Select the correct answer.
Tires need to be regularly:
A.
Replaced
B.
Rotated
C.
Both A and B
D.
None of the above
Support with three reasons the decision to use a plastic material for the package in the following
scenario.
Situation: A client has hired Jose, a materials engineer, to develop a package for an item he has begun
to market. The object needs to be mailed to customers within three days of being ordered.
Answer:
its durable. it's cheap. its recyclable
Explanation:
Plastic is made of lots of recycled materials that make it very useful and cheap.
A system will never enter a deadlocked state if:__________A) the system chooses to ignore the problem altogether.B) the system uses the detection and recovery technique.C) the system uses the deadlock avoidance technique.D) None of the above.
A system will never enter a deadlocked state if the system uses the detection and recovery technique. Thus the correct option is B.
What is deadlocked state?A deadlock in desktop software happens when a procedure or task enters a waiting state as a result of another waiting process holding the requested system resource.
When a group of processes is in a wait state, a deadlock occurs because each process is awaiting a resource that is being held by another waiting process.
The wait-for graph must be maintained by the system in order to detect deadlocks, and the system periodically runs an operation that looks for cycles in the wait-for graph.
There is no method used by the OS to avoid or stop deadlocks. The OS checks the system on a regular basis for any deadlocks in an effort to break them. Therefore, option B is appropriate.
Learn more about the detection and recovery technique, here:
https://brainly.com/question/29107758
#SPJ5
eggzOG43199
:) it has to be more than 20 characters so I'm just saying this
Answer:
giberishgiberishgiberishgiberishgiberishgiberishgiberishgiberishgiberish
Explanation:
i have no idea what the question is but do u 4 real need help?
An astronomer of 65 kg of mass hikes from the beach to the observatory atop the mountain in Mauna Kea, Hawaii (altitude of 4205 m). By how much (in newtons) does her weight change when she goes from sea level to the observatory?
Answer:
[tex]0.845\ \text{N}[/tex]
Explanation:
g = Acceleration due to gravity at sea level = [tex]9.81\ \text{m/s}^2[/tex]
R = Radius of Earth = 6371000 m
h = Altitude of observatory = 4205 m
Change in acceleration due to gravity due to change in altitude is given by
[tex]g_h=g(1+\dfrac{h}{R})^{-2}\\\Rightarrow g_h=9.81\times(1+\dfrac{4205}{6371000})^{-2}\\\Rightarrow g_h=9.797\ \text{m/s}^2[/tex]
Weight at sea level
[tex]W=mg\\\Rightarrow W=65\times 9.81\\\Rightarrow W=637.65\ \text{N}[/tex]
Weight at the given height
[tex]W_h=mg_h\\\Rightarrow W_h=65\times 9.797\\\Rightarrow W_h=636.805\ \text{N}[/tex]
Change in weight [tex]W_h-W=636.805-637.65=-0.845\ \text{N}[/tex]
Her weight reduces by [tex]0.845\ \text{N}[/tex].
Determine the size of memory needed for CD recording of a piece of music, which lasts for 26 minutes, is done with a 20-bit Analog-to-Digital Converter (ADC) in stereo (2 channels), at the rate of 44.1 kSa/s, with the compression factor 6 (allow 10% error margin).
Answer: the size of memory needed for the CD recording is 28.7 MB
Explanation:
so in the case of stereo, the bitrate is;
⇒ 26 × 60 × 44.1 × 10³ × 2
= 137592 × 10³
for 10 bit
⇒ 137592 × 10³ × 10
= 1375920 × 10³ bits
now divide by 8 (convert to bytes)
⇒ (1375920 × 10³) / 8
= 171,990,000 BYTE
divide by 1000 (convert to kilobytes)
= 171,990,000 / 1000
= 171,990 KILOBYTES
now Given that, the compression ratio is 6
so
171,990 / 6
= 28665 KB
we know that. 1 MB = 1000 KB
x MB = 28665 KB
x MB = 28665 / 1000
⇒ 28.665 MB ≈ 28.7 MB
Therefore the size of memory needed for the CD recording is 28.7 MB
700.0 liters of a gas are prepared at 760.0 mmHg and 100.0 °C. The gas is placed into a tank under high pressure. When the tank cools to 32.0 °C, the pressure of the gas is 20.0 atm. What is the volume of the gas?
Answer:
The volume of the gas is 11.2 L.
Explanation:
Initially, we have:
V₁ = 700.0 L
P₁ = 760.0 mmHg = 1 atm
T₁ = 100.0 °C
When the gas is in the thank we have:
V₂ =?
P₂ = 20.0 atm
T₂ = 32.0 °C
Now, we can find the volume of the gas in the thank by using the Ideal Gas Law:
[tex] PV = nRT [/tex]
[tex]V_{2} = \frac{nRT_{2}}{P_{2}}[/tex] (1)
Where R is the gas constant
With the initials conditions we can find the number of moles:
[tex] n = \frac{P_{1}V_{1}}{RT_{1}} [/tex] (2)
By entering equation (2) into (1) we have:
[tex] V_{2} = \frac{P_{1}V_{1}}{RT_{1}}*\frac{RT_{2}}{P_{2}} = \frac{1 atm*700.0 L*32.0 ^{\circ}}{100.0 ^{\circ}*20.0 atm} = 11.2 L [/tex]
Therefore, When the gas is placed into a tank the volume of the gas is 11.2 L.
I hope it helps you!
what are the SURVEYING INSTRUMENTS
Answer:
the main surveying instruments is use around the world are the theodolite, measuring tape, total station, 3D scanners ,GPS/GNSS, level and rod.Most instruments screw into a tripod when in use.How many flip-flop values are complemented in an 8-bit binary ripple counter to reach the next count value after: 0110111 and 01010110?
Answer:
- Four (4) flip-flop values will complemented
- one (1) flip-flop value will complemented
Explanation:
To find how many flip flop number of bits complemented, we just need to figure out what the next count in the sequence is and find how many bits have changed.
taking a look at the a) 00110111
we need to just 1 to the value,
so
00110111 + 0000001 = 00111000
So here, only the first four bits are complemented.
Therefore Four (4) flip-flop values will complemented
Next
b) 01010110
we also add 1 to the value
01010110 + 00000001 = 01010111
only the first bit is complemented.
Therefore one (1) flip-flop value will complemented
How is the law of conservation of matter best represented in a chemical reaction
Answer:
Umm.... because the spit that comes up of your mouth when you talk mixes with the air
Explanation:
1. Discuss how products incorporate aesthetic design and why this appeals to target markets 2. Discuss how the universal design process has impacted engineering design and the impact these expectations will have on the future of product design.
Explanation:
Remember, to say a product is incorporated with aesthetic design implies that its overall appearance is designed to look beautiful to the eyes of the user/buyer. For example, a clothing company whose target market is mainly focused on women's clothing would need to take into consideration that certain colors like pink, blue, etc are attractive to women more than men. So they'll have to ensure the colors of their clothing are suitable to the needs of their target market.
The Universal Design process involves building products that can be used by a wide range of users at ease. For example, you may ask yourself: Is my product/service easily accesible to those with disabilities?
Other processes include;
Defining who the users (or universe) are of the products. Involve consumers in the design.Follow the existing standards of product designEvaluate and review your universal design methodsWhich of the following terms describes the path from an electrical source to a switch or plug?
transmitter
circuit breaker
raceway
breaker panel
Answer:
transmitter hope thus helped!
Explanation:
Raceway is the answer
"A raceway is an enclosed conduit that forms a physical pathway for electrical wiring."
It is desired to produce and aligned carbon fiber-epoxy matrix composite having a longitudinal tensile strength of 630 MPa. Calculate (a) the critical fiber length, and (b) the volume fraction of fibers necessary if (1) the average fiber diameter is 0.030 mm, (2) the average fiber length is 2.4 mm, (3) the fiber fracture strength is 5100 MPa, (4) the fiber-matrix bond strength is 17 MPa, (5) the matrix stress at fiber failure is 17.5 MPa.
Answer:
The answer is below
Explanation:
Given that:
Diameter (D) = 0.03 mm = 0.00003 m, length (L) = 2.4 mm = 0.0024 m, longitudinal tensile strength [tex](\sigma_{cd})=630\ MPa = 630*10^6\ Pa[/tex], Fracture strength
[tex](\sigma_f)=5100\ MPa=5100*10^6\ Pa,fiber-matrix\ stres(\sigma_m)=17.5\ MPa=17.5*10^6\ Pa,matrix\ strength=\tau_c=17\ MPa=17 *10^6\ Pa[/tex]
a) The critical length ([tex]L_c[/tex]) is given by:
[tex]L_c=\sigma_f*(\frac{D}{2*\tau_c} )=5100*10^6*\frac{0.00003}{2*17*10^6}=0.0045\ m=4.5\ mm[/tex]
The critical length (4.5 mm) is greater than the given length, hence th composite can be produced.
b) The volume fraction (Vf) is gotten from the formula:
[tex]\sigma_{cd}=\frac{L*\tau_c}{D}*V_f+\sigma_m(1-V_f)\\\\V_f=\frac{\sigma_{cd}-\sigma_{m}}{\frac{L*\tau_c}{D}-\sigma_{m}} \\\\Substituting:\\\\V_f=\frac{630*10^6-17.5*10^6}{\frac{0.0024*17*10^6}{0.00003} -17.5*10^6} \\\\V_f=0.456[/tex]
An engineer must design a rectangular box that has a volume of 9 m3 and that has a bottom whose length is twice its width. What are the dimensions of the box so that the total surface area (of all six sides) of the box is minimized
Answer:
[tex]Length =3[/tex] [tex]Height = 2[/tex] and [tex]Width = \frac{3}{2}[/tex]
Explanation:
Given
[tex]Volume = 9m^3[/tex]
Represent the height as h, the length as l and the width as w.
From the question:
[tex]Length = 2 * Width[/tex]
[tex]l = 2w[/tex]
Volume of a box is calculated as:
[tex]V = l*w*h[/tex]
This gives:
[tex]V = 2w *w*h[/tex]
[tex]V = 2w^2h[/tex]
Substitute 9 for V
[tex]9 = 2w^2h[/tex]
Make h the subject:
[tex]h = \frac{9}{2w^2}[/tex]
The surface area is calculated as:
[tex]A = 2(lw + lh + hw)[/tex]
Recall that: [tex]l = 2w[/tex]
[tex]A = 2(2w*w + 2w*h + hw)[/tex]
[tex]A = 2(2w^2 + 2wh + hw)[/tex]
[tex]A = 2(2w^2 + 3wh)[/tex]
[tex]A = 4w^2 + 6wh[/tex]
Recall that: [tex]h = \frac{9}{2w^2}[/tex]
So:
[tex]A = 4w^2 + 6w * \frac{9}{2w^2}[/tex]
[tex]A = 4w^2 + 6* \frac{9}{2w}[/tex]
[tex]A = 4w^2 + \frac{6* 9}{2w}[/tex]
[tex]A = 4w^2 + \frac{3* 9}{w}[/tex]
[tex]A = 4w^2 + \frac{27}{w}[/tex]
To minimize the surface area, we have to differentiate with respect to w
[tex]A' = 8w - 27w^{-2}[/tex]
Set A' to 0
[tex]0 = 8w - 27w^{-2}[/tex]
Add [tex]27w^{-2}[/tex] to both sides
[tex]27w^{-2} = 8w[/tex]
Multiply both sides by [tex]w^2[/tex]
[tex]27w^{-2}*w^2 = 8w*w^2[/tex]
[tex]27 = 8w^3[/tex]
Make [tex]w^3[/tex] the subject
[tex]w^3 = \frac{27}{8}[/tex]
Solve for w
[tex]w = \sqrt[3]{\frac{27}{8}}[/tex]
[tex]w = \frac{3}{2}[/tex]
Recall that : [tex]h = \frac{9}{2w^2}[/tex] and [tex]l = 2w[/tex]
[tex]h = \frac{9}{2 * \frac{3}{2}^2}[/tex]
[tex]h = \frac{9}{2 * \frac{9}{4}}[/tex]
[tex]h = \frac{9}{\frac{9}{2}}[/tex]
[tex]h = 9/\frac{9}{2}[/tex]
[tex]h = 9*\frac{2}{9}[/tex]
[tex]h= 2[/tex]
[tex]l = 2w[/tex]
[tex]l = 2 * \frac{3}{2}[/tex]
[tex]l = 3[/tex]
Hence, the dimension that minimizes the surface area is:
[tex]Length =3[/tex] [tex]Height = 2[/tex] and [tex]Width = \frac{3}{2}[/tex]
Compute the weight fraction of graphite, in a 3 wt% C Ferritic Gray cast iron, assuming that all the carbon exists as the graphite phase. Assume densities of 7.9 and 2.3 g/cm3 for ferrite and graphite, respectively.
Answer:
9.60%
Explanation:
Computation for the weight fraction of graphite
First step
Computation for the mass fraction for Wa using this formula
Wa=Cg-Co/Cg-Ca
Let plug
Wa=10-3/100-0
Wa=0.97
Computation for the mass fraction for Wg using this formula
Wg=Co-Ca/Cg-Ca
Let plug in the formula
Wg=3-0/100-0
Wg=0.03
Second step is to convert the mass fraction to Volume Fraction using this formula
Volume Fraction =[Wg/Pg÷(Wa/Pa)+(Wg/Pg)]*100
Let plug in the formula
Volume =[0.03/2.3 ÷(0.97/7.9)+(0.03/2.3)]*100
Volume=[0.0130435÷0.1227848+0.0130435]*100
Volume=[0.0130435÷0.135828]*100
Volume=0.096*100
Volume=9.60%
Therefore the weight fraction of graphite will be 9.60%
LOLOLOLOKOLLOLLOLOLOO STRIKER KID THINKS HES SO GOOD LLOLOLOLOLOLOLOLOLOLOOLOLOLOLOLOLOL
Answer:
UUUUUUMMMM do you mean in soccer ????????????????
Explanation: