__M+__Q2----->___MQ3
Answer: 2M + 3Q2 -----> 2MQ3
Explanation:
2 Ms either side, and 6 Qs either side
dlaczego emaliowane garnki rdzewieją w miejscach uszkodzenia emalii
Answer:
Explanation: I don’t even know what you said
Answer:
so basically
Explanation:
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what is the Ka of a 0.0592 M solution of hydrofluoric acid (HF) with a pH of 6.90
Answer:
2.7*10^-13
coefficient= 2.7
exponent= -13
Explanation:
Answer: 2.7 x 10^-13
Explanation:
If the speed of a wave is 150 m/s and its frequency is 2 Hz, what is its wavelength?
A. 300m
B. 75m
C. 152m
D. 148m
Answer:
75m
Explanation:
A gas system has an initial number of moles of 0.693 moles with the volume unknown. When the number of moles changes to 0.928 moles volume is found to be 7.98 L. What was the initial volume in mL?
Answer:
The initial volume in mL is 5959.2 mL
Explanation:
As the number of moles of a gas increases, the volume also increases. Hence, number of moles and volumes are directly proportional i.e
n ∝ V
Where n is the number of moles and V is the volume
Then, n = cV
c is the proportionality constant
∴n/V = c
Hence n₁/V₁ = n₂/V₂
Where n₁ is the initial number of moles
V₁ is the initial volume
n₂ is the final number of moles
and V₂ is the final volume.
From the question,
n₁ = 0.693 moles
V₁ = ?
n₂ = 0.928 moles
V₂ = 7.98 L
Putting the values into the equation
n₁/V₁ = n₂/V₂
0.693 / V₁ = 0.928 / 7.98
Cross multiply
∴ 0.928V₁ = 0.693 × 7.98
0.928V₁ = 5.53014
V₁ = 5.53014/0.928
V₁ = 5.9592 L
To convert to mL, multiply by 1000
∴ V₁ = 5.9592 × 1000 mL
V₁ = 5959.2 mL
Hence, the initial volume in mL is 5959.2 mL