The owner of a manufacturing plant employs eighty people. As part of their personnel file, she asked each one to record to the nearest one-tenth of a mile the distance they travel one way from home to work. The distances for a random sample of six employees are listed below:

26 32 29 16 45 19

Required:
Compute mean, variance, and standard deviation for these data, with a step-by-step explanation for each. Round your answer to one more decimal place than the original data.

Answers

Answer 1

Answer:

Mean of the sample = 27.83

The variance of the the sample = 106.96

Standard deviation of the sample = 10.34

Step-by-step explanation:

Step(i):-

Given random sample of six employees

x     26    32    29    16     45    19

mean of the sample

[tex]x^{-} = \frac{26+32+29+16+45+19}{6} = 27.83[/tex]

Mean of the given data = 27.83

Step(ii):-

Given data

x           :       26         32           29           16           45        19

x - x⁻     :      -1.83      4.17        1.17       -11.83     17.17    -8.83

(x - x⁻)²  :    3.3489   17.3889   1.3689   139.9489  294.80 77.9689

∑ (x-x⁻)²  =   534.8245

Given sample size 'n' =6

The variance of given data

           S²  = ∑(x-x⁻)² / n-1  

           [tex]S^{2} = \frac{534.8245}{6-1} = 106.9649[/tex]

The variance of the given sample = 106.9649

Step(iii):-

Standard deviation of the given data

[tex]S = \sqrt{variance} = \sqrt{106.9649} =10.3423[/tex]

Standard deviation of the sample = 10.3423


Related Questions

Find the standard deviation, σ, for the binomial distribution which has the stated values of n and p. Round your answer to the nearest hundredth. n = 38; p = 2/5 Group of answer choices σ = 13.55 σ = 14.40 σ = 7.87 σ = 10.28

Answers

Answer:

[tex] X \sim Binom (n=38, p=2/5)[/tex]

By properties the mean is given by:

[tex]\mu = np =38 *\frac{2}{5}= 15.2[/tex]

And the standard deviation would be:

[tex] \sigma = \sqrt{np(1-p)}= \sqrt{38* \frac{2}{5}* (1-\frac{2}{5})}= 3.02[/tex]

Step-by-step explanation:

For this case we know that the random variable follows a binomial distribution given by:

[tex] X \sim Binom (n=38, p=2/5)[/tex]

By properties the mean is given by:

[tex]\mu = np =38 *\frac{2}{5}= 15.2[/tex]

And the standard deviation would be:

[tex] \sigma = \sqrt{np(1-p)}= \sqrt{38* \frac{2}{5}* (1-\frac{2}{5})}= 3.02[/tex]

0.006772 to 1 significant number

Answers

Answer:

0.006772

If the last dropping digit is less than 5 then it will be ignored

0.00677

if the last dropping digit is greater than 5 than the the last retained digit increases by 1

0.0068

if  the last dropping digit is greater than 5 than the the last retained digit increases by 1

0.007

if  the last dropping digit is greater than 5 than the the last retained digit increases by 1

0.01

if the last digit is less than 5 so it will be ignored

0.0 is significant figure because zero to the right of decimal point are significant

Step-by-step explanation:

i hope this will help you :)

Answer:

0.007

Step-by-step explanation:

Rounding off 0.006772 to 1 significant figures:

=> 0.007

There is only 1 significant figure in this , since the zeroes on the left are not counted as significant figures.

The pH scale measures the amount of alkalinity or acidity in a liquid and ranges from 0-14. The ideal pH for a swimming pool is 7.2. A pH that is too high or low can cause discomfort for the swimmers, especially in the eyes. High variability in the pH readings across the swimming pool can be problematic. The following data shows seven pH readings that were taken at the Wilson Community Pool from different locations at 10 a.m. this morning. The average pH reading from this sample was 7.02 with a sample standard deviation of 0.40. Using α= 0.05 and the critical value approach, determine if correctiveaction is needed at this pool to adjust the pH value.

Required:
State your conclusion.

a. Because calculated t statistic is greater than t critical value, we reject the null hypothesis. Therefore, Wilson Community Pool cannot conclude that the pH value is not equal to 7.2. Based on this sample, corrective action needs to be
taken.
b. Because calculated t statistic is less than critical t value, we reject the null hypothesis. Therefore, Wilson Community Pool cannot conclude that the pH value is not equal to 7.2. Based on this sample, corrective action needs to be
taken.
c. Because the t calculated is greater than the critical t, we fail to reject the null hypothesis. Therefore, Wilson Community Pool conclude that the pH value is equal to 7.2. Based on this sample, no corrective action is needed.
d. Because the t calculated is less than the critical t, we fail to reject the null hypothesis. Therefore, Wilson Community Pool conclude that the pH value is equal to 7.2. Based on this sample, no corrective action is needed.

Answers

Answer:

the answer for the question is b.because calculated statistic less than critical t,value we reject the null hypothesis. Therefore, Wilson Community Pool cannot conclude............

The Conclusion of the Hypothesis is; D. Because the t calculated is less than the critical t, we fail to reject the null hypothesis.

How to State A Hypothesis Conclusion?

From the given question, we see that;

Population Mean; μ = 7.2

Sample Mean; x⁻ = 7.02

Significance level; α = 0.05

Now, in hypothesis, If the absolute value of the t-value is less than the critical value, you fail to reject the null hypothesis whereas if the absolute value of the t-value is greater than the critical value, you reject the null hypothesis.

Thus, the conclusion is that d. Because the t calculated is less than the critical t, we fail to reject the null hypothesis. Therefore, Wilson Community Pool conclude that the pH value is equal to 7.2. Based on this sample, no corrective action is needed.

Read more about Hypothesis Conclusion at; https://brainly.com/question/15980493

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PLEASE HELP Kelly wants to join an aerobics class. The initial membership fee is $25.00, and each clas costs $10.00. She pays a total of $115.00 to register for a certain number of classes. Create an equation to find the number of classes Kelly registered for.

Answers

Answer:

$25.00 + $10x = $115.00

Step-by-step explanation:

We know that the initial charge of joining is $25. Each class costs $10 each. She spent a total of $115. What we don't know is how many classes she took. With this equation, we can easily find out how many classes she took.

A rectangle has length(4x+5) and breadth 3x.Find the area of the rectangle.​

Answers

Answer:

Length = 4x+5

Breadth = 3x

Area = l × b

= (4x+5) × 3x

= 12 x² + 15 x

Consider it this cone with a diameter of 19 cm use the drop-down menus to describe the con measurements

Answers

Answer:

1) Radius of the cone = 9.5 cm

2) BA = 90.25 π cm²

3) SA = 384.7 π cm²

Step-by-step explanation:

1) Radius of the cone = 9.5 cm

2) Base Area of the cone = [tex]\pi r^2[/tex]

BA = (π)(9.5)²

BA = 90.25 π cm²

3) Surface Area of Cone = [tex]\pi r(r+\sqrt{h^2+r^2)}[/tex]

SA = π(9.5)(9.5 + √(29.5)²+(9.5)²)

SA = 9.5π(9.5 + 31)

SA = 9.5π(40.5)

SA = 384.7 π cm²

A LINE PASSES THROUGH THE POINTS. what is the EQUATION OF THE LINE? (2,-4) and (6,10)?

Answers

Hey there! :)

Answer:

y = 7/2x - 11

Step-by-step explanation:

Use the slope formula to calculate the slope:

[tex]m = \frac{\text{rise}}{\text{run}} = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

Plug in the coordinates:

[tex]m = \frac{10-(-4)}{6-2}[/tex]

Simplify:

[tex]m= \frac{14}{4}[/tex]

[tex]m = \frac{7}{2}[/tex]

Slope-intercept form is y = mx + b. Plug in the slope, as well as the coordinates of a point given to solve for b:

10 = 7/2(6) + b

10 = 42/2 + b

10 = 21 + b

10 - 21 = b

b = -11.

Write the equation:

y = 7/2x - 11

The mean amount spent by a family of four on food is $500 per month with a standard deviation of $75. Assuming that the food costs are normally distributed, what is the probability that a family spends less than $425 per month?​

Answers

Answer:

[tex] z=\frac{x- \mu}{\sigma}[/tex]

And replacing we got:

[tex] z=\frac{425-500}{75}= -1[/tex]

And we can calculate this probabilit using the normal standard distribution or excel and we got:

[tex] P(z<-1)= 0.159[/tex]

Step-by-step explanation:

If we define the random variable of interest "the amount spent by a family of four of food per month" and we know the following parameter:

[tex] \mu = 500, \sigma = 75[/tex]

And we want to find the following probability:

[tex] P(X<425)[/tex]

And we can use the z score formula given by:

[tex] z=\frac{x- \mu}{\sigma}[/tex]

And replacing we got:

[tex] z=\frac{425-500}{75}= -1[/tex]

And we can calculate this probabilit using the normal standard distribution or excel and we got:

[tex] P(z<-1)= 0.159[/tex]

PLEASE help, thanks will give 5 stars

Answers

Answer:

x=4/3

Step-by-step explanation:

By using the formula =

MQ/QP=MN/NO

4/x=6/2

Cross multiply

6x=8

x=4/3

The figure below is made of 2 rectangular prisms. What is the volume of this figure?



_____ cubic units.

Answers

Answer:

100

Step-by-step explanation:

The Volume of the Rectangular prism on the left is 60

The Volume of the Rectangular prism on the right is 40

Answer:

Your correct answer is 40

Step-by-step explanation:

Multiply 8 x 5.

8 x 5 = 40

MUltiply 40 x 1.

40 x 1 = 40

So, it stays the same. Anything multiplied by 1 stays the same.

Therefore, your correct answer is 40.

A rocket is stopped 34 feet from a satellite when it begins accelerating away from the satellite at a constant rate of 18 feet per second per second. The distance between the rocket and the satellite is given by the polynomial P(t) = 9t2 + 34. Find the distance between the rocket and the satellite 10 seconds after the rocket started moving.

Answers

Answer:

The distance between the rocket and the satellite 10 seconds after the rocket started moving is of 934 feet.

Step-by-step explanation:

The distance between the rocket and the satellite, in feet, after t seconds, is given by the following equation:

[tex]P(t) = 9t^{2} + 34[/tex]

Find the distance between the rocket and the satellite 10 seconds after the rocket started moving.

This is P(10).

[tex]P(t) = 9t^{2} + 34[/tex]

[tex]P(10) = 9*(10)^{2} + 34 = 934[/tex]

The distance between the rocket and the satellite 10 seconds after the rocket started moving is of 934 feet.

Calculate the net price that a chain store pays if the price of an item is 25.99 but the invoice stipulates 40/10 chain discount

Answers

Answer:

$14.034

Step-by-step explanation:

40/10 means that the price has a 40% discount and then, a 10% discount from what is left. To calculate the net price, first you have to calculate the price with the 40% discount:

25.99*(1-0.4)= 15.594

Then, you have to calculate the price with the 10% discount:

15.594*(1-0.1)= 14.034

According to this, the net price is $14.034.

Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (if it is actually spam) 95% of the time. On the other hand, if an email isn't spam, the test will incorrectly classify it as spam 5% of the time. The prevalence of spam emails is 3 in 10.i) What's the probability that an email picked at random is spam? What's the probability that an email picked at random isn't spam?ii) If you test an email and it reports positive for spam, what is the probability that it is spam? Show your work.iii) If you test an email and it reports negative for spam, what is the probability that it is spam? Show your work.

Answers

Answer and Step-by-step explanation:

The computation is shown below:

Let us assume that

Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

[tex]P(\frac{T}{S}) = 0.95[/tex]

[tex]P(\frac{T}{S^c}) = 0.05[/tex]

Now based on the above information, the probabilities are as follows

i. P(Spam Email) is

= P(S)

= 0.3

[tex]P(S^c) = 1 - P(S)[/tex]

= 1 - 0.3

= 0.7

ii. [tex]P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}[/tex]

[tex]= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }[/tex]

[tex]= \frac{0.95 \times 0.3}{0.95 \times 0.3 + 0.05 \times 0.7}[/tex]

= 0.8906

iii. [tex]P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}[/tex]

[tex]= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }[/tex]

[tex]= \frac{(1 - 0.95)\times 0.3}{ (1 -0.95)0.95 \times 0.3 + (1 - 0.05) \times 0.7}[/tex]

= 0.0221

We simply applied the above formulas so that the each part could come

Answer:

0.0221

Step-by-step explanation:

What is the value of y?

Answers

Answer:

B. 65°

Step-by-step explanation:

Angles on a straight line add up to 180 degrees.

180 - 130 = 50

Angles in a triangle add up to 180 degrees.

y + y + 50 = 180

2y + 50 = 180

2y = 180 -50

2y = 130

y = 130/2

y = 65

A theater group made appearances in two cities. The hotel charge before tax in the second city was $ 1500 higher than in the first. The tax in the first city was 5 % , and the tax in the second city was 8.5 % . The total hotel tax paid for the two cities was $ 836.25 . How much was the hotel charge in each city before tax?

Answers

Answer:

In city one, the hotel charges before taxes were $5,250.

In city two, the hotel charges before taxes were $6,750.

Step-by-step explanation:

Let the hotel charge in the first city be x and in the second city be y.

Given that the hotel charge before tax in the second city was $ 1500 higher than in the first. That can be written as:

[tex]y - x = \$1500[/tex] ...[1]

The tax in the first city was 5 %, and the tax in the second city was 8.5 %.

The total hotel tax paid for the two cities was $ 836.25

5% of x + 8.5% of y = $836.25

[tex]0.05x+0.085y=\$836.25[/tex]...[2]

Now putting value of y from [1] in to [2]:

[tex]y = \$1500+x[/tex]

[tex]0.05x+0.085\times (\$1500+x)=\$836.25[/tex]

On solving we get :

x = $5,250

Using vakue of x in [1] to find y:

[tex]y=\$1500+\$5,250=\$ 6,750[/tex]

In city one, the hotel charges before taxes were $5,250.

In city two, the hotel charges before taxes were $6,750.

pls help i give brainliest ​

Answers

Answer:

Step-by-step explanation:

Area of triangle = 1/2 × b × h

69.3 = 8.4 × h

h = 69.3 / 8.4

h = 8.25 mm

hope this helps

plz mark as brainliest!!!!!!

Answer:

16.5mm

Step-by-step explanation:

1. 69.3 x 2

2. 138.6 divided by 8.4

3. solve which equals 16.5mm

Hope this helps you:)

Divide 180 into ratio of 2:3

Answers

Answer:

72 : 108

Step-by-step explanation:

180/(total parts)

180/(2+3)

180/5

= 36

Find the ratio:

2 : 3

2 × 36 : 3 × 36

72 : 108

Answer:

72:108

Step-by-step explanation:

180 dived by 5 = 36

36 times 2 = 72

36 times 3 = 108

72:108

hope this helps ; )

If $17,800 is invested at an interest rate of 8% per year, find the value of the investment at the end of 5 years for the following compounding methods, to the nearest cent.

Answers

Answer:

7120

Step-by-step explanation:

HELP PLS!!! ITS DUE ASAP AND I NEED HELP ITS THE LAST QUESTION

Answers

Answer:

See below.

Step-by-step explanation:

Recall the volume of a sphere: [tex]V=\frac{4}{3}\pi r^3[/tex]

We know that the diameter is 14, so the radius is 7.

Plug it into the equation:

[tex]V=\frac{4}{3}(3.14)(7^3)\approx 1436.03cm^3[/tex]

The volume of the sphere is 1081.2

Solve 6 + 5 √ 2 4 9 − 2 x = 7

Answers

[tex]

6+5\sqrt{249}-2x=7 \\

-2x=7-6-5\sqrt{249} \\

-2x\approx-77.9 \\

x\approx\frac{-77.9}{2}\approx38.95

[/tex]

Hope this helps.

Anybody can help me out?

Answers

Answer:

answer D

Step-by-step explanation:

Hello

(fog)(x)=f(g(x))=|4x+9|

so g(x)=4x+9

and f(x)=|x|

hope this helps

Use the 4 step process to find the f'(x) of the function f(x)=x^2-3/2

Answers

Answer:

see below

Step-by-step explanation:

Modified problem

(x)^2-3/x

Step 1: Find f(x+h)

(x+h)^2-3/(x+h)

x^2 +2hx + h^2 -3/(x+h)

Step 2: Find f(x + h) − f(x)

x^2 +2hx + h^2 -3/(x+h) - ( x^2-3/x)

Distribute the minus sign

x^2 +2hx + h^2 -3/(x+h) -  x^2+3/x

Combine like terms and get a common denominator

2hx + h^2  -3x/(x(x+h)) +3(x+h)/(x(x+h)

2hx + h^2  +3h/(x(x+h))

Step 3: Find (f(x + h) − f(x))/h

(2hx + h^2+3h/(x(x+h)) )/h

2hx/h  + h^2/h+3h/(x(x+h)) /h

2x +h +3/(x(x+h))

Step 4: Find lim  h→0  (f(x + h) − f(x))/h

2x+0 +3/(x(x+0))

2x +3/x^2

Find the surface area of this triangular prism. Be sure to include the correct unit in your answer.

Answers

Answer:  360 square inches

Work Shown:

A = area of bottom rectangular face = 10*5 = 50

B = area of back rectangular face = 12*10 = 120

C = area of slanted front rectangular face = 13*10 = 130

D = area of left triangle = 0.5*base*height = 0.5*5*12 = 30

E = area of triangle on right = 0.5*base*height = 0.5*5*12 = 30

S = total surface area

S = A+B+C+D+E

S = 50+120+130+30+30

S = 360

Identify the glide reflection rule in the given figure

Answers

Answer:

Option (3)

Step-by-step explanation:

Glide reflection of a figure is defined by the translation and reflection across a line.

To understand the glide rule in the figure attached we will take a point A.

Coordinates of the points A and A' are (2, -1) and (-2, 4).

Translation of pint A by 5 units upwards,

Rule to be followed,

A(x, y) → A"[x, (y + 5)]

A(2, -1) → A"(2, 4)

Followed by the reflection across y-axis,

Rule to be followed,

A"(x, y) → A'(-x, y)

A"(2, 4) → A'(-2, 4)

Therefore, by combining these rules in this glide reflections of point A we get the coordinates of the point point A'.

Option (3) will be the answer.

Answer:Reflection along the line y= -1

Step-by-step explanation:

took test

The given function is analytic at a = 0. Use appropriate series in (2) and long division to find the first four nonzero terms of the Maclaurin series of the given function.
Sec x.

Answers

Answer:

[tex]\mathbf{1 + \dfrac{x^2}{2!}+ \dfrac{5}{24}x^4+\dfrac{61}{720}x^6}[/tex]

Step-by-step explanation:

From the given information:

we are to find the first four nonzero terms of the Maclaurin series of the given function.

Sec x.

If we recall ; we will realize that the derivative of sec x = [tex]\dfrac{1 }{cos \ x}[/tex]

Also; for cos x ; the first four terms of its Maclaurin Series can be expressed as ;

=[tex]1- \dfrac{x^2}{2!}+\dfrac{x^4}{4!}- \dfrac{x^6}{6!}+...[/tex]

However, using the long division method: we have;

[tex]\dfrac{1}{1- \dfrac{x^2}{2!}+\dfrac{x^4}{4!}- \dfrac{x^6}{6!}}[/tex]

the rule of the long division method is to first use the 1 from the denominator to divide the 1 from the numerator. the multiply it with the answer we get which is (1) before subtracting it from  that answer (1).

i.e

1/1 = 1

1 × 1 = 1

1 - 1 = 0

Afterwards; we will subtract the remaining integers from this numerator.

So, we have:

[tex]\dfrac{-(1 - \dfrac{x^2}{2!}+\dfrac{x^4}{4!}- \dfrac{x^6}{6!} )}{0+ \dfrac{x^2}{2!}-\dfrac{x^4}{4!}+ \dfrac{x^6}{6!}}[/tex]

We are going to apply the same process to the remainder [tex]\dfrac{x^2}{2!}[/tex];

which is to divide the second integer with 1

[tex]\dfrac{\dfrac{x^2}{2!}}{1}= \dfrac{x^2}{2!}[/tex]

Then we will multiply the numerator with [tex]\dfrac{x^2}{2!}[/tex] ; the result will then be subtracted from the polynomial.

[tex]= \dfrac{-( \dfrac{x^2}{2!} - \dfrac{x^4}{2! 2!} + \dfrac{x^6}{2! 4!}- \dfrac{x^8}{2! 6!}) }{0 + \dfrac{5}{24}x^4 - \dfrac{7}{360}x^6- \dfrac{x^8}{2!6!} }[/tex]

Repeating the same process for remainder  [tex]\dfrac{5}{24}x^4[/tex]; we have:

[tex]\dfrac{ \dfrac{5}{24}x^4 }{1}= \dfrac{5}{24}x^4[/tex]

so; we will need to multiply 1 with [tex]\dfrac{5}{24}x^4[/tex] and subtract it from the rest of the polynomial

[tex]=\dfrac{{0 + \dfrac{5}{24}x^4 - \dfrac{7}{360}x^6- \dfrac{x^8}{2!6!} }}{ 1-x^2+ \dfrac{x^4}{4!} - \dfrac{x^6}{6!} }[/tex]

[tex]= \dfrac {- ( \dfrac{5}{24}x^4 -\dfrac{5}{2!4!}x^6 - \dfrac{5x^8}{4!4!} - \dfrac{5x^{10}}{6!4!} } {0+ \dfrac{61}{720}x^6}[/tex]

Here ; the final remainder is [tex]\dfrac{61}{720}x^6}[/tex]; repeating the usual process for long division method; we have:

[tex]\dfrac{\dfrac{61}{720}x^6}{1}= \dfrac{61}{720}x^6}[/tex]

So;

[tex]= \dfrac{0+ \dfrac{61}{720}x^6}{1-x^2+ \dfrac{x^4}{4!} - \dfrac{x^6}{6!} }[/tex]

[tex]= \dfrac{-( \dfrac{61}{720}x^6)}{0 }[/tex]

Now the  first four nonzero terms of the Maclaurin series is the addition of all the integers used as remainders ; i.e

[tex]\mathbf{1 + \dfrac{x^2}{2!}+ \dfrac{5}{24}x^4+\dfrac{61}{720}x^6}[/tex]

What angle is included by AB and BC ?
B
A
O A. ZB
OB. ZA
O c. Zc​

Answers

Answer:

[tex] \angle B[/tex]

Step-by-step explanation:

[tex] \angle B[/tex] is included by AB and BC, because B is the common vertex in AB and BC,


Given the probability density function f(x) = 1/5 over the interval [4, 9], find the expected value, the
mean, the variance and the standard deviation.
Expected value:
Mean:
Variance:
Standard Deviation:

Answers

Answer:

Step-by-step explanation:

Assume that f(x) = 0 for x outside the interval [4,9]. We will use the following

[tex]E[X^k] = \int_{4}^{9}x^k f(x) dx[/tex]

[tex]Var(X) = E[X^2}- (E[X])^2[/tex]

Standard deviation = [tex] \sqrt[]{Var(X)}[/tex]

Mean = [tex]E[X][/tex]

Then,

[tex]E[X] = \int_{4}^{9}\frac{1}{5}dx = \frac{9^2-4^2}{2\cdot 5} = \frac{13}{2}[/tex]

[tex]E[X^2] = \int_{4}^{9}\frac{x^2}{5}dx = \frac{9^3-4^3}{3\cdot 5} = \frac{133}{3}[/tex]

Then, [tex]Var(x) = \frac{133}{3}-(\frac{13}{2})^2 = \frac{25}{12}[/tex]

Then the standard deviation is [tex]\frac{5}{2\sqrt[]{3}}[/tex]

Possibilities Density Functions are a set of data measures that can be used to anticipate that a discontinuous value will turn out as the following calculation:

Density function calculated value:

Given function= [tex]\frac{1}{5}[/tex]

interval= [4,9]

Assuming that the given function that is [tex]fx) = 0[/tex] .

For this, the x outside the interval is [4,9].

Equation:

[tex]E[X^k] = \int^{9}_{4} x^k\ f(x) \ dx\\\\[/tex]

[tex]Var(X) = E(X)^2 - (E[X])^2[/tex]

The values are:

Standard deviation [tex]= \sqrt{Var(X)}[/tex]

Mean [tex]= E[X][/tex]

Solving the equation then:

[tex]E[X] =\int^{9}_{4} \frac{1}{5}\ dx[/tex]

         [tex]= \frac{9^2-4^2}{2\cdot 5} \\\\ = \frac{81-16}{10} \\\\ = \frac{65}{10} \\\\=\frac{13}{2} \\\\[/tex]

[tex]E[X^2] =\int^{9}_{4} \frac{x^2}{5}\ dx[/tex]

          [tex]= \frac{9^3-4^3}{3\cdot 5} \\\\= \frac{729-64}{15} \\\\ = \frac{665}{15}\\ \\=\frac{133}{3} \\\\[/tex]

[tex]\to Var(x) = \frac{133}{3} - (\frac{13}{2})^2 = \frac{25}{12}\\\\[/tex]

Therefore the standard deviation value is [tex]\frac{5}{2\sqrt{3}}[/tex]

Find out more about the probability here:

brainly.com/question/11234923

A new soft drink is being market tested. a sample of 400 individuals participated in the taste test and 80 indicated they like the taste.

A. At a 5% significant level, test to determine if at least 22% of the population will like the new soft drink.

B. Determine the p-value

Answers

Answer:

Step-by-step explanation:

p/100* 400=80

*100               *100

400p=8000

:400     :400

p=20

With 5% significant level I think we consider that 22% likes the drink

Which equation can be used to solve for x in the following diagram?

Answers

Answer:

x + (4x-85) = 90

Step-by-step explanation:

The two angles are complementary which means they add to 90 degrees

x + (4x-85) = 90

Answer: A

Step-by-step explanation:

Both angles are makes a right angle which adds up to 90 degrees so they both have to add up to 90 degrees.

Find the height of cylinder when volume is 154 cm^3 volume and radius is 3 cm

Answers

Answer:

Volume of a cylinder is πr²h

Where

r is the radius

h is the height

Volume = 154cm³

radius = 3cm

height = ? cm

154 = π × 3² × h

154 = π × 9 × h

154 = 9πh

divide both sides by 9π

h = 154/9π

h = 5.4cm

Height is 5.4cm

Hope this helps

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