Answer:
c) marketing and selling products that use ore materials
What affect does doubling the net force have on the acceleration of the object (when
the mass of the object stays the same)? Identify a set of two trials that support your answer to question 1
===========================================================
Explanation:
Consider a mass of 10 kg, so m = 10
Let's say we apply a net force of 20 newtons, so F = 20
The acceleration 'a' is...
F = ma
20 = 10a
20/10 = a
2 = a
a = 2
The acceleration is 2 m/s^2. Every second, the velocity increases by 10 m/s.
---------------
Now let's double the net force on the object
F = 20 goes to F = 40
m = 10 stays the same
F = ma
40 = 10a
10a = 40
a = 40/10
a = 4
The acceleration has also doubled since earlier it was a = 2, but now it's a = 4.
---------------
In summary, if you double the net force applied to the object, then the acceleration doubles as well.
Acceleration is directly proportional to the net force on an object, and inversely proportional to its mass.
So if an object's mass stays the same while the net force on it doubles, then its acceleration will also double.
We don't know anything about the "trials". This sounds like it might be a follow-up to a lab experiment that was performed when we weren't there.
We also don't know anything about "question 1".
What does Newton's third law describe?
A. Equal and opposite forces
B. How the amount of mass influences the amount of force needed
to move an object
C. The tendency of moving objects to stay in motion
D. The attractive force between two objects due to their masses
a meteor Falls towards Earth's surface given that the acceleration due to gravity is 9.8 m/s^2 what is the meteors potential energy if it has a mass of 20kg at an altitude of 500
Answer: It’s 98,000
Explanation: Just did it on apex
Given 1 inch ≡ 2.54 cm and 1 foot ≡
12 inches, how many square centimeters are
in 3.22 ft2
?
Answer:
2991.47 [cm^2]
Explanation:
To solve this problem we must perform a dimensional analysis and use the corresponding conversion values:
[tex]3.22[ft^{2}]*\frac{12^{2}in^{2} }{1^{2}ft^{2}} *\frac{2.54^{2}cm^{2} }{1^{2}in^{2} } \\2991.47[cm^{2}][/tex]
If a hypothesis is.......
additional tests should be done to ensure accurate results.
a. correct
b.incorrect
c. unknown
d. inconclusive
Answer:
a correct
Explanation:
a hypothesis is a supposition made of a basis of limited evidence
A 2000 kg car moves along a horizontal road at speed vo
15.9 m/s. The road is
wet, so the static friction coefficient between
the tires and the road is only pls 0.105 and
the kinetic friction coefficient is even lower,
= 0.0735.
The acceleration of gravity is 9.8 m/s2.
What is the shortest possible stopping dis-
tance for the car under such conditions? Use
g= 9.8 m/s² and neglect the reaction time of
the driver.
Answer in units of m.
Answer:
The shortest possible stopping distance of the car is 175.319 meters.
Explanation:
In this case we see that driver use the brakes to stop the car by means of kinetic friction force. Deceleration of the car is directly proportional to kinetic friction coefficient and can be determined by Second Newton's Law:
[tex]\Sigma F_{x} = -\mu_{k}\cdot N = m \cdot a[/tex] (Eq. 1)
[tex]\Sigma F_{y} = N-m\cdot g = 0[/tex] (Eq. 2)
After quick handling, we get that deceleration experimented by the car is equal to:
[tex]a = -\mu_{k}\cdot g[/tex] (Eq. 3)
Where:
[tex]a[/tex] - Deceleration of the car, measured in meters per square second.
[tex]\mu_{k}[/tex] - Kinetic coefficient of friction, dimensionless.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
If we know that [tex]\mu_{k} = 0.0735[/tex] and [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], then deceleration of the car is:
[tex]a = -(0.0735)\cdot (9.807\,\frac{m}{s^{2}} )[/tex]
[tex]a = -0.721\,\frac{m}{s^{2}}[/tex]
The stopping distance of the car ([tex]\Delta s[/tex]), measured in meters, is determined from the following kinematic expression:
[tex]\Delta s = \frac{v^{2}-v_{o}^{2}}{2\cdot a}[/tex] (Eq. 4)
Where:
[tex]v_{o}[/tex] - Initial speed of the car, measured in meters per second.
[tex]v[/tex] - Final speed of the car, measured in meters per second.
If we know that [tex]v_{o} = 15.9\,\frac{m}{s}[/tex], [tex]v = 0\,\frac{m}{s}[/tex] and [tex]a = -0.721\,\frac{m}{s^{2}}[/tex], stopping distance of the car is:
[tex]\Delta s = \frac{\left(0\,\frac{m}{s} \right)^{2}-\left(15.9\,\frac{m}{s} \right)^{2}}{2\cdot \left(-0.721\,\frac{m}{s^{2}} \right)}[/tex]
[tex]\Delta s = 175.319\,m[/tex]
The shortest possible stopping distance of the car is 175.319 meters.
What is better for measuring how hard you are actually working, Target Heart Rate or Rating of perceived exertion?
Answer:
Rating of percieved exertion
Can you pls answer the 2 questions
Answer:
1) False, since constant speed means constant velocity, but with constant direction as well. Velocity is speed with direction. When you move in a circle, there are boundaries which means that a constant moving speed will cause the object to veer(move in different directions) to maintain movement, If it doesn't veer, the object will deflect(rebound) off the surface due to friction, and impact force or depending on its physical bond of malleability or density.
2a) Create position vectors by drawing a ray from the center(origin) of the circle to each of your desired points, it's magnitude will be the radius(how convenient). Both of these vectors go from the center of the circle to the position on the circle. In general, the distance from the origin to a point is called the radius vector.
2b)
does anyone know how to do this
Polymetrics can help a person maintain cardiorespitory fitness T or F
Answer:
True
Explanation:
The term 'plyometrics' is used interchangeably with the term 'jump training'. The technique can be used for training in sports that require explosive movements.
what is measurement ?
Answer: Measurement is the assignment of a number to a characteristic of an object or event, which can be compared with other objects or events. The scope and application of measurement are dependent on the context and discipline. In the natural sciences and engineering, measurements do not apply to nominal properties of objects or events, which is consistent with the guidelines of the International vocabulary of metrology published by the International Bureau of Weights and Measures. However, in other fields such as statistics as well as the social and behavioural sciences, measurements can have multiple levels, which would include nominal, ordinal, interval and ratio scales.
Explanation:
Covert 1 mile to feet. Then convert to inches. Then covert to centimeters. How many centimeters are in a mile?
Answer:
160,934.4 cm or in other words *160,934*
Explanation:
1 mile = 5280 ft.
5280 ft. = 63360 in.
63360 in. = 160934.4
a car travels 200m in 30 s and 400m in the next 90s. Whats the average speed?
Answer:
300m per minute or 5m per second
I WILL GIVE BRAINLIEST A battery contains two metals that have different tendencies to attract electrons. If one is lithium with an electron affinity of −3.05, and the other is zinc with an electron affinity of −0.76, describe how the electrons will flow. Then, describe how you could make this an even stronger battery. (4 points)
Answer:
electrons will flow from lower (lithium) to higher (zinc)
You can make a stronger battery by having a larger electron affinity difference.
Hope this helps \(-._.-)/
PLEASE HURRYYYYYY:
Students had two batteries and two different resistors. During four trials, they build four different circuits and plan to measure the circuit’s current in Amps according to the following table.
Trial Number
Voltage (V)
Resistance (Ω)
Current (A)
1
1.5
200
2
1.5
100
3
3.0
200
4
3.0
100
For which trial would the students measure the smallest current in the circuit?
Answer: C. Trial 3
Explanation:
Trial 1 and 2 equal 1.5, Trial 3 equals 1 and Trial 4 equals 3. Trial 3 is the smallest current .
The trial for which the students would measure the smallest current is the circuit is trial 2 and trial 3.
To know the trial which generates the smallest current, we need to determine the current in each trial.
Since current I = V/R where V = voltage and R = resistance.
For trial 1, V = 1.5 V and R = 200 Ω
So, I = 1.5 V/200 Ω
= 0.0075 A
= 7.5 mA
For trial 2, V = 1.5 V and R = 100 Ω
So, I = 1.5 V/100 Ω
= 0.015 A
= 15 mA
For trial 3, V = 3 V and R = 200 Ω
So, I = 3 V/200 Ω
= 0.015 A
= 15 mA
For trial 4, V = 3 V and R = 100 Ω
So, I = 3 V/100 Ω
= 0.03 A
= 3 mA
Trial 2 and trial 3 both produce a the smallest current of 15 mA.
