Answer: x= 10
Step-by-step explanation:
l= 40
w=20
P=l+w+l+w
120=5x-10+2x+5x-10+2x
120= 14x-20
120+20=14
140=14x
x=10
Answer:
x=10
L=40
W=20
Step-by-step explanation:
P=2L+2W
120=2(5x-10)+2(2x)
120=10x-20+4x
120=14x-20
14x=140
x=140/14=10
then substitute
In right angle ABC, a = 12, b = 9, and c = 15. Find tan ∠B
Which of the following expression is equivalent to 6^-7?
Answer:
B
Step-by-step explanation:
Find the measure of the numbered angles in each rhombus
Answer:
Step-by-step explanation:
I thought those lines mean that they are equal meaning that the number is 68.
A warehouse has 1,750 boxes of water bottles. A truck unloaded another 530 boxes at the warehouse. Each box holds 48 bottles of water. How many bottles of water are in the warehouse?
Answer:
109440
Step-by-step explanation:
1750 boxes of water bottles with 48 bottles of water each: 1750 x 48 = 84000
plus the other 530 boxes at the warehouse which alone are: 530 x 48 = 25440
adding up 84000 + 25440 = 109440
The total number of bottles of water in the warehouse will be 27,190.
What is Algebra?The analysis of mathematical representations is algebra, and the handling of those symbols is logic.
A warehouse has 1,750 boxes of water bottles.
A truck unloaded another 530 boxes at the warehouse.
Each box holds 48 bottles of water.
Then the number of bottles that were unloaded by truck will be
⇒ 530 x 48
⇒ 25,440
Then the total number of bottles of water in the warehouse will be
⇒ 25,440 + 1,750
⇒ 27,190
The total number of bottles of water in the warehouse will be 27,190.
More about the Algebra link is given below.
https://brainly.com/question/953809
#SPJ2
In ΔDEF, the measure of ∠F=90°, the measure of ∠E=41°, and FD = 79 feet. Find the length of DE to the nearest tenth of a foot.
Answer:
120.4ft
Step-by-step explanation:
Find the diagram in the attachment.
The triangle shown is a right angled triangle with the side DE as the hypotenuse, EF is adjacent side while DF is the opposite side.
To get DE, we will use the SOH CAH TOA trigonometry identity
Using CAH which is defined as:
Cos(theta) = Adjacent/Hypotenuse
Cos 79°= 23/Hypotenuse
Hypotenuse = 23/cos79°
Hypotenuse = 23/0.191
Hypotenuse = 120.4feet
DE = 120.4feet (to nearest tenth)
Find the distance between (-5,6)and (3,2).
Answer:
[tex]\displaystyle d = 4\sqrt{5}[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
Coordinates (x, y)Algebra II
Distance Formula: [tex]\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]Step-by-step explanation:
Step 1: Define
Point (-5, 6) → x₁ = -5, y₁ = 6
Point (3, 2) → x₂ = 3, y₂ = 2
Step 2: Find distance d
Simply plug in the 2 coordinates into the distance formula to find distance d
Substitute in points [Distance Formulas]: [tex]\displaystyle d = \sqrt{(3+5)^2+(2-6)^2}[/tex][Distance] [√Radical] (Parenthesis) Add/Subtract: [tex]\displaystyle d = \sqrt{(8)^2+(-4)^2}[/tex][Distance] [√Radical] Evaluate exponents: [tex]\displaystyle d = \sqrt{64+16}[/tex][Distance] [√Radical] Add: [tex]\displaystyle d = \sqrt{80}[/tex][Distance] [√Radical] Simplify: [tex]\displaystyle d = 4\sqrt{5}[/tex]A fish tank is initially filled with 400 liters of water containing 1 g/liter of dissolved oxygen. At noon, oxygenated water containing 10g/liter of oxygen flows in at a rate of 5 liters per minute and the well-mixed water is pumped out at a rate of 7 liters per minute.Let A(t) represent the amount of dissolved oxygen in the tank at time t. a) Write the differential equation that represents the problem.b) Solve the differential equation. c) At 1 p.m., what is the amount of dissolve oxygen in the fish tank
Answer:
a. [tex]dA(t)/dt = 50 - \frac{7A(t)}{400} where A(0) = 400[/tex]
b. [tex]A(t) = \frac{20000}{7} + \frac{17200}{7}e^{-7t/400}[/tex]
c. 3.717 kg
Step-by-step explanation:
a) Write the differential equation that represents the problem.
