Answer:
weight=mass×gravity
the mass in this question is 54kg and the gravity is 10
therefore:
w=54×10
=540N
I hope this helps
A projectile is to be launched at an angle of 30° so that it falls beyond the pond of length 20 meters as shown in the figure.
a) What is the range of values of the initial velocity so that the projectile falls between points M and N?
Answer: A
Explanation:
I want my points so yea
What net force is needed to increase the velocity of a 5 kg object by 3 m/s over the course of 2.5 seconds?
Hi there!
Recall Newton's Second Law:
[tex]\large\boxed{\Sigma F = ma}[/tex]
∑F = net force (N)
m = mass (kg)
a = acceleration (m/s²)
We must begin by solving for the acceleration using the following:
a = Δv/t
In this instance:
Δv = 3 m/s
t = 2.5 sec
a = 3/2.5 = 1.2 m/s²
Now, plug this value along with the mass into the equation for net force:
[tex]\Sigma F = 5(1.2) = \boxed{6 N}}[/tex]
Answer:
[tex]\boxed {\boxed {\sf 6 \ Newtons}}[/tex]
Explanation:
According to Newton's Second Law of Motion, force is the product of mass and acceleration. The mass of the object is 5 kilograms, but the acceleration is unknown.
We can find acceleration using the following formula:
[tex]a= \frac{ \Delta v}{t}[/tex]
The velocity of the object increases by 3 meters per second. It accelerates in 2.5 seconds.
Δv= 3 m/s t= 2.5 sSubstitute the values into the formula.
[tex]a= \frac{3 \ m/s}{2.5 \ s}[/tex]
[tex]a= 1.2 \ m/s/s = 1.2 \ m/s^2[/tex]
Now we know the mass and acceleration.
m= 5 kg a= 1.2 m/s²Substitute the values into the force formula.
[tex]F=ma[/tex]
[tex]F= (5 \ kg)(1.2 \ m/s^2)[/tex]
[tex]F= 6 \ kg*m/s^2[/tex]
Convert the units. 1 kilogram meter per second squared is equal to 1 Newton. Our answer of 6 kilogram meters per second squared is equal to 6 Newtons.
[tex]F= 6 \ N[/tex]
A 2-kg object is pulled to the left with a force of 30 N and to the right with a force of 9 N. What is the acceleration of the object?
An object that weighs 75 N is pulled horizontally to the right with a force of 50 N. The force of friction on this object is 30 N to the left. What is the acceleration of the object?
The force on the object is 50 N to the right and 30 N to the left.
⇒ The net force on the object is, =50−30=20 N to the right.
The weight of the object is, =75 N.
⇒ The mass of the object is ==759.8 kg.
⇒ The acceleration of the object is ==20759.8=2.613 m/s 2.
The acceleration of the object is 10 [tex]m/s^2[/tex].
What is Acceleration?Acceleration is defined as the rate of change of velocity of an object with respect to time which are vector quantities i.e. both magnitude and direction. The orientation of an object's acceleration is given by the orientation of the net force acting on that object.
It can be expressed as:
a= v/t
where, a is the acceleration
v is the velocity
t is the time taken
It can also be expressed as F=ma
where, F= force applied
m= mass of the object
So, for above given information
The force on the object is 9N to the right and 30N to the left. The net force on the object is 21N to the left
The mass of the object is 2kg
So, a= 21N/ 2 kg = 10.5 [tex]m/s^2[/tex]
Thus, the acceleration of the object is 10 [tex]m/s^2[/tex].
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A new moon is discovered orbiting Neptune with an orbital speed of 9.3 x103 m/s. Neptune's mass is 1.0 x1026 kg. A) What is the radius of the new moon's orbit? B) What is the orbital period? Assume that the orbit is circular. (G = 6.673 x10-11 N-m²/kg?
please help answer the question in the image!!!
Answer:
C (only)
Explanation:
Often, we consider the 0 position on a graph like this to be the starting point. However, the position on this graph is indicated as positive at time = 0. The motion shown can be described in each stage as follows.
