The pressure on 200 mL of a gas is reduced from 80 kPa to 40 kPa. The final volume is Page
A)400 mL
B)40 mL
C)16 mL
D)100 mL

Answer:

the effect on energy is due to the force applied to the frisbee to throw it back in the tree.

Explanation:

Answer:

yes its c

Explanation:

took it already

Answer:

PE=mgh

M= Mass (kg)

G= Gravitational field strength (N/kg)

H= Hight (m)

PE= Gravitational Potential Energy (J)

Explanation:

Gravitational Potential Energy is the energy stored in a object due to its position above the Earth's surface.

The potential energy of the ball is 29.4 joules

The parameters given are;

mass= 3 kg

height= 1 meter

g= 9.8 m/s²

P.E= mgh

= 3 × 9.8 × 1

= 29.4

Hence the potential energy is 29.4 joules

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Answer:

I believe its a and c but my notes are all kinds of messed up so im sorry if its wrong

Explanation:

None of the  regions can the gravitational field strength due to the two planets be zero.

What is gravitational field?

A gravitational field is a model used in physics to explain the effects that a large thing has on the area surrounding it, exerting a force on smaller, less massive bodies. Consequently, a gravitational field, which is measured in newtons per kilogram, is employed to describe gravitational processes.

Field due to given masses can not be zero in the given region they do not cancel each other.

None of the  regions can the gravitational field strength due to the two planets be zero.

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Answer:

160 watts.

Explanation:

Remark

Power = Work / Time

Work = F * d

Note: Since he is running up stairs he is doing work against gravity.

Givens

Formula

Solution

Explanation:

The diameter of a record, d = 0.3 cm

Radius, r = 0.15 cm

It rotates 33.5 times per minute.

(a) Frequency, f = 33.5 rotation/minute

= (33.5/60) rotation/second

= 0.55 rotation/second

(b) Time period,

T = 1/f

So,

[tex]T=\dfrac{1}{0.55}\\\\T=1.81\ s[/tex]

(c) Linear speed of a point on its rim,

[tex]v=r\omega\\\\v=0.15\times 10^{-2}\times 2\pi \times 0.55\\\\v=5.18\times 10^{-3}\ m/s[/tex]

(d) Centripetal acceleration,

[tex]a=\dfrac{v^2}{r}\\\\a=\dfrac{(5.18\times 10^{-3})^2}{0.15\times 10^{-2}}\\\\a=0.017\ m/s^2[/tex]

Hence, this is the required solution.

Answer:

25.1

Explanation:

Answer:

Sledgehammer A has more momentum

Explanation:

Given:

Mass of Sledgehammer A = 3 Kg

Swing speed = 1.5 m/s

Mass of Sledgehammer B = 4 Kg

Swing speed = 0.9 m/s

Find:

More momentum

Computation:

Momentum = mv

Momentum sledgehammer A = 3 x 1.5

Momentum sledgehammer A = 4.5 kg⋅m/s

Momentum sledgehammer B = 4 x 0.9

Momentum sledgehammer B = 3.6 kg⋅m/s

Sledgehammer A has more momentum

Answer:

(C) Either no magnetic field exists or the particle is moving parallel to B.

Explanation:

31kg

Explanation:

F = ma

m = F/a

m = 744N/24m/s^2

m = 31kg

(*Newton's Second Law*)

Answer:

The answer is B: microwaves, visible light, X-rays, gamma rays

Explanation:

I had the same question and I got option B as the correct answer.

The waves arranged in their order of increasing frequency will be

Generally, frequency is the numeral of occurrences of a repeating event per unit of duration.

Therefore, gamma rays, microwaves, visible light, and X-rays  will be arranged in their order of  increasing frequency

In conclusion, The order is given as folllows

microwaves, Visible light, X-rays, and Gamma rays.

Option B is correct

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Answer:

Explanation:

Suppose m₂ is greater than m₁ and it is going down . m₁ will be going up.

Let tension in string be T₁ and T₂  . Let common acceleration of system be a

For motion of m₁

T₁-m₁g = m₁a ----- (1)

For motion of m₂

m₂g- T₂ = m₂a ------- (2)

For motion of pulley

(T₂-T₁ )R represents net torque

(T₂-T₁ )R = I x α where I is moment of inertia of disc and α is angular acceleration of disc

(T₂-T₁ )R = 1/2 M R² x a / R

(T₂-T₁ ) = M a /2

Adding (1) and (2)

(m₂-m₁)g = (m₂+m₁)a + (T₂-T₁ )

(m₂-m₁)g = (m₂+m₁)a + Ma/2

(m₂-m₁)g = (m₂+m₁+ 0.5M)a

a = (m₂-m₁)g / ( (m₂+m₁+ 0.5M)

The acceleration of the masses is [tex]\dfrac{g(m_2+m_1)}{(m_2-m_1-0.5M)}[/tex].

Given to us

Masses = m₁, m₂

The radius of the pulley = R

Mass of the pulley = M

Assumption

We know the acceleration due to gravity is denoted by g,

[tex]T_1 = m_1(a+g)[/tex]......... equation 1

[tex]T_2 = m_2(a-g)[/tex]......... equation 2

The inertia of the pulley,  [tex]I = \dfrac{1}{2}MR^2[/tex]

Acceleration of the pulley, [tex]a = {\alpha }\times {R}[/tex]

[tex](T_2-T_1)R = I \times \alpha \\\\[/tex]

Substitute the values we get,

[tex][m_2(a-g)-m_1(a+g)]R = \dfrac{1}{2} MR^2 \times \dfrac{a}{R}\\\\[/tex]

[tex][m_2a-m_2g-m_1a-m_1g]R= \dfrac{1}{2} MR \times a[/tex]

[tex]m_2a-m_1a-m_2g-m_1g= \dfrac{1}{2} M \times a[/tex]

[tex]a(m_2-m_1)-g(m_2+m_1)= 0.5M \times a[/tex]

[tex]a(m_2-m_1)-0.5Ma=g(m_2+m_1)\\\\a(m_2-m_1-0.5M) = g(m_2+m_1)\\\\a = \dfrac{g(m_2+m_1)}{(m_2-m_1-0.5M)}[/tex]

Hence, the acceleration of the masses is [tex]\dfrac{g(m_2+m_1)}{(m_2-m_1-0.5M)}[/tex].

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Answer:

B = 5.23 T

Explanation:

Given that,

Electric field, E = 550 V/m

The speed of the proton, v = 105 m/s

We need to find the magnitude of the magnetic field such that the beam of protons continues along its straight-line trajectory.

To move in a straight line, the magnitude of the electric force from the field and the magnetic field must be equal i.e.

[tex]qE=qvB\\\\B=\dfrac{E}{v}\\\\B=\dfrac{550}{105}\\\\B=5.23\ T[/tex]

So, the magnitude of the magnetic field is equal to 5.23 T.

Explanation:

W=F×s

w=20N×6m=120J

W=120J

Answer:

the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²

Explanation:

Given the data in the question;

To determine the maximum intensity of an electromagnetic wave, we use the formula;

[tex]I[/tex] = [tex]\frac{1}{2}[/tex]ε₀cE[tex]_{max[/tex]²

where ε₀ is permittivity of free space ( 8.85 × 10⁻¹² C²/N.m² )

c is the speed of light ( 3 × 10⁸ m/s )

E[tex]_{max[/tex] is the maximum magnitude of the electric field

first we calculate the maximum magnitude of the electric field ( E[tex]_{max[/tex]  )

E[tex]_{max[/tex] = 350/f kV/m

given that frequency of 60 Hz, we substitute

E[tex]_{max[/tex] = 350/60 kV/m

E[tex]_{max[/tex] = 5.83333 kV/m

E[tex]_{max[/tex] = 5.83333 kV/m × ( [tex]\frac{1000 V/m}{1 kV/m}[/tex] )

E[tex]_{max[/tex] = 5833.33 N/C

so we substitute all our values into the formula for  intensity of an electromagnetic wave;

[tex]I[/tex] = [tex]\frac{1}{2}[/tex]ε₀cE[tex]_{max[/tex]²

[tex]I[/tex] = [tex]\frac{1}{2}[/tex] × ( 8.85 × 10⁻¹² C²/N.m² ) × ( 3 × 10⁸ m/s ) × ( 5833.33 N/C )²

[tex]I[/tex] = 45 × 10³ W/m²

[tex]I[/tex] = 45 × 10³ W/m² × ( [tex]\frac{1 kW/m^2}{10^3W/m^2}[/tex] )

[tex]I[/tex] = 45 kW/m²

Therefore, the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²

Answer:

1×10⁶ J/Kg

Explanation:

From the question given above, the following data were obtained:

Mass (m) of metal = 2 Kg

Heat (Q) = 2 MJ

Latent heat of Fusion (Hf) =?

Next, we shall convert 2 MJ to J. This can be obtained as follow:

1 MJ = 1×10⁶ J

Therefore,

2 MJ = 2 MJ × 1×10⁶ J / 1 MJ

2 MJ = 2×10⁶ J

Finally, we shall determine the latent heat of fusion. This can be obtained as follow:

Mass (m) of metal = 2 Kg

Heat (Q) = 2×10⁶ J

Latent heat of Fusion (Hf) =?

Q = m•Hf

2×10⁶ = 2 × Hf

Divide both side by 2

Hf = 2×10⁶ / 2

Hf = 1×10⁶ J/Kg

Thus, the latent heat of fusion for the metal is 1×10⁶ J/Kg

Answer:

hello your question has some missing parts below are the missing parts

A Circular, 10-turn coil has a radius of 10.7 cm and is oriented with its plane perpendicular to a 0.2-T magnetic field.

answer : 1 volt

Explanation:

Determine the Average induced EMF during this mishap

A' = A/2  ( for a semi circle )

where A = [tex]\frac{\pi r^2}{2}[/tex]

To determine the Average induced EMF apply the relation below

| E | =  η * [tex]\frac{\beta A}{T}[/tex]   ----- ( 1 )

Replace A in equation 1 with  A = [tex]\frac{\pi r^2}{2}[/tex]

hence equation becomes : | E | =  η * βπr^2 / 2T'

where : T' = 0.0365 ,  β = 0.2 , η = 10 , r = 0.107

∴| E |  = 0.999 ≈ 1volts

Answer:

A mass of 10 kilograms lifted 10 meters in 5 seconds.

Explanation:

Power can be defined as the energy required to do work per unit time.

Mathematically, it is given by the formula;

[tex] Power = \frac {Energy}{time} [/tex]

But Energy = mgh

Substituting into the equation, we have

[tex] Power = \frac {mgh}{time} [/tex]

Given the following data;

Mass = 10kg

Height = 10m

Time = 5 seconds

We know that acceleration due to gravity is equal to 9.8 m/s²

[tex] Power = \frac {10*9.8*10}{5} = 490 Watts [/tex]

Hence, a mass of 10 kilograms lifted 10 meters in 5 seconds would produce the most power.

The greatest electric field between them is Option B.

An electric field is the physical subject that surrounds electrically charged particles and exerts a force on all other charged debris inside the area, either attracting or repelling them. It also refers back to the bodily field of a machine of charged particles.

Reasoning:-

Electric field = Kq/r²

Since the distance is inversely proportional to the square root of the distance between them. therefore decreasing the distance electric field will be the greatest. Hence Option B.

The electrical field is defined mathematically as a vector discipline that can be related to each point in space, the force in step with unit charge exerted on a fine take a look at the price at rest at that factor. the electric field is generated by the electrical rate or through time-varying magnetic fields. electric fields provide us with the pushing force we need to set off the contemporary float.

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Answer:

D.The striking foot pushes backward against the ground. The friction with the ground provides an equal and opposite force forward

Answer:

d

Explanation:

Answer:

The magnitude of the lift generated by the wings of the airplane is 130,340 N.

Explanation:

Given;

mass of the airplane, m = 13,300 kg

speed of the airplane, v = 560 km/h = 155.56 m/s

The magnitude of the lift generated by the wings of the airplane is calculated as;

[tex]F_l = mg\\\\where;\\\\F_l \ is \ the \ magnitude \ of \ the \ lift \ generated\\g \ is \ acceleration \ due \ to \ gravity = 9.8 \ m/s^2\\\\F_l = 13,300 \times \ 9.8\\\\F_l = 130,340 \ N[/tex]

Therefore, the magnitude of the lift generated by the wings of the airplane is 130,340 N.

Answer:

C?

Explanation:

Yep,It's C all right.

Answer:

Yep,It's C all right.

Explanation:

Answer:

Explanation:

In order to answer this question, we simply have to refer to the laws of the equations of gravitational mechanics.

The equation given by Newton tells us that  

[tex]F = \frac{Gm_{1} m_{2} }{r^{2} }[/tex]

In the case where we compare a specific place where the Force of Gravity is greater or lesser, we focus on the term assigned to the Planet's Radius.

In the case of [tex]G, m_{1} ,m_{2}[/tex], we understand that they are constant.

We can easily notice that the more the Radius (Height seen from a viewer on the ground), the lower the force will be.

In other words, the smaller the radius in which the measurement is made with respect to the center of the earth, the greater the gravitational force.

In that order of ideas the smallest radio has South Pole, which is about 6356 km from the center of the Earth on the Equator line

Hello,

✔ We have: KE = PE (potential energy)

PE = m x g x h

The potential energy that the pebble of mass 1 has is called PE1 and the potential energy that the pebble of mass 2 has is called PE2  

PE1 = PE2 ⇔ PE1/PE2 = 1

[tex]\frac{m_1\times g\times h}{m_2\times g\times 4h} = 1 \\ \\ \frac{m_1}{m_2\times 4} = 1 \\ \\ \frac{m_1}{m_2} = 4[/tex]

The mass m1 is therefore 4 times greater than that of the stone of mass m2.