The sampling distribution for a goodness of fit test is the a. Poisson distribution b. t distribution c. normal distribution d. chi-square distribution

Answers

Answer 1

The chi-square distribution serves as the sampling distribution for the goodness of fit test since it quantifies how well the distribution derived from the data fits the empirical distribution.

What is sampling distribution?

The sampling distribution is the probability distribution of a statistic that is obtained by repeated sampling of a certain population. The mean or mode of a population's mean or mode of a variable is one example of the many different choices for a statistic that are described in this passage. The sampling distribution of a proportion is obtained by repeating your survey or poll for each possible sample of the population. For instance, instead of asking 1,000 cat owners what cat food they prefer, you could conduct a number of polls.

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Related Questions

Triangle ABCis transformed with the center of dilation at the origin.

Pre-image: △ABC with vertices A(−3, 4), B(−1, 12), C(4, −2)

Image: △A′B′C′with vertices A′(−0.6, 0.8), B′(−0.2, 2.4), C′(0.8, −0.4)

What is the scale factor of the dilation that maps the pre-image to the image?
Enter your answer in the box.

Answers

Answer:

take any point on the triangle and any point on the image: for now let's take point A(-3,4) A`(-0.6

Step-by-step explanation:

sf =3/4

scale factor=5

Describe and correct the error in solving the equation for x.

Answers

Answer:

[tex]\frac{10 +3b}{a} =x[/tex]

Step-by-step explanation:

By manipulating equations, we can solve for different variables.

Error

The error in the equation is in the factoring. In the second line, the x is factored out of the expression; however, this cannot be factored. Factoring is like dividing. When you factor x out you divide the terms by x. Since there is not an x in 3b, x cannot be factored out.

A correct version of factoring looks like:

ax - 3bx + 2cx = x (a - 3b + 2c)

Correction

Now, we can go back to the beginning and solve for x correctly using the properties of equality. First, rewrite the equation.

10 = ax - 3b

Then, add 3b to both sides.

10 + 3b = ax

Finally, divide by a.

[tex]\frac{10 +3b}{a} =x[/tex]

This is the final, correct equation solved for x.

does someone know this?

Answers

Multipluy the equations i think...

If I buy a new video game set that is originally $40, how much will I save if they are 40% off?

Answers

Answer: $16 dollars

Step-by-step explanation: 40% of 40 is 16 so you save $16. Game would now cost $24.

24$ you will have to pay

6.
2x + 5y = -7
7x + y = -8

Answers

Answer:

(- 1, - 1 )

Step-by-step explanation:

2x + 5y = - 7 → (1)

7x + y = - 8 → (2)

multiplying (2) by - 5 and adding to (1) will eliminate y

- 35x - 5y = 40 → (3)

add (1) and (3) term by term to eliminate y

(- 35x + 2y) + (5y - 5y) = - 7 + 40

- 33x + 0 = 33

- 33x = 33 ( divide both sides by - 33 )

x = - 1

substitute x = - 1 into either of the 2 equations and solve for y

substituting into (1)

2(- 1) + 5y = - 7

- 2 + 5y = - 7 ( add 2 to both sides )

5y = - 5 ( divide both sides by 5 )

y = - 1

solution is (- 1, - 1 )

78. the probability that a marksman will hit a target each time he shoots is 0.89. if he fires 15 times, what is the probability that he hits the target at most 13 times?

Answers

The probability that the marksman will hit the target 13 times is 0.279.

Here, we are given that the probability that a marksman will hit a target each time he shoots is 0.89.

Thus, the probability that he will not hit the target = 1 - 0.89 = 0.11

Here, we can use the concept of binomial distribution to find the probability.

There are a total number of 15 trials, thus, n = 15

Success ⇒ marksman hits the target

Probability of success ⇒ p = 0.89

Failure ⇒ marksman fails to hit the target

Probability of failure ⇒ q = 0.11

Number of successful outcomes required ⇒ x = 13

Now, according to the formula for calculating binomial probability-

P(x) = [tex]nCx *p^{x} *q^{n-x}[/tex]

P(x) = [tex]15!/(13!*2!) *(0.89)^{13} *(0.11)^{2}[/tex]

P(x) = (15*14/2) (0.2198) (0.0121)

P(x) = 105* 0.0026

P(x) = 0.279

Thus, the probability that the marksman will hit the target 13 times is 0.279.