A: moving away from the starting position toward the reference position (position = 0)
B: stationary at the reference position
C: moving away from the reference position toward the starting position
D: stationary at a point just short of the starting position
E: moving away from the starting position toward, then beyond, the reference position
The relationship between Acceleration and Mass is described as:
O a. Equal
O b. Directly Proportional
O c. Inversely Proportional
O d. Opposite
O e. None of these
Explanation:
According to Newton's second law
[tex]\\ \sf{:}\dashrightarrow Force=Mass\times Acceleration [/tex]
[tex]\\ \sf{:}\dashrightarrow Mass=\dfrac{Force}{Acceleration}[/tex]
[tex]\\ \sf{:}\dashrightarrow Mass\propto \dfrac{1}{Acceleration}[/tex]
Option C
what is the purpose of the thermal energy tranfer lab
Answer:thermal Energy Transfer in Mixtures Purpose: The purpose of this experiment is to discover how exactly the final temperature of a mixture, involving a substance and hot water, is affected and impacted by the type of substance used. This means that when hot water is mixed with another substance, it must be determined
Explanation:
did this on edge
3. Which is not an example of energy
(5 Points)
light
thermal
heat
chemical
Answer:
Heat, Chemical
Answer:
heat is not an energy is a process.
Explanation:
A weightlifter lifts a 350 N set of weights over his head a vertical distance of 2.5 meters above the floor. Calculate the work the athlete does on the weights, assuming he lifts them at a constant speed.
A. 525 J
B. 750 J
C. 1005 J
D. 700 N•m
E. 875 J
A600kg car is acted force of 1200N starting from rest.how travel in 10 seconds?
Answer:
x= 100 m
Explanation:
m= 600 kg
t= 10 s
F= 1200N
v0= 0
-----
F=ma
a=F/m
x= (v0)t + (1/2)(a)(t^2)
x= (1/2)(F/m)(t^2)
x= (1/2)(1200/600)(10^2)
x= 100m
the image in figure 16.36 combines observations made with visible light and radio telescopes. which color in the image represents the radio emission?
Answer: pinkish- white
Purple
Explanation:
The force of gravity can also be referred to as the force of _____________.
Answer:
Gravitational.
Explanation:
In Earth, everything have a volume and mass, or downward force of gravity, which Earth's mass exerts on them.
Physicists call any change in energy an impulse true or false?
what was stored when you bent the ruler in your left hand?
Answer:
potential energy
the name comes from the fact that the ruler has "potential" to act
Explanation:
Explanation:
The deformation of the ruler creates a force in the opposite direction, known as a restoring force.
I'm not sure if it's correct...
Convert 8 m/s to miles per hour
Answer:
17.8954903 or 17.9 mph
Explanation:
m/s is meters per second. 1609.344 meters is one mile. There are 3,600 seconds in an hour. 8 meters *3600 seconds= 28,800. 28,800/1609.344 = 17.8954903. Simplify to 17.9
You roll a toy car, and it moves 10 meters in five seconds. What is the car's velocity?
The car's velocity is 2 m/s.
Hope you could get an idea from here.
Doubt clarification - use comment section.
Help me pls both answers i’ll give brainly
2 questions, 100 points
Gravitational force between objects ____________ as objects move farther apart, and it is ___________ between objects that are closer together.
increases, weaker
increases, stronger
decreases, weaker
decreases, stronger
In science, weight is measure in
Pounds
Kelvin
Newtons
Liters
Answer:
decreases, stronger
newtons
Explanation:
will mark brainliest if answer
I won't touch the object because there is a warning sign and that means you stay out if it because it is a danger sign that High Resistance Material that means it is dangerous.
Give 4 facts about the alkali metals
Answer:
there very old
Explanation:
if clarisses mass on earth is 52kg what would be her weight on venus if the acceleration due to gravity on that planet is 8.87 m/s^2
Answer:
Weight=F=MA=52*8.87=461.24
Consider a car of mass m moving with an initial speed Vo on a straight, flat road. At time t=0, the driver fully applies the breaks to avoid colliding with debris in the road in front of the car. The car’s wheels lock, causing the car to slide on the roadway until the car stops, before running over the debris. The distance that the car slides is D. The coefficient of kinetic friction between the car’s tires and the roadway is a constant value of Uk.
A) Sketch a free body diagram for the car sliding to rest and write Fnet equations
A) does the value D increase or decrease with increasing initial speed?
B) does the value D increase or decrease with increasing the coefficient of friction?
C) derive an equation for the acceleration of the car in terms of Uk and physical consonants
What two things related to sedimentary rocks do you see at the Grand Canyon ?
Answer:
sandstone and mudstone
Explanation:
The deceleration of the dummy is less than the deceleration of the passenger compartment.
Explain why this is of benefit for the safety of a passenger.
Based on the information given, this is beneficial because the passenger is less likely to be injured.
Deceleration simply means acceleration in a reverse way. Deceleration simply means the rate at which an object slows down.
From the complete information, it should be noted that the fact that the deceleration of the dummy is less than the deceleration of the passenger compartment is beneficial as it impacts on passenger or dummy less than without the airbag or seat belt.
Therefore, this is important as the passenger is less likely to be injured.
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If a planet has an eccentricity of 0.92 and a distance of the major axis is 5,000,000 km, then what is the distance between foci?(1 point)
460,000,000 km
0.00000018 km
4,600,000 km
5,000,000 km
Answer:
it’s the third option: 4,600,000 km
Explanation:
just took the test and that was correct
a 25 kg crate is pushed horizontally with a force of 70N. if the coefficient of friction is .20, calculate the acceleration of the crate.
From Newton's second law of motion, the acceleration of the crate is 0.84m/[tex]s^{2}[/tex]
Given that a 25 kg crate is pushed horizontally with a force of 70N and the coefficient of friction is 0.20
To calculate the acceleration of the crate, We will consider the net force acting on the crate. The net force will be sum of the applied force F and the frictional force [tex]F_{r}[/tex].
Let us first calculate the frictional force [tex]F_{r}[/tex]. That is,
[tex]F_{r}[/tex] =- μN
[tex]F_{r}[/tex] = μmg
[tex]F_{r}[/tex] = 0.2 x 25 x 9.8
[tex]F_{r}[/tex] = 49N
Using Newton's second law,
F = ma
F - [tex]F_{r}[/tex] = ma
70 - 49 = 25 a
21 = 25a
a = 21 / 25
a = 0.84 m/[tex]s^{2}[/tex]
Therefore, the acceleration of the crate is 0.84m/[tex]s^{2}[/tex]
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1. Taking accurate measurements of small values using the ‘measure many and average’ method.
Each oscillation takes a small amount of time, and your reaction time is about 0.1 seconds. This means too much of the time you measure is your reaction time. Find out the percentage error with this calculation;
a. ((reaction time)⁄(time for one oscillation))x100=% error
b. To reduce the percentage error, time for ten oscillations.
c. Take the average time by dividing your answer by ten.
d. Your reaction time is still the same, 0.1 s. Find out the new percentage error with this calculation;
Answer:
i need free answers here
Explanation:
Hi, please help! •_•
One workman is measured as having a power of 528W. His weight is 800N. He can develop the same power climbing a ladder, whose rungs are 30cm apart. How many rungs can he climb in 5s?
Answer:
He can climb 11 rungs
Explanation:
Power = 528W, Force = 800N, Time= 5s Total Distance moved = 30x cm or 0.3x m, where x is the number of rungs he climbed
Power = Work done/time
Work done = Power × time
= 528 × 5
= 2640Joules
Also Work done = Force × total distance moved
Total Distance moved = Work done/force
0.3x = 2640/800
0.3x = 33
x = 3.3/0.3
x = 11
a)iii) as the wheelbarrow was being pushed, the tyre went over a small stone. Describe and explain how the pressure changes.
Answer:
it changed because the rock put the pressure all in one spot.
Explanation:
In the Bohr model of the hydrogen atom, the speed of the electron is approximately 2.2 106 m/s.
Find the central force acting on the electron as it revolves in a circular orbit of radius 4.63 x 10-11 m.
Answer in units of N.
The central force acting on the electron as it revolves in a circular orbit is [tex]9.52 \times 10^{-8} \ N[/tex].
The given parameters;
speed of electron, v = 2.2 x 10⁶ m/sradius of the circle, r = 4.63 x 10⁻¹¹ mThe central force acting on the electron as it revolves in a circular orbit is calculated as follows;
[tex]F = \frac{M_e v^2}{r} \\\\[/tex]
where;
[tex]M_e[/tex] is mass of electron = 9.11 x 10⁻³¹ kg
[tex]F = \frac{(9.11 \times 10^{-31}) \times(2.2\times 10^6)^2 }{4.63 \times 10^{-11}} \\\\F = 9.52 \times 10^{-8} \ N[/tex]
Thus, the central force acting on the electron as it revolves in a circular orbit is [tex]9.52 \times 10^{-8} \ N[/tex].
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