ill answer again

Answer:

Taking 45 degree as reference angle

Then using sine rule

sin 45=

p/h

replacing the value of sin 45 degree by 1/root 2.so

1/root 2=9/c

doing cross multiplication

9*root 2=1*c

9 root 2 =c

therefore the value of c is 9 root 2

Step-by-step explanation:

Answer:

Hello! answer: 62.8

Step-by-step explanation:

Cirmcumfrence is just diameter × pi so since we are using 3.14 for pi we can just do 3.14 × 20 so...

3.14 × 20 = 62.8 Therefore the circumference is 62.8 Hope that helps!

Answer:

There is a little over 1 gallon

Step-by-step explanation:

Answer:

The angle between the two blades is 120 degree.

Step-by-step explanation:

number of blades = 3

The blades are equally spaced.

The total angle around a circle is 360 degree.

So, the angle between the two blades is given by

[tex]\theta =\frac{360}{n}\\\theta =\frac{360}{3} = 120^{o}[/tex]

Answer:

Step-by-step explanation:

so we know that a triangle degrees have to add up to 180 in the inside right? So we know c is 90 and so you need to find A and B. The left over degrees you have is 90 so the sum of B and A would have to be 90, thats all i can help you with sorry.

Answer:

12

Step-by-step explanation:

Number of years to make a worth of $45000 with Depreciation rate of 12% and Total worth $45000 is 4 years

Years= 4 year

The term depreciation refers to an accounting method used to allocate the cost of a tangible or physical asset over its useful life. Depreciation represents how much of an asset's value has been used. It allows companies to earn revenue from the assets they own by paying for them over a certain period of time.

Given that:

limousine costs $75000

Depreciation rate = 12% per year= 0.12

Total worth= $45000

By using the formula for year we have

total worth = cost of object [tex](1- Depreciation \;rate)^{year}[/tex]

45000= 75000x [tex](1-0.12)^{year}[/tex]

0.6= [tex](0.88)^{year}[/tex]

Now taking log on both side we have

log 0.6= year x  log0.88

-0.2218 = year x -0.05551

year= 4.049

year≈ 4 year(rounding off nearest year)

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Answer:

-|7|, |4|, |2-9|, |6+4|

Step-by-step explanation:

I think this is correct

The total mass of 5 x 10³ microorganisms is  1.2 x [tex]10^{-2}[/tex].

Option C is the correct answer.

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

Example: 2 + 3x + 4y = 7 is an expression.

We have,

Mass of an organism = 2.4 x [tex]10^{-6}[/tex] grams

The total mass of 5 x 10³ microorganism.

= 5 x 10³ x 2.4 x [tex]10^{-6}[/tex]

= 12.0 x [tex]10^{3 - 6}[/tex]

= 12 x [tex]10^{-3}[/tex]

= 1.2 x [tex]10^{-2}[/tex]

Thus,

The total mass is 1.2 x [tex]10^{-2}[/tex]

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Answer:

I do believe that it is Option B

(Assuming the true population proportion of shoppers who will make a purchase differs from 0.60, the probability of obtaining a sample statistic of 0.40 in a random sample of 40 customers is 0.0098.)

Step-by-step explanation:

This sample provide evidence that the grocery store manager overstated the true proportion P-value = 0.0333.

In null-hypothesis significance testing, the p-value is the probability of obtaining test results at least as extreme as the result actually observed, under the assumption that the null hypothesis is correct.

here, we have,

Given data in the question:

To test whether population proportion p is overstated;

Null hypothesis H₀ : p = (75%) = 0.75  

Alternative hypothesis H₁ : = < (75%) < 0.75

Now, sample proportion p" = 64 / 100 = 0.64

From the dot plot below,

we will determine the p-value for test { P(p" < 0.64)}

The number of times p"<0.64 in 150 simulations is 5

Therefore:

P(p" < 0.64 ) = 5 / 150 = 0.0333

P-value = 0.0333

At 5% level of significance;

0.0333 < 0.05

Therefore, we reject null hypothesis H₀ at 5% level of significance,

We conclude that proportion of shoppers who bought bananas at least once in the past month is overstated.

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complete question:

A grocery store manager claims that 75% of shoppers purchase bananas as least once a month. Technology was used to simulate choosing 150 SRSs of size n = 100 from a population of shoppers where 75% buy bananas. The dotplot shows pˆ = the sample proportion of shoppers who bought bananas in the past month. A random sample of 100 shoppers from the store were selected and 64 bought bananas in the past month. Does this sample provide evidence that the grocery store manager overstated the true proportion? Justify your answer.

Answer:

∠ G ≈ 8.3°

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan G = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{HI}{GI}[/tex] = [tex]\frac{1.1}{7.5}[/tex] , then

∠ G = [tex]tan^{-1}[/tex] ([tex]\frac{1.1}{7.5}[/tex] ) ≈ 8.3° ( to the nearest tenth )

Answer:

hope this helps

Step-by-step explanation:

31 divided by 2 = 15.5 then do 15.5 x 15.5= 240.25 then you do 240.25 x 3.14 = 754.385

Answer:

4.2

Step-by-step explanation:

By intersecting chords theorem:

[tex]x \times 10 = 6 \times 7 \\ \\ 10x = 42 \\ \\ x = \frac{42}{10} \\ \\ x = 4.2[/tex]

Answer:

8 1/3 or 8.33 yards per second

Step-by-step explanation:

100/12 = 8 1/3

Answer:

8 months and $320

Step-by-step explanation:

To find when 30m + 80 = 40m, isolate m.

30m + 80 = 40m

Subtract 40m from both sides.

-10m + 80 = 0

Subtract 80 from both sides.

-10m = -80

Divide both sides by -10

m = 8

To find the cost, substitute 8 as m in one of the equations.

40(8) = 320

I'll do problem 1 to get you started

First sort the values from smallest to largest and you should end up with this set

{1, 6, 7, 11, 13, 16, 18, 21, 22, 23}

The smallest value is 1 and the largest value is 23, so the min and max are 1 and 23 in that order.

We have ten values in this set. The middle-most number is going to be between the 10/2 = 5th slot and the 6th slot. The numbers 13 and 16 are in the fifth and sixth slots respectively. Average those values to get (13+16)/2 = 29/2 = 14.5

The median is 14.5 which is another name for the second quartile (Q2).

Now split the data set into two halves

L = lower half of values smaller than the median

U = upper half of values larger than the median

In this case,

L = {1, 6, 7, 11, 13}

U = {16, 18, 21, 22, 23}

sets L and U have five items each

Find the median of set L and U to get 7 and 21 respectively. These medians of L and U represent the values of Q1 and Q3 in that order.

Q1 = first quartile = 7

Q3 = third quartile = 21

===================================================

Answer:

The five number summary for problem 1 is

Answer:

[tex] \rm\displaystyle \displaystyle \displaystyle θ= {60}^{ \circ} , {300}^{ \circ} [/tex]

[tex] \rm \displaystyle a = - \frac{ \sqrt{3} }{2} - 1, \frac{\sqrt{3}}{2} - 1[/tex]

Step-by-step explanation:

we are given two coincident points

[tex] \displaystyle P( \sin(θ)+2, \tan(θ)-2) \: \text{and } \\ \displaystyle Q(4 \sin ^{2} (θ)+4 \sin(θ) \cos(θ)+2a \cos(θ), 3 \sin(θ)-2 \cos(θ)+a)[/tex]

since they are coincident points

[tex] \rm \displaystyle P( \sin(θ)+2, \tan(θ)-2) = \displaystyle Q(4 \sin ^{2} (θ)+4 \sin(θ )\cos(θ)+2a \cos(θ), 3 \sin(θ)-2 \cos(θ)+a)[/tex]

By order pair we obtain:

[tex] \begin{cases} \rm\displaystyle \displaystyle 4 \sin ^{2} (θ)+4 \sin(θ) \cos(θ)+2a \cos(θ) = \sin( \theta) + 2 \\ \\ \displaystyle 3 \sin( \theta) - 2 \cos( \theta) + a = \tan( \theta) - 2\end{cases}[/tex]

now we end up with a simultaneous equation as we have two variables

to figure out the simultaneous equation we can consider using substitution method

to do so, make a the subject of the equation.therefore from the second equation we acquire:

[tex] \begin{cases} \rm\displaystyle \displaystyle 4 \sin ^{2} (θ)+4 \sinθ \cos(θ)+2a \cos(θ )= \sin( \theta) + 2 \\ \\ \boxed{\displaystyle a = \tan( \theta) - 2 - 3 \sin( \theta) + 2 \cos( \theta) } \end{cases}[/tex]

now substitute:

[tex] \rm\displaystyle \displaystyle 4 \sin ^{2} (θ)+4 \sin(θ) \cos(θ)+2 \cos(θ) \{\tan( \theta) - 2 - 3 \sin( \theta) + 2 \cos( \theta) \}= \sin( \theta) + 2 [/tex]

distribute:

[tex]\rm\displaystyle \displaystyle 4 \sin ^{2}( θ)+4 \sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta) - 6 \sin( \theta) \cos( \theta) + 4 \cos ^{2} ( \theta) = \sin( \theta) + 2 [/tex]

collect like terms:

[tex]\rm\displaystyle \displaystyle 4 \sin ^{2}( θ) - 2\sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta) + 4 \cos ^{2} ( \theta) = \sin( \theta) + 2 [/tex]

rearrange:

[tex]\rm\displaystyle \displaystyle 4 \sin ^{2}( θ) + 4 \cos ^{2} ( \theta) - 2\sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta) + = \sin( \theta) + 2 [/tex]

by Pythagorean theorem we obtain:

[tex]\rm\displaystyle \displaystyle 4 - 2\sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta) = \sin( \theta) + 2 [/tex]

cancel 4 from both sides:

[tex]\rm\displaystyle \displaystyle - 2\sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta) = \sin( \theta) - 2[/tex]

move right hand side expression to left hand side and change its sign:

[tex]\rm\displaystyle \displaystyle - 2\sin(θ) \cos(θ)+\sin(θ ) - 4\cos( \theta) + 2 = 0[/tex]

factor out sin:

[tex]\rm\displaystyle \displaystyle \sin (θ) (- 2 \cos(θ)+1) - 4\cos( \theta) + 2 = 0[/tex]

factor out 2:

[tex]\rm\displaystyle \displaystyle \sin (θ) (- 2 \cos(θ)+1) + 2(- 2\cos( \theta) + 1 ) = 0[/tex]

group:

[tex]\rm\displaystyle \displaystyle ( \sin (θ) + 2)(- 2 \cos(θ)+1) = 0[/tex]

factor out -1:

[tex]\rm\displaystyle \displaystyle - ( \sin (θ) + 2)(2 \cos(θ) - 1) = 0[/tex]

divide both sides by -1:

[tex]\rm\displaystyle \displaystyle ( \sin (θ) + 2)(2 \cos(θ) - 1) = 0[/tex]

by Zero product property we acquire:

[tex] \begin{cases}\rm\displaystyle \displaystyle \sin (θ) + 2 = 0 \\ \displaystyle2 \cos(θ) - 1= 0 \end{cases}[/tex]

cancel 2 from the first equation and add 1 to the second equation since -1≤sinθ≤1 the first equation is false for any value of theta

[tex] \begin{cases}\rm\displaystyle \displaystyle \sin (θ) \neq - 2 \\ \displaystyle2 \cos(θ) = 1\end{cases}[/tex]

divide both sides by 2:

[tex] \rm\displaystyle \displaystyle \displaystyle \cos(θ) = \frac{1}{2}[/tex]

by unit circle we get:

[tex] \rm\displaystyle \displaystyle \displaystyle θ= {60}^{ \circ} , {300}^{ \circ} [/tex]

so when θ is 60° a is:

[tex] \rm \displaystyle a = \tan( {60}^{ \circ} ) - 2 - 3 \sin( {60}^{ \circ} ) + 2 \cos( {60}^{ \circ} ) [/tex]

recall unit circle:

[tex] \rm \displaystyle a = \sqrt{3} - 2 - \frac{ 3\sqrt{3} }{2} + 2 \cdot \frac{1}{2} [/tex]

simplify which yields:

[tex] \rm \displaystyle a = - \frac{ \sqrt{3} }{2} - 1[/tex]

when θ is 300°

[tex] \rm \displaystyle a = \tan( {300}^{ \circ} ) - 2 - 3 \sin( {300}^{ \circ} ) + 2 \cos( {300}^{ \circ} ) [/tex]

remember unit circle:

[tex] \rm \displaystyle a = - \sqrt{3} - 2 + \frac{3\sqrt{ 3} }{2} + 2 \cdot \frac{1}{2} [/tex]

simplify which yields:

[tex] \rm \displaystyle a = \frac{ \sqrt{3} }{2} - 1[/tex]

and we are done!

disclaimer: also refer the attachment I did it first before answering the question