The terms of a mathematical expression are parts of the expression that are connected with addition or subtraction. The factors in a mathematical expression are parts of the expression that are connected with multiplication.
I don't know what you meant but I hope this helps.
round to the nearest 10th
An expression equivalent to -4(2k-6)
Answer:
-8k + 24
Step-by-step explanation:
Is your expression.
I need help please.
A television is discounted 20% in a sale. A shopper has a coupon for an additional 15% off the sale price. Which of the following is the total percent discount from the original price of the television?
The total percent discount arises from the real price of the television is 32%.
Given that,
The television should be discounted at 20% in the sale i.e. price after discount should be 0.80 of the real price There is an additional 15% off the sale price. So, 15% of 80% i.e. 12%.So, the total percent discount should be
= 20% + 12%
= 32%
Therefore we can conclude that The total percent discount arises from the real price of the television is 32%.
Learn more about the discount here: brainly.com/question/2736271
Use the distributive property to simplify the following expression: 3 (2 + 5z)
What is the value of x?
Enter your answer in the box.
X=l_l
9514 1404 393
Answer:
x = 62
Step-by-step explanation:
The angle marked x° is shown as the complement of the angle marked 28°. This means ...
x = 90 -28 = 62
25 points True or False.
The expressions 4(y−3)
and 4y−12
are equivalent?
Answer: true
Step-by-step explanation:
Simplifying the expression you end up with 4y^2 + 4y - 15 which is 3 terms.
The answer would be True.
Plzz help me I am timed plzz!
Answer:
B) 2
Step-by-step explanation:
6/3 = 2
3/3 = 1
6÷3 = 2
Hopefully this helps :3 Sorry if wrong :( Plz mark brainiest if correct :D Your bootiful/handsome! Have a great day luv <3
-Bee~
help will give crown
Answer:
112 meters squared
Step-by-step explanation:
Rectangle area: 72
Triangle area: 20 times 2 (because there are two triangles) = 40
72 + 40 = 112
How would I solve this ? And what’s the answer..... ;\
(x + 3;x 23
Function: g = 6;1
x?;x51
find g(-3)
a) 0
b) 9
c) 6
d) -9
Answer:
Static Public Member Functions ... Get FWORD from string (Big Endian 16-bit signed integer). ... (62x88 mm ; 2.44x3.46 in); B9 (44x62 mm ; 1.73x2.44 in); B10 (31x44 mm ; 1.22x1.73 in) ...
The length of a cell phone is 1.41.4 inches and the width is 4.44.4 inches. The company making the cell phone wants to make a new version whose length will be 1.751.75 inches. Assuming the side lengths in the new phone are proportional to the old phone, what will be the width of the new phone?
Answer:
Step-by-step explanation:
Answer:
5.573.75
Step-by-step explanation:
because math
Rackham Graduate School has 8,000 students (5,000 PhD students and 3,000 masters stu- dents). The Rackham Student Government Executive Board has 4 student members: a President, a VP of Operations, a VP of Finance, and a VP of Administration. Reminder: no need to simplify your answers in this homework (unless problem explicitly says to).
a) How many ways are there to choose the Exec Board from all Rackham students?
b) How many ways are there to choose the Exec Board so that there is at least one masters student and one PhD student? (for any of the 4 positions)
c) How many ways are there to choose the Exec Board if the VP positions have to be PhD students (the president can be either a PhD or Masters student)?
d) How many ways are there to choose the Exec Board so that there is at least one masters student VP?
Answer:
a) 8,000!/(8000 - 4)! ways
b) 15,000,000 + 7998!/(7998 - 2)! ways
c) 5,000 + 7,999!/(7,999- 3)! ways
d) 3,000 + 7,999!/(7,999- 3)! ways
Step-by-step explanation:
The number of students at Rackham Graduate School = 8,000 students
The number of PhD students = 5,000
The number of masters students = 3,000
The number of student members of the Rackham Student Government Executive Board = 4 students
a) The number of ways there are to choose the Exec Board from all Rackham students = The number of ways to choose 4 students from 8,000 = 8,000!/(8000 - 4)!
b) The number of ways of having one Master student in the board = 3,000 ways
The number of ways of having one PhD student in the board after selecting a masters student = 5,000 ways
The number of ways of selecting the remaining 2 members =
7998!/(7998 - 2)!
