The Oort Cloud is about 70 000 times as far as from Earth as Earth is from the Sun. How far away is the Oort Cloud?

Answer:

[tex]m=1.01\times 10^6\ kg[/tex]

Explanation:

Given that,

Pressure, P = 1 atm = 101325 Pa

Area of the square surface, A = 10² = 100 m²

We need to find the mass of vertical column of air. We know that, pressure is equal to the force acting per unit area. So,

[tex]P=\dfrac{mg}{A}\\\\m=\dfrac{PA}{g}\\\\m=\dfrac{101325\times 10^2}{10}\\\\m=1.01\times 10^6\ kg[/tex]

So, the required mass of the vertical column of air is [tex]1.01\times 10^6\ kg[/tex].

Answer:the answer is conduction

Answer:

A. Gravitational force

C. Their charges

Explanation:

As we'll discuss in this lesson, he found that the force between charged particles was dependent on only two factors: the distance between the particles and the amount of electric charge that they carried.

Hope it help you

have a good day :)

poste en français s’il vous plaît

Answer:

Assume that [tex]g =9.81\; \rm m\cdot s^{-1}[/tex], and that the air resistance on the stone is negligible.

a.

Height of the stone: [tex]389.5\; \rm m[/tex] (above the ground.)

Velocity of the stone: [tex]\left(-110.5\; \rm m \cdot s^{-1}\right)[/tex] (the stone is travelling downwards.)

b.

Height of the stone: [tex]629.5\; \rm m[/tex] (above the ground.)

Velocity of the stone: [tex]\left(-86.5\; \rm m \cdot s^{-1}\right)[/tex] (the stone is travelling downwards.)

Explanation:

If air resistance on the stone is negligible, the stone would be accelerating downwards at a constant [tex]a = -g = -9.81\; \rm m \cdot s^{-2}[/tex].

Let [tex]h_0[/tex] denote the initial height of the stone (height of the stone at [tex]t = 0[/tex].)

Similarly, let [tex]v_0[/tex] denote the initial velocity of the stone.

Before the stone reaches the ground, the height [tex]h[/tex] (in meters) of the stone at time [tex]t[/tex] (in seconds) would be:

[tex]\displaystyle h(t) = -\frac{1}{2}\, g \cdot t^{2} + v_0 \cdot t + h_0[/tex].

Similarly, before the stone reaches the ground, the velocity [tex]v[/tex] (in meters-per-second) of the stone at time [tex]t[/tex] (in seconds) would be:

[tex]v(t) = -g\cdot t + v_0[/tex].

In section a., [tex]h_0 = 1000\; \rm m[/tex] while [tex]v_0 = -12\; \rm m\cdot s^{-1}[/tex] (the stone is initially travelling downwards.) Evaluate both [tex]h(t)[/tex] and [tex]v(t)[/tex] for [tex]t = 10\; \rm m \cdot s^{-1}[/tex]:

[tex]\begin{aligned} h(t) &= -\frac{1}{2}\, g \cdot t^{2} + v_0 \cdot t + h_0 \\ &= -\frac{1}{2}\ \times 9.81\; \rm m\cdot s^{-2}\times (10\; \rm s)^{2} \\&\quad\quad + \left(-12\; \rm m \cdot s^{-1}\right) \times 10\; \rm s + 1000\; \rm m \\[0.5em] &= 389.5\; \rm m \end{aligned}[/tex].

Indeed, the value of [tex]h(t)[/tex] at [tex]t = 10\; \rm m \cdot s^{-1}[/tex] is greater than zero. The stone hasn't yet hit the ground, and both the representation for the height of the stone and that for the velocity of the stone are valid.

[tex]\begin{aligned} v(t) &= -g\cdot t + v_0 \\ &= -9.81\; \rm m\cdot s^{-2}\times 10\; \rm s - 12\; \rm m\cdot s^{-1} \\ &= -110.5\; \rm m \cdot s^{-1} \end{aligned}[/tex].

The value of [tex]v(t)[/tex] at [tex]t = 10\; \rm m \cdot s^{-1}[/tex] is negative, meaning that the stone would be travelling downwards at that time.

In section b., [tex]h_0 = 1000\; \rm m[/tex] while [tex]v_0 = 12\; \rm m\cdot s^{-1}[/tex] (the stone is initially travelling upwards.) Evaluate both [tex]h(t)[/tex] and [tex]v(t)[/tex] for [tex]t = 10\; \rm m \cdot s^{-1}[/tex]:

[tex]\begin{aligned} h(t) &= -\frac{1}{2}\, g \cdot t^{2} + v_0 \cdot t + h_0 \\ &= -\frac{1}{2}\ \times 9.81\; \rm m\cdot s^{-2}\times (10\; \rm s)^{2} \\&\quad\quad + 12\; \rm m \cdot s^{-1} \times 10\; \rm s + 1000\; \rm m \\[0.5em] &= 629.5\; \rm m \end{aligned}[/tex].

Verify that the value of [tex]h(t)[/tex] at [tex]t = 10\; \rm m \cdot s^{-1}[/tex] is indeed greater than zero.

[tex]\begin{aligned} v(t) &= -g\cdot t + v_0 \\ &= -9.81\; \rm m\cdot s^{-2}\times 10\; \rm s + 12\; \rm m\cdot s^{-1} \\ &= -86.5\; \rm m \cdot s^{-1} \end{aligned}[/tex].

Similarly, the value of [tex]v(t)[/tex] at [tex]t = 10\; \rm m \cdot s^{-1}[/tex] is negative because the stone would be travelling downwards at that time.

Answer:

24

Explanation:

momentum= mass* velocity

velocity= momentum/ mass

Answer:

2m/s^2

Explanation:

Force is equal to;

mass × acceleration

therefore;

acceleration equals

force divided by mass

acceleration = 2m/s ^2

Answer:

f = 60N

m = 30kg

f= m×a

60N= 30 × a

a = 60/30

a = 2

Answer:

The electric force decrease as the distance increase and vice versa

As it obeys inverse square law that states ththaforce is inversly proportional to square if distance

so if the distance increased to twice the force will be decreased to quarter.

And that is coloumb's law of electrostatic force:

Coulomb's law states that the electrical force between two charged objects is directly proportional to the product of the quantity of charge on the objects and inversely proportional to the square of the separation distance between the two objects.

F=k(Q1.Q2)/r2

So as you increase the distance between charged objects, Force(attraction/repulsion) weakens by the square of their distance.

As you decrease the distance between charged objects, Force strengthens by the square of their distance.

Inverse relationships are common in nature. In electrostatics, the electrical force between two charged objects is inversely related to the distance of separation between the two objects. Increasing the separation distance between objects decreases the force of attraction or repulsion between the objects. And decreasing the separation distance between objects increases the force of attraction or repulsion between the objects. Electrical forces are extremely sensitive to distance. These observations are commonly made during demonstrations and lab experiments. Consider a charged plastic golf tube being brought near a collection of paper bits at rest upon a table. The electrical interaction is so small at large distances that the golf tube does not seem to exert an influence upon the paper bits. Yet if the tube is brought closer, an attractive interaction is observed and the strength is so significant that the paper bits are lifted off the table. In a similar manner, charged balloons are observed to exert their greatest influence upon other charged objects when the separation distance is reduced. Electrostatic force and distance are inversely related.

The pattern between electrostatic force and distance can be further characterized as an inverse square relationship. Careful observations show that the electrostatic force between two point charges varies inversely with the square of the distance of separation between the two charges. That is, the factor by which the electrostatic force is changed is the inverse of the square of the factor by which the separation distance is changed. So if the separation distance is doubled (increased by a factor of 2), then the electrostatic force is decreased by a factor of four (2 raised to the second power). And if the separation distance is tripled (increased by a factor of 3), then the electrostatic force is decreased by a factor of nine (3 raised to the second power). This square effect makes distance of double importance in its impact upon electrostatic

Answer:

Charge

Explanation:

Answer:

nuclear energy

Explanation:

Answer:

the  frame of reference requires deciding where the object's initial position is and which direction will be considered positive.

Explanation:

Answer:

motion example of kinetic energy charged particle such as electrons and protons create electromagnetic field when they move in this field transport the type of energy vehicle electromagnetic radiation or light

Answer:

sound waves

Explanation:

this is because sound waves are longitudinal waves, and longitudinal waves are waves that travel parallel to the direction of the wave motion

thus it cannot be light or electromagnetic waves but only sound waves

hope this helps, please mark it

Answer:

Explanation:

20 watts

Answer:

The current flowing through the 4Ω resistor is;

C. 2.0 A

Explanation:

In the given figure, we have;

The series resistors in the bridge = 8Ω, and 4Ω are in series and 20Ω and 10Ω are in series

The sum of each of the series resistors are;

