The probability of randomly meeting someone with a phone number that ends in 3 is

Answer:

Step-by-step explanation:

25 km / 100 km/hr = 0.25 hr or 15 minutes

It will take 0.25 hours to travel 25 km.

Given

A train travels from point A to B at a speed of 100km/h.

Distance;

Distance is defined as the product of speed and time.

The following formula is used to calculate the time;

[tex]\rm Time =\dfrac{Distance}{Speed}\\\\[/tex]

Substitute all the values in the formula;

[tex]\rm Time =\dfrac{Distance}{Speed}\\\\\rm Time =\dfrac{25}{100}\\\\Time = 0.25 \ hours[/tex]

Hence, it will take 0.25 hours to travel 25 km.

To know more about distance click the link given below.

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Answer:

n = 34/13

Step-by-step explanation:

13 x 4 = n x 26

=> 68 = 26n

=> n = 68/26

=> n = 34/13

Therefore, n = 34/13

Hoped this helped.

[tex]GeniusUser[/tex]

Answer:

half-class

Step-by-step explanation:

Answer:

42.86%

Step-by-step explanation:

Event = Girl

Therare 6 girls and 8 boys, which are thus 6+8 =14 students in total and thus there are 14 possible out comes.

# of possible outcomes = 14

There are 6 girls in the class and thus there are 6 favorable outcomes.

# of favorable outcomes = 6

The probability is the number of favorable outcomes divided by the number of possible outcomes.

P(Girl) = # of favorable outcomes

            # of possible outcomes

= [tex]\frac{6}{14}[/tex]

= [tex]\frac{3}{7}[/tex]

≈ 0.4286

= 42.86%

Result

[tex]\frac{3}{7}[/tex] ≈ 0.4286 = 42.86%

Answer:

12

Step-by-step explanation:

You do 6+6, or 2+2+2+2+2+2=12

Answer:

hello which grade question i

Answer:

y= -x -3

Step-by-step explanation:

A perpendicular bisector of a line cuts through the line at its midpoint perpendicularly (90°).

Let's find the slope of the line segment.

\boxed{ slope = \frac{y _{1} - y_2 }{x_1 - x_2} }slope=x1−x2y1−y2

Slope of line segment

= \frac{4 - ( - 8)}{5 - ( - 7)}=5−(−7)4−(−8)

= \frac{4 + 8}{5 + 7}=5+74+8

= \frac{12}{12}=1212

= 1

The product of the slopes of 2 perpendicular lines is -1.

Let the slope of the perpendicular bisector be m.

m(1)= -1

m= -1

y= -x +c

To find the value of c, substitute a pair of coordinates in which the line passes through into the above equation.

Since the perpendicular bisector cuts through the midpoint of the line segment, let's find the coordinates of this midpoint.

\boxed{midpoint = ( \frac{x _{1} + x _2}{2} , \frac{y_1 + y_2}{2} )}midpoint=(2x1+x2,2y1+y2)

Midpoint of line segment

= ( \frac{5 - 7}{2} , \frac{4 - 8}{2} )=(25−7,24−8)

= ( \frac{ - 2}{2} , \frac{ - 4}{2} )=(2−2,2−4)

= (-1, -2)

y= -x +c

When x= -1, y= -2,

-2= -(-1) +c

-2= 1 +c

c= -2 -1

c= -3

Thus, the equation of the perpendicular bisector is y= -x -3.

Answer:

Down, Down, Right, Right, diagonal left, up, right

Step-by-step explanation:

Not gonna do every equation here tho lol

Answer:

AOB forms must be collected every time a beneficiary fills a Medicare part b prescription

Answer:

The first recipe - 3/4 tsp of salt in 1 cup of water

Step-by-step explanation:

1st recipe Salt per cup = 3/4 tsp / 1 cup = 3/4 tsp salt

2nd recipe Salt per cup = 1 tsp / 2 cups = 1/2 tsp salt

3/4 tsp > 1/2 tsp, hence the first recipe is saltier

Answer:

12x

Step-by-step explanation:

I am not really sure how to explain it I just looked it up

Answer:

Step-by-step explanation:

The decrease in value is ...

  15% of $233,000 = $34,950

The current house value is ...

  $233,000 -34,950 = $198,050

The most no. of tickets sold is 60.

The pictorial representation of data in the form of vertical or horizontal rectangular bars, whose length is proportional to the data's measurement, is known as a bar graph. Data are typically grouped in this way. Bar charts are another name for them. In statistics, bar graphs are one way to handle data.

Given  the graph between total student and number of ticket sold,

where students shown in Y axis and tickets sold in X axis,

as Shown in graph maximum number of tickets sold are 51 to 60

Hence the maximum number of ticket sold is 60.

Learn more about bar graph;

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#SPJ2

100 mph per hour

Step-by-step explanation:

solution

speed of auto mobile=50mph

distance already traveled when the airplane took out in pursuit=200miles

time taken to overtake the car=4 hours

Now,

let the speed of airplane be X

X=50×4+200

or,X=200+200

or,X=400

or, X=400÷4

Therefore, X=100

If my calculations are correct, the percentage decrease faced here is roughly 38.2%. Based on the calculations, the bicycle costs 199$ and when the cost is subtracted from 520, you would create the percentage of 38.2%.

Answer:

1a. 2 is the solution

1b. -3 is because square root of 1 doesn't equal -1.

1c.-3

Step-by-step explanation:

1.

[tex](x + 2 = \sqrt{3x + 10} [/tex]

Square both sides

[tex](x + 2) {}^{2} = 3x + 10[/tex]

Remeber perfect square Rule

[tex](x + y) {}^{2} = {x}^{2} + 2xy + {y}^{2} [/tex]

So now we got

[tex]x {}^{2} + 4x + 4 = 3x + 10[/tex]

[tex] {x}^{2} + x + 4 = 10[/tex]

[tex] {x}^{2} + x - 6 = 0[/tex]

Factor into binomial.

[tex](x + 3)(x - 2) = 0[/tex]

So our solution is 3 or 2. However, let's check our work.

[tex] - 3 + 2 = \sqrt{3( - 3) + 10} [/tex]

[tex] - 1 = \sqrt{1} [/tex]

However square root of 1 is 1. It could be 1 but in Math, We only take the principal square root which is positive always. So -3 isn't a solution.

So let try 2.

[tex]2 + 2 = \sqrt{3(2) + 10} = 4 = \sqrt{16} = 4 = 4[/tex]

So this is indeed the solution.

Make up equation for 2 and 3. Ask me if you need help.

Answer:W= B-3 or 3=B-W

Step-by-step explanation:

Answer:

A. (A) Yes

B. (A) Yes

C. (B) No

Step-by-step explanation:

A is Categorical because it is not based on numbers.

B is Categorical because it is not based on numbers.

C is Not Categorical because it is based on numbers.

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Step-by-step explanation:

several possibilities to solve this.

let's start with subtracting the second equation from the first

-x + 2y - z = 0

- -x - y +2z = 0

-------------------------

0 3y - 3z = 0

y - z = 0

y = z

now we use this in e.g. the first equation :

-x + 2z - z = 0

-x + z = 0

z = x (therefore, also x = y)

now we use this in the third equation :

2x - x = 8

x = 8 = y = z

======================================================

Explanation:

PDF = probability density function

The given joint PDF is

[tex]f(x,y) = \begin{cases}ax \ \ \ \text{ if } 1 \le x \le y \le 2\\0 \ \ \ \ \ \text{ otherwise}\end{cases}[/tex]

Let's focus on the [tex]1 \le x \le y \le 2[/tex]. Specifically the x term for now. Erasing out the y term, we have the inequality [tex]1 \le x \le 2[/tex] which says x is between 1 and 2, inclusive. We have almost the same story for y, but there's another condition attached to it: y must also be equal to or larger than x.

So let's say x = 1.5. This would mean [tex]1.5 \le y \le 2[/tex]. As another example, x = 1.7  leads to [tex]1.7 \le y \le 2[/tex]. In general, we would say [tex]x \le y \le 2[/tex] where x is between 1 and 2.

As x gets bigger, the range of possible y values gets smaller. If x = 2, then y has no choice but to be 2 as well.

-----------------

Based on that, we'll have a double integral that looks like this:

[tex]\displaystyle V = \int_{1}^{2}\int_{x}^{2}f(x,y)dydx\\\\[/tex]

The outer integral handles the x terms that range from 1 to 2, describing [tex]1 \le x \le 2[/tex]. Note the dx on the outside. The order of the dy and dx matters.

On the inside, we have the integral for dy ranging from x to 2 to describe the interval [tex]x \le y \le 2[/tex]

To have f(x,y) be a PDF, the volume under the f(x,y) surface must be 1, where the volume is based on the bounds set up. So we must have V = 1. We'll use this later.

-----------------

Let's simplify the double integral.

We'll start by computing the inner integral with respect to y.

[tex]\displaystyle V = \int_{1}^{2}\int_{x}^{2}f(x,y)dydx\\\\\displaystyle V = \int_{1}^{2}\int_{x}^{2}\left(ax\right)dydx\\\\\displaystyle V = \int_{1}^{2}\left(axy\Bigg|_{x}^{2}\right)dx\\\\\displaystyle V = \int_{1}^{2}\left(ax(2) - ax(x)\right)dx\\\\\displaystyle V = \int_{1}^{2}\left(2ax - ax^2\right)dx\\\\[/tex]

Then we'll finish it off by integrating with respect to x.

[tex]\displaystyle V = \int_{1}^{2}\left(2ax - ax^2\right)dx\\\\\displaystyle V = \left(ax^2 - \frac{1}{3}ax^3\right)\Bigg|_{1}^{2}\\\\\displaystyle V = \left(a(2)^2 - \frac{1}{3}a(2)^3\right) - \left(a(1)^2 - \frac{1}{3}a(1)^3\right)\\\\\displaystyle V = \left(4a - \frac{8}{3}a\right)-\left(a - \frac{1}{3}a\right)\\\\[/tex]

[tex]\displaystyle V = 4a - \frac{8}{3}a-a + \frac{1}{3}a\\\\\displaystyle V = 3a - \frac{8}{3}a + \frac{1}{3}a\\\\\displaystyle V = \frac{9}{3}a - \frac{8}{3}a + \frac{1}{3}a\\\\\displaystyle V = \frac{9-8+1}{3}a\\\\\displaystyle V = \frac{2}{3}a\\\\[/tex]

Side note: We don't have to worry about the "plus C" integration constant when working with definite integrals.

Recall that V = 1. So,

[tex]\displaystyle V = \frac{2}{3}a\\\\\displaystyle \frac{2}{3}a = 1\\\\\displaystyle a = \frac{3}{2} = 1.5\\\\[/tex]

a = 3/2 is the final answer.

Answer:

7

Step-by-step explanation:

12-(-3)-2(4)

12-(-3)-8

15-8=7

Answer:

y = [tex]\frac{5}{4}[/tex] x + 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = [tex]\frac{5}{4}[/tex] and c = 2 , then

y = [tex]\frac{5}{4}[/tex] x + 2 ← equation of line

Answer:

so you just use the equation to get the formula and extract the common denominator

Step-by-step explanation:

because i said so

Answer: 2135

step by step explanation:

I don't really think this is necessary

Answer:

I don't know

Step-by-step explanation:

Answer:

11/18

Explanation:

Find the LCM

6 × 3 = 18

9 × 2 = 18

Since you found the LCM, multiply the numerators by the number you multiplied the denominators by.

[tex]\frac{5 *3}{6*3}= \frac{15}{18}[/tex]

[tex]\frac{2*2}{9*2}=\frac{4}{18}[/tex]

Now subtract.

[tex]\frac{15}{18} -\frac{4}{18} =\frac{11}{18}[/tex]

[tex]x^{\tfrac 16} \left(x^{\tfrac 16} + x^{\tfrac 34} \right)\\\\\\=x^{\tfrac 16} \cdot x^{\tfrac 16} + x^{\tfrac 16} \cdot x^{\tfrac 34}\\\\\\=x^{\left(\tfrac 16 + \tfrac 16\right)} + x^{\left(\tfrac 16 +\tfrac 34\right)}\\\\\\=x^{\tfrac 26} + x^{\tfrac {11}{12}}\\\\\\=x^{\tfrac 13} +x^{\tfrac{11}{12}}[/tex]