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what is the largest area of a rectangle that can be inscribed in a semicircle of radius 6? round to the nearest whole numb

Answers

The area of the largest rectangle is 46.47 square root.

Consider a semi-circle with a rectangle ABCD inscribed in it.

Let, O = centre of the semi-circle

A and B lies on the base of the semi-circle

OA = OB = x

D and C lie on the semi-circle

BC = AD = y

AB = CD = 2x

By Pythagorean theorem,

CB² + OB² = OC²

⇒ y² + x² = (6)²

⇒ y² = 36 - x²

⇒ y = √(36 - x²)

Now, area of rectangle in terms of x,

Area, A = 2x × y

= 2x × √(36 - x²)

Differentiating,

A' = 2 × √(36 - x²) - 2x²/(36 - x²)

When x = 0, y = 6 and when x = 6, y = 0, area = 0.

It implies that area is maximum when the value of x lies between 0 and 6.

This will occur where A’ = 0.

⇒ 2 × √(36 - x²) - 2x²/(36 - x²) = 0

⇒ 2 × √(36 - x²) = 2x²/(36 - x²)

On simplification, we get,

⇒ 2 × (36 - x²) = 2x²

⇒ 36 - x² = x²

⇒ 2x² = 36

⇒ x² = 36/2

⇒ x = √36/2

Now, y = √(36 - x²) becomes

⇒ y = √(36 - (√36/2)²)

⇒ y = √(36 - 36/2)

⇒ y = √(96 - 36)/2

⇒ y = √60/2

Maximum area = 2xy

= 2(√36/2)(√60/2)

= 46.47

Therefore, the area of the largest rectangle = 46.47 square units.

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It is a function written as f(x)=b^x where bis greater than 0, b is not equal to 1, and x is any real number.

Answers

The function with the following formula is an exponential function with base b:

Given: f(x) = b^x, where b > 0, b ≠ 1 is a real number.

If r is a rational number, we can determine what b means.

An exponential function's domain is all real numbers since b^x may be defined for all real values r.

Now, all you need to know is that any positive number b^x and any real number r can be used to approximate the value of b using this approximation.

B can be any real number greater than 0 in the range.

An exponential function is always positive. And if in addition 0 < b < 1, f is a decreasing function.

Hence, f(x) decreases as x increases.

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The regular price of a sweater is $32. For a sale, the price of the sweater is marked down 30%. What is the sale price of the sweater?​

Answers

Answer: $22.40

Step-by-step explanation:

30% of 32, or 0.3(32) is equal to 9.6. Then you have to subtract that amount, which is 32 - 9.6, which then gets us to 22.40.

determine the equation of the ellipse with foci (2,4)(2,4) and (2,-8)(2,−8), and co-vertices (10,-2)(10,−2) and (-6,-2)(−6,−2).

Answers

The equation of the ellipse with given foci (2,4) and (2,-8) and co-vertices (10, -2) and ( -6 , -2) is equal to (x - 2)²/40 + ( y + 2)²/36 = 1.

As given in the question,

Given foci of the ellipse :

( 2,4) and ( 2, -8)

Co-vertices of the ellipse :

( 10,-2) and (-6 , -2)

From the given foci and vertices ,

Centre 'c' = 2

b = 6

( h, k) = (2, -2)

a² = c² + b²

⇒a² = 4 + 36

⇒a = √40

⇒a = 2√10

Equation of the ellipse is given by:

( x - h)²/ a² + (y - k)²/b² =1

⇒( x - 2)²/ (2√10)² + (y + 2)²/6² = 1

⇒( x - 2)²/ 40 + (y + 2)²/36 = 1

Therefore, equation of the ellipse is equal to (x - 2)²/ 40 + (y +2)²/36 = 1.

The complete question is:

Determine the equation of the ellipse with foci (2,4) and (2,−8), and co-vertices (10,−2) and(−6,−2).

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a rancher has 80 feet of fencing with which to enclose two adjacent rectangular corrals (see figure). what dimensions should be used so that the enclosed area will be a maximum?