Let A(t) be the amount of dissolved oxygen in the tank at any time, t.
The net flow rate dA(t)/dt = mass flow in - mass flow out
Since 10 g/l of oxygen flows in at a rate of 5 l/min, the mass flow in is 10 g/l × 5 l/min = 50 g/min
Since A(t) is the amount of oxygen present in the tank at time, t, and the volume of the tank is 400 liters. The concentration of oxygen in the tank is thus A(t)/400 g/l.
Also, water is being pumped out at a rate of 7 l/min. So, the mass flow out is thus concentration × flow rate out = A(t)/400 g/l × 7 l/min = 7A(t)/400 g/min
So, dA(t)/dt = mass flow in - mass flow out
dA(t)/dt = 50 - 7A(t)/400 with A(0) = 400 l × 1 g/l = 400 g since the tank initially contains 1 g/l of dissolved oxygen and has a volume of 400 l
So, the differential equation is
dA(t)/dt = 50 - 7A(t)/400 where A(0) = 400 g
[tex]dA(t)/dt = 50 - \frac{7A(t)}{400} where A(0) = 400[/tex]
b) Solve the differential equation
To solve the equation, we use separation of variables, so
dA(t)/dt = 50 - 7A(t)/400 where A(0) = 400 g
dA(t)/(50 - 7A(t)/400) = dt
Integrating both sides, we have
∫dA(t)/(50 - 7A(t)/400) = ∫dt
-7/400 ÷ -7/400∫dA(t)/(50 - 7A(t)/400) = ∫dt
1/ (-7/400)∫-7/400dA(t)/(50 - 7A(t)/400) = ∫dt
(-400/7)㏑(50 - 7A(t)/400) = t + C
㏑(50 - 7A(t)/400) = -7t/400 + (-7/400)C
㏑(50 - 7A(t)/400) = -7t/400 + C' (C' = (-7/400)C)
taking exponents of both sides, we have
50 - 7A(t)/400 = exp[(-7t/400) + C']
50 - 7A(t)/400 = exp(-7t/400)expC'
[tex]50 - \frac{7A(t)}{400} = e^{-7t/400}e^{C'} \\50 - \frac{7A(t)}{400} = Ae^{-7t/400} A = e^{C'}\\ \frac{7A(t)}{400} = 50 - Ae^{-7t/400} \\A(t) = \frac{400}{7} X 50 - \frac{400}{7} Ae^{-7t/400} \\A(t) = \frac{20000}{7} - \frac{400}{7} Ae^{-7t/400}[/tex]
when t = 0 , A(0) = 400. So,
[tex]A(t) = \frac{20000}{7} - \frac{400}{7} Ae^{-7t/400} \\A(0) = \frac{20000}{7} - \frac{400}{7} Ae^{-7(0)/400}\\A(0) = \frac{20000}{7} - \frac{400}{7} Ae^{0/400}\\A(0) = \frac{20000}{7} - \frac{400}{7} Ae^{0}\\A(0) = \frac{20000}{7} - \frac{400}{7} A\\400 = \frac{20000}{7} - \frac{400}{7} A\\\frac{400}{7} A = 400 - \frac{20000}{7}\\\frac{400}{7} A = \frac{2800}{7} - \frac{20000}{7}\\\frac{400}{7} A = -\frac{17200}{7}\\\\A = -\frac{17200}{7} X \frac{7}{400} \\A = -43[/tex]
So,
[tex]A(t) = \frac{20000}{7} - \frac{400}{7} X -43e^{-7t/400} \\A(t) = \frac{20000}{7} + \frac{17200}{7}e^{-7t/400}[/tex]
c) At 1 p.m., what is the amount of dissolve oxygen in the fish tank.
At 1 p.m, t = 60 min
So, the amount of dissolved oxygen in the fish tank is A(60)
So,
[tex]A(t) = \frac{20000}{7} + \frac{17200}{7}e^{-7t/400}\\A(60) = \frac{20000}{7} + \frac{17200}{7}e^{-7X60/400}\\A(60) = \frac{20000}{7} + \frac{17200}{7}e^{-420/400}\\A(60) = \frac{20000}{7} + \frac{17200}{7}e^{-1.05}\\A(60) = \frac{20000}{7} + \frac{17200}{7} X 0.3499\\A(60) = \frac{20000}{7} + \frac{6018.93}{7} \\A(60) = \frac{26018.93}{7} \\A(60) = 3716.99 g[/tex]
A(60) ≅ 3717 g
A(60) ≅ 3.717 kg
HELP ME PLSSS IM GIVING BRAINLIEST!!!
Answer:
B
Step-by-step explanation:
Evaluate −nz−z2−2z when n=3. Simplify your answer.
Answer: n=
−z2−5
z
Step-by-step explanation:
Let's solve for n.
(−n)(z)−z2−2=3
Step 1: Add z^2 to both sides.
−nz−z2−2+z2=3+z2
−nz−2=z2+3
Step 2: Add 2 to both sides.
−nz−2+2=z2+3+2
−nz=z2+5
Step 3: Divide both sides by -z.
−nz
−z
=
z2+5
−z
Answer:
-z^2-5z
Step-by-step explanation:
To evaluate a polynomial at a given value, we substitute the given value for the variable and then simplify using order of operations. We are given n=3, so we substitute 3 for n in the polynomial −nz−z2−2z and simplify as follows.
−nz−z2−2z
−(3)z−z2−2z
−3z−z2−2z
−z2−5z
Is 13:15 and 30:26 a pair of equivalent ratios and why?
Given:
The two ratios are 13:15 and 30:26.
To find:
Whether the given ratios are equivalent or not.
Solution:
Two ratios are equivalent if the values of the ratio are equal after simplification.
[tex]13:15=\dfrac{13}{15}[/tex]
And,
[tex]30:26=\dfrac{30}{26}[/tex]
[tex]30:26=\dfrac{15}{13}[/tex]
[tex]30:26=15:13[/tex]
The first ratio is 13:15 and the value of second ratio after simplification is 15:13 both ratios are different, so,
[tex]\dfrac{13}{15}\neq \dfrac{30}{26}[/tex]
Therefore, the required answer is "No", the given ratios are not a pair of equivalent ratios.
Simplify the expression 1 + 4.25n + 3/2p -3 + (-2p) + 5/4n
Answer:
5.5n -2 -0.5p
Step-by-step explanation:
Make Everything to either decimals or fractions.
then simplify as shown
The volume of a cuboid is 189cm3.
The length is 7cm and the width is 9cm.
Work out the height of the cuboid.
Find the equation of the line that is perpendicular to the x-axis and passes through the point (-10,-1). Give the full equation as your answer. The equation is _______________
Answer:
x = -10
Step-by-step explanation:
First, determine the slope of the answer. The x-axis is a horizontal line, thus the new line must be vertical. All vertical lines are represented by the equation x = a number. That number represents the x-value of all the points the vertical line passes through.
So, since the line passes through (-10, -1), take the x-value of that point and put it into that equation. Thus, x = -10.
Doughnuts are sold in bag and cartons. A bag holds 4 doughnuts and a carton holds 10 doughnuts. Tome buys b bags of doughnuts and c cartons of doughnuts. He buys a total of t doughnuts. Write down the formula for t in terms of b and c
Answer:
[tex]t = 4b + 10c[/tex]
Step-by-step explanation:
Given
1 bag = 4 doughnuts
1 carton = 10 doughnuts
Required
Determine the amount of doughnuts in b bags and c cartons
If 1 bag contains 4 doughnuts, then b bags contain 4b doughnuts
If 1 carton contains 10 doughnuts, then c cartons contain 10b doughnuts
So, the total (t) is calculated by adding up the amount of doughnuts in the cartons and the bags:
i.e.
[tex]t = 4b + 10c[/tex]
e Michael is working on the roof of his house. Michael is on the ground, standing 5 feet away from the house. A ladder touches the house at a point 20 feet above the ground, and the ground at Michael's feet. What is the approximate distance between Michael and the point where the ladder touches the house?
Answer:
Step-by-step explanation:
25
Expand 6(3x-5)
I know it looks easy but I can't
Answer:
18x - 30
Step-by-step explanation:
in order to expand the expression, you need to use the distributive property to simplify 6(3x - 5).
first, distribute 6 to 3x, which is just 6 • 3x.
6 • 3x = 18xnow distribute 6 to -5, which is just 6 • -5.
6 • -5 = -30therefore, 6(3x - 5) expanded is 18x - 30 :) i hope this helps!! have a lovely rest of your day <3
The volume of the box is 448 ft'. Find its length and width.
4 ft
X-6
X
The box has a length of
ft and a width of
ft.
What is length and width
Answer:
hi
Step-by-step explanation:
Find an answer to your question The volume of the box is 448 ft'. Find its length and width. 4 ft X-6 X The box has a length of ft and a width of ft.
hope this helps
James wants to tile his floor using tiles in the shape of a trapezoid. To make
the pattern a little more interesting he has decided to cut the tiles in half
along the median. The top base of each tile is 13 inches in length and the
bottom base is 19 inches. How long of a cut will John need to make so that
he cuts the tiles along the median?
A. 16 inches
B. 3 inches
C. 6 inches
D. 32 inches
Three hermit crabs at a pet store cost $ 21.75 . If each hermit crab, h , costs the same amount, which equation can be used to find the cost per hermit crab correctly?
Answer:
Step-by-step explanation:
$21.75/(3 crabs) = $7.25/crab
PLZ HELY ILL MARK BRANILEST
Answer:
518
Step-by-step explanation:
14 x 74 = 1036 1036 / 2 = 518
( really need brainliest , hope it helps )
( first )
Suppose you are driving to visit a friend in another state. You are driving 65 miles per hour.
You must drive 520 miles total. If you have already driven 195 miles, how long will it take you
to reach your destination? Use h to represent the number of hours it will take to reach your
destination. Use the equation 65h+195 = 520.
A.2 hours
B. 5 hours
C. 15 hours
D. 22 hours
Answer:
b.5 hours
520-195=325
325/65=5
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
........................ .....
Algebra 2 Unit 1 Assessment
Which of the following contains multiple variables?
4a + 5b + 1
4a + 5a + 1
4a - 1
4 - 1
Answer:
I would have to say A
Step-by-step explanation:
B has 2 of the same variables while A has to different variables and C&D have no variables there for the answer is A
The system of equations y = 2x + 5 and y = –3x – 15 is shown on the graph below.
On a coordinate plane, 2 lines intersect at (negative 4, negative 3).
According to the graph, what is the solution to this system of equations?
(–4, –3)
(–3, –4)
(–5, 5)
(5, –5)
Answer: A
Explanation:
Answer:
A. (–4, –3)
Step-by-step explanation:
This is in case any one else had the answer on a different letter.
A large store has a warehouse it uses for storage. Trucks back up to the loading dock where merchandise is unloaded, sorted, and stacked in the correct area of the warehouse. The large shelves in the storage area are 17 feet 8 inches apart so the forklift machines can operate between the shelves. Is that distance greater than or less than 216 inches?
Answer:
The distance is less than 216 inches.
Step-by-step explanation:
Each feet has 12 inches.
The large shelves in the storage area are 17 feet 8 inches apart
So, in inches, this distance is of:
17*12 + 8 = 212
This distance is less than 216 inches.
Three sets of data are given below. What is the
median of the ranges?
Data A: -3,2,-5,6,8
Data B: 4,9,6,2
Data C: 8,3,0,4
A) 2
B) 5
C) 7
D) 8
Evaluate the expression: 16.2 x 2 + 1/2 x 8.5 x 12
Answer:
83.4
Step-by-step explanation:
16.2 x 2
=
32.4 +
1/2 x 8.5 x 12
=
51 + 32.4 = 83.4
Hope this helps!
Verify that parallelogram ABCD with vertices A(-5, -1), B(-9, 6), C(-1, 5), and D(3, is a rhombus by showing that it is a parallelogram with perpendicular diagonals.
multiplication of the gradients of the two diagonals is equals to -1 if they are perpendicular
Let y = 5e5z
A. Find the differential dy
25e53
dy
B. Use part A. to find dy when x = - 3 and dir = 0.4.
Round your answer to 2 decimal(s).
dy =
Submit Question
Answer:
[tex]\displaystyle dy = 25e^{5x}dx\\dy = 3.27 \cdot 10^7[/tex]
General Formulas and Concepts:
Math
RoundingEuler's Number e - 2.71828Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightCalculus
Derivatives
Derivative Notation
Differentials
Basic Power Rule:
f(x) = cxⁿ f’(x) = c·nxⁿ⁻¹eˣ Derivative: [tex]\displaystyle \frac{dy}{dx}[e^u] = u'e^u[/tex]
Step-by-step explanation:
Part A
Step 1: Define
[tex]\displaystyle y = 5e^{5x}[/tex]
Step 2: Differentiate
[Function] eˣ Derivative: [tex]\displaystyle \frac{dy}{dx} = \frac{dy}{dx}[5x] \cdot 5e^{5x}[/tex][Derivative] Basic Power Rule: [tex]\displaystyle \frac{dy}{dx} = 5x^{1 - 1} \cdot 5e^{5x}[/tex][Derivative] Simplify: [tex]\displaystyle \frac{dy}{dx} = 5 \cdot 5e^{5x}[/tex][Derivative] Multiply: [tex]\displaystyle \frac{dy}{dx} = 25e^{5x}[/tex][Derivative] [Multiplication Property of Equality] Isolate dy: [tex]\displaystyle dy = 25e^{5x}dx[/tex]Part B
Step 1: Define
[Differential] [tex]\displaystyle dy = 25e^{5x}dx[/tex]
[Given] x = 3, dx = 0.4
Step 2: Evaluate
Substitute in variables [Differential]: [tex]\displaystyle dy = 25e^{5(3)}(0.4)[/tex][Differential] [Exponents] Multiply: [tex]\displaystyle dy = 25e^{15}(0.4)[/tex][Differential] Evaluate exponents: [tex]\displaystyle dy = 25(3.26902 \cdot 10^6)(0.4)[/tex][Differential] Multiply: [tex]\displaystyle dy = (8.17254 \cdot 10^7)(0.4)[/tex][Differential] Multiply: [tex]\displaystyle dy = 3.26902 \cdot 10^7[/tex][Differential] Round: [tex]\displaystyle dy = 3.27 \cdot 10^7[/tex]Topic: AP Calculus AB/BC (Calculus I/II)
Unit: Differentials
Book: College Calculus 10e
An inequality is like an equation, but instead of an equal sign (=) it has one of these signs: ______________, _______________ , ________________, _____________.
Answer:
An inequality sign is like an equal sign with a line through it
so, like, if you put = and / together
Answer:
<, >, =>, =<
Step-by-step explanation:
How many cubes with side lengths of 1/3 cm does it take to fill the prism
Answer:
Answer:48 cubes
You could fit 48 cubes with side lengths of 1/3 cm inside a rectangular prism with dimensions of 1 cm X 2 2/3 cm X 2/3 cm.
I hope it's helpful!