So, the trial for which the students would measure the smallest current is the circuit is trial 2 and trial 3.
Learn more about current here:
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A battery of emf 24v and terminal resistance 4 ohms is connected to a resistor of 32 ohms. What is the terminal pd of the battery?
Answer:
21.3V
Explanation:
Explanation
E = V + Ir
V = E- Ir
V = 24 - {(24/36) x 4}
V = 21.3V
A ball of mass 200 g rolls along the ground at a speed of 5.2 m/s. Calculate the kinetic energy of the ball.
Answer:
We have a mass of 200g (0.2kg) moving at 20m/s
Kinetic Energy KE = ½ mv^2 where m is mass and v is velocity
Actually, v is a vector quantity, so KE = ½ mv•v
The dot product of 2 vectors a and b is abCosθ where θ is the angle between the vectors.
Obviously v•v = v^2 Cos0 = v^2
In this case, we have KE = ½ (0.2)(20^2) = 40kg-m^2/s^2 = 40J
So we have kinetic energy in the amount of 40 Joules.
Explanation:
The right answer is "2.7 J"
Answer explanation:
Remember to convert grams to kilograms first by dividing by 1000.
Kinetic energy
= 1/2 × mass × speed2
= 1/2 × 0.2 kg × (5.2 m/s)^2
= 2.7 J (to 2 sig. fig.)
Hope it helps ✨✨
Muscles covert chemicals energy int
Answer:
Mechanical energy
Explanation:
Mechanical energy is needed for movement of objects. Muscles convert chemical energy provided by the rest of the body to allow movement.
how many apples are in 29 trees if each tree has 45 apples?
Answer:
1305 I think but not sure
A book with a mass of 1kg is dropped from a height of 3m . What is the potential energy of th book when it reaches the floor?
Answer:
30 J
Explanation:
height = 3 m
mass = 1kg
acceleration due to gravity = 10m/s²
Potential Energy = mass× gravity × height
= 1kg ×10m/s²× 3m
= 30 J
If a bicyclist travels at 15 km/h, how long will it take her to travel 30 km?
The level of toluene (a flammable hydrocarbon) in a storage tank may fluctuate between 10 and 400 cm from the top of the tank. since it is impossible to see inside the tank, an open-end manometer with water or mercury as the manometer fluid is to be used to determine the toluene level. one leg of the manometer is attached to the tank 500 cm from the top. a nitrogen blanket at atmospheric pressure is maintained over the tank contents. felder, richard m.; rousseau, ronald w.; bullard, lisa g.. elementary principles of chemical processes, 4th edition (page 81). wiley. kindle edition.
Complete Question
The complete question is shown on the first and second uploaded image
Answer:
When water is used the reading is [tex] R = 2281.6 \ cm [/tex]
When mercury is used the reading is [tex] R = 23.83 \ cm [/tex]
The best fluid to use is mercury because for water a slight change in toluene level will cause a large change in height .
