The random variables X and Y are jointly continuous, with a joint PDF of the form fX,Y(x,y)={cxy,0,if 0≤x≤y≤1,otherwise, where c is a normalizing constant. For x∈[0,0.5] , the conditional PDF fX|Y(x|0.5) is of the form axb . Find a and b .

Answers

Answer 1

Answer:

The value of a and b are 8 and 1 respectively

Step-by-step explanation:

[tex]f_{x,y}(x,y)=\left\{\begin{matrix}cxy ,\text{if} 0 \leq x \leq y \leq 1\\ 0 , \text{otherwise}\end{matrix}\right.[/tex]

[tex]\int_{0}^{1}\int_{x}^{1}cxy \text{dy dx}=1\\\\c\int_{0}^{1}x\left ( \frac{y^2}{2}\right )_{x}^{1} \text{ dx}=1\\\\\frac{c}{2}\int_{0}^{1}x\left ( 1-y^2\right )\text{dx}=1\\\\\frac{c}{2}\int_{0}^{1}(x-x^3)\text{dx}=1\\\\\frac{c}{2}\left [ \frac{x^2}{2}-\frac{x^5}{4} \right ]_{0}^1=1\\\\\frac{c}{2}\left [ \frac{1}{2}-\frac{1}{4} \right ]=1\\\\\frac{c}{2}\left ( \frac{1}{4} \right )=1\\\\c=8[/tex]

Conditional pdf of [tex]f_{x,y}(x|0.5)[/tex]

[tex]f_{x,y}(x|0.5)=\frac{f_{xy}(x,y=0.5)}{f_{y}y}[/tex]

Normalizing pdf of 1

[tex]f_{y}y=\int_{0}^{y} 8yx \text{dx}[/tex]

[tex]f_{y}y=8y[\frac{x^2}{2}]_{0}^{y}\\f_{y}y=4y(y^2)\\f_{y}y=4y^3\\f_{x|y}(x|0.5)=\frac{8x(0.5)}{4(0.5)^3}=\frac{2x}{0.25}=8x[/tex]

We are given that PDF [tex]f_{x|y}(x|0.5)[/tex] is of the form [tex]ax^b[/tex]

So, on comparing 8x with [tex]ax^b[/tex]

So, a = 8 , b = 1

So, the value of a and b are 8 and 1 respectively

Answer 2

The resulting value of a and b given  the conditional PDF of fX|Y(x|0.5) is mathematically given as

a = 8 , b = 1 .

What are the values of a and b?

Question Parameters:

a joint PDF of the form fX,Y(x,y)={cxy,0,if 0≤x≤y≤1,

For x∈[0,0.5]

the conditional PDF fX|Y(x|0.5)

Generally, the equation for the function of (x,y)   is mathematically given as

[tex]f_{x,y}(x,y)=\left\{\begin{matrix}cxy ,\text{if} 0 \leq x \leq y \leq 1\\ 0 ,\end{matrix}\right.[/tex]

Therefore

[tex]\int_{0}^{1}\int_{x}^{1}cxy \text{dy dx}=1[/tex]

[tex]c\int_{0}^{1}x\left ( \frac{y^2}{2}\right )_{x}^{1} \text{ dx}=1[/tex]

[tex]\frac{c}{2}\left [ \frac{x^2}{2}-\frac{x^5}{4} \right ]_{0}^1=1[/tex]

[tex]\\\\\frac{c}{2}\left ( \frac{1}{4} \right )=1[/tex]

C=8

Where, the conditional PDF fX|Y(x|0.5)

[tex]f_{x,y}(x|0.5)=\frac{f_{xy}(x,y=0.5)}{f_{y}y}[/tex]

We have

[tex]f_{y}y=8y[\frac{x^2}{2}]_{0}^{y}\[/tex]

[tex]f_{y}y=4y^3[/tex]

[tex]f_{x|y}(x|0.5)=\frac{8x(0.5)}{4(0.5)^3}[/tex]

f_{x|y}(x|0.5)=8x

In conclusion. with the pdf in the form of ax^2

8x comparing ax^b

The value of a = 8 , b = 1 .

Read more about Arithmetic

https://brainly.com/question/22568180


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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

[tex]\frac{dh}{dt} = \frac{216}{1875\pi}[/tex]

Step-by-step explanation:

Given

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Height of 12 ft and radius of 10 ft, thus [tex]h = 12, r = 10[/tex].Radius does not change, thus [tex]\frac{dr}{dt} = 0[/tex].Water leaks at a rate of 8 cubic feet per minute, thus [tex]\frac{dV}{dt} = -8[/tex]

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[tex]\frac{dh}{dt} = -0.0764[/tex]

The depth of water changes at a rate of -0.0764 feet per minute.

A similar problem is given at https://brainly.com/question/9543179

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Answer:

cell wall :)

Answer:

Lysosome.

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Answer:

2:3 is equivalent to 4:6

Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answer:

(7,5)

Step-by-step explanation:

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B

Step-by-step explanation:

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B! It's B!

Step-by-step explanation:

With A, there is a difference of 75 meters.

With C, there is a difference of 25 seconds.

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Constraints:

Objective Formula:

Answers

Answer:

The maximum revenue for the week is $19,000.

Step-by-step explanation:

Denote the variables as follows:

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Y = tax return

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The maximizing function is subjected to the constraints:

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The problem can be solved using the simples method as follows:

Let s and t be slack variables.

Initial:

         x           y         s       t       b                Basic

       100        10        1       0     900               s (departing)

       12.5      2.5        0       1      100                t

Z   -2000    -300     0       0       0

   (entering)

Step 1:

         x           y         s           t       b                Basic

         1          1/10     1/100     0      9               x

         0           1        -1/10      1       10              t (departing)

Z        0        -100       20      0       18000

               (entering)

Step 2:

         x       y         s           t         b                Basic

         1       0       1/50     -1/10      8               x

         0      1       -1/10         1        10              y

Z        0      0       10         100     19000

               (entering)

The optimal solution is:

X = 8

Y = 10

The maximum revenue for the week is $19,000.

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°
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Answers

Step-by-step explanation:

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form

Answers

9514 1404 393

Answer:

  y = -3/5x +27/5

Step-by-step explanation:

Since we want a parallel line, we can use the same x- and y-coefficients to find the new constant in the given form:

  -3(4) -5(3) = -12 -15 = -27

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Answers

Answer:

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explanation:

2/3× 6/7 = 4/7

4/7 ÷ 2/5 = 1 3/7

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