The total number of ways of selecting at least one masters and one PhD in the board is therefore equal to 5,000 × 3,000 + 7998!/(7998 - 2)! ways
c) The number of ways of choosing the VP position as PhD = 5,000 ways
The number of ways of choosing the other three members = 7,999!/(8000 - 3)!
Therefore, the total number of ways = 5,000 + 7,999!/(7,999- 3)! ways
d) The number of ways of choosing a masters student as the VP position = 3,000 ways
The number of ways of choosing the other three members = 7,999!/(8000 - 3)!
Therefore, the total number of ways = 3,000 + 7,999!/(7,999- 3)! ways
Find the measure of 2.
50 2.
1130
< 2 =
[?]
What Is 1 x 2 x 3 x 4 x 5/2
Answer:
60
Step-by-step explanation:
Please refer to the attachment
What is the slope of the line that goes through (-3, 2) and (3, 2)?
Answer:
m = 0
Step-by-step explanation:
Hope this helps:)
Need help plz and thank u
Which is correct a or b
Answer:
B is correct hope this helps
Select the correct answer. Sarah owns a flower shop and can model the profits from selling springtime bouquets using this equation, where b is the number of springtime bouquets. P = -5b^2 + 450b - 1,000
Which statement is true if Sarah needs to make a profit of at least $9,000?
A. Sarah must sell more than 90 bouquets.
B. Sarah must sell between 40 and 50 springtime bouquets.
C. Sarah must sell between 0 and 40 springtime bouquets.
D. Sarah must sell more than 50 springtime bouquets.
Answer:
B
Step-by-step explanation:
If you plug in the answers for guess and repeat this one works.
The correct statement is Sarah must sell between 40 and 50 springtime bouquets true if Sarah needs to make a profit of at least $9,000.
Given that,
Sarah owns a flower shop and can model the profits from selling springtime bouquets using this equation,
Where b is the number of springtime bouquets, [tex]P = -5b^2 + 450b - 1,000[/tex].
We have to determine,
Which statement is true if Sarah needs to make a profit of at least $9,000.
According to the question,
Sarah owns a flower shop and can model the profits from selling springtime bouquets using this equation,
[tex]P = -5b^2 + 450b - 1,000[/tex]
Divide the equation by -5,
[tex]P = -5b^2 + 450b - 1,000\\\\P = -b^2 + 90b - 200[/tex]
Factorize the equation for the value of profit,
[tex]b^2 - 90b +200 = 0\\\\b^2 -50b -40b +200= 0\\\\b ( b-50) - 40(b-50) = 0 \\\\(b-50) (b-40) = 0 \\\\b- 50 = 0, \ b = 50\\\\b - 40 = 0, \ b = 40[/tex]
Hence, Sarah must sell between 40 and 50 springtime bouquets.
To know more about Quadratic equations click the link given below.
https://brainly.com/question/22364785
Jose Luis desea colocar una línea de azulejos alrededor de toda la piscina de su casa. La piscina tiene forma rectangular con un ancho de 10 m y una longitud de 25 m. , ¿cuántos metros lineales de azulejos necesitará comprar?
Answer:
70
Step-by-step explanation:
2 x (25 + 10) = 2 x 35 = 70
What is the value of c so that −15 and 15 are both solutions of x^2−c=157?
Answer: -c= 157+X^2
Step-by-step explanation:
with one of these is a function
a
b
c
d
Answer:
It's B
Step-by-step explanation:
Answer:
B is a functional answer
On a recent test, Ahmed knew many of the answers, but there were four questions he was unsure of. In each of the four questions, he was able to eliminate two answers as being clearly wrong and was left with three answer choices to choose from. In each of the four questions, he randomly selected one of the remaining three answers. Which of these statements describes how Ahmed could simulate this situation with a random number generator to determine if he will select the correct answers for these four questions?
