the partner who can lose only what he or she has invested in business is the

Answer:

max shear = R = V = 15 kN

Explanation:

given:

load = 10 kn/m

span = 3m

max shear = R = V = wL / 2

max shear = R = V = (10 * 3) / 2

max shear = R = V = 15 kN

Q:What velocity does the boy attain if he throws the bricks one at a time?

Answer:Linear velocity since it moves back and firth and does not rotate like angular velocity.

Answer:

Enthalpy is a function of pressure hence normalized enthalpy departure values will approach zero with reduced pressure approaching zero

Explanation:

On the generalized enthalpy departure chart, the normalized enthalpy departure values seem to approach zero as the reduced pressure PR approaches zero. this is because enthalpy is a function of pressure therefore as the Pressure is reducing towards the zero value, the gas associated with the pressure tends to behave more like an Ideal gas.

For an Ideal gas the Normalized enthalpy departure value will be approaching the zero value.

Answer:

(a) The value of the resistance is 3.431 Ω

(b) The value of the inductance is 0.0264 H

Explanation:

Given;

frequency of the source, f = 60 Hz

rms voltage, V-rms = 220 V

real power, Pr = 1500 W

apparent power, Pa = 4600 VA

(a). Determine the value of the resistance

[tex]P_r = I_{rms}^2R[/tex]

where;

R is resistance

[tex]I_{rms} = \frac{Apparent \ Power}{V_{rms}} \\\\I_{rms} = \frac{P_a}{V_{rms}}\\\\I_{rms}= \frac{4600}{220} \\\\I_{rms}= 20.91 \ A[/tex]

Resistance is calculated as;

[tex]R = \frac{P_r}{I_{rms}^2} \\\\R = \frac{1500}{(20.91)^2} \\\\R = 3.431 \ ohms[/tex]

(b). Determine the value of the inductance.

[tex]Q_L = I_{rms}^2 X_L[/tex]

where;

[tex]Q_L[/tex] is reactive power

[tex]X_L[/tex] is inductive reactance

[tex]Apparent \ power = \sqrt{Q_L^2 + P_r^2} \\\\P_a^2 = Q_L^2 + P_r^2\\\\Q_L^2 = P_a^2 - P_r^2\\\\Q_L^2 = 4600^2 - 1500^2\\\\Q_L^2 = 18910000\\\\Q_L = \sqrt{18910000}\\\\Q_L = 4348.56 \ VA[/tex]

inductive reactance is calculated as;

[tex]X_L = \frac{Q_L}{I_{rms}^2} \\\\X_L = \frac{4348.56}{(20.91)^2} \\\\X_L = 9.95 \ ohms[/tex]

inductance is calculated as;

[tex]X_L = \omega L\\\\X_L = 2\pi f L\\\\L = \frac{X_L}{2\pi f} \\\\L = \frac{9.95}{2\pi *60} \\\\L = 0.0264 \ H\\\\L = 26.4 \ mH[/tex]

Answer:

Explanation:

Known: flow rate and inlet temperature for automobile radiator.

Overall heat transfer coefficient.

Find: Area required to achieve a prescribed outlet temperature.

Assumptions: (1) Negligible heat loss to surroundings and kinetic and

potential energy changes, (2) Constant properties.

Analysis: The required heat transfer rate is

q = (m c)h (T h,i - T h,o) = 0.05 kg/s (4209J / kg.K) 70K = 14,732 W

Using the ε-NTU method,

Cmin = Ch = 210.45 W / K

Cmax = Cc = 755.25W / K

Hence, Cmin/Cmx(Th,i - Th,o) = 210.45W / K(100K) = 21,045W

and

ε=q/qmax = 14,732W / 21,045W = 0.700

NTU≅1.5, hence

A=NTU(cmin / U) = 1.5 x 210.45W / K(200W) / m² .K) = 1.58m²

1. the air outlet is..

Tc,o = Tc,i + q / Cc = 300K + (14,732W / 755.25W / K) = 319.5K

2. using the LMTD approach ΔTlm = 51.2 K,, R=0.279 and P=0.7

hence F≅0.95 and

A = q/FUΔTlm = (14,732W) / [0.95(200W / m².K) 51.2K] = 1.51m²

Answer:

a) 0.42

b) Independent

c) 30%

d) 0.88

Explanation:

Person chooses Chicken's item : 70% = 0.7

Person chooses fish's item : 30% = 0.3

Visits in which he orders Afghani Chicken = 60% = 0.6

a) Probability that he goes to KARIM and orders Afghani Chicken:

P = 0.7 * 0.6 = 0.42

b) Two events are said to be independent when occurrence of one event does not affect the probability of the other event's occurrence. Here the person orders Afghani Chicken regardless of where he visits so the events are independent.

c)  P = 0.30 because he orders Afghani Chicken regardless of where he visits.

d)  Let A be the probability that he goes to KARIM:

P(A) = 0.7 * ( 1 - 0.6 ) = 0.28

Let A be the probability that he orders Afghani Chicken:

P(B) =  0.3 * 0.6 = 0.18

Let C be the probability that he goes to KARIM and orders Afghani chicken:

= 0.7 * 0.6 = 0.42

So probability that he goes to KARIM or orders Afghani Chicken or both:

P(A) + P(B) + P(C) = 0.28 + 0.18 + 0.42 = 0.88

Answer:

An improper integral is a definite integral that has either or both limits infinite or an integrand that approaches infinity at one or more points in the range of integration

Explanation:

Answer:

The discharge temperature is 259.82 K

Explanation:

In this question, we are concerned with calculating the discharge temperature

Please check attachment for complete solution

Answer:

A.) 0 > K > 9.6

B.) K = 9.6

C.) w = +/- 2 sqrt (3)

Explanation:

G(s)= K(s+4)/s(s+1.2)(s+2)

For a closed loop stability, we can analyse by using Routh - Horwitz analysis.

To make the pole completely imaginary, K must be equal to 9.6 Because for oscillations. Whereas, one pair of pole must lie at the imaginary axis.

Please find the attached files for the solution

Answer + Explanation:

For computing the displacement at point B and D we need to determine the following calculations

Pnet = Pc + Pe + Pb

Pnet = 250 + 350 - 50

Pnet = 550 N

Now the deflection for bar AB is

           PLab

δab = -------------

            ae

     550 * 500

= -------------------------

     6,000 * 200 x 10³

= 2.292 x 10⁻⁴mm

Now for bar BC it is

           PLbc

δbc = ------------

             ae

  (550 + 50) * 250

=  ----------------------

   5,000 * 200 x 10³

= 1.5 x 10⁻⁴mm

And for bar CD it is

           PLcd

δcd = ------------

             ae

  (550 - 250 + 50) * 250

=  --------------------------------

   5,000 * 200 x 10³

= 0.875 x 10⁻⁴mm

Now the displacement is as follows

For B = 2.292 × 10⁻⁴ mm

For D = 4.667 × 10⁻⁴ mm

= 2.292 × 10⁻⁴ + 1.5 × 10⁻⁴ + 0.875 × 10⁻⁴

= 4.667 × 10⁻⁴ mm

We simply applied the above formulas for determining the  displacements at points B, D and the same is to be considered

Answer:

no need for that

Explanation:

they are not the same at all

Answer:

hello your question is incomplete here is the complete question

. “ABC construction Inc.” company becomes the lowest in the bed process to get a $21 million construction project for “Northern Inc.”. Now “ABC construction Inc.” planning to make a formal contract agreement with the “Northern Inc.”. What are the main elements of this agreement to consider it as a legal contract?

Answer : elements of the agreement

Explanation:

Offer : an offer is the beginning element for any valid agreement to be started or reached between two or more bodies. ABC construction would have to make an offer first for the agreement to be valid

Acceptance: This is part where by the company "Northern Inc" after receiving the offer from ABC construction Inc would have to consent to the approval of the offer made.

capacity : This the element of the agreement that helps to ensure that both parties have the legal and financial backings to embark on the contract agreement .

certainty : This element ensures that both parties understands the terms and conditions attached to the agreement and this to ensure that there are no bogus conditions

Consideration : This is a very vital element because the both parties have to give something in return while going into a valid agreement

Intention to create legal relation : Legal relations are applied to contract agreements whereby both parties want the contract agreement to b legally enforced and this is important in order to prevent contract breach by any party involved in the agreement

Answer:

Hello the needed relation is missing below is the required relation

[tex]X_{p} = \frac{x_{s} }{1+x_{s} }[/tex]   composition : propane = 0.70, butane = 0.3

Answer : ≈ 5.75 hrs

Explanation:

Applying the data given in regards to the material balance

Butane balance input into the still = 5 mole feed/hr | 0.30 mol butane/molfeed

since the total volume of the liquid in the still is constant

The output from the still is = 5mol condensed/hr | x[tex]_{p}[/tex] mol butane/mol condensed

unsteady state equation = [tex]\frac{dx_{s} }{dt}[/tex] = 0.15 - [tex]0.5X_{p}[/tex]

note : to reduce the equation a single dependent variable we have to substitute for [tex]x_{p}[/tex]

[tex]\frac{dx_{s} }{dt}[/tex] [tex]= 0.15 + x_{s} / 1 + (0.5)x_{s}[/tex]

In order to find the time it will take for X to change from 0.3 to 0.35

integrate the above equation using the limits : t = 0, x[tex]_{s}[/tex] = 0.3 and t = Ф,

x[tex]_{s} = 0.35[/tex]

= [tex][ - (x_{s} /0.35 - (1/(0.35)^2)* In(0.15 - 0.35x_{s} ) ]_{0.3} ^{0.35}[/tex]

hence t = Ф ≈ 5.75 hrs

The red and green lights are sidelights that are positioned on the port side (red) (left as facing the bow) and starboard (green) (right as facing the bow) side of the boat. Various white lights are required depending on the size of the boat, but generally, a white masthead light and stern light are required. See the US Coast Guard site in the link below for more specific information.

Hope this helps

Answer:

24 hours

Explanation:

you must exchange insurance details after a collision if someone is injured. Otherwise you must report the collision to us as soon as possible (and no later than 24 hours). Although you must report such a collision straight away you should always seek medical help in the first instance.

Answer:

a. True

Explanation:

Apply the principle of conservation of mass.

and also the expression for the steady flow energy equation.

kinetic and potential energy effects can be neglected.

The given statement by the inventor who is claiming the development of a device that requires no work or heat transfer input yet is able to produce hot and cold air streams at a steady state is definitely false.

Heat transfer may be characterized as a type of process which involves the migration of heat from one object or component to another by numerous mechanisms like conduction, convection, and/or radiation.

The process of heat transfer may occur where there is a temperature difference between two objects exist. It significantly utilizes the mechanism of exchanging thermal energy between two or more physical systems.

According to the concept of physics, no object or thing has the ability to perform its function without the utilization of any source of heat or energy. Then, how it is possible for that device to produce hot and cold air streams at a steady state.

Therefore, the given statement by the inventor is absolutely false.

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Answer:

The normal stress is 0.7821 MPa

Explanation:

The external diameter D = 160 mm

The thickness t = 3.8 mm = 3.8 x 10^-3 m

gauge pressure P = 78 kPa = 78 x 10^3 Pa

The maximum shear stress τmax = ?

The external radius of the shell from the external surface R = D/2 = 160/2 = 80 mm

The internal radius of the shell r = R - t

==> 80 - 3.8 = 76.2 mm

Therefore the internal diameter d = 2r = 2 x 76.2 = 152.4 mm

==> d = 152.4 x 10^-3 m

The normal stress σ = [tex]\frac{Pd}{4t}[/tex] = [tex]\frac{78*10^{3}*152.4*10^{-3} }{4*3.8*10^{-3} }[/tex] = 782052.63 Pa

==>  σ = 0.7821 MPa

Answer:

Voltage across resistor = 2 v

Explanation:

Given data

pulse height = 2 v

pulse width = 4s

calculate voltage across resistor ( the free hand sketch attached below explains more )

pulse height is also = amplitude of voltage ) = 2v

The voltage across the resistor = 2v  Since  the voltage from the source of the circuit is equal to the amplitude voltage in the circuit ( assuming no loss of voltage )

also the graphical representation of the problem is attached below

Answer:

Maneuvering speed.

Explanation:

The speed above which an airplane will experience structural damage when a load is applied, instead of stalling, is called the maneuvering speed and varies with weight.

In aeronautical engineering, the maneuvering speed (Va) of an aircraft such as an aeroplane, helicopter, or jet is an airspeed limitation which is mainly selected by an aircraft designer.

Generally, at speeds higher or greater than the manoeuvring speed, aircraft pilots are advised not to attempt a full deflection of any flight control surface because it's capable of resulting in a damage to the structure of an aircraft.

If you're a pilot, to find the maneuvering speed of an aircraft, you should look at the flight manual of the aircraft or on the cockpit placard in the aircraft. The maneuvering speed of an aircraft is a calibrated speed and should not be exceeded by any pilot.

Answer:

1) There are  three (3) PWM generator blocks in LM3S1968 and they are

2)  Two (2) independent  PWM outputs can be generated on an LM3S1968

3) Applications for PWM

4) NVIC in a timer stand for ; Nested Vectored Interrupt Controller

its significance is that it is used to handle  and give priorities to exception and Interrupts

5) The counter/timer derive its time period from  counting the output pulses for one cycle which is the duration over which gate is open

Explanation:

1) There are  three (3) PWM generator blocks in LM3S1968 and they are

2)  Two (2) independent  PWM outputs can be generated on an LM3S1968

3) Applications for PWM

4) NVIC in a timer stand for ; Nested Vectored Interrupt Controller

its significance is that it is used to handle  and give priorities to exception and Interrupts

5) The counter/timer derive its time period from  counting the output pulses for one cycle which is the duration over which gate is open

6) THE WAVEFORM DIAGRAMS IS ATTACHED BELOW

it can be seen  that 50 % rises and goes down at half interval. 75 % goes down at half more of 50% and 25% goes down at half less of 50%

Answer:

from the below explanation...  we can say that, in the series circuit, flowing current remains the same at each part of the circuit. While in parallel circuits, the voltage across two endpoints of the branches is the same as the supplied voltage.

Explanation:

1.

The components in a series circuit are arranged in a single path from one end of supply to another end. However, the multiple components in a parallel circuit are arranged in multiple paths wrt the two end terminals of the battery.

2.

In a series circuit, a common current flows through all the components of the circuit. While in a parallel circuit, a different amount of current flows through each parallel branch of the circuit.

3.

In the series circuit, different voltage exists across each component in the circuit. Whereas in the parallel circuit, the same voltage exists across the multiple components in the circuit.

4.

A fault in one of the components of the series circuit causes hindrance in the operation of a complete circuit. As against fault in a single component in a parallel network do not hinder the functioning of another part of the circuit.

5.

The detection of a fault in case of a series circuit is difficult, but it is quite easy in parallel circuits.

6.

The equivalent resistance in case of a series circuit is always more than the highest value of resistance in the series connection. While the equivalent resistance in the parallel circuit is always less than any of the individual resistances in parallel combination.

Answer: 0.002174

Explanation:

Given that the

Yield strength rho = 450 MPa

Length = 2 m

Elastic modulus E= 207 GPa

According to Hook's law, if the elastic limits is not reached, the elastic modulus is the ratio of elastic strength to the elastic strain ə

E = rho/ə

Make ə the subject of formula

ə = rho/ E

ə = (450 × 10^6) / (207 × 10^9)

ə = 2.174 × 10^-3

Therefore, the engineering strain which depends on engineering stress and elastic modulus is 2.174 × 10^-3

Elastic Strain has no S.I Units.

In this exercise we have to calculate the formula that will be able to determine the length of the cantilevered, like this:

[tex]\sigma_{max}C=\frac{M_{max}C}{I}[/tex]

So to determinated the maximum tensile and compreensive stress due to bending we can describe the formula as:

[tex]\sigma_b = \frac{MC}{I}[/tex]

Where,

So making this formula for the max, we have:

[tex]\sigma_c=\frac{MC}{I} \\\sigma_T=-\sigma_c=-\frac{MC}{I}\\\sigma_{max}=M_{max}\\[/tex]

With all this information we can put the formula as:

[tex]\sigma_{max}C=\frac{M_{max}C}{I}[/tex]

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Answer:

a) The spring constant is 50 lb/ft

b) The man is 26.3 ft close to the ground.

Explanation:

Height of tower is 130 ft

Specification calls for a cable of length 85 ft

the maximum this length stretches is 100 ft when subjected to a load of 750 lb

The extension of the cable is calculated from the formula from Hooke's law

F = kx

where F is the load or force on the cable

k is the spring constant of the cable

x is the extension on the cable

a) The extension on the cable is

x = 100 ft - 85 ft = 15 ft

substituting into the formula above, we'll have

750 = k*15

k = 750/15 = 50 lb/ft

b) for a 185 lb man, jumping down will give an extension gotten as

F = kx

185 = 50*x

x = 185/50 = 3.7 ft

The total length of the cable will be extended to 100 ft + 3.7 ft = 103.7 ft

closeness to the ground = 130 ft - 103.7 ft = 26.3 ft

Answer:

a) This cycle observes the First and Second Laws of Thermodynamics, b) This cycle observes the First and Second Laws of Thermodynamics, c) This cycle does not observe the First Law of Thermodynamics, d) This cycle does not observe the Second Law of Thermodynamics.

Explanation:

The Carnot cycle offers a reliable criterion to determine the maximum theoretical efficiency ([tex]\eta_{th,max}[/tex]) for a power cycle in term of the temperatures of hot and cold reservoirs and expressed in percentage:

[tex]\eta_{th, max} = \left(1-\frac{T_{L}}{T_{H}} \right)\times 100\,\%[/tex]

Where:

[tex]T_{L}[/tex], [tex]T_{H}[/tex] - Temperatures of cold and hot reservoirs, measured in kelvins.

If [tex]T_{L} = 400\,K[/tex] and [tex]T_{H} = 1000\,K[/tex], the maximum theoretical thermal efficiency is:

[tex]\eta_{th, max} = \left(1-\frac{400\,K}{1000\,K} \right)\times 100\,\%[/tex]

[tex]\eta_{th,max} = 60\,\%[/tex]

In addition, the real efficiency of the heat engine is described by the following formula:

[tex]\eta_{th} = \left(1-\frac{Q_{L}}{Q_{H}} \right)\times 100\,\%[/tex]

Where:

[tex]Q_{H}[/tex] - Heat absorbed by the heat engine from hot reservoir, measured in kilojoules.

[tex]Q_{L}[/tex] - Heat released by the heat engine to the cold reservoir, measured in kilojoules.

The following conditions must be observed by all heat engines:

First Law of Thermodynamics

[tex]W = Q_{H}-Q_{L}[/tex]

Second Law of Thermodynamics

[tex]\eta_{th} \leq \eta_{th,max}[/tex]

Now, each cycle is checked:

a) [tex]Q_{H} = 300\,kJ[/tex], [tex]Q_{L} = 140\,kJ[/tex] and [tex]W = 160\,kJ[/tex]

First Law of Thermodynamics

[tex]W = 300\,kJ-140\,kJ[/tex]

[tex]W = 160\,kJ[/tex]

This cycle observes the First Law of Thermodynamics.

Second Law of Thermodynamics

[tex]\eta_{th} = \left(1-\frac{140\,kJ}{300\,kJ} \right)\times 100\,\%[/tex]

[tex]\eta_{th} = 53.333\,\%[/tex]

This cycle observes the Second Law of Thermodynamics.

b) [tex]Q_{H} = 300\,kJ[/tex], [tex]Q_{L} = 120\,kJ[/tex] and [tex]W = 180\,kJ[/tex]

First Law of Thermodynamics

[tex]W = 300\,kJ-120\,kJ[/tex]

[tex]W = 180\,kJ[/tex]

This cycle observes the First Law of Thermodynamics.

Second Law of Thermodynamics

[tex]\eta_{th} = \left(1-\frac{120\,kJ}{300\,kJ} \right)\times 100\,\%[/tex]

[tex]\eta_{th} = 60\,\%[/tex]

This cycle observes the Second Law of Thermodynamics.

c) [tex]Q_{H} = 300\,kJ[/tex], [tex]Q_{L} = 140\,kJ[/tex] and [tex]W = 170\,kJ[/tex]

First Law of Thermodynamics

[tex]W = 300\,kJ-140\,kJ[/tex]

[tex]W = 160\,kJ[/tex]

This cycle does not observe the First Law of Thermodynamics.

Second Law of Thermodynamics

[tex]\eta_{th} = \left(1-\frac{140\,kJ}{300\,kJ} \right)\times 100\,\%[/tex]

[tex]\eta_{th} = 53.333\,\%[/tex]

This cycle observes the Second Law of Thermodynamics.

d) [tex]Q_{H} = 300\,kJ[/tex], [tex]Q_{L} = 200\,kJ[/tex] and [tex]W = 100\,kJ[/tex]

First Law of Thermodynamics

[tex]W = 300\,kJ-100\,kJ[/tex]

[tex]W = 200\,kJ[/tex]

This cycle observes the First Law of Thermodynamics.

Second Law of Thermodynamics

[tex]\eta_{th} = \left(1-\frac{100\,kJ}{300\,kJ} \right)\times 100\,\%[/tex]

[tex]\eta_{th} = 66.667\,\%[/tex]

This cycle does not observe the Second Law of Thermodynamics.

Based on the first parameters, the power cycle obeys both the First and Second Law of Thermodynamics.

Given the following data:

In order to verify a power cycle obeys the first and second laws of thermodynamics, we would use the Carnot cycle.

Mathematically, the maximum theoretical efficiency for a power cycle in terms of the temperature is given by this formula:

[tex]\eta_{th, max}=(1-\frac{T_c}{T_h} ) \times 100[/tex]

Where:

Substituting the given parameters into the formula, we have;

[tex]\eta_{th, max}=(1-\frac{400}{1000} ) \times 100\\\\\eta_{th, max}=60\%[/tex]

Similarly, the real efficiency of a power cycle, we have:

[tex]\eta_{th}=(1-\frac{Q_c}{Q_h} ) \times 100[/tex]

According to the First Law of Thermodynamics, the following condition must be met:

[tex]W_{cycle}=Q_h-Q_c[/tex]

According to the Second Law of Thermodynamics, the following condition must be met:

[tex]\eta_{th }\leq \eta_{th, max }[/tex]

Next, we would determine whether or not each obeys the first and second laws of thermodynamics:

When [tex]Q_h=300\; kJ, \;W_{(cycle)}=160kJ, \;and\;Q_c=140\; kJ[/tex]

For the First Law:

[tex]W_{cycle}=Q_h-Q_c\\\\160=300-140\\\\160=160[/tex]

Therefore, the power cycle obeys the First Law of Thermodynamics.

For the Second Law:

[tex]\eta_{th}=(1-\frac{Q_c}{Q_h} ) \times 100\\\\\eta_{th}=(1-\frac{140}{300} ) \times 100\\\\\eta_{th}=53.33\%\\\\\eta_{th }\leq \eta_{th, max } =53.33\%\leq 60\%[/tex]

Therefore, the power cycle obeys the Second Law of Thermodynamics.

When [tex]Q_h=300\; kJ, \;W_{(cycle)}=180kJ, \;and\;Q_c=120\; kJ[/tex]

For the First Law:

[tex]W_{cycle}=Q_h-Q_c\\\\180=300-120\\\\180=180[/tex]

Therefore, the power cycle obeys the First Law of Thermodynamics.

For the Second Law:

[tex]\eta_{th}=(1-\frac{Q_c}{Q_h} ) \times 100\\\\\eta_{th}=(1-\frac{120}{300} ) \times 100\\\\\eta_{th}=60\%\\\\\eta_{th }\leq \eta_{th, max } =60\%\leq 60\%[/tex]

Therefore, the power cycle obeys the Second Law of Thermodynamics.

When [tex]Q_h=300\; kJ, \;W_{(cycle)}=170kJ, \;and\;Q_c=140\; kJ[/tex]

For the First Law:

[tex]W_{cycle}=Q_h-Q_c\\\\170=300-140\\\\170\neq 160[/tex]

Therefore, the power cycle doesn't obey the First Law of Thermodynamics.

For the Second Law:

[tex]\eta_{th}=(1-\frac{Q_c}{Q_h} ) \times 100\\\\\eta_{th}=(1-\frac{140}{300} ) \times 100\\\\\eta_{th}=53.33\%\\\\\eta_{th }\leq \eta_{th, max } =53.33\%\leq 60\%[/tex]

Therefore, the power cycle obeys the Second Law of Thermodynamics.

When [tex]Q_h=300\; kJ, \;W_{(cycle)}=200kJ, \;and\;Q_c=100\; kJ[/tex]

For the First Law:

[tex]W_{cycle}=Q_h-Q_c\\\\200=300-100\\\\200=200[/tex]

Therefore, the power cycle obeys the First Law of Thermodynamics.

For the Second Law:

[tex]\eta_{th}=(1-\frac{Q_c}{Q_h} ) \times 100\\\\\eta_{th}=(1-\frac{100}{300} ) \times 100\\\\\eta_{th}=66.67\%\\\\\eta_{th }\leq \eta_{th, max } \neq 63.33\%\geq 60\%[/tex]

Therefore, the power cycle doesn't obey the Second Law of Thermodynamics.

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Answer:

A to C = 6.4 km

Explanation:

A to B = 4 km

B to C = 5 km

A to C =  using pythagorean theorem

a² + b² = c²

a = A to B = 4

b = B to C = 5

c = A to C

c² = 4² + 5²

c = 6.4 km (A to C)

According to the scenario, the distance between town C from town A is found to be 6.40 Km.

The background that this question depends on is known as the direction-based question. These types of questions completely depend on the distance of moving bodies like cars, persons, or any other objects as well with respect to the initial position.

According to the question,

The distance between town A to town B = 4 km.

The distance between town B to town C = 5 km.

Now, according to the Pythagoras theorem, the distance between town C to town A is as follows:

[tex]AC^2[/tex] = [tex]AB^2 +BC^2[/tex].

[tex]AC^2[/tex] = [tex]4^2+5^2[/tex]

[tex]AC^2[/tex] = 16 + 25 = 41.

AC = √41 = 6.40 km.

Therefore, the distance between town C from town A is found to be 6.40 Km.

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Answer:

We can prevent it by:

a) By wearing GOOGLES.

b) By wearing our Lab coat.

c) Fire extinguisher should always be present in the lab.

d) Hand Gloves must be worn.

e) No playing in the lab.

f) No touching of things/equipment's e.g bottles, in the lab.

g) No eating/snacking in the lab.

h) Always pay attention, no gisting.

i) Adult/qualified person must be present in the lab with pupils/students.

Explanation:

Hope it helps.

Answer:

0.285 lbm per cubic feet

Explanation:

length of tank = 50 inches = 50/12 feet = 4.17 feet

diameter of tank = 16 inches = 16/12 feet = 1.33 feet

weight of water = 1.65 lbm

density of water = ?

We know that the density of a substance is given as

ρ = w/v

where ρ is the density in Ibm per cubic feet

w is the weight in lbm

v is the volume in cubic feet

Volume of a cylinder = [tex]\frac{\pi d^{2} l}{4}[/tex]

where d is the diameter

l is the length

volume = [tex]\frac{3.142*1.33^{2}* 4.17}{4}[/tex] = 5.79 cubic feet

Therefore, the density of water will be

ρ = w/v = 1.65/5.79 = 0.285 lbm per cubic feet

The density of water will be "0.285 lbm per cubic feet".

According to the question :

Length of tank = 50 inches or,

                        = [tex]\frac{50}{12}[/tex]

                        = 4.17 feet

Diameter of tank = 16 inches or,

                            = [tex]\frac{16}{12}[/tex]

                            = 1.33 feet

Weight of water = 1.65 lbm

We know the formula,

Volume of cylinder,

= [tex]\frac{\pi d^2 l}{2}[/tex]

By substituting the values, we het

= [tex]\frac{3.142\times (1.33)^2\times 4.17}{4}[/tex]

= 5.79 cubic feet

hence,

The density of water will be:

→ ρ = [tex]\frac{w}{v}[/tex]

By substituting the values,

      = [tex]\frac{1.65}{5.79}[/tex]

      = 0.285 lbm/cubic feet

Thus the above answer is correct.  

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Answer:

The liquids are TOLUENE because the equilibrum vapor above it will be flammable ( D )

Explanation:

Liquids stored at : 1 atm , 25⁰c  and they are vented with air

Determining whether the equilibrum vapor above the liquid will be flammable

We can determine this by using Antoine equation to calculate saturation vapor pressure also apply Dalton's law to determine the volume % concentration of air and finally we compare answer to flammable limits to determine which liquid will be flammable

A) For acetone

using the Antoine equation to calculate saturation vapor pressure

[tex]In(P^{out} ) = A - \frac{B}{C + T}[/tex]

values gotten appendix E ( chemical process safety (3rd edition) )

A = 16.6513

B = 2940.46

C = -35.93

T = 298 k      input values into Antoine equation

therefore ; [tex]p^{out}[/tex] = 228.4 mg

calculate volume percentage using Dalton's law

= V% = (saturation vapor pressure / pressure ) *100

         = (228.4 mmHg / 760 mmHg) * 100 = 30.1%

The liquid is not flammable because its UFL = 12.8%

B) For Benzene

using the Antoine equation to calculate saturation vapor pressure

[tex]In(P^{out} ) = A - \frac{B}{C + T}[/tex]

values gotten appendix E ( chemical process safety (3rd edition) )

A= 15.9008

B = 2788.52

C = -52.36

T = 298 k   input values into the above equation

[tex]p^{out}[/tex] = 94.5 mmHg

calculate volume percentage using Dalton's law

V% = (saturation vapor pressure / pressure ) *100

      = (94.5 / 760 ) * 100 = 12.4%

Benzene is not flammable under the given conditions because its UFL =7.1%

C) For cyclohexane

using the Antoine equation to calculate saturation vapor pressure

[tex]In(P^{out} ) = A - \frac{B}{C + T}[/tex]

values gotten appendix E ( chemical process safety (3rd edition) )

A = 15.7527

B = 2766.63

c = -50.50

T = 298 k

solving the above equation using the given values

[tex]p^{out}[/tex] = 96.9 mmHg

calculate volume percentage using Dalton's law

V% = (saturation vapor pressure / pressure ) *100

      = ( 96.9 mmHg /760 mmHg) * 100 = 12.7%

cyclohexane not flammable under the given conditions because its UFL= 8%

D) For Toluene

using the Antoine equation to calculate saturation vapor pressure

[tex]In(P^{out} ) = A - \frac{B}{C + T}[/tex]

values gotten from appendix E ( chemical process safety (3rd edition) )

A = 16.0137

B = 3096.52

C = -53.67

T = 298 k

solving the above equation using the given values

[tex]p^{out}[/tex] = 28.2 mmHg

calculate volume percentage using Dalton's law

V% = (saturation vapor pressure / pressure ) *100

     = (28.2 mmHg / 760 mmHg) * 100 = 3.7%

Toluene is flammable under the given conditions because its UFL= 7.1%

Answer:

A. Forces that act perpendicular to the surface and pull an object apart exert a tensile stress on the object.

Explanation:

Tensile stress is due to tension forces on a material. Tensile force acts perpendicularly away from the surface of the substance. The pull on the material due to the tensile force exerts tensile stress on the material, that tends to pull the material apart. The magnitude of the tensile stress is given as

σ = [tex]\frac{P}{A}[/tex]

where σ is the tensile stress

P is the tensile force pulling the material apart

A is the cross-sectional area through which the tensile force acts perpendicularly.