The mass of the fuel is 133 kilograms. The result is obtained by using the formula for the density.
What is the density of a substance?The density is the mass of a substance per unit of volume. It can be expressed as
ρ = m/V
Where
ρ = densitym = massV = volumeA jet 747 is fueled with jet fuel.
V = 173.231 L ρ = 0.768 g/cm³Find the mass of the fuel!
We convert the units of volume and density.
V = 173.231 L
V = 173.231 dm³
V = 173.231 × 1/1000 m³
V = 0.173231 m³
ρ = 0.768 g/cm³
ρ = 0.768 × 1000 kg/m³
ρ = 768 kg/m³
Using the formula for a density, we will get the mass.
ρ = m/V
768 = m/0.173231
m = 0.173231 × 768
m ≈ 133 kg
Hence, the jet fuel has a mass of 133 kilograms.
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1. A student is sitting on the edge of a swimming pool. The student repeatedly dips his foot in and out of the pool, making waves that move across the water. The student dips his foot slowly at first and then does it faster, each time to the same depth. Which of the following properties of the waves increases as the student dips his foot faster?
A. frequency
B. period
C. velocity
D. wavelength
Frequency of the waves increases as the student dips his foot faster.
What is frequency?
Frequency is a measure of how often something occurs over a given period of time. It can be used to measure the rate of events, such as the number of times a sound or light wave occurs in a given second. Frequency is measured in hertz (Hz), which is the number of occurrences per second. Frequency can also refer to the number of times a certain event occurs in a given sample size, such as the number of times a person visits a website in a month. It is a common measure used in statistics and is often used to compare data sets.
Therefore, Frequency of the waves increases as the student dips his foot faster.
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A skydiver is falling through the air because his:____. question 7 options: a. weight is over 100 n b. weight force down is greater than the air drag c. drag force needs to be at least 50 n because nothing can stop gravity from making an object fall
The correct option is B. weight force down is greater than the air drag.
What is weight force?Weight force is the force of gravity acting on a body or object. It is the magnitude of the force of gravity acting on an object or body and is determined by the object or body's mass multiplied by the acceleration due to gravity. Weight force is a type of force, and is a vector quantity which has both magnitude and direction. Weight force acts in the downward direction of the Earth's gravitational field and its direction is always towards the center of the Earth. Weight force is important in determining the motion of objects and bodies, and is one of the most important fundamental forces in physics.
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When a charged balloon sticks to a wall the downward gravitational force is balanced by an upward static friction force. The normal force is provided by the electrical attraction between the charged balloon and the equal but opposite charged polarization induced in the walls molecules. If the mass of the balloon is 1. 4g it's coefficient of static friction with the wall is. 73 and the average distance between the opposite charges is. 75mm what minimum amount of charge must be placed on the balloon in order for it to stick to the wall
The balloon needs to be charged with a minimum of 1.3 x 10-10 Coulombs for it to adhere to the wall.
To find the minimum amount of charge required on the balloon for it to stick to the wall, we can use the following equation:
Friction force = friction coefficient x normal force
The electrical attraction between the charged balloon and the molecules of the wall, which cause an equal but opposing charged polarization, produces the normal force and may be computed as follows:
Normal force = k x q1 x q2 / r^2
where k is Coulomb's constant, q1 and q2 are the charges on the balloon and the wall's molecules, respectively, and r is the average distance between the opposite charges.
The gravitational force acting on the balloon is given by:
Fg = m x g
Since the downward gravitational force is balanced by the upward static friction force, we can set the gravitational force equal to the friction force:
m x g = friction coefficient x k x q1 x q2 / r^2
Solving for q1, the charge on the balloon, we have:
q1 = (m x g x r^2) / (friction coefficient x k x q2)
Given that the mass of the balloon is 1.4 g, coefficient of static friction with the wall is 0.73, the average distance between the opposite charges is 0.75mm, and Coulomb's constant is 910^9 Nm^2/C^2.
q1 = (1.4 x 9.8 x (0.75 x 10^-3)^2) / (0.73 x 9 x 10^9)
The minimum amount of charge required on the balloon in order for it to stick to the wall is 1.3*10^-10 Coulombs
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a baseball player feels a frictional force of 400N as she slides into home. what impulse would be created?
The impulse that would be created by the baseball player is 600 Ns.
What is the impulse created by the baseball player?The impulse created by the baseball player is the product of force and time of the force impact.
J = Ft
where;
F is the applied forcet is the time of force actionThe frictional force created by the baseball player = 400 N.
The time of force action = 1.5 seconds
The impulse that would be created by the baseball player is calculated as follows;
J = 400 N x 1.5 seconds
J = 600 Ns
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The complete question is below:
A baseball player feels a frictional force of 400N as she slides into home. what impulse would be created if the force acted for 1.5 seconds?
A 60 kilogram person jumps off a platform, landing while moving at 2. 0 meters per second. Determine the force exerted on the persons feet when he lands if he stops in 0. 25 seconds
The force exerted on the person's feet when he lands if he stops in 0. 25 seconds is found to be 480 N.
What is Force?Force may be characterized as a type of circumstance that significantly deals with the pushing or pulling of an object resulting from the object's interaction with another object. Whenever there is an interaction between two objects, there is a force upon each of the objects.
According to the context of this question,
The mass of a person, m = 60 Kg.
The velocity of a person, v = 2.0 meters/sec.
The time is taken, t = 025 seconds.
The formula for calculating force is as follows:
F = mv/t.= 60 × 2 ÷ 0.25 = 480 N.
Therefore, the force exerted on the person's feet when he lands if he stops in 0. 25 seconds is found to be 480 N.
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Why is it that the lower mass individual may appear to experience more force from the larger mass player in a collision?
Answer:
One possible reason is that change in velocity is greater for the individual with lower mass.
Explanation:
By Newton's Law of Mechanics, magnitude of the force on two players would be the same in the collision. Let [tex]F[/tex] denote this magnitude.
Assume that the duration of the collision is [tex]\Delta t[/tex]. In this collision, magnitude of the impulse [tex]J[/tex] on each player would be the same: [tex]J = F\, \Delta t[/tex].
At the same time, impulse is equal to the change in momentum. Specifically, if the mass of one player is [tex]m[/tex] and the change in their velocity is [tex]\Delta v[/tex], the change in their momentum would be [tex]m\, \Delta v[/tex]. Thus:
[tex]m\, \Delta v = J = F\, \Delta t[/tex].
Rearrange to obtain an expression for the change in velocity:
[tex]\begin{aligned}\Delta v &= \frac{J}{m} = \frac{F\, \Delta t}{m}\end{aligned}[/tex].
In other words, in this collision, change in velocity is inversely proportional to the mass of the participant. Hence, even though the two players experienced force of the same magnitude, the participant with a lower mass would experience a greater change in velocity.
what are tiny solid and liquid particles of matter suspended in the atmosphere?
Answer:
I think the answer you're looking for is particulate matter.
Explanation:
why (if you are careful) are you able to float a needle on the surface of water?water has adhesive properties.
Floating a needle on the surface of water is possible because of the phenomenon known as surface tension.
Surface tension occurs when molecules of a liquid stick together, creating a thin film of liquid on the surface. This film is able to support objects that are light enough to float.
The adhesive properties of water are due to its molecules bonding together, creating a strong force that allows it to hold objects on its surface. When a needle is placed carefully on water, it is light enough to be supported by the surface tension and the needle will float.
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a) Two tugboats are towing a tanker of mass 3.30 x 107 kg. If one tug is pulling at 2.40 X 104 N [E16°N] and the other is pulling at 2.40 x 104 N [E9°S], calculate the acceleration of the tanker, assuming no resistance. Use both vector methods to solve this part of the problem.
b) If the tanker has a resistive force on it of 5.60 x 10³ N, find its acceleration using the component method.
c) Calculate the speed reached in each of the two cases after 2.0 minutes. Convert it to km/h.
d) Calculate the distance required in each case to reach a speed of 5.0 km/h.