Explanation:
From the question we are told that
The length of the leg of the manometer to the top of the tank is d = 500cm
The toluene level where in the tank where the height of the manometer fluid level in the open arm is equal to the height where the manometer is connected to the tank is h =150 cm
The manometer reading is R
Generally at the point where the height of the open arm is equal to the height of the of the point connected to the tank ,
The pressure at the height of the both arms of the manometer corresponding to the base of the tank are equal
i.e [tex]P_1 = P_2[/tex]
Here [tex]P_1[/tex] is the pressure of the manometer at the point corresponding to the base of the tank and this is mathematically represented as
[tex] P_{atm} + P_1 = P_{atm} + P_t[/tex]
Here [tex]P_t[/tex] is the pressure due to the toluene level in the tank and in the arm of the manometer connected to the tank and this is mathematically represented as
[tex]P_t = \rho_t * g * h_i[/tex]
Here
[tex]\rho_t [/tex] is the density of toluene with value [tex]\rho_t = 867 kg/m^3 [/tex]
[tex]h_i[/tex] is the height of the connected arm above the point equivalent to the base of the tank , this mathematically represented as
[tex]h_i = d - h + R[/tex]
and [tex] P_2 [/tex] is the the pressure at the open arm of the manometer at the point equivalent to the base of the base of the tank and this is mathematically represented as
[tex] P_2 = \rho_f * g * h_f [/tex]
Here
[tex]\rho_f[/tex] is the density of the fluid in use , if it is water the density is
[tex]\rho_w = 1000 \ kg /m^3 [/tex]
and if it is mercury the density is
[tex]\rho_m = 13600 \ kg /m^3 [/tex]
[tex]h_f[/tex] is the height of the fluid in the open arm of the manometer from the point equivalent to the base of the tank which is equivalent the manometer reading R
So when the fluid is water we have
[tex] P_{atm} + \rho_t* g *(d - h + R) = P_{atm} + \rho_f * g * h_f[/tex]
=> [tex] \rho_t* (d - h + R) = \rho_w * h_f[/tex]
=> [tex] 867 (500 - 150 + R) = 1000 * R [/tex]
=> [tex] R = 2281.6 \ cm [/tex]
So when the fluid is mercury we have
[tex] \rho_t* (d - h + R) = \rho_m * h_f[/tex]
=> [tex] 867 (500 - 150 + R) = 13600 * R [/tex]
=> [tex] R = 23.83 \ cm [/tex]
The difference in the mercury reading for mercury due to the fact that they have different densities as we have seen in this calculation
So the best fluid to use is mercury because for water a slight change in toluene level will cause a large change in height .
How do you calculate the radius of a planets orbit with mass and time ?
Answer:
By observing the time between transits, we know the orbital period. Kepler's Third law can be used to determine the orbital radius of the planet if the mass of the orbiting star is known (R3=T2−Mstar/Msun, the radius is in AU and the period is in earth years).
Explanation:
hope this helps!
A tree is turned into sawdust is that physical change or chemical change?
Answer:
Physical change
Explanation:
A physical change can be reversible where the original form of the matter can be restored, or irreversible where the original form cannot be restored. Therefore, sawdust is a physical change.
I need help with this physics question
Using only one management style with all people is the most effective leadership technique for any organization.
Answer:
False
Explanation:
More than one management style with all people is the most effective leadership technique for any organization. So, the given statement is False.
What is Leadership technique?Leadership styles are defined as those adopted by company leaders to increase efficiency, satisfaction, growth and advancement in all positions in the organization. It requires a different style in different situations and each leader needs to know when to show a special behavior.
These strategies define every leader's personal leadership style. Some effective leadership Techniques are as follows:
Understanding the objectives clearlyGet to know the teamAlways be a learnerListen.Learn to delegate.Thus, more than one management style with all people is the most effective leadership technique for any organization. So, the given statement is False.
Learn more about Marketing techniques, here:
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a student pushes a book with a force of 5 N to the east.which statement
describes the reaction force?
Answer:
5N westward, acting on the student
Explanation:
Answer: 5N westward, acting on the student
Explanation:
A loaf of bread bakes in an oven. The bread is on a rack about one foot above the heat source. However, the top of the bread cooks just as fast as the bottom. How is heat being added to the bread?
Answer:
the bread is getting heated from top and bottom because the oven is heated all over and the particles from the oven makes the bread's particles heat up and the bread will be done
Explanation:
i have the same answer
Answer:
The air is heated by the heat source in the oven. The hot air rises, surrounds the bread, and heats the bread on all sides.
Explanation:
What is a scientific theory?
Answer:
Scientific theories are explanations of some aspect of the natural world based on repeated observations.
Hope this helps!!!!
Answer:
The way that scientists use the word 'theory' is a little different than how it is commonly used in the lay public," said Jaime Tanner, a professor of biology at Marlboro College. "Most people use the word 'theory' to mean an idea or hunch that someone has, but in science the word 'theory' refers to the way that we interpret facts.
Explanation:
HELP ME PLEASE. i need to turn this in by tomorrow, also pls use the words above^ thank you i’ll mark u the brainliest.
Answer:
the corrdct answer is core