R₁ = 8Ω + 4Ω = 12Ω

R₂ = 20Ω + 10Ω = 30Ω

The equivalent resistors of the series resistors, R₁ and R₂ are parallel to each other

The current flowing through the 4Ω resistor = The current in R₁ = I₁

By the current divider rule, we have;

[tex]I_1 = \dfrac{R_2}{R_1 + R_2} \cdot I[/tex]

[tex]I_1 = \dfrac{30\Omega }{12 \Omega + 30 \Omega} \times 2.8 \, A = 2.0 \, A[/tex]

Therefore, I₁ = 2.0 A

The current flowing through the 4Ω resistor = I₁ = 2 A

Answer:

friction as friend

friction as foe

hope it helps

Answer:

Wear and tear of soles of our shoes is due to friction.

When a tyre deflates, it is difficult to move the vehicle because of increased friction between the tyre and the road surface.

Machines get heated up and produce noise because of friction.

Inner Planets:

- Rocky

- Small

- Only 3 moons total

- Very close to each other (for space)

- Underweight

Outer Planets:

- Gassy oop-

- GIANT

- Over 200 moons total

- VERY far from each other

- Obese

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Good luck foe.

Lb.

Answer:

Follows are the soplution to this question:

Explanation:

In the given scenario it would be like a fluid in a simple harmonic in contact with the earth. Whenever a cheetah hops quicker, oscillatory amplitude rises, while the duration stays the same since it does not depend on frequency, which mostly means that time will be the same if you're in contact with the substrate.

Answer:

the number of donated valence electrons

Explanation:

  A metallic bond is formed when atoms come together in a metallic crystal lattice.

The metal atoms are usually ionized such that in a metallic crystal lattice consists of metal ions and a sea of mobile electrons. Attraction between these positively charged ions and the sea of electrons constitutes the metallic bond.

Hence, the more the number of donated valence electrons, the stronger the metallic bond.

Answer:

papa's donuteria

Explanation:

:rawr:

Answer:

300 pascals

Explanation:

P=F/A

P=15N/0.05

P=300 pascals

Answer:

P = 22 watts

Explanation:

Given that,

The output power of the generator = 2 a

The output potential difference = 11 V

We need to find the output power of the generator. The formula for the output power is given by :

[tex]P=V\times I\\\\P=11\times 2\\\\P=22\ W[/tex]

So, the output power of the generator is equal to 22 Watts.

Answer:

  w = 16.73 rad / s,  v = - 1.04 m / s

Explanation:

This is an exercise in oscillatory motion of a system of a spring and a mass, the angular velocity is

         w = [tex]\sqrt{ \frac{k}{m} }[/tex]

To calculate the spring constant we use the data that Δx = 3.5 cm = 0.035 m with a mass of m = 0.38 kg, let's write Hooke's law

          F = -kx

in this case the applied force is the weight of the body

          F = W

we substitute

          mg =  k x

          k = m g / x

         k = 0.38 9.8 / 0.035

         k = 106.4 N / m

let's find the angular velocity

         w = Ra 106.4 / 0.38

         w = 16.73 rad / s

the movement of this system is described by the expression

          ax = A cos (wt + Ф)

the quantity A is called the amplitude of the movement in this case A = 7.5 cm = 0.075 m

to encode the constant we use that the system is released from its position of maximum displacement (x = A)

we substitute

          A = A cos (0 + Ф)

         cos Ф = 1

         Ф = cos-1 1

         Ф = 0º

by substituting in the equation of motion

            x = 0.075  cos (16.73 t)

Let's find the time it takes to reach the desired position x = 4.2 cm = 0.042 m

           cos 16.73 t = 0.042 / 0.075 = 0.56

            16.73 t = cos -1 0.56

remember that angles must be expressed in radians

            t = 0.976 / 16.73

            t = 0.0583 s

body velocity is

           v = [tex]\frac{dx}{dt}[/tex]

            v = -0.075 16.73 sin 16.73t

let's calculate for the time found

           v = - 1.25475 sin (16.73  0.0583)

           v = - 1.04 m / s

Answer:

yellow

Explanation:

yellow

make me brain

Answer:

The trucks must have equal masses that is they must have same load.

Explanation:

Momentum refers to the product of the mass of the object and velocity.

As momentum has both magnitude and direction, it is a vector quantity.

In the given problem, it is given that after the collision, the trucks move at more than half the original speed of the moving truck. Therefore, the trucks must have equal masses that is they must have the same load.

Answer: The answer is A

Explanation: