The manager of a grocery store has taken a random sample of 100 customers. The average length of time it took the customers in the sample to check out was 3.1 minutes with a standard deviation of 0.5 minutes. We want to test to determine whether or not the mean waiting time of all customers is significantly more than 3 minutes.

Refer to Exhibit 9-4. At 95% confidence, it can be concluded that the mean of the population is
Select one:
a.
significantly greater than 3
b.
not significantly greater than 3
c.
significantly less than 3
d.
significantly greater then 3.18

Answers

Answer 1

Answer:

Step-by-step explanation:

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

H0: µ = 3

For the alternative hypothesis,

H1: µ > 3

This is a right tailed test.

Since the population standard deviation is not given, the distribution is a student's t.

Since n = 100

Degrees of freedom, df = n - 1 = 100 - 1 = 99

t = (x - µ)/(s/√n)

Where

x = sample mean = 3.1

µ = population mean = 3

s = samples standard deviation = 0.5

n = number of samples = 100

t = (3.1 - 3)/(0.5/√100) = 2

We would determine the p value using the t test calculator. It becomes

p = 0.024

Alpha = 1 - confidence level = 1 - 0.95 = 0.05

Since alpha, 0.05 > than the p value, 0.024, then we would reject the null hypothesis. Therefore, at 95% confidence level, it can be concluded that the mean of the population is significantly greater than 3.


Related Questions

Need Assistance With This Problem​

Answers

Answer:

not sure how to really answer this question.

Answer:

4.56,  4.65, 5.46, 5.64, 6.45, 6.54

Step-by-step explanation:

First we have to compare the first digits in each number as less is this digit as less is the number. So the least off all are

4.56 and 4.65

which of these two numbers is least ? Now we have to look to the 2-nd digits of these numbers:

they are 5 and 6 . 5<6 so 4.56<4.65

Lets select next numbers whicj first digit is 5. They are:

5.46 and 5.64. However the second digit of the number 5.64 -6 is bigger than the second digit of number 5.46 -4. That is why 5.46<5.64

Similarly 6.45< 6.54

I want to fence in a rectangular vegetable patch. The fencing for the east and west sides costs $2 per foot, and the fencing for the north and south sides costs only $1 per foot. I have a budget of $40 for the project. What is the largest area I can enclose

Answers

Answer:

largets area is 32 feet cubed

Step-by-step explanation:

8=4  foot 2 for each  side w and e and 32feet n and s  16 each side

Please answer this correctly

Answers

Answer:

7/8 chance

Step-by-step explanation:

There are 7 numbers that are either even or greater than 2: 2, 3, 4, 5, 6, 7, and 8. There is a 7/8 chance choosing either of those.

Answer:

7/8

Step-by-step explanation:

there are 6 numbers that are greater than 2: 3,4,5,6,7,8

there are 4 even numbers: 2,4,6,8

a. What is a​ residual? b. In what sense is the regression line the straight line that​ "best" fits the points in a​ scatterplot? a. What is a​ residual?

Answers

Answer:

a. A residual is how far off a point is from the expected value. For example, if I were to estimate the weight of my Southeastern Lubber Grasshopper, I would say it's maybe 5 ounces. But, in reality, it might be 4 ounces. So, the residual would be the reality minus the prediction, or 4 - 5, or -1 ounce.

b. The regression line is the line of predicted values for the points in the scatterplot. It tries to predict the points and make all the points be on the line.

Hope this helps!

f(x) = 9 + 4x f(0) = f(-1) = Find the value of x for which f(x) =6 x=

Answers

Answer: x=-3/4

Step-by-step explanation:

Since we know f(x)=6, we can set it equal to the equation.

