Answer:
(-4,-9)
Step-by-step explanation:
multiply (a,b)
What is the solution of 3(x + 4) = -12 ? Group of answer choices 3 0 8 -8
Answer:
Step-by-step explanation:
3(x + 4) = -12
3x+12 = -12
3x= -12-12
3x= -24
x = -24/3
x= -8
Answer:
x = -8
Step-by-step explanation:
3(x+4) = -12
3*x + 3*4 = -12
3x + 12 = -12
3x = -12 - 12
3x = -24
x = -24/3
x = -8
Check:
3(-8+4) = -12
3*-4 = -12
☆ =
MODULE
The length of a rectangle is eight centimeter less than
twice the width. The area of the rectangle is 24
centimeters squared. Determine the dimensions of the
rectangle in centimeters.
Answer: The length is 4 centimeters and the width is 6 centimeters.
Step-by-step explanation:
If the length of the rectangle is eight centimeters less than twice the width then we could represent it by the equation L= 2w - 8 . And we know that to find the area of a rectangle we multiply the length by the width and they've already given the area so we will represent the width by w since it is unknown.
Now we know the length is 2w- 8 and the width is w so we would multiply them and set them equal to 24.
w(2w-8) = 24
2[tex]w^{2}[/tex] - 8w = 24 subtract 24 from both sides to set the whole equation equal zero and solve. solve using any method. I will solve by factoring.
2[tex]w^{2}[/tex] - 8w -24 = 0 divide each term by 2.
[tex]w^{2}[/tex] - 4w - 12 = 0 Five two numbers that multiply to get -12 and to -4
[tex]w^{2}[/tex] +2w - 6w - 12 = 0 Group the left hand side and factor.
w(w+2) -6( w + 2) = 0 factor out w+2
(w+2)(w-6) = 0 Set them both equal zero.
w + 2 =0 or w - 6 = 0
-2 -2 + 6 +6
w= -2 or w=6
Since we are dealing with distance -2 can't represent a distance so the wide has to 6.
Now it says that the length is 8 less that twice the width.
So 2(6) - 8 = 12 -8 = 4 So the length in this care is 4.
Check.
6 * 4 = 24
24 = 24
If h(x)=-2x-10 ,find h(-4)
Answer:
h(-4) = -2
Step-by-step explanation:
h(x)=-2x-10
Let x = -4
h(-4)=-2*-4-10
=8-10
= -2
Answer:
[tex]\huge \boxed{{-2}}[/tex]
Step-by-step explanation:
[tex]\sf The \ function \ is \ given:[/tex]
[tex]h(x)=-2x-10[/tex]
[tex]\sf To \ find \ h(-4), \ put \ x=-4.[/tex]
[tex]h(-4)=-2(-4)-10[/tex]
[tex]h(-4)=8-10[/tex]
[tex]h(-4)=-2[/tex]
If a, b, c are in A.P. show that
a (b + c)/bc,b(c + a) /ca, c(a-b )/bc
are in A.P.
Answer:
Step-by-step explanation:
[tex]\frac{a(b+c)}{bc} ,\frac{b(c+a)}{ca} ,\frac{c(a+b)}{ab} ~are~in~A.P.\\if~\frac{ab+ca}{bc} ,\frac{bc+ab}{ca} ,\frac{ca+bc}{ab} ~are~in~A.P.\\add~1~to~each~term\\if~\frac{ab+ca}{bc} +1,\frac{bc+ab}{ca} +1,\frac{ca+bc}{ab} +1~are~in~A.P.\\if~\frac{ab+ca+bc}{bc} ,\frac{bc+ab+ca}{ca} ,\frac{ca+bc+ab\\}{ab} ~are~in~A.P.\\\\divide~each~by~ab+bc+ca\\if~\frac{1}{bc} ,\frac{1}{ca} ,\frac{1}{ab} ~are ~in~A.P.\\if~\frac{a}{abc} ,\frac{b}{abc} ,\frac{c}{abc} ~are~in~A.P.\\if~a,b,c~are~in~A.P.\\which~is~true.[/tex]
Which is greater 9/20 or 60%
Answer:
60%
Step-by-step explanation:
9/20 is 45%
Answer:
60 %
Step-by-step explanation: If you divide 9/20, it equals to 0.45, makes it 45% and the number 45 in general is smaller than 60. Thus, 60% is greater than 9/20. I hope this helps.
Lines a and b are parallel. If the slope of line a is , what is the slope of line b?
A.
-
B.
4
C.
D.
-4
Answer:
C. 1/4
Step-by-step explanation:
Parallel lines always have the same slope.
Answer:
C. 1/4
Step-by-step explanation:
Parallel lines have the same slope. If line b is parallel to line a, and line a has slope 1/4, then line b has slope 1/4.
Priya is buying raisins and almonds to make trail mix. Almonds cost $5.20 per pound and raisins cost $2.75 per pound. Priya spent $11.70 buying almonds and raisins. The relationship between pounds off almonds a, pounds of raisins r, and the total cost is represented by the equation 5.20a + 2.75r = 11.70.
How many pounds of raisins did Priya buy if she bought the following amount of almonds:
a pounds of almonds
Answer:
2.25 pounds of raisins
Step-by-step explanation:
Write the quadratic function f(x) = x2 - 2x - 8 in factored form.
A) f(x) =(x - 4)(x - 2)
B) f(x) =(x + 4)(x - 2)
C) f(x) =(x - 4)(x + 2)
D) Rx) =(x + 4)(x + 2)
Answer:
Hello,
answer C
Step-by-step explanation:
[tex]f(x)=x^2+2x-8\\\\=x^2-4x+2x-8\\\\=x(x-4)+2(x-4)\\\\=(x-4)(x+2)\\\\Answer\ C[/tex]
What is the answer, what are the steps to solve this, and what do the parts of the equation represent?
Step-by-step explanation:
Just sub 4 into where n is
What is the base and height of parallelogram S?
12/1,000 into decimal
0.012 is the answer!
I hope this helps you out! :D
[tex]\\ \sf\longmapsto \dfrac{12}{1000}[/tex]
1000 has 3zeros hence decimal will go 3 points left[tex]\\ \sf\longmapsto 0.012[/tex]
More:-
[tex]\\ \sf\longmapsto \dfrac{1}{10}=0.1[/tex]
[tex]\\ \sf\longmapsto \dfrac{1}{100}=0.01[/tex]
What is the difference? Complete the equation. -1 2/5 - (-4/5) = ?
Answer:
First convert them which will be
-7/5 - (-4/5)
so when you subtract a negative number from negative number they actually subtract ex = -4-(-2) = -2
so its simply 7/5-4/5 then add a negative sign
so
3/5
now add negative sign so
-3/5
Musah stands at the centre of a rectangular field. He first takes 50 steps north, then 25 steps
west and finally 50 steps on a bearing of 3150
.
i. Sketch Musah’s movement
Answer:
Step-by-step explanation:
Following the cardinal points as regards location of points, the sketch of Musah's movement can be as what is attached to this answer.
Solve this and get 12 points
Answer:
9
Step-by-step explanation:
First, find x. Since x is the average of the three number, add the three up and then divided by three. Thus:
[tex]x=\frac{13+-16+6}{3}=3/3=1[/tex]
y is the cube root of 8. Thus:
[tex]y=\sqrt[3]{8}=2[/tex]
So:
[tex]x^2+y^3\\=(1)^2+(2)^3\\=1+8=9[/tex]
Answer:
ljih
Step-by-step explanation:
The present price of a bus is rs 3000000if the price of bus depreciated the first two yrs by 10% and then 15% and 20% respectively in follow yrs.what is the price of bus after 4 yrs?
Answer:
The price of bus after 4 yrs is Rs.1652400
Step-by-step explanation:
Present price of car = Rs.3000000
We are given that the price of bus depreciated the first two yrs by 10%
So, The price after first two years =[tex]3000000(1-0.1)^2=2430000[/tex]
Now the price of bus depreciated by 15%
So, The price after third year = 2430000-0.15(2430000)=2065500
Now the price of bus depreciated by 20%
The price after fourth year =2065500-0.2(2065500)=1652400
Hence the price of bus after 4 yrs is Rs.1652400
A sample of 45 bottles of soft drink showed a variance of 1.1 in their contents. The process engineer wants to determine whether or not the standard deviation of the population is significantly different from 0.9 ounces. What is the value of the test statistic
Answer:
The value of the test statistic is 59.75.
Step-by-step explanation:
The test statistic for the population standard deviation is:
[tex]\chi^2 = \frac{n-1}{\sigma_0^2}s^2[/tex]
In which n is the sample size, [tex]\sigma_0[/tex] is the value tested and s is the sample standard deviation.
A sample of 45 bottles of soft drink showed a variance of 1.1 in their contents.
This means that [tex]n = 45, s^2 = 1.1[/tex]
The process engineer wants to determine whether or not the standard deviation of the population is significantly different from 0.9 ounces.
0.9 is the value tested, so [tex]\sigma_0 = 0.9, \sigma_0^2 = 0.81[/tex]
What is the value of the test statistic
[tex]\chi^2 = \frac{n-1}{\sigma_0^2}s^2[/tex]
[tex]\chi^2 = \frac{44}{0.81}1.1 = 59.75[/tex]
The value of the test statistic is 59.75.
The numbers of words defined on randomly selected pages from a dictionary are shown below. Find the mean, median, mode of the listed numbers. 72 58 62 38 44 66 42 49 76 52 What is the mean? Select the correct choice below and ,if necessary ,fill in the answer box within your choice.(around to one decimal place as needed)
Answer:
Mean: 55.9
Median: 55
Mode: None
Step-by-step explanation:
First, find the mean by dividing the sum by the number of elements:
(72 + 58 + 62 + 38 + 44 + 66 + 42 + 49 + 76 + 52) / 10
= 55.9
Next, find the median by putting the numbers in order and finding the middle one:
38, 42, 44, 49, 52, 58, 62, 66, 72, 76
There is no middle number, so we will take the average of 52 and 58, which is 55.
Lastly, to find the mode, we have to find the number that occurs the most.
All of the numbers occur one time, so there is no mode.
Write the equation of the trigonometric graph
Answer:
y = sin(4(x+π/8)) + 1
Step-by-step explanation:
For a trigonometric equation of form
y = Asin(B(x+C)) + D,
the amplitude is A, the period is 2π/B, the phase shift is C, and the vertical shift is D (shifts are relative to sin(x) = y)
First, the amplitude is the distance from the center to a top/bottom point (also known as a peak/trough respectively). The center of the function given is at y=1, and the top is at y=2, Therefore, 2-1= 1 is our amplitude.
Next, the period is the distance between one peak to the next closest peak, or any matching point to the next matching point. One peak of this function is at x=0 and another is at x= π/2, so the period is (π/2 - 0) = π/2. The period is equal to 2π/B, so
2π/B = π/2
multiply both sides by b to remove a denominator
2π = π/2 * B
divide both sides by π
2 = 1/2 * B
multiply both sides by 2 to isolate b
4 = B
After that, the phase shift is the horizontal shift from sin(x). In the base function sin(x), one center is at x=0. However, on the graph, the closest centers to x=0 are at x=± π/8. Therefore, π/8 is the phase shift.
Finally, the vertical shift is how far the function is shifted vertically from sin(x). In sin(x), the centers are at y=0. In the function given, the centers are at y=1, symbolizing a vertical shift of 1.
Our function is therefore
y = Asin(B(x+C)) + D
A = 1
B = 4
C = π/8
D = 1
y = sin(4(x+π/8)) + 1
Answer(s):
[tex]\displaystyle y = sin\:(4x + \frac{\pi}{2}) + 1 \\ y = -cos\:(4x \pm \pi) + 1 \\ y = cos\:4x + 1[/tex]
Explanation:
[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{\pi}{8}} \hookrightarrow \frac{-\frac{\pi}{2}}{4} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\frac{\pi}{2}} \hookrightarrow \frac{2}{4}\pi \\ Amplitude \hookrightarrow 1[/tex]
OR
[tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\frac{\pi}{2}} \hookrightarrow \frac{2}{4}\pi \\ Amplitude \hookrightarrow 1[/tex]
You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the cosine graph, if you plan on writing your equation as a function of sine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = sin\:4x + 1,[/tex] in which you need to replase “cosine” with “sine”, then figure out the appropriate C-term that will make the graph horisontally shift and map onto the cosine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the sine graph [photograph on the right] is shifted [tex]\displaystyle \frac{\pi}{8}\:unit[/tex] to the right, which means that in order to match the cosine graph [photograph on the left], we need to shift the graph BACK [tex]\displaystyle \frac{\pi}{8}\:unit,[/tex] which means the C-term will be negative, and perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{-\frac{\pi}{8}} = \frac{-\frac{\pi}{2}}{4}.[/tex] So, the sine graph of the cosine graph, accourding to the horisontal shift, is [tex]\displaystyle y = sin\:(4x + \frac{\pi}{2}) + 1.[/tex] Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [0, 2],[/tex] from there to [tex]\displaystyle [\frac{\pi}{2}, 2],[/tex] they are obviously [tex]\displaystyle \frac{\pi}{2}\:unit[/tex] apart, telling you that the period of the graph is [tex]\displaystyle \frac{\pi}{2}.[/tex] Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 1,[/tex] in which each crest is extended one unit beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.