It is impossible to simulate this with a random number generator without knowing what the correct answer choices were Using his calculator, Ahmed could use the Randint(1,4) command three times to select three integers from 1 to 4. Let a 1 indicate a correct guess, and a 2, 3, or 4 indicate an incorrect guess. Count the number of 1s to correspond to the number of correct guesses. Using his calculator, Ahmed could use the Randint(1,4) command to select a random integer from 1 to 4. This would be the number of correct guesses he made on the four questions. Using his calculator, Ahmed could use the Randint(1,3) command four times to select four integers from 1 to 3. Leta 1 indicate a correct guess, and a 2 or 3 indicate an incorrect guess. Count the number of 1s to correspond to the number of correct guesses. It is impossible to simulate this with a random number generator without knowing what the correct answer choices were. Using his calculator, Ahmed could use the Randint(1,4) command three times to select three integers from 1 to 4. Let a 1 indicate a correct guess, and a 2, 3, or 4 indicate an incorrect guess. Count the number of 1s to correspond to the number of correct guesses. Using his calculator, Ahmed could use the Randint(1,4) command to select a random integer from 1 to 4. This would be the number of correct guesses he made on the four questions. Using his calculator, Ahmed could use the Randint(1,3) command four times to select four integers from 1 to 3. Let a 1 indicate a correct guess, and a 2 or 3 indicate an incorrect guess. Count the number of 1s to correspond to the number of correct guesses. Using his calculator, Ahmed could use the Randint(1,5) command four times to select four integers from 1 to 5. Leta 1 indicate a correct guess, and a 2, 3, 4, or 5 indicate an incorrect guess. Count the number of 1s to correspond to the number of correct guesses.
Answer:
It is impossible to simulate this with a random number generator without knowing what the correct answer choices were
Step-by-step explanation:
Given
[tex]Questions = 4[/tex]
[tex]Options = 5[/tex]
Required
How can he select the right answer
Using randint will only generate a random number which could or could not be the answer to the question.
This is so because each of the 5 options for the question has the same probability of 1/5. So, using randint will only generate a random number. This generated random number has 1/5 chance of being the answer and 4/5 of not being the answer to the question.
In a nutshell, he can not make use of a simulator to select the answer to the questions in this scenario, unless he knows the solution.
Hence (a) answers the question.
Find the missing angle
bro what angle I don't see one here so how we are able to solve this problem
Solve for x Enter the solutions from least to greatest . (x - 4)(- 5x + 1) = 0 lesser x = greater x =
Answer: lesser x = 1/5 greater x = 4
Step-by-step explanation:
A circle of sunflowers is planted in Stanford's central Park. The circle has a diameter of 12 feet. What is the circle's radius?
Answer:
Step-by-step explanation:
radius = ½×diameter = 6 ft
CL 6-153
In 2012 the average cost for a new midsized car was about
$31,000. New car prices tend to go up about 2% every year.
a. What is the multiplier for this situation?
b. If this trend continues, what will the cost be in 4 years?
c. Write an equation to calculate the cost in n years. What does
each of the factors in your equation represent?
Answer:
A) The multiplier for this situation is 0.02.
B) The cost in 4 years will be $ 33,555.39.
C) 31,000 x 1.02 ^ N = X
Step-by-step explanation:
Since in 2012 the average cost for a new midsized car was about $ 31,000, and new car prices tend to go up about 2% every year, to determine what is the multiplier for this situation, what will the cost be in 4 years if this trend continues and to write an equation to calculate the cost in n years the following calculations must be performed:
A)
31,000 x 2/100 = X
31,000 x 0.02 = X
Thus, the multiplier for this situation is 0.02.
B)
31,000 x 1.02 ^ 4 = X
33,555.39 = X
Thus, the cost in 4 years will be $ 33,555.39.