6=9+4x           [subtract 9 on both sides]

-3=4x              [divide both sides by 4]

x=-3/4

To test H0​: μ=100 versus H1​:≠​100, a simple random sample size of nequals=24 is obtained from a population that is known to be normally distributed. Answer parts​ (a)-(d).(a) If x =104.2 and s=9.6, compute the test statistic.t= _ ​(Round to three decimal places as​ needed.)(b) If the researcher decides to test this hypothesis at the α=0.01 level of​ significance, determine the critical values.The critical values are __ .(c) Draw a​ t-distribution that depicts the critical​ region(s). Which of the following graphs shows the critical​ region(s) in the​t-distribution?(d) Will the researcher reject the null​ hypothesis?

Answers

Answer:

a) Test statistic = 1.960

b) The critical values include -2.50 and 2.50.

The critical regions of rejection are thus

t < -2.50 or t > 2.50

c) The sketch of the curve is presented in the attached image to this solution. The shaded parents indicate the rejection regions.

d) The t-statistic obtained (1.96), lies within the acceptance region (-2.50 ≤ x ≤ 2.50), we fail to reject the null hypothesis.

Step-by-step explanation:

a) Test statistic is computed using the expression

t = (x - μ₀)/σₓ

x = Sample mean = 104.2

μ₀ = the standard we are comparing Against

σₓ = standard error of the mean = (σ/√n)

σ = 9.6

n = Sample size = 24

σₓ = (9.6/√24) =

t = (0.425 - 0.35) ÷ 0.07816

t = 1.9595917942 = 1.960

b) To obtain these critical values, we first find the degree of freedom

Degree of freedom = n - 1 = 24 - 1 = 23

The critical values for significance level of 0.01 and degree of freedom of 23 is given as

t(0.01, 23) = 2.50

So, since the test is two-tailled (we are testing in both directions; greater than or less than), the regions of rejection include

t < -2.50 and t > 2.50

c) since the test is two-tailled (we are testing in both directions; greater than or less than), the regions of rejection include

t < -2.50 and t > 2.50

The t-distribution curve is very similar to the normal distribution curve. The t-distribution curve is also a bell shaped curve, but it is heavier at the limits indicating that the t-distribution favours outliers more than the normal distribution.

The sketch of the curve is presented in the attached image with the shaded regions indicating the rejection region.

d) Since the t-statistic obtained (1.96), lies within the acceptance region (-2.50 ≤ x ≤ 2.50), we fail to reject the null hypothesis.

Hope this Helps!!!

Which expression is the simplest form of -(x + 5) - 3(x + 2)?

Answers

Answer:

-4x -11

Step-by-step explanation:

-(x + 5) - 3(x + 2)

Distribute

-x -5  -3x -6

Combine like terms

-x-3x   -5-6

-4x -11

Answer:

[tex] = - (4x + 11)[/tex]

Step-by-step explanation:

[tex]-(x + 5) - 3(x + 2) \\ -x - 5 - 3x - 6 \\ -x - 3x -5 - 6 \\ - 4x - 11 \\ = -(4x + 11)[/tex]

convert 3days to minutes

Answers

Answer:

4320 minutes

Step-by-step explanation:

Recall,

1 day --->  24 hours

but each hour has 60 minutes, hence 1 day can also be expressed:

1 day -----> 24 x 60 = 1440 minutes

3 days -----> 1440 min/day  x 3 days = 4320 minutes

Answer: 4,320 minutes

Step-by-step explanation: 1 day = 1440 days. 1440 * 3 = 4,320 minutes

Solve the problem. The scores on a certain test are normally distributed with a mean score of 60 and a standard deviation of 5. What is the probability that a sample of 90 students will have a mean score of at least 60.527? Write your answer as a decimal rounded to 4 places.

Answers

Answer:

15.87%

Step-by-step explanation:

We have to calculate the value of z:

z = (x - m) / (sd / n ^ (1/2))

where x is the value to evaluate, m is the mean, n is the sample size and sd is the standard deviation, we replace:

p (x <60,527) = z = (x - m) / (sd / n ^ (1/2))

p (x <60,527) = z = (60,527 - 60) / (5/90 ^ (1/2))

z = 1

if we look in the attached table, for z = 1 it is 0.8413

p (x> 60,527) = 1 - 0.8413

 p (x> 60,527) = 0.1587

Therefore the probability is 15.87%

if a^2+b^2+c^2=169. find a, given that b=2√2, 3√c=9.​

Answers

Answer:

a = ±4√5

Step-by-step explanation:

Solve for c.

3√c = 9

√c = 9/3

√c = 3

c = 3²

c = 9

Put b=2√2 and c=9, solve for a.

a² + (2√2)² + 9² = 169

a² + 8 + 81 = 169

a² = 169 - 81 - 8

a² = 80

a = ±√80

a = ±4√5

The life in hours of a battery is known to be normally distributed, with a standard deviation of 1.25 hours. A random sample of 10 batteries has a mean life x = 40.5 hours.
a) Is there evidence to support the claim that battery life exceeds 40 hours? Use
α = 0.05.
b) What is the P-value for this test?

Answers

Answer:

a) Test statistic

    Z = 1.265 < 1.96 at 0.05 level of significance

The battery life is not exceeds 40 hours

b)

p- value = 0.8962

Step-by-step explanation:

Step(i):-

Given sample size 'n' =10

Mean of the sample x⁻ = 40.5 hours

Mean of  of the Population μ = 40 hours

Standard deviation of the Population = 1.25 hours

Step(ii):-

Null Hypothesis:H₀: μ = 40 hours

Alternative Hypothesis :H₁ : μ < 40 hours

step(ii):-

Test statistic

               [tex]Z = \frac{x^{-} -mean}{\frac{S.D}{\sqrt{n} } }[/tex]

              [tex]Z = \frac{40.5 -40}{\frac{1.25}{\sqrt{10} } }[/tex]

             Z = 1.265

Level of significance = 0.05

Z₀.₀₅ = 1.96

Z = 1.265 < 1.96 at 0.05 level of significance

The battery life is not exceeds 40 hours

Step(iii):-

P - value        

P( Z < 1.265) = 0.5 + A( 1.265)

                     = 0.5 + 0.3962  

                    = 0.8962

P( Z < 1.265) = 0.8962

i ) p- value = 0.8962 > 0.05

Accept H₀

There is no significant

The battery life is not exceeds 40 hours

     

what it 17.15 in 12hour clock

Answers

Answer:

Step-by-step explanation:

Hello friend

The answer is 5:15 in 12 hour clock

Answer:

5:15 PM

Step-by-step explanation:

12:00 + 5:00

17:00 in 12 hour clock is 5:00 PM.

15 minutes + 5:00 PM

⇒ 5:15 PM

The perimeter of a rectangular city park is 1,428 feet. The length is 78 feet more than twice the width. Find the length and width of the park.

Answers

Answer:

Length =  502 ft

Width = 212 ft

Step-by-step explanation:

Recall the formula for the perimeter of a rectangle of length "L" and width "W":

Perimeter = 2 L + 2 W = 1428  ft

Now, since the length is 78 ft more than twice the width, then we can write this in mathematical form as:

L = 2 W +78

so, 2 W = L -7 8

and now replace "2 W" with it equivalent  "L - 78"  in the first perimeter equation and solve for "L":

2 L + L - 78 = 1428

3 L = 1428 + 78

3 L = 1506

L = 1506/3

L = 502 ft

Then the width W can be obtained via:

2 W = L - 78

2 w = 502 -78

2 W = 424

w = 212 ft

The Rocky Mountain district sales manager of Rath Publishing Inc., a college textbook publishing company, claims that the sales representatives make an average of 41 sales calls per week on professors. Several reps say that this estimate is too low. To investigate, a random sample of 38 sales representatives reveals that the mean number of calls made last week was 42. The standard deviation of the sample is 3.9 calls. Using the 0.025 significance level, can we conclude that the mean number of calls per salesperson per week is more than 41?H0 : µ = 40
H1 : µ > 401. Compute the value of the test statistic. 2. What is your decision regarding H0?

Answers

Answer:

1. Test statistic t=1.581.

2. The null hypothesis H0 failed to be rejected.

There is not enough evidence to support the claim that the mean number of calls per salesperson per week is significantly more than 41.

NOTE: if the null hypothesis is µ = 40, there is enough evidence to support the claim that the mean number of calls per salesperson per week is significantly more than 40 (test statistic t=3.161).

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the mean number of calls per salesperson per week is significantly more than 41.

Then, the null and alternative hypothesis are:

[tex]H_0: \mu=41\\\\H_a:\mu> 41[/tex]

The significance level is 0.025.

The sample has a size n=38.

The sample mean is M=42.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=3.9.

The estimated standard error of the mean is computed using the formula:

[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{3.9}{\sqrt{38}}=0.633[/tex]

Then, we can calculate the t-statistic as:

[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{42-41}{0.633}=\dfrac{1}{0.633}=1.581[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=38-1=37[/tex]

This test is a right-tailed test, with 37 degrees of freedom and t=1.581, so the P-value for this test is calculated as (using a t-table):

[tex]\text{P-value}=P(t>1.581)=0.061[/tex]

As the P-value (0.061) is bigger than the significance level (0.025), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the mean number of calls per salesperson per week is significantly more than 41.

For µ = 40:

This is a hypothesis test for the population mean.

The claim is that the mean number of calls per salesperson per week is significantly more than 40.

Then, the null and alternative hypothesis are:

[tex]H_0: \mu=40\\\\H_a:\mu> 40[/tex]

The significance level is 0.025.

The sample has a size n=38.

The sample mean is M=42.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=3.9.

The estimated standard error of the mean is computed using the formula:

[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{3.9}{\sqrt{38}}=0.633[/tex]

Then, we can calculate the t-statistic as:

[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{42-40}{0.633}=\dfrac{2}{0.633}=3.161[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=38-1=37[/tex]

This test is a right-tailed test, with 37 degrees of freedom and t=3.161, so the P-value for this test is calculated as (using a t-table):

[tex]\text{P-value}=P(t>3.161)=0.002[/tex]

As the P-value (0.002) is smaller than the significance level (0.025), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the mean number of calls per salesperson per week is significantly more than 40.  

researchers are interested in the average size of a certain species of mouse. They collect the length and gender of each mouse. What is the parameter likely estimated and the sample statistic

Answers

Answer:

E. The parameter is μmale - μfemale and the statistic is xmale - xfemale.

Step-by-step explanation:

The sample statistic is a piece of information about the individuals or objects that were selected from a given population. The sample is just a fraction of the total population. Since it is a herculean task studying an entire population, the sample forms a manageable size that allows us to have an insight into the entire population. The sample statistics are now the piece of information about the sample being studied such as the average, mean, median, or mode.  The sample statistics have to be as specific as possible of the factors being measured. In the question, we would have to obtain the mean of both the male and female genders. This gives us an insight into the population under study.

The parameter, on the other hand, is a description of the entire population being studied. For example, we might want to determine the population mean. That is the factor we seek to measure. It is represented by the sign mu (μ).  

A certain group of test subjects had pulse rates with a mean of 80.9 beats per minute and a standard deviation of 10.7 beats per minute. Use the range rule of thumb to identify the limits separating values that are significantly low or significantly high. Is a pulse rate of 142.3 beats per minute significantly low or significantly​ high?

Answers

Answer:

We want to find the usual limits using the rule of thumb and for this case rule states that we have most of the values within 2 deviations from the mean so then we can find the usual limits like this:

[tex] \mu -2*\sigma = 80.9 -2*10.7= 59.5[/tex]

[tex] \mu +2*\sigma = 80.9 -2*10.7= 102.3[/tex]

And for this case a value of 142.3 is higher than the upper limti so then we can conclude that would be significantly high with the rule of thumb criteria

Step-by-step explanation:

For this case we have the follwing info given:

[tex] \mu = 80.9[/tex] represent the mean

[tex]\sigma = 10.7[/tex] represent the deviation

We want to find the usual limits using the rule of thumb and for this case rule states that we have most of the values within 2 deviations from the mean so then we can find the usual limits like this:

[tex] \mu -2*\sigma = 80.9 -2*10.7= 59.5[/tex]

[tex] \mu +2*\sigma = 80.9 -2*10.7= 102.3[/tex]

And for this case a value of 142.3 is higher than the upper limti so then we can conclude that would be significantly high with the rule of thumb criteria

I need help on question 8.

Answers

Answer:

  50.18°

Step-by-step explanation:

  ∠BAD = ∠BAC +∠CAD

  102° = (8x+17)° +(9x+11)° . . . . . substitute given values

  102 = 17x +28 . . . . . . . . . . simplify, divide by degrees

  x = (102 -28)/17 = 74/17 . . . . . solve for x

Then the angle of interest is ...

  ∠CAD = (9x +11)° = (9(74/17) +11)° = 50 3/17°

  ∠CAD ≈ 50.18°

Simplify.
In e =
In e 2x=
In 1 =

Answers

Answer:

ln e = 1

ln e 2x = 2x

ln 1 = 0

Step-by-step explanation:

ln e

ln(2.718282) = 1

In e 2x

ln(2.718282)(2)x = 2x

ln 1 = 0

Find all the missing side lengths for the following triangles.

Answers

Answer:

Step-by-step explanation:

A) u = 4      v = 4/(sqrt)3

B) b = 5      c = 10

C) b = 2(sqrt)2     a = 4

D) m and n are both 7(sqrt)2/2

The missing side lengths for the three triangles are 10√3, 12, and 8. The first triangle is a 30-60-90 triangle, the second triangle is a 45-45-90 triangle, and the third triangle is a right triangle. The missing side lengths were found using the properties of special triangles and the Pythagorean Theorem.

Here are the missing side lengths for the following triangles:

Triangle 1:

The missing side length is 15.

The triangle is a 30-60-90 triangle, so the ratio of the side lengths is 1:√3:2. The hypotenuse of the triangle is 20, so the shorter leg is 10 and the longer leg is 10√3. The missing side length is the longer leg, so it is 10√3.

Triangle 2:

The missing side length is 12.

The triangle is a 45-45-90 triangle, so the ratio of the side lengths is 1:1:√2. The hypotenuse of the triangle is 12√2, so each of the legs is 12. The missing side length is one of the legs, so it is 12.

Triangle 3:

The missing side length is 8.

We can use the Pythagorean Theorem to find the missing side length. The Pythagorean Theorem states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

In this case, the hypotenuse is 10 and one of the other sides is 6. Let x be the missing side length.

[tex]10^{2}[/tex] = [tex]6^{2}[/tex] + [tex]x^{2}[/tex]

100 = 36 +[tex]x^{2}[/tex]

[tex]x^{2}[/tex] = 64

x = 8

Therefore, the missing side length is 8.

Learn more about side lengths here: brainly.com/question/18725640

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the distance around the edge of a circular pond is 88m. the radius in meters is ?

(a)88π
(b)176π
(c)88/π
(d)88/2π​

Answers

Answer: (d) 88/ 2π

Step-by-step explanation:

Perimeter = 88m

Perimeter of a circle = 2πr

88 = 2π x r

r = 88 / 2π

Answer:

88/2π​ = r

Step-by-step explanation:

The circumference is 88 m

The circumference is given by

C = 2*pi*r

88 = 2 * pi *r

Divide each side by 2 pi

88 / 2pi = 2 * pi *r / 2 * pi

88 / 2 pi = r

PLEASE QUICK!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! Which number completes the system of linear inequalities represented by the graph? y > 2x – 2 and x + 4y > -12 -3 4 6

Answers

Answer:

-12

Step-by-step explanation:

Edge 2021

please assist me with the power of i(imaginary)​

Answers

Let's raise i to various powers starting with 0,1,2,3...

i^0 = 1

i^1 = i

i^2 = ( sqrt(-1) )^2 = -1

i^3 = i^2*i = -1*i = -i

i^4 = (i^2)^2 = (-1)^2 = 1

i^5 = i^4*i = 1*i = i

i^6 = i^5*i = i*i = i^2 = -1

We see that the pattern repeats itself after 4 iterations. The four items to memorize are

i^0 = 1

i^1 = i

i^2 = -1

i^3 = -i

It bounces back and forth between 1 and i, alternating in sign as well. This could be one way to memorize the pattern.

To figure out something like i^25, we simply divide the exponent 25 over 4 to get the remainder. In this case, the remainder of 25/4 is 1 since 24/4 = 6, and 25 is one higher than 24.

This means i^25 = i^1 = i

Likewise,

i^5689 = i^1 = i

because 5689/4 = 1422 remainder 1. The quotient doesn't play a role at all so you can ignore it entirely

A U.S. dime has a diameter of about 18 millimeters. What is the area of one side of a dime to the nearest square millimeter? Use 3.14 as an approximation for pi. The area of one side of a U.S. dime is approximately _____ square millimeters.

Answers

123 square millimeters

Area of one side of a U.S. dime is approximately 254  square millimeters.

What is Circle?

A circle is a shape consisting of all points in a plane that are at a given distance from a given point, the centre.

Given that  U.S. dime has a diameter of about 18 millimeters.

We need to find the area of one side of a dime to the nearest square millimeter.

Diameter=18 millimeters

Diameter is two times of radius

D=2R

18=2R

Divide both sides by 2

Radius is 9 millimeters.

Area of dime=πr²

=3.14×(9)²

=3.14×81

=254 square millimeters.

Hence, area of one side of a U.S. dime is approximately 254  square millimeters.

To learn more on Circles click:

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a. dashed line, shade below
b. dashed line, shaded above
c. solid line, shade above
d. solid line, shade below

Answers

Answer:

the answer is A

Step-by-step explanation:

You have different video games. How many different ways can you arrange the games side by side on a​ shelf? You can arrange the different video games in nothing different ways.

Answers

Answer:

See Explanation below

Step-by-step explanation:

This question has missing details because the number of video games is not stated;

However, you'll arrive at your answer if you follow the steps I'll highlight;

The question requests for the number of arrangement; That means we're dealing with permutation

Let's assume the number of video games is n;

To arrange n games, we make use of the following permutation formula;

[tex]^nP_n = \frac{n!}{(n-n)!}[/tex]

Simplify the denominator

[tex]^nP_n = \frac{n!}{0!}[/tex]

0! = 1; So, we have

[tex]^nP_n = \frac{n!}{1}[/tex]

[tex]^nP_n = n![/tex]

Now, let's assume there are 3 video games;

This means that n = 3

[tex]^3P_3 = 3![/tex]

[tex]^3P_3 = 3 * 2 * 1[/tex]

[tex]^3P_3 = 6\ ways[/tex]

So, whatever the number of video games is; all you have to do is; substitute this value for n;

the figure below shows a square ABCD and an equilateral triangle DPC:

Answers

Answer:  c) SAS Postulate

Step-by-step explanation:

DP = PC              Sides are congruent

∠ADP ≡ ∠BCP    Angles are congruent (angles are between the sides)

AD = BC             Sides are congruent

To finish the proof, we can state that ΔADP ≡ ΔBCP by the Side-Angle-Side (SAS) Postulate

The probability of rolling two dice at the same time and getting a 4 with either die or the sum of the dice is 6

Answers

Answer:

Suppose that the first die we roll comes up as a 1. The other die roll could be a 1, 2, 3, 4, 5, or 6. Now suppose that the first die is a 2. The other die roll again could be a 1, 2, 3, 4, 5, or 6. We have already found 12 potential outcomes, and have yet to exhaust all of the possibilities of the first die. But with a second dice, there will be 24 different possibilities.

Step-by-step explanation:

   1     2        3 4   5     6

1 (1, 1)   (1, 2)   (1, 3)   (1, 4)  (1, 5)   (1, 6)

2 (2, 1)   (2, 2)  (2, 3)  (2, 4) (2, 5)  (2, 6)

3 (3, 1)   (3, 2)  (3, 3)  (3, 4)  (3, 5)  (3, 6)

4 (4, 1)   (4, 2)  (4, 3)  (4, 4)  (4, 5)  (4, 6)

5 (5, 1)   (5, 2)  (5, 3)  (5, 4)  (5, 5)  (5, 6)

6 (6, 1)   (6, 2)  (6, 3)  (6, 4)  (6, 5)  (6, 6)

Given the equation y = 7 sec(6x– 30)

The period is:

The horizontal shift is:

Answers

Answer:

The period is of [tex]\frac{\pi}{3}[/tex] units.

The horizontal shift is of 30 units to the left.

Step-by-step explanation:

The secant function has the following general format:

[tex]y = A\sec{(Bx + C)}[/tex]

A represents the vertical shift.

C represents the horizontal shift. If C is positive, the shift is to the right. If it is negative, it is to the left.

The period is [tex]P = \frac{2\pi}{B}[/tex]

In this question:

[tex]y = 7\sec{6x - 30}[/tex]

So [tex]B = 6, C = -30[/tex]

Then [tex]P = \frac{2\pi}{6} = \frac{\pi}{3}[/tex]

The period is of [tex]\frac{\pi}{3}[/tex] units.

The horizontal shift is of 30 units to the left.

A sample of 26 offshore oil workers took part in a simulated escape exercise, and their escape time (unit: second) were observed. The sample mean and sample standard deviation are 370.69 and 24.36, respectively. Suppose the investigators had believed a priori that true average escape time would be at most 6 minutes. Does the data contradict this prior belief? Assuming normality, test the appropriate hypotheses using the rejection region method at a significance level of 0.05.

Answers

Answer:

Yes, it contradict this prior belief as there is enough evidence to support the claim that the true average escape time is significantly higher than 6 minutes.

Test statistic t=2.238>tc=1.708.

The null hypothesis is rejected.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the true average escape time is significantly higher than 6 minutes (360 seconds).

Then, the null and alternative hypothesis are:

[tex]H_0: \mu=360\\\\H_a:\mu> 360[/tex]

The significance level is 0.05.

The sample has a size n=26.

The sample mean is M=370.69.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=24.36.

The estimated standard error of the mean is computed using the formula:

[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{24.36}{\sqrt{26}}=4.777[/tex]

Then, we can calculate the t-statistic as:

[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{370.69-360}{4.777}=\dfrac{10.69}{4.777}=2.238[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=26-1=25[/tex]

The critical value for a  right-tailed test with a significance level of 0.05 and 25 degrees of freedom is tc=1.708. If the test statistic is bigger than 1.708, it falls in the rejection region and the null hypothesis is rejected.

As the test statistic t=2.238 is bigger than the critical value t=1.708, the effect is significant.  The null hypothesis is rejected.

There is enough evidence to support the claim that the true average escape time is significantly higher than 6 minutes (360 seconds).

The straight line L has equation y = 1/2x+7 The straight line M is parallel to L and passes through the point (0, 3). Write down an equation for the line M.

Answers

Answer:

y = [tex]\frac{1}{2}[/tex] x + 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = [tex]\frac{1}{2}[/tex] x + 7 ← is in slope- intercept form

with slope m = [tex]\frac{1}{2}[/tex]

Parallel lines have equal slopes

line M crosses the y- axis at (0, 3) ⇒ c = 3

y = [tex]\frac{1}{2}[/tex] x + 3 ← equation of line M

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