Answers

If a rancher has 80 feet of fencing with which to enclose two adjacent rectangular corrals, then for the maximum area the dimensions will be 10 feet and 40/3 feet

From the given figure

4x + 3y = 80 feet

3y = 80 - 4x

y = (80 - 4x) / 3

The area of the rectangle

A = length × width

A = 2x × y

= 2x × (80 - 4x) / 3

Apply distributive property

= (160/3)x - (8/3)x^2

For the maximum area differentiate the values

0 = 160/3 - 16/3x

16/3x = 160/3

x = 160/3 ÷ 16/3

x = 160/3 × 3/16

x = 10 feet

The value of y = (80 - 4x) / 3

y = (80 - 4(10))/3

y = (80-40) / 3

y = 40/3 feet

Therefore, the dimensions are 10 feet and 40/3 feet

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Point O is the incenter of triangle A B C. Lines are drawn from the points of the triangle to point O. Lines are drawn from point O to the sides of the triangle to form right angles and line segments O Q, O R, and O S. Angle O B C is 15 degrees. Angle O C R is 30 degrees.
What is mAngleQOB?
a. 30°
b. 60°
c. 75°
d. 90°

Answers

The measure of angle QOB is  75°.

What is right angle?

90 degrees is the angle of a right.

The right angle is created when two straight lines cross at a 90° angle or when they are perpendicular at the intersection. The symbol stands for a right angle.

Given:

Point O is the incenter of triangle ABC.

Lines are drawn from the points of the triangle to point O.

Lines are drawn from point O to the sides of the triangle to form right angles and line segments OQ, OR, and OS.

Angle OBC is 15 degrees. Angle OCR is 30 degrees.

OBC= 15

OCR =30

In OBQ

OBQ + QOB + OQB = 180

OBQ= OBC=15

OQB= 90

So,

QOB = 180- OBQ- OQB

= 180-15 -90

= 75

Hence, the measure of angle QOB is  75°.

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Overall, 148 6th-grade scholars voted in the class president election. How many votes did each class president candidate receive?

Answers

The number of votes that each class president candidate receive is 59.2 votes and 88.8 votes respectively.

What is Percentage?

To determine the quantity or percentage of something in terms of 100, use the percentage formula. Per cent simply means one in a hundred. Using the percentage formula, a number between 0 and 1 can be expressed. A number that is expressed as a fraction of 100 is what it is. It is primarily used to compare and determine ratios and is represented by the symbol %.

The number of votes gotten by each person will be:

A = Percentage × Number of votes

= 40% × 148

= 0.4 × 148.

= 59.2 votes.

B. = Percentage × Number of votes

= 60% × 148

= 0.6 × 148.

= 88.8 votes.

Therefore, A got 59.2 votes and B had 88.8 votes.

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Given are five observations collected in a regression study on two variables.
xi 2 6 9 13 20
yi 7 18 9 26 23
(a) Compute b0 and b1 (to 1 decimal).
b1
b0
(b) Complete the estimated regression equation (to 1 decimal).
Y^ =_ + _ x
(c) Use the estimated regression equation to predict the value of y when x = 6 (to 1 decimal).
Y^ = _?

Answers

a) The coefficients of the regression equation are given as follows:

b1 = 0.9. b0 = 7.6.

b) The regression equation is defined as follows: y = 0.9x + 7.6.

c) The estimate of y when x = 6 is given as follows: y = 13.

How to obtain the regression equation?

The slope-intercept definition of the regression equation is given as follows:

y = b1x + b0.

In which the parameters are given as follows:

b1 is the slope.b0 is the intercept.

The points from the table in this problem are given as follows:

(2,7), (6, 18), (9,9), (13, 26), (20,23).

Inserting these points into a linear regression calculator, the equation is given as follows:

y = 0.9x + 7.6.

Then the estimate of the value of y when x = 6 is obtained as follows:

y = 0.9(6) + 7.6 = 13.