I am delighted to assist you at any time.
If 30 percent of the people surveyed use both of the methods "exercise near home or work" and "exercise outdoors", what percent of people surveyed use at least one of the two methods?
A 26%
B 52%
C 56%
D 74%
E 86%
A. 26%
There are 30% people who use both methods, Exercise near home or work and Exercise outdoor.
There are 46% people who prefer exercise near home or office rather than outdoor.
There are 40% people who prefer exercise outdoor rather than near home or office.
Then there are 30% people among them who use both methods. The remaining 26% people use one of the method.
Learn more at https://brainly.com/question/24371331
Adding Fractions: What is 9/8 + 5/6? I would like an explanation for mebecause I am confused about this problem, it will be nice if someone explained it to me. Thanks!
Answer:
4/3
Step-by-step explanation:
just do the lcm of denomination and after that start solving
9514 1404 393
Answer:
1 23/24
Step-by-step explanation:
Fractions can be added when they have the same denominator. Then the addition is performed by adding the numerators, and expressing the sum over the common denominator.
Here, your fractions have denominators of 8 and 6. Usually, we want to find a "least common denominator" to use to express the fractions. There are various ways to find that value. One of the easiest is to consult your memory of multiplication tables to find the smallest number that both a multiple of 8 and a multiple of 6. That number is 24.
An equivalent fraction is one that has the same value, but a different denominator than the one it is being compared to. Equivalent fractions can be made by multiplying by "1" in the form of "a/a" where "a" is any non-zero value. Here, it is useful to multiply 9/8 by 3/3 to make the equivalent fraction 27/24, which has a denominator of 24.
Similarly, we can multiply 5/6 by 4/4 to get the equivalent 20/24, which also has a denominator of 24.
These two fractions can now be added:
[tex]\dfrac{9}{8}+\dfrac{5}{6}=\dfrac{27}{24}+\dfrac{20}{24}=\dfrac{27+20}{24}=\dfrac{47}{24}[/tex]
If you want to turn this into a "mixed number", you need to find how many times 24 goes into 47: 47÷24 = 1 remainder 23. The quotient is the integer part of the mixed number; the remainder is the numerator of the fractional part. Then the mixed number value of the sum is ...
[tex]\dfrac{47}{24}=1\dfrac{23}{24}[/tex]
_____
Additional comments
The product of the denominators can always serve as a common denominator. That may not be the "least" common denominator. If you use that here, you would have ...
[tex]\dfrac{9}{8}+\dfrac{5}{6}=\left(\dfrac{9}{8}\cdot\dfrac{6}{6}\right)+\left(\dfrac{5}{6}\cdot\dfrac{8}{8}\right)=\dfrac{54+40}{48}=\dfrac{94}{48}[/tex]
This result can be reduced by removing a factor of 2 from numerator and denominator to give 47/24, the sum we had above.
The "least common denominator" (LCD) is the Least Common Multiple (LCM) of the denominators. It can be found by forming the product of the unique factors of the denominators. Here, we have 8 = 2·2·2 and 6 = 2·3. The LCD is the product 2·2·2·3. We recognize that 2³ and 3 are unique factors that need to contribute to the LCD. 2 is subsumed by 2³.
As you can see from the factoring, 2 is a common factor of both numbers. Another way to find the LCD (or LCM of the denominators) is to form their product (8×6 = 48) and divide that by the greatest common factor (GCF), which is 2. (48/2 = 24, the LCD) Sometimes it is easier to find the GCF and compute (product/GCF) than to find the LCM using factoring.
__
If you don't mind the possibility of having to reduce the resulting fraction, the sum of fractions can always be computed as ...
[tex]\dfrac{a}{b}+\dfrac{c}{d}=\dfrac{ad+bc}{bd}[/tex]
This formula computes 94/48 as the sum of these fractions, effectively leaving out the middle step (9/8×6/6 +...) shown in the work above. I find this especially useful for adding rational expressions, not just numerical fractions.
solve for x: -3(x + 1)= -3(x + 1) - 5
Answer:
No solution : 0= -5Step-by-step explanation:
[tex]-3\left(x+1\right)=-3\left(x+1\right)-5\\\\\mathrm{Add\:}3\left(x+1\right)\mathrm{\:to\:both\:sides}\\\\-3\left(x+1\right)+3\left(x+1\right)=-3\left(x+1\right)-5+3\left(x+1\right)\\\\\mathrm{Simplify}\\\\0=-5\\\\\mathrm{The\:sides\:are\:not\:equal}\\\\\mathrm{No\:Solution}[/tex]
if it can be assumed that the population is normal, then what is the probability that one man sampled from this population has a weight between 72kg and 88kg
Answer:
The probability that one man sampled from this population has a weight between 72kg and 88kg is 0.6826.
Step-by-step explanation:
The complete question has the data of mean = 80 kg and standard deviation = 8kg
We have to find the probability between 72 kg and 88 kg
Since it is a normal distribution
(x`- u1 / σ/ √n) < Z >( x`- u2 / σ/ √n)
P (72 <x>88) = P ( 72-80/8/√1) <Z > ( 88-80/8/√1)
= P (-1<Z> 1) = 1- P (Z<1) - P (Z<-1)
= 1- 0.8413- (- 0.8413)= 1- 1.6826= 0.6826
So the probability that one man sampled from this population has a weight between 72kg and 88kg is 0.6826.
. A discount brokerage selected a random sample of 64 customers and reviewed the value of their accounts. The mean was $32,000 with a population standard deviation of $8,200. What is a 90% confidence interval for the mean account value of the population of customers
Answer:
The 90% confidence interval is [tex]\$ \ 30313.9< \mu < \$ \ 33686.13[/tex]
Step-by-step explanation:
From the question we are told that
The sample size is n = 64
The sample mean is [tex]\= x = \$ 32, 000[/tex]
The standard deviation is [tex]\sigma= \$ 8, 200[/tex]
Given that the confidence interval is 90% then the level of significance is mathematically evaluated as
[tex]\alpha = 100 - 90[/tex]
[tex]\alpha = 10 \%[/tex]
[tex]\alpha = 0.10[/tex]
Next we obtain the critical value of [tex]\frac{ \alpha }{2}[/tex] from the normal distribution table , the value is
[tex]Z_{\frac{\alpha }{2} } = 1.645[/tex]
Generally the margin of error is mathematically represented as
[tex]E = Z_{\frac{\alpha }{2} } * \frac{ \sigma }{ \sqrt{n} }[/tex]
=> [tex]E = 1.645 * \frac{ 8200 }{ \sqrt{64} }[/tex]
=> [tex]E = 1686.13[/tex]
The 90% confidence interval is mathematically represented as
[tex]\= x - E < \mu < \= x + E[/tex]
=> [tex]32000 - 1689.13 < \mu < 32000 + 1689.13[/tex]
=> [tex]\$ \ 30313.9< \mu < \$ \ 33686.13[/tex]
Answer two questions about Equations A and B:
A. 2x-1=5x
B. -1=3x
1) How can we get Equation B from Equation A?
Choose 1 answer:
Add/subtract the same quantity to/from both sides
Add/subtract a quantity to/from only one side
Rewrite one side (or both) by
combining like terms
Rewrite one side (or both) using the distributive property
NEXT QUESTION
based on the previous answer, are the equations equivalent? In other words, do they have the same solution?
A. Yes
B. No
Answer:
B: Add/subtract the same quantity to/from both sides
Next Question: Yes
Step-by-step explanation:
thats what the answer is dunno what else to tell you lol
Algebraic equations are mathematical equations that contain unknown variables.
To get Equation B from Equation A, we add/subtract the same quantity to/from both sides. Option A is the correct option. Equation A is equivalent to Equation BQuestion 1: We are given equation A as:2x - 1 = 5x .............Equation A
To get Equation B from A, we would subtract 2x from both sides of the equation.
2x - 2x - 1 = 5x - 2x
- 1 = 3x This is Equation B
Question 2: Based on the previous answer,2x - 1 = 5x is equal to -1 = 3x.
Hence, both Equation A and Equation B are equivalent expressions.
Therefore,
To get Equation B from Equation A, we add/subtract the same quantity to/from both sides. Option A is the correct option.Equation A is equivalent to Equation BTo learn more, visit the link below:
https://brainly.com/question/22299566
if y = 2√x÷ 1–x', show that dy÷dx = x+1 ÷ √x(1–x)²
Answer: see proof below
Step-by-step explanation:
Use the Quotient rule for derivatives:
[tex]\text{If}\ y=\dfrac{a}{b}\quad \text{then}\ y'=\dfrac{a'b-ab'}{b^2}[/tex]
Given: [tex]y=\dfrac{2\sqrtx}{1-x}[/tex]
[tex]\sqrtx[/tex][tex]a=2\sqrt x\qquad \rightarrow \qquad a'=\dfrac{1}{\sqrt x}\\\\b=1-x\qquad \rightarrow \qquad b'=-1[/tex]
[tex]y'=\dfrac{\dfrac{1-x}{\sqrt x}-(-2\sqrt x)}{(1-x)^2}\\\\\\.\quad =\dfrac{\dfrac{1-x}{\sqrt x}-(-2\sqrt x)\bigg(\dfrac{\sqrt x}{\sqrt x}\bigg)}{(1-x)^2}\\\\\\.\quad =\dfrac{1-x+2x}{\sqrt x(1-x)^2}\\\\\\.\quad =\dfrac{x+1}{\sqrt x(1-x)^2}[/tex]
LHS = RHS: [tex]\dfrac{x+1}{\sqrt x(1-x)^2}=\dfrac{x+1}{\sqrt x(1-x)^2}\qquad \checkmark[/tex]
I need one quarter liter of milk to make a milkshake. A.How much milk will I need to make 3 milkshakes?. B. How many ml will that be?.
Answer:
a: 750 ml (three quarters)
b: 750 ml
Step-by-step explanation:
1/4 liter= 250ml
A) 250*3= 750ml
B) the same as A
Solve the system by substitution.
Answer:
1st, keep value of x in 1st equation
Step-by-step explanation:
-6(-2y-1)+2y=48
12y+6+2y=48
14y=48-6
y=42/14
y=3
Now putting value of y in equation ii)
x= - 2y-1
x= - 2×3-1
x= - 6-1
x= - 7
Therefore, x= - 7
y=3
5-_=4 pls help.......
Answer:
5 - ? = 4
5- 1 = 4
use simple method ..➪5 - 4 = ?
➪1 = 5-4
➪ 5- 1 = 4
hopes its helps you ..
For the following function, solve both f'(x) = 0 and f''(x) = 0 for x.
f(x) = x(x - 3)^4
Point E lies within rectangle ABCD. If AE = 6, BE = 7, and CE = 8, what is the length of DE?
Answer:
[tex]\sqrt{51}[/tex] units.
Step-by-step explanation:
Point E is inside a rectangle ABCD.
Please refer to the attached image for the given statement and dimensions.
Given that:
Sides AE = 6 units
BE = 7 units and
CE = 8 units
To find:
DE = ?
Solution:
For a point E inside the rectangle the following property hold true:
[tex]AE^2+CE^2=BE^2+DE^2[/tex]
Putting the given values to find the value of DE:
[tex]6^2+8^2=7^2+DE^2\\\Rightarrow 26+64=49+DE^2\\\Rightarrow DE^2=100-49\\\Rightarrow DE^2=51\\\Rightarrow \bold{DE = \sqrt{51}\ units}[/tex]