The price of petrol increased by 8% to Rs 540 per litre. Find the old price.​

Answer:

6

Step-by-step explanation:

Answer:

-486

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

I am doing fine thanks bro.

The best method that would lead to a more effective study is:

Double blind experiments are usually better than single blind experiments because they will account for experimenter bias which is where the technicians influence the project whether knowingly or unknowingly.

The placebo effect is also better studied because the participants will not know whether they are receiving a placebo or the real thing.

In conclusion, option A is correct.

Find out more about double blind experiments at https://brainly.com/question/9292513.

Answer:

A ON EDGE2022 :)))))))

Step-by-step explanation:

Answer:

no these degrees do not make a right triangle

x=57

Step-by-step explanation:

x+x+2+x+4=177

3x+6=177

3x=177-6

3x=171

x=57

Therefore the three consecutive numbers are:

57;59;61

Answer:

∠DAB=140

∠BAC=60

∠EBF=40

∠ACB=80

∠BCG=100

Step-by-step explanation:

Answer: c = 6.5I

Step-by-step explanation:

C = the cost of the fabric

I = the length of the fabric

C : I = 13 : 2

C : I = 32.50 : 5

C : I = 6.5

C = 6.5I

<ABD and <EBC are equal  to each other. In order to solve for the x value, set the equations  equal to each other;

4x = 2x + 40,

x = 20

Based off what angle you are trying to find, you would plug x = 20 into the equation.

[tex]\mathfrak{7x(-4)} [/tex]

[tex]\mathfrak{=7x*-4} [/tex]

[tex]\boxed{\mathfrak{=-28x}} [/tex]

[tex]\mathbb{MIREU} [/tex]

Answer:

a. 54, b. 117, c. 63

Step-by-step explanation:

a. Angle 11 is corresponding to angle 1, which is linear to angle 2, which is 126 degrees. So angle 11 is 180 - 126 = 54 degrees

b. Angle 8 corresponds to angle 14, which is 117 degrees.

c. Angle 7 is linear to angle 8, so it is 180 - 117 = 63 degrees

Answer:

a or <11 is 54 degrees, b or <8 is 117 degrees, c or <7 is 63 degrees

Step-by-step explanation:

A. <2 = <12, <12 + <11 = 180, 180 - 126 = 54

B. <14 = <8, 117 = 117

C. <7 + <8 = 180, 180 - 117 = 63

The inequalities to find the acceptable range for the length and the width w are - 0.005 ≤ l - 11.125 ≤ 0.005 and - 0.005 ≤ w - 7.625 ≤ 0.005 respectively.

length = 11.125 in

width = 7.625 in

Range of value must be less than orequal to 0.005 in

let

l = Length

w = width

Length inequality:

l - 11.125 ≤ 0.005

write as a compound inequality

- 0.005 ≤ l - 11.125 ≤ 0.005

Width inequality:

w - 7.625 ≤ 0.005

write as a compound inequality

- 0.005 ≤ w - 7.625 ≤ 0.005

Therefore, the inequalities to find the acceptable range for the length and the width w are - 0.005 ≤ l - 11.125 ≤ 0.005 and - 0.005 ≤ w - 7.625 ≤ 0.005 respectively.

Learn more about inequality:

https://brainly.com/question/11234618

Answer:

Step-by-step explanation:

ok

Answer:

Angle E is 88º

Step-by-step explanation:

If angle A is 46, then angle B is 46. Angle C in triangle ABC then has to be 88. Because of this, angle C in triangle CDE has to be 88 as well. Hence, E is 88.

g(−3)=2

g(0) = 3g(0)=3

Step-by-step explanation:

Given

The attached graph

Required

Determine

g(-3)g(−3)

g(x) = 3g(x)=3

Since a graph has been provided, the question will be solved graphically;

Solving g(-3)

This implies that;

x = -3

And the interpretation is to solve for the y value when x = -3

From the attached graph;

When x = -3; y = 2

Hence;

g(-3) = 2g(−3)=2

Solving g(x) = 3

This implies that;

y = 3

And the interpretation is to solve for the x value when y = 3

From the attached graph;

When y = 3; x = 0

Answer:

Step-by-step explanation:

y = 5x is the reference line (as best as I can interpret " y = 5* - .").

We want a line, y=mx+b, where m is the slope and b is the y-intercept, that is parallel to y=5x.

Parallel lines will have the same slope as the reference line, in this case m=5.  Our new line will take the form of y=5x+b.  An important difference is that the new line must go through (2,6).  We need to find a value of b that will make that work.

Use y=5x + b with point (2,6) and solve for b:

6 = 5*(2) + b

b = -4

The line that is parallel to y=5x and goes through the point (2,6) is thus:

y = 5x - 4

See the attachment.

The equation of line [d] in the slope intercept form can be written as -

y = 5x - 4

The general equation of a straight line is of the form -

y = mx + b

where -

[m] is slope of line

[b] is y - intercept

Given is the equation of line [c] is y = 5x and Line [d] is parallel to line [c] and passes through (2, 6).

The equation of line [d] in the slope intercept form can be derived as follows -

Slope of line [c] = Slope of line [d]  (parallel lines)

m[d] = 5

Assume the equation of line [d] as -

y = m[d]x + b

6 = 5 x 2 + b

b = 6 - 10

b = - 4

The equation will be -

y = 5x - 4

Therefore, the equation of line [d] in the slope intercept form can be written as -

y = 5x - 4

To solve more questions on straight lines, visit the link below-

https://brainly.com/question/22038782

#SPJ1

Selling Price = 1004r

Cost Price = 804r

1004-804=200r

Gain% = 200/804 · 100 = 20000/804 = 23.80% or 29%

Answer:

x (upper level) = 12,000 tickets

Step-by-step explanation:

Firstly, let's convert this gibberish text into the information we want. :D

Total amount of people = 52,000

Main floor tickets = $25 each

Total: $1,144,000

Let the amount of people who brought upper level tickets be x and main floor tickets be y. (assumming 1 ticket = 1 person)

Thus, we come up with this simultaneous equation:

[tex]12x + 25y = 1,144,000\\x + y = 52,000[/tex]

The first equation finds the price of the ticket, while the second is the amount of people.

x (upper level) = 12,000

y = 40,000

Hope this helps! :)

Answer:

Which graph?

Step-by-step explanation:

Answer:

where is the graph

Step-by-step explanation:

umm i dont know how to answer

Answer:

A

Step-by-step explanation:

Use the formula rise/run. The rise, in this case, was 3 and the run was 1. There for it would be 3/1 which is simplified to 3.

Answer:

Step-by-step explanation:

(-7, 8) (-8, 8)

(y2 - y1) / (x2 - x1)

(8 - 8) / (-8 + 7)

0 / -1

the slope is 0

you could also see this because the y value doesn't change

if the y value doesn't change the slope is 0, if the x value doesn't change the slope is undefined

Answer:

slope = 0

Step-by-step explanation:

Calculate the slope m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 7, 8 ) and (x₂, y₂ ) = (- 8, 8 )

m = [tex]\frac{8-8}{-8-(-7)}[/tex] = [tex]\frac{0}{-8+7}[/tex] = [tex]\frac{0}{-1}[/tex] = 0

Answer:

7%

Step-by-step explanation:

The additional tax is $0.42, we just have to find how much percent the tax ($0.42) is of the original cost ($6.00).

To do this, we can use the following formula:

[tex]\frac{x}{y} = \frac{p}{100}[/tex]

Where x is the part (in this case, the tax ($0.42)), y is the whole (in this case, the original cost ($6.00)), and p being the percent (the tax rate in this case). We can replace the values in:

[tex]\frac{0.42}{6} = \frac{p}{y}[/tex]

We can cross multiply and simplify to find the tax rate:

[tex]0.42y=600\\ y=\frac{600}{0.42} \\ y=0.07[/tex]

We're not done yet! We still need to turn it to percent. But we can do this by just multiplying our result by 100:

[tex]0.07 * 100=7[/tex]

Place the percent sign and we are done.

Hope this helps.

Answer: good for him... how much did he spend on it?

Answer:

y=3x-4

Step-by-step explanation:

Answer: 5 kilometers.

Step-by-step explanation:

She needs 1 box of strawberries

She needs 2 cups of strawberries total

Answer:

necklace

Step-by-step explanation:

It is the only one with a negative elevation

Answer:

3) a = 9

4) v = 16

Step-by-step explanation:

Assuming here that the two questions you're talking about are problem 3 and problem 4, here is my work to find each answer.

Problem 3

First, let's distribute the 5 onto both terms in the parentheses.

5(a - 3) = 30

5(a) - 5(3) = 30

5a - 15 = 30

Next, we can add 15 to both sides to isolate a.

5a - 15 = 30

5a = 45

Finally, divide both sides by 5 to find the value of a.

5a = 45

a = 9

Problem 4

First, let's remove 2 from both sides of the equation.

v/2 + 2 = 10

v/2 = 8

Then, we can multiply both sides by 2 to find the value of v.

v/2 = 8

v = 16

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\text{Number 1}[/tex]

[tex]\text{QUESTION: 5(a - 3) = 30}\\\\\large\textsf{DISTRIBUTE 5 WITHIN the PARENTHESES}\\\\\rm{5(a) + 5(-3) = 30}\\\\\rm{5a - 15 = 30}\\\\\large\textsf{ADD 15 to BOTH SIDES}\\\\\rm{5a - 15 + 15 = 30 + 15}\\\\\large\textsf{CANCEL out: -15 + 15 because it gives you 0}\\\large\textsf{KEEP: 30 + 15 because it helps solve for the a-value}\\\\\text{NEW EQUATION: 5a = 30 + 15}\\\\\large\textsf{SIMPLIFY IT!}\\\\\rm{5a = 45}\\\\\large\textsf{DIVIDE 5 to BOTH SIDES}\\\\\rm{\dfrac{5a}{5} = \dfrac{45}{5}}[/tex]

[tex]\large\textsf{CANCEL out: }\mathsf{\dfrac{5}{5}}\large\textsf{ because it gives you 1}\\\large\textsf{KEEP: }\mathsf{\dfrac{45}{5}}\large\textsf{ because it helps solve for the a-value}\\\\\text{YOUR NEW EQUATION: }\rm{a = \dfrac{45}{5}}\\\\\large\textsf{SIMPLIFY IT!}\\\\\large\text{a = 9}\\\\\huge\text{Therefore, your answer is: \boxed{\textsf{a = 9}}}\huge\checkmark[/tex]

[tex]\huge\text{NUMBER 2}[/tex]

[tex]\text{QUESTION: }\rm{\dfrac{v}{2} + 2 = 10}\\\\\rm{\rightarrow \dfrac{1}{2}v + 2 = 10}\\\\\large\textsf{SUBTRACT 2 to BOTH SIDES}\\\\\rm{\dfrac{1}{2}v + 2 - 2 = 10 - 2}\\\\\large\textsf{CANCEL out: 2 - 2 because it gives you 0}\\\large\textsf{KEEP: 10 - 2 because it helps solve for the v-value.}\\\\\text{YOUR NEW EQUATION: }\rm{\dfrac{1}{2}v = 10 - 2}\\\\\text{SIMPLIFY IT!}\\\\\rm{\dfrac{1}{2}v = 8}\\\\\large\textsf{MULTIPLY 2 to BOTH SIDES}\\\\\rm{2\times \dfrac{1}{2}v = 2\times8}[/tex]

[tex]\large\textsf{CANCEL out: }\mathsf{2\times\dfrac{1}{2}}\large\textsf{ because it gives you 1}\\\large\textsf{KEEP: }\mathsf{2\times8}\large\textsf{ because it helps solve for the v-value}\\\\\text{YOUR NEW EQUATION: }\rm{v = 2\times8}\\\\\large\textsf{SIMPLIFY IT!}\\\\\rm{v = 16}\\\\\huge\text{Therefore, your answer is: \boxed{\textsf{v = 16}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]