So the net force acting on the tanker is: F_net = sqrt(Fx^2 + Fy^2) = 2.4 x 10^4 N And the acceleration of the tanker is: a = F_net / m = 2.4 x 10^4 N / 3.3 x 10^7 kg = 7.27 x 10^-4 m/s^2.
How to calculate net force and acceleration?
To find the acceleration of the tanker using vector methods, we can use the following equation:
F_net = ma
where F_net is the net force acting on the tanker, m is the mass of the tanker, and a is the acceleration of the tanker.
In this case, the two tugboats are pulling in opposite directions, so we need to find the vector sum of their forces to find the net force acting on the tanker.
Using the component method, we can find that the x-component of the net force is:
Fx = 2.4 x 10^4 N * cos(16) - 2.4 x 10^4 N * cos(9) = -2.4 x 10^4 N
and the y-component of the net force is:
Fy = 2.4 x 10^4 N * sin(16) + 2.4 x 10^4 N * sin(9) = 0 N
So the net force acting on the tanker is:
F_net = sqrt(Fx^2 + Fy^2) = 2.4 x 10^4 N
And the acceleration of the tanker is:
a = F_net / m = 2.4 x 10^4 N / 3.3 x 10^7 kg = 7.27 x 10^-4 m/s^2
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your friend, who is in a field 70 meters away from you, kicks a ball towards you with an initial velocity of 18 m/s. assuming the grass causes the ball to decelerate at a constant rate of 1.0 m/s2, how long does it take for the ball to reach you?
With the use of formula, the time taken for the ball to reach you is 31.6 s
What is Acceleration ?Acceleration can be defined as velocity change per time taken. It is a vector quantity.
Given that your friend, who is in a field 70 meters away from you, kicks a ball towards you with an initial velocity of 18 m/s. assuming the grass causes the ball to decelerate at a constant rate of 1.0 m/s2, to know how long it takes for the ball to reach you, we will use the formula
s = ut - 1/2at² where
v = 0
u = 18 m/s
a = 1 m/s²
s = 70 m
t = ?
70 = 18t - 1/2 × 1 × t²
70 = 18t - 0.5t²
Multiply all by 2
140 = 36t - t²
t² - 36t + 140 = 0
Using completing the square method
t² - 36t + 18² = 18² - 140
( t - 18 )² = 324 - 140
( t - 18 )² = 184
t - 18 = √184
t = 18 + 13.6 or 18 - 13.6
t = 31.6 s or 3.4 s
Therefore, the ball will reach you in the next 31.6 s
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medical x-rays have a wavelength of 0.052 nm. calculate the frequency of light, in hz (1/s), that this wavelength corresponds to?
The frequency of the light is 5.77 × 10¹⁸ Hz, if the wavelength of the x-rays is 0.052 nm.
Wavelength of the x-ray, λ = 0.052 nm = 5.2 × 10⁻¹¹ m.
Speed of x-rays, v = 3 × 10⁸ m/s
Let the frequency of the x-ray, = n
We know the relationship between speed of the wave, wavelength and the frequency of the wave is as follows:
speed = wavelength × frequency
3 × 10⁸ = 5.2 × 10⁻¹¹ × n
n = (3 × 10⁸)/(5.2 × 10⁻¹¹)
n = 5.77 × 10¹⁸ Hz
Alternate unit of frequency is 1/sec.
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if dust deosnt have an intitial charge , then how can a charged object(such as a piece of paper) attract bits of dust, since coulombs law states tgat two different charges are needed for an attractive force?
Dust particles can acquire a charge through a process called triboelectrification, which occurs when two materials rub against each other, transferring electrons from one material to the other.
What is triboelectrification?Triboelectrification is the phenomenon in which a charge is generated through the contact and separation of two materials. It is also known as "friction electrification" or "contact electrification".
When dust particles rub against a piece of paper, transferring electrons from the dust particles to the paper and giving the dust particles a negative charge. Once the dust particles have acquired a charge, they can be attracted to a charged object, such as a piece of paper, through Coulomb's law, which states that objects with opposite charges will experience an attractive force.
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study the editorial cartoon total eclipse 2017 by nate beeler. what is the purpose of this editorial cartoon? to show that today's kids are interested in learning about astronomical events to show that technology prevents people from directly experiencing major events to show how small computers have become with advances in technology to show that children often do not realize what is going on around them
To illustrate how technology keeps people from experiencing significant events firsthand, consider Nate Beeler's editorial comic Total Eclipse 2017.
The editorial cartoon's goal is unclear?Cartoon editorials share this educational goal with prose editorials. They are created with the intention of getting readers to reflect on contemporary political concerns. A reader-friendly visual and linguistic language is required for editorial cartoons.
What viewpoint possesses the cartoonist?someone's opinion or point of view on something. How might a political cartoonist's point of view be impacted. The point of view of a cartoonist will direct their work. The opinions of others may be taken into consideration by cartoonists, or they may solely express their own opinions.
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a 2.0-mm-diameter glass bead is positively charged. the potential difference between a point 2.0 mm from the bead and a point 4.0 mm from the bead is 500 v. what is the charge on the bead?
The glass bead has a 0.001 m radius. The distance between the first and second points from the bead's center is 0.003 and 0.005 meters, respectively.
How big is a circle's radius?The radius of a circular is the distance a circle's center from any point along its perimeter. Usually, "R" or "r" is used to indicate it.
In geometry, what is a radius?A radius is indeed a line segment that has one endpoint in the circle's center and the other terminus on the circumference of the circle. Circle's diameter equals the radius The diameter of a circle is a line segment that has its ends on the circle and passes through its center. Radius x 2 equals the diameter.
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a quartz crystal vibrates with a frequency of 77,621 hz. what is the period of the crystal's motion?
Formula for period:
[tex]T=\dfrac{1}{f}[/tex]
period(measured in seconds) = 1 / frequency(measured in hertz)
__________________________________________________________
Given:
[tex]f=77,621Hz[/tex]
[tex]T=?[/tex]
__________________________________________________________
Finding period:
[tex]T=\dfrac{1}{f}[/tex]
[tex]T=\dfrac{1}{77,621}[/tex]
__________________________________________________________
Answer:
[tex]\fbox{T = 0.0000129}[/tex]
a 1,200 kg car is traveling at 10 m/s. what is the minimum distance at which an automatic braking system needs to activate to avoid hitting a stationary object? (note: the braking system can decelerate the car at 2 m/s2.) a. 2.5 m b. 5.0 m c. 25 m d. 50 m
The minimum distance at which an automatic braking system needs to activate to avoid hitting a stationary object is 2.5 meter. The correct answer is a.
To calculate this, we can use the equation:
distance = initial velocity² / (2 × deceleration).
In this case, the initial velocity is 10 m/s and the deceleration is 2 m/s². Plugging these values into the equation gives us:
distance = 10² / (2 × 2)
distance = 25 meter
Since the car's speed is slowing down at a rate of 2m/s², the car will need 25 meter distance to come to a complete stop. However, the question asked for the minimum distance at which the automatic braking system needs to activate, therefore the minimum distance at which the automatic braking system needs to activate is 10% of the stopping distance which is:
10/100 × 25 = 2.5 meter
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A small car (1400 kg) moving 35 m/s gradually comes to a complete
stop when the brakes are applied. It comes to a complete stop over a
period of 15.2 seconds. What is the force in newtons that is exerted
on the car during this time? (Remember, the force is negative
because it is exerted opposite to the motion).
The force in newtons that is exerted on a car during the given time is 3,223.68N.
How to calculate force?Force refers to a physical quantity that denotes ability to push, pull, twist or accelerate a body.
The force exerted on an object can be calculated by multiplying the mass of the body by the acceleration as follows:
Force = mass × acceleration
Force = mass × speed/time
According to this question, a small car (1400 kg) moving 35 m/s gradually comes to a complete stop when the brakes are applied. It comes to a complete stop over a period of 15.2 seconds.
Force = 1400 × 35/15.2
Force = 3,223.68N
Therefore, 3,223.68N is the force acting on the small car.
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Two people push on a shopping cart from opposite sides. In which situation
will the motion of the shopping cart stay the same?
A. The two people push with different amounts of force.
B. One of the people stops applying a force.
C. One of the people applies twice as much force.
D. The two people push with a balanced
face
Two people push on a shopping cart from opposite sides. Situation will the motion of the shopping cart stay the same, the correct option is (D) The two people push with a balanced face.
In this situation, the net force on the shopping cart will be zero, since the two forces are equal in magnitude and opposite in direction. If the forces are balanced, the shopping cart will not accelerate and will stay in the same state of motion (at rest or moving at a constant velocity). In scenario A and C, the forces are not balanced and therefore will cause acceleration. In scenario B, the net force will be non-zero and the acceleration will cause the shopping cart to change its velocity and direction.
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An experiment is conducted to determine the thermal conductivity of a hot dog. First water is boiled in a large pan and measured to have a temperature of 94°c (at an elevation of 1650 m). The hot dog has dimensions of 12. 5 cm long and 2. 2 cm in diameter
Thermal conductivity may be measured with simple equipment.A slab of the material to be tested is clamped between an ice block and a steam chamber that both maintain constant temperatures of 0 °C and 100 °C.
How is thermal conductivity experiment measured? Thermal conductivity may be measured with simple equipment.A slab of the material to be tested is clamped between an ice block and a steam chamber that both maintain constant temperatures of 0 °C and 100 °C.Temperature variation and nonlinear heat flow specifically are the error sources.There are two ways that temperature can vary at contact surfaces: (a) gradually drifting over the board, and (b) momentarily varying throughout the platen surface.Using the Searle's bar method, calculate Copper's thermal conductivity.Steam is heated in this experiment.Don't touch the steam generator, tubing, or the Searle's bar equipment because they have hot surfaces.To learn more about Thermal conductivity refer
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Suppose that Ben Pumpiniron elevates his 80-kg body up the 2.0-meter stairwell in 1.8
seconds. Calculate Ben's power.
Ben's power is 871W
What is the short definition of power?
Power can be defined as the amount of work completed in a given amount of time. Watt (W), which is derived from joules per second (J/s), is the SI unit of power. Horsepower, or roughly 745.7 watts, is a unit of measurement used to describe the power of machinery and motor vehicles.
We could determine Ben's power rating if this were the case. Ben must presumably push down on the stairs with an 800-Newton force in order to raise his body. Ben's body would be pushed upward by the stairs in this way with just enough force to raise him up the stairs. Ben's power rating might be calculated using these two estimations, as illustrated below.
Power = work done / time
Power = 784*2/ 1.8
P= 871W
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Decribe how an electric field and potential gradient affect the performance of inulation
Only in the presence of an electric potential difference does the electric field exist. There won't be any electric field if the charge is homogeneous throughout, regardless of how high the electric potential is.
What connection exists between the potential gradient and the electric field?Potential gradient is calculated by integrating the negative of the electric field's intensity with respect to distance. E = - d V d r describes the relationship between the magnitude of the electric field and the potential gradient.Of course, an insulator can let an electric field through. As it passes through an insulator or dielectric medium, the electric field polarises it.Only in the presence of an electric potential difference does the electric field exist. There won't be any electric field if the charge is homogeneous throughout, regardless of how high the electric potential is.To learn more about electric potential difference refer to:
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what is the process of splitting a uranium atom called?
a. Nuclear Fusion
b. Nuclear Fission
c. Nuclear Confusion
d. Nuclear Dillusion
Nuclear fission produces energy when atoms split apart. All nuclear power plants utilise nuclear fission, and uranium atoms are frequently employed in nuclear power reactors.
When a neutron meets with a uranium atom during nuclear fission, it splits the atom, releasing a large amount of energy in the form of heat and radiation. Nuclear fission, another name for the splitting of atoms, generates radiation and radioactivity. In 1939, Dr. Lise Meitner made the discovery of how radioactivity may be created. She discovered that radiation could be released when a neutron, a tiny particle, was fired into another atom. Fission is the process by which a heavy, unstable nucleus splits into two lighter nuclei, whereas fusion is the joining of two light nuclei to release large amounts of energy.
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what is the magnitude and direction of the electric force on an electron ina uniform electric field of strenght 2360n/c that points due east
The magnitude of the electric force on the electron is 2360 N and it points due east.
What is electric force?Electric force is an attractive or repulsive force between two particles that have an electric charge. This force is generated when two charged particles interact due to their charges. The strength of the electric force depends on how much charge each particle has, as well as their distance from each other. Electric forces are responsible for phenomena such as static electricity and lightning, and they can also be used to power electric motors and other devices.
This is because an electric field exerts a force on a charged particle in the direction that is opposite to the direction of the field. Since the electric field points due east, then the force on the electron will point due west.
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question in a certain region of space, there is an electric potential difference of 120v between two points that are 0.25m apart. what is the magnitude of the average electric field in between the two points?
The magnitude of the average electric field in between the two points is 480V/m
What is electric field?Electric field is an important concept in physics that describes the force exerted by a charged particle or object on other particles or objects in its vicinity. It is a vector field, meaning it has both magnitude and direction. The electric field is created when an electric charge is placed in a region of space. The electric field will then act on any other charges in the region, producing a force on them.
Electric field (E) is defined as the electric potential difference (V) divided by the distance (d) between two points:
E = V / d
In this case, the electric potential difference is 120V and the distance between the two points is 0.25m. Therefore, the magnitude of the average electric field in between the two points is:
E = 120V / 0.25m = 480V/m
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while in horizontal flight at a speed of 20 m/s, a baseball of mass 0.11 kg is struck by a bat. after leaving the bat, the baseball has a speed of 29 m/s in a direction opposite to its original direction. the magnitude of the impulse given the ball is
The baseball's change in momentum is equal to the impulse applied to it. An object's momentum is determined by multiplying its mass by its velocity. The baseball received an impulse with a magnitude of -5.39 kg*m/s.
The baseball's change in momentum is equal to the impulse applied to it. An object's momentum is determined by multiplying its mass by its velocity.
The baseball's initial momentum is equal to 0.11 kg times 20 m/s, or 2.2 kg/s.
The baseball's ultimate velocity is calculated as (0.11 kilogramme) * (-29 m/s) = -3.19 kgm/s.
The difference between the baseball's final and starting velocities, or its change in momentum, is equal to 5.39 kg*m/s (final momentum - beginning velocities = -3.19 kgm/s - 2.2 kgm/s).
As a result, the baseball received an impulse with a magnitude of -5.39 kg*m/s.
Due to the ultimate velocity being in the opposite direction of the original vector, the impulse is negative.
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note that in this arrangement, the net charge is zero (so we expect no monopolar field far away). the two visible dipoles also cancel, so we expect no dipolar field far away. what might we call the first surviving term in the distant field?
The first surviving term in the distant field in this situation might be referred to as a quadrupolar field.
The Distant Field SituationThe determination that the first surviving term in the distant field is a quadrupolar field is based on the fact that the net charge and the visible dipoles in the arrangement cancel out, leaving no monopolar or dipolar fields.
A quadrupole is a distribution of charges in which there are two positive and two negative charges of equal magnitude and opposite sign, arranged symmetrically about a central point.
A quadrupole generates a quadrupolar field, which falls off as the inverse cube of the distance from the source, as opposed to the inverse square of the distance for a dipole.
So when a net charge and dipoles are cancelled, the next term that could survive is the quadrupolar term.
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7. Inferring Suppose you plot the distance
traveled by an object at various times and
you discover that the graph is not a straight
line. What does this indicate about the
object's acceleration?
When the graph of distance travelled with time is not straight, it implies that the acceleration is constant.
What is the acceleration of an object?The acceleration of an object is the rate of change of velocity with time.
Mathematically, the formula for the acceleration of an object is given as;
a = Δv / Δt
where;
Δv is the change in velocity of the objectΔt is the change in time of motionThe slope of velocity time graph is acceleration. This implies that acceleration increases with increase in velocity of an object.
However, if the graph of the distance travelled by an object with time is straight, it implies that the velocity is not uniform.
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a point charge of 8.74 x 10-6 c is at the origin while a second point charge of -5.91 x 10-6 c is at the coordinates (0.53, 0.41) meters. in degrees relative to the positive x direction, what is the direction of the force exerted on the charge at the origin?
The direction of the force on the charge at the origin is towards the charge at (0.53, 0.41) m, since the charges have opposite signs and attract each other.
The direction of the force exerted on a point charge at the origin by a second point charge can be found using Coulomb's law, which states that the force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between them. The formula for the force is:
F = k * q1 * q2 / r^2
where k is the Coulomb constant (8.99 x 10^9 N * m^2 / C^2), q1 and
q2 are the charges, and
r is the distance between the charges.
To find the direction, we must first find the components of the force along the x and y axes.
Then, we can use arctan to find the angle relative to the positive x direction.
The distance between the charges can be found using the Pythagorean theorem:
[tex]r = \sqrt{((0.53 m)^2 + (0.41 m)^2)[/tex] = 0.65 m
The x and y components of the force can then be found using the formula:
Fx = F * cos(θ) = k * q1 * q2 * x / r^3
Fy = F * sin(θ) = k * q1 * q2 * y / r^3
where θ is the angle between the force and the positive x direction, and x and y are the x and y components of the displacement vector between the charges, respectively.
Finally, the direction of the force can be found using arctan:
θ = arctan(Fy / Fx)
The direction of the force on the charge at the origin is towards the charge at (0.53, 0.41) m,
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A simple pendulum and a mass hanging on a spring both have a period of 1$ when set into small oscillatory
motion on Earth. They are taken to Planet X, which has a larger acceleration due to gravity. Which of the
following statements is true about the periods of the two objects on Planet X compared to their periods on Earth
a. Both are shorter
b. Both are the same
e. Both are longer
d. The period pf the mass on the spring is shorter, that of the pendulum is the same
e. The period of the pendulum is shorter, that of the mass on the spring is the same,
The pendulum's period is shorter, but the mass on the spring's is unchanged. A planet with twice the mass of Earth and the same size will accelerate through space twice as fast.
Given that the time period of a simple pendulum is = T
T = 2π√l/g where l is the pendulum length and g is the gravitational acceleration of the planet.
The time period of a mass-spring system is written as: T = 2π√m/k where m is the mass of system and k is spring constant.
The gravitational acceleration is defined as: g = GM/r^2
AS the acceleration due to gravity on planet X is greater than that of on earth we know that the time period is inversely proportional to g.
So, on planet X the time period is shorter and the mass-spring will remain same because the attached mass and spring constant are the same, the mass spring system is unaffected.
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asportscar, electro-fiasco i, can accelerate uniformly to 100 km/h in 3.5 s. its maximum braking rate can not exceed 0.7g. what is the minimum time required to go 1.0 km, assuming it begins and ends at rest?
The minimum time required to travel 1.0 km is 8.75 seconds.
What is travel?Travel is the movement of people from one place to another, usually over a certain distance and for a certain period of time. It can be done for many reasons, including pleasure, business, or to visit family or friends.
This can be calculated by taking the total distance traveled (1.0 km) and dividing it by the average speed (100 km/h). The average speed is 100 km/h because the car accelerates uniformly from 0 km/h to 100 km/h in 3.5 seconds.
Therefore, the total time required is 10 seconds (1 km / 100 km/h). However, this does not take into account the deceleration time of the car, which must also be taken into account.
The maximum braking rate of the car is 0.7 g, which is equivalent to 7 m/s2. Since the car must come to a complete stop at the end of the 1.0 km journey, the time required for deceleration must be calculated. This can be done using the equation:
Time for deceleration = (Final Velocity - Initial Velocity) / Acceleration
Since the initial velocity is 0 m/s and the final velocity is 0 m/s, the equation simplifies to:
Time for deceleration = 0 / 7 m/s2 = 0 seconds
Therefore, the total time required to travel 1.0 km is 10 seconds (for acceleration) + 0 seconds (for deceleration) = 10 seconds. Subtracting this from the total time required gives us the minimum time required to travel 1.0 km, which is 8.75 seconds.
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