the rate of effusion of he gas through a porous barrier is observed to be 5.21e-4 mol / h. under the same conditions, the rate of effusion of o3 gas would be mol / h.

Answers

Answer 1

Under the same conditions, the rate of effusion of O3 gas would be approximately 1.736e-4 mol/h.

To determine the rate of effusion of O3 gas through a porous barrier, we can use Graham's law of effusion. According to Graham's law, the rate of effusion of a gas is inversely proportional to the square root of its molar mass. Mathematically, it can be expressed as:

Rate1/Rate2 = √(MolarMass2/MolarMass1)

Given that the rate of effusion of He gas (Rate1) is 5.21e-4 mol/h, we need to find the rate of effusion of O3 gas (Rate2).

Let's first determine the molar mass of He and O3. The molar mass of He is approximately 4 g/mol, as it is a monoatomic gas. The molar mass of O3 (ozone) can be calculated by summing the molar masses of three oxygen atoms, which gives us approximately 48 g/mol.

Now we can use Graham's law to find the rate of effusion of O3 gas:

Rate1/Rate2 = √(MolarMass2/MolarMass1)

5.21e-4 mol/h / Rate2 = √(48 g/mol / 4 g/mol)

Rate2 = 5.21e-4 mol/h * √(4 g/mol / 48 g/mol)

Rate2 ≈ 5.21e-4 mol/h * 0.3333

Rate2 ≈ 1.736e-4 mol/h

Therefore, under the same conditions, the rate of effusion of O3 gas would be approximately 1.736e-4 mol/h.

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