The perimeter of the rectangle below is 94 units. Find the length of side WX.
Write your answer without variables.

The Perimeter Of The Rectangle Below Is 94 Units. Find The Length Of Side WX.Write Your Answer Without

Answers

Answer 1

Answer:

24units

Step-by-step explanation:

2(4y + 3) + 2(5y - 1) = 94

18y + 4 = 94

y = 5

WX = 5y - 1 = 5(5) - 1 = 24units

Answer 2

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First we need to find the value of y .

[tex]Perimeter = 2 \times ( \: (4y + 3) + (5y - 1) \: ) \\ [/tex]

[tex]Perimeter = 2 \times (9y + 2)[/tex]

[tex]Perimeter = 18y + 4[/tex]

Question told us that perimeter is 94 ,

Thus :

[tex]94 = 18y + 4[/tex]

[tex]18y + 4 = 94[/tex]

Subtract sides 4

[tex]18y + 4 - 4 = 94 - 4[/tex]

[tex]18y = 90[/tex]

Divide sides by 18

[tex] \frac{18y}{18} = \frac{90}{18} \\ [/tex]

[tex]y = 5[/tex]

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The face sides in the rectangular are same.

Thus :

[tex]VY = WX[/tex]

So ;

[tex] WX = 5y - 1[/tex]

[tex]WX = 5(5) - 1[/tex]

[tex]WX = 25 - 1[/tex]

[tex]WX = 24[/tex]

Done...

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A curve is such that (dy)/(dx) = 12/(2x + 1) ^ 2 and P(1, 5) is a point on the curve . (i) The normal to the curve at P crosses the x-axis at Q. Find the coordinates of Q (ii) Find the equation of the curve. (iii) A point is moving along the curve in such a way that the x-coordinate is increasing at a constant rate of 0.3 units per second. Find the rate of increase of the y-coordinate when x=1

Answers

(i) The coordinates of the point Q is [tex](x, y) = (21, 0)[/tex].

(ii) The equation of the curve is [tex]y = 6\cdot \ln (2\cdot x + 1)-1.592[/tex].

(iii) The rate of increase of the y-coordinate is 1.2 units per second.

(i) By analytical geometry, we know that the slope of a line normal of a curve ([tex]m_{\perp}[/tex]) by the following expression:

[tex]m_{\perp} = - \frac{1}{\frac{dy}{dx} }[/tex] (1)

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[tex]\frac{dy}{dx} = \frac{12}{2\cdot (1)+1}[/tex]

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[tex]m_{\perp} = -\frac{1}{4}[/tex]

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[tex]m_{\perp} = \frac{y_{Q}-y_{P}}{x_{Q}-x_{P}}[/tex] (2)

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[tex]x_{P}[/tex], [tex]x_{Q}[/tex] - x-coordinates of points P and Q. [tex]y_{P}, y_{Q}[/tex] - y-coordinates of points P and Q.

If we know that [tex](x_{P}, y_{P}) = (1, 5)[/tex], [tex](x_{Q}, y_{Q}) = (x, 0)[/tex] and [tex]m_{\perp} = -\frac{1}{4}[/tex], then the remaining coordinate of point Q is:

[tex]-\frac{1}{4} = \frac{0-5}{x-1}[/tex]

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[tex]-\frac{1}{4}\cdot x +\frac{1}{4} = -5[/tex]

[tex]\frac{1}{4}\cdot x = \frac{21}{4}[/tex]

[tex]x = 21[/tex]

The coordinates of the point Q is [tex](x, y) = (21, 0)[/tex].

(ii) The equation of the curve is derived by separating the variables and integrating the resulting expression:

[tex]dy = \frac{12}{2\cdot x + 1}\,dx[/tex]

[tex]\int\, dy = 6\int {\frac{2\,dx}{2\cdot x + 1} }[/tex]

[tex]\int \, dy = 6\int {\frac{du}{u} }[/tex]

[tex]y = 6\cdot \ln u[/tex]

[tex]y = 6\cdot \ln (2\cdot x + 1)+C[/tex]

And the integration constant is found for [tex](x,y) = (1, 5)[/tex]:

[tex]5 = 6\cdot \ln(2\cdot 1 + 1) + C[/tex]

[tex]C = -1.592[/tex]

The equation of the curve is [tex]y = 6\cdot \ln (2\cdot x + 1)-1.592[/tex].

(iii) The rate of increase of the y-coordinate by using the differential equation presented in statement and the definition of rate of change:

[tex]\frac{dy}{dt} = \left(\frac{12}{2\cdot x +1}\right)\cdot \frac{dx}{dt}[/tex] (3)

If we know that [tex]\frac{dx}{dt} = 0.3[/tex] and [tex]x = 1[/tex], then the rate of increase of the y-coordinate is:

[tex]\frac{dy}{dt} = \left[\frac{12}{2\cdot (1)+1} \right]\cdot (0.3)[/tex]

[tex]\frac{dy}{dt} = 1.2[/tex]

The rate of increase of the y-coordinate is 1.2 units per second.

To learn more on differential equations, we kindly invite to check this verified question: https://brainly.com/question/25731911

i). The coordinates of Q is equal to:

[tex](x,y) = (21, 0)[/tex]

ii). The equation of the curve is:

[tex]y = 6. In(2.x + 1) - 1.592[/tex]

iii). The rate of increase for y-coordinate when x = 1:

[tex]1.2 units[/tex] per second

i). Using analytical geometry,

[tex]xp[/tex] and [tex]xq[/tex] are the P and Q's x-coordinates.

[tex]yp[/tex] and [tex]yq[/tex] are the P and Q's y-coordinates.

Since ([tex]xp[/tex], [tex]yp[/tex]) = (1,5) and ( [tex]xq[/tex], [tex]yq[/tex]) = [tex](x, 0)[/tex] and m⊥ = - 1/4, the left coordinate of Q's point:-

-1/4 = (0-5)/(x - 1)

∵[tex]x = 21[/tex]

Thus, the coordinates of y = (21, 0)

ii). Through isolating the variables and employing integration:-

[tex]dy = \frac{12}{(2.x + 1)} dx[/tex]

by integration and integration constant (1,5), the equation is:

[tex]y = 6. In(2.x + 1) - 1.592[/tex]

iii). The rate of increase for y-coordinate:

[tex]dy/dt[/tex] = [tex]\frac{(12)}{(2.1 + 1)} .0.3[/tex]

∵ [tex]dy/dt[/tex] [tex]= 1.2[/tex]

Thus, the rate of increase for y-coordinate when x = 1 is 1.2 units per second.

Learn more about "Co-ordinates" here:

brainly.com/question/21902081

Can someone please help me with this proof?!

Given: AC and BD bis, each other.

Prove: ABCD is a parallelogram

Answers

Answer:

because AC and BD bis => AX = XC; BX = XD

ΔAXD ≅ ΔCXB (SAS) because: AX = CX

                                                    DX = BX

                                                    m∠AXD = m∠BXC ( 2 opposing angles)

because ΔAXD ≅ ΔCXB (SAS)

=> AD = BC and m∠DAX = m∠BCX

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Step-by-step explanation:

Where in the real-world is the Pascal Triangle used? Provide an example.

Answers

Answer:

There are many colored pebbles to choose from out of the driveway. Karmin could not decide what one he wanted for his school project. So he took the best looking 4 from the driveway. 3 of them are now his backups.

You use this tequnic (sorry I can't spell) almost everyday. When ever you think about how much of something to take, you could be using this Pascal Triangle.

I hope this helped.

pleaseeee hurryyy i needd helppp
How many solutions are there for this equation? Why?
2(m+2)=12−6m
Select the option that correctly answers both questions.
a. There is one solution, because the coefficients of the variables on both sides of the equation are the same.
b. There are no solutions, because the coefficients of the variables on both sides of the equation are different.
c .There is one solution, because the coefficients of the variables on both sides of the equation are different.
d. There are no solutions, because the coefficients of the variables on both sides of the equation are the same.

Answers

Answer:

C. There is one solution, because the coefficients of the variables on both sides of the equation are different.

Step-by-step explanation:

The solution is m = 1

~theLocoCoco

of
be
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Answer: 18

Step-by-step explanation:

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