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taxes: the internal revenue service reports that the mean federal income tax paid in the year 2010 was $8040. assume that the standard deviation is $5000. the irs plans to draw a sample of 1000 tax returns to study the effect of a new tax law. part: 0 / 50 of 5 parts complete part 1 of 5 (a) what is the probability that the sample mean tax is less than $7900? round the answer to at least four decimal places. the probability that the sample mean tax is less than $7900 is .

Answers

The probability for sample mean tax is less than $7,900 is 0.1894.

How to calculate the probability?

μ = population mean = 8,040

σ = standard deviation = 5,000

n = amount of sample = 1,000

[tex]\bar x[/tex] = sample mean = 7,900

The probability for sample mean tax can be calculated using z test formula.

P(x < 7,900) = P(z < [tex]\frac{\bar x - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex] )

= P(z < [tex]\frac{7,900 - 8,040}{\frac{5,000}{\sqrt{1,000}}}[/tex])

= P(z < [tex]\frac{-140}{\frac{5,000}{31.622}}[/tex])

= P(z < -0.88)

Using z table for P(z < -0.88). So,

= 0.1894

Thus, the probability is 0.1894 for sample tax mean is less than $7,900.

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Assume that the height of your cylinder is 6 inches. Consider A as a function of r, so we can write that as A(r)=2πr2+12πr. What is the domain of A(r)? In other words, for which values of r is A(r) defined?

Answers

Can 'r' be 0? No, because a cylinder wouldn't exist otherwise. Because a radius on Earth cannot be endlessly vast, the highest limit would be constrained. But it is hard to say what is excessive, so I'd probably just say that the domain is r > 0.

What do you mean by a domain?

The set of values that can be plugged into a function's domain are called its parameters. The x values for a function like f are contained in this set. The collection of values that the function assumes is known as its range. Following the insertion of an x value, the function outputs this set of values. The domains of f(x)=x2 and g(x)=1/x, respectively, are all real numbers with the exception of x=0.

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evaluate the cross product (3iˆ 5jˆ)×(−3iˆ 8jˆ), which expands to −9 iˆ×iˆ 24 iˆ×jˆ−15 jˆ×iˆ 40 jˆ×jˆ. write your answer in vector form physics

Answers

The required cross product of given vectors is 39k

What is cross product?

Cross product is a parallel procedure on two vectors in three-layered space. It brings about a vector that is opposite to the two vectors. The Vector result of two vectors, an and b, is meant by a × b. Its resultant vector is opposite to an and b. Vector items are additionally called cross items.

According to question:

A = 3i + 5j , B = -3i + 8j

Then, cross product of A and B,

A×B = i(5×0 - 8×0) - j(3×0 - (-3)×0) + k(3×8 - (-3)×5)

A×B = i(0) - j(0) + k(24 + 15)

A×B  = 39k

Thus, cross product of A and B is 39k

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If x varies inversely as y and x=32 when y=3,find y when x=11

Answers

[tex]\qquad \qquad \textit{inverse proportional variation} \\\\ \textit{\underline{y} varies inversely with \underline{x}} ~\hspace{6em} \stackrel{\textit{constant of variation}}{y=\cfrac{\stackrel{\downarrow }{k}}{x}~\hfill } \\\\ \textit{\underline{x} varies inversely with }\underline{z^5} ~\hspace{5.5em} \stackrel{\textit{constant of variation}}{x=\cfrac{\stackrel{\downarrow }{k}}{z^5}~\hfill } \\\\[-0.35em] ~\dotfill[/tex]

[tex]\begin{array}{llll} \textit{"x" varies}\\ \textit{inversely with "y"} \end{array}\implies x=\cfrac{k}{y}\hspace{5em}\textit{we also know that} \begin{cases} x=32\\ y=3 \end{cases} \\\\\\ 32=\cfrac{k}{3}\implies 96=k\hspace{10em}\boxed{x=\cfrac{96}{y}} \\\\\\ \textit{when x = 11, what's "y"?}\qquad 11=\cfrac{96}{y}\implies y=\cfrac{96}{11}[/tex]

Please help me I give points

Answers

Answer:

17 degrees

Step-by-step explanation:

<ABD = 25. We know that ABD has a right triangle included. Therefore we know that 25 + 90 + <A = 180.

Therefore 115 + <A = 180.

<A = 65 degrees.

This means that part of <A = 65 degrees. The other part of <A is 44 degrees, add the two to find the whole of angle A.

65 + 44 = 109.

Angle CAD would be congruent to angle C due to alternate interior angles. meaning <C is 44 degrees. Since the angles in a triangle add up to 180 you can write the equation:

109 + 44 + <B = 180.

Combine the like terms.

163 + <B = 180.

Subtract to find angle B.

<B = 17

Given the piecewise function defined below; answer the questions at the bottom of the page regarding the continuity and differentiability of f at x = 1. In(52 4) + 3 for I < 1 412 for T > 1 f(c) lim f(2) I 1 lim f(z) I f( lim f' (€) I_] lim f' (1) So the function f () is Submnlt Answcr att = [

Answers

The given function is neither continuous nor differentiable at x = 1.

Given the piecewise function defined below, the function is not continuous at x = 1 because the left-hand limit is not equal to the right-hand limit. Specifically, the left-hand limit of f(x) as x approaches 1 is 3, while the right-hand limit of f(x) as x approaches 1 is 4. Furthermore, the function is not differentiable at x = 1 because the derivative does not exist at this point. This is because the derivative of the function is discontinuous at x = 1, with a derivative of 0 for x < 1 and a derivative of 1 for x > 1.

Therefore, the function f(x) is not continuous or differentiable at x = 1.

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The unit rate for inches
per centimeter is 0.39.

Answers

Answer:

The inches unit number 0.39 in converts to 1 cm, one centimeter. It is the EQUAL length value of 1 centimeter but in the inches length unit alternative.

Step-by-step explanation:

convert 6 yards 5 feet to inches

(conversion factors) 12 inches = 1 foot; 3 feet + 1 yard

NEED HELP ASAP PLEASE

Answers

276 inches

1 yard-36 inches
5*12=60
6*36=216
60+216=276

Answer:

276 inches

Step-by-step explanation:

︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎

Joey is considering two bowling membership plans. The plans are detailed here. Plan 1: $30 for a monthly pass and a $3 fee for each bowling visit Plan 2: $10 for each bowling visit Select the equation for Plan 1.

y = -10

y = 10x

y = 30x +3

3x+30​

Answers

Answer:

This equation represents Plan 1, since it shows that the cost to join the plan is $30 and the cost for each bowling visit is $3.

Step-by-step explanation:

Answer: 3x + 30

Step-by-step explanation: the $3 fee depends on how many times joey goes bowling so it will be 3x + the flat $30 per month

Which graph matches the following system of equations?

Answers

The answer would be A

Solve for d -9a-12=12-d

Answers

Answer:

d= 24 + 9a

Step-by-step explanation:

– 9a – 12 = 12 – d

by collecting like terms

–9a +d = 12 +12

–9a +d = 24

d= 24 + 9a

Answer:

Step-by-step explanation:

-9a-12=12-d

d=9a+24

Help solve the proportion

Answers

Answer: 9

Step-by-step explanation:

Factor the polynomial function over the complex numbersf(x)=x^4+9x^3+15x^2+9x+14

Answers

The polynomial function over the complex numbers is,

(x + 1i) ( x - 1i) (x+ 7) ( x + 2).

What is factoring a polynomial?

Factorization of polynomials, also known as polynomial factorization, is a mathematical and computer algebraic technique that combines irreducible factors with coefficients in the same domain to produce a polynomial with coefficients in a given field or in integers.

Consider, the given polynomial

f(x) = x^4 + 9x^3 + 15x^2 + 9x + 14

We can use a factoring "trick" here....write this as

x^4 +  9x^3 + 14x^2  + x^2  + 9x  + 14 = 0    factor by grouping

x^2 ( x^2 + 9x + 14)  +  1 ( x^2 + 9x + 14) = 0

(x^2 + 1) (x^2 + 9x + 14) = 0

(x^2 + 1) (x^2 + 9x + 14) = 0

⇒ (x^2 + 1) = 0,  (x^2 + 9x + 14) = 0

x^2 = -1,          x^2 + 7x + 2x + 14 = 0

x = ±i ,              x(x + 7) + 2(x + 7) = 0

x = ±i ,              (x + 7)(x + 2) = 0

⇒ (x + i)(x - i)(x + 7)(x - 7) = 0

(x + 1i) ( x - 1i) (x+ 7) ( x + 2) = 0

Hence, the polynomial function over the complex numbers is,

(x + 1i) ( x - 1i) (x+ 7) ( x + 2).