C)
31,000 x 1.02 ^ N = X
Here, N represents the number of years over which the price increase will be calculated, and X represents the price after that number of years.
equation, find y when x=-3.
y = -x + 5
When x = -3, y =
You are traveling down a country road at a rate of 95 feet/sec when you see a large cow 300 feet in front of you and directly in your lane. The cow is fearless, and staring you down. (Or perhaps she does not understand the gravity of the situation.) Regardless, if you simply hit your brakes, after t seconds, the car will be j(t) = 95t - 9t^2 feet from the point where the brakes were first applied.
1) Must you steer to avoid the cow, or can you rely solely on your brakes? Explain.
2) Graph J(t), j'(t), and j"(t) and Interpret their meanings in context.
3) Is there a time t after which the graphs in part (ii) probably do not accurately model the path of the car?
4) Write a piece-wise function using j(t) that would more accurately model the path of the car on the interval [0, 10], assuming the car did not move after it stopped. Sketch this graph and its derivative.
Answer:
1) You can rely solely on your brakes because when doing so the car will just travel 250ft from the point you hit your brakes till the point the car stopped completely, leaving you 50ft away from the cow.
2) See attached picture.
j(t) represents the distance from the point you hit the brake t seconds after you hit it in feet
j'(t) represents the velocity of the car t seconds after the brakes have been hit in ft/s.
j"(t) represents the acceleration of the car t seconds after the brakes have been hit in [tex]ft/s^{2}[/tex]
3) yes, any time after t=5.28 will not accurately model the path of the car since at that exact time the car will reach a velocity of 0ft/s and unless another force is applied to the car, then the car will not move after that time.
4) [tex]j(t)=\left \{ {{95t-9t^{2}; 0\le t<5.28s} \atop {250.69; 5.28s\leq t \leq 10s}} \right.[/tex]
[tex]j'(t)=\left \{ {{95-18t; 0\leq t<5.28s} \atop {0 ; 5.28s\leq t \leq 10s}} \right.[/tex]
(see attached picture for graph)
Step-by-step explanation:
1) In this part of the problem we need to find the time when the speed of the car is 0. Gets to a complete stop. For this we will need to take the derivative of the position function so we get:
[tex]j(t)=95t-9t^2[/tex]
[tex]j'(t)=95-18t[/tex]
and we set the first derivative equal to zero so we get:
95-18t=0
and solve for t
-18t=-95
[tex]t=\frac{95}{18}[/tex]
t=5.28s
so now we calculate the position of the car after 5.28 seconds, so we get:
[tex]j(5.28)=95(5.28)-9(5.28)^{2}[/tex]
[tex]j(5.28)=250.69ft[/tex]
so we have that the car will stop 250.69ft after he hit the brakes, so there will be about 50ft between the car and the cow when the car stops completely, so he can rely just on the breaks.
2) For answer 2 I take the second derivative of the function so I get:
[tex]j(t)=95t-9t^{2}[/tex]
[tex]j'(t)=95-18t[/tex]
j"(t)=-18
and then we graph them. (See attached picture)
j(t) represents the distance from the point you hit the brake t seconds after you hit it in feet
j'(t) represents the velocity of the car t seconds after the brakes have been hit in ft/s.
j"(t) represents the acceleration of the car t seconds after the brakes have been hit in [tex]ft/s^{2}[/tex]
3) yes, any time after t=5.28 will not accurately model the path of the car since at that exact time the car will reach a velocity of 0ft/s and unless another force is applied to the car, then the car will not move after that time.
4) [tex]j(t)=\left \{ {{95t-9t^{2}; 0\le t<5.28s} \atop {250.69; 5.28s\leq t \leq 10s}} \right.[/tex]
[tex]j'(t)=\left \{ {{95-18t; 0\leq t<5.28s} \atop {0 ; 5.28s\leq t \leq 10s}} \right.[/tex]
(see attached picture for graph)
What do I do from here?
49627/28000 or you can use the decimal 1.77
Step-by-step explanation:
28x=49.627
divide both sides by 28