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A florist has 72 red roses and 40 white roses. If the florist creates the greatest number of identical bouquets possible with a combination of red and white roses without any roses leftover, how many white roses are in each bouquet?.

Answers

The number of white roses left in each bouquet is 5.

Explain the term Greatest Common Factor?A group of numbers' greatest common factor (GCF) is the biggest factor that almost all numbers have in common. The biggest number it is a factor for two or more integers is known as the GCF.

You must identify the most prevalent common factor for this task (GCF).

The actions are:

1. Divide the supplied numbers into prime factors.2. Select the usual ones, then multiply them.

The florist's stock of 72 red roses with 40 white roses reveals what the most common factor is, which is:

72 = 2×2×2×3×3 = 2³×3²

40 = 2×2×2×5 = 2³×5

GCF = 2³

Divide this number of white roses in the first bouquet (40 roses) first by Greatest Common Factor to get how many white roses are in each arrangement.

The result is:

= 40 white roses / 8

= 5 white roses

Thus, number of white roses left in each bouquet is 5.

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is the sum of a certain pair of integers odd? (1) the difference between the integers is odd. (2) one of the integers is even and the other is odd.

Answers

For first case, It is even integer. The difference of odd integers is always even integer. For second case, It is odd integer. The difference of an odd and even integers is always odd integer.

What is integer?

Zero, a positive natural number, or a negative integer denoted by a minus sign are all examples of integers. The inverse additives of the corresponding positive numbers are the negative numbers. The boldface Z is a common mathematical symbol for the set of integers.

Here,

a. If there is an odd pair of integers,

for example,

=3 and 5

The difference,

5-3=2

It is even integer. The difference of odd integers is always even integer.

b. If one integer is even and other is odd,

for example,

=6 and 3

The difference,

6-3=3

It is odd integer. The difference of an odd and even integers is always odd integer.

It is an even integer in the first scenario. Odd integer differences always result in even integer differences. It is an odd integer in the second case. An odd integer is always the difference between an odd and an even integer.

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if four residential fires are idpenently reported on a single day, what is the probability that two are in family homes, one is in an apartment, and one is in another type of dwelling

Answers

The probability that out of four residential fires who independently reported on a single day, two are in family homes, one is in an apartment, and one is in another type of dwelling is 0.0895 or 8.95%.

The multinomial distribution deals specifically with events that have multiple discrete outcomes. The multinomial distribution is not limited to events with only discrete outcomes.

We have given that

The National Fire Incident Reporting Service stated, among all residential fires.

Let consider the number of events ,

X₁---> fires residential who are in home

X₂--> fires residential who are in appartment

X₃--> fires residential who are in another type of dwelling

The probability of ae X₁ occured (p₁)

= 73% = 0.73

The probability of event X₂ occured (p₂) = 20% =0.20

The probability of event X₃ occurred (p₃) = 7% = 0.07

Four residential fires are independently reported on a single day.

we have to calculate probability that two are in family homes, one is in an apartment, and one is in another type of dwelling?

Now, Using the Multinomial distribution,

X₁= 2 , X₂= 1, X₃ = 1 and n = 4

P( X₁, X₂,-----,Xₙ ) =( n!/(X₁! X₂! ----Xₙ!) )( p₁ˣ₁ × p₂ˣ₂ × ----× pₙˣₙ)

P( 2,1,1) = 4!/2! 1! 1! ( 0.73² × 0.2× 0.07¹)

= 12 ( 0.014 × 0.5329)

= 0.0895272

Hence, the required probability is 0.089..

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Complete question:

The National Fire Incident Reporting Service stated that, among residential fires, 73% are in family homes, 20% are in apartments, and 7% are in other types of dwellings.

a) If four residential fires are independently reported on a single day, what is the probability that two are in family homes, one is in an apartment, and one is in another type of dwelling?

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