The magnitude of the line voltage at the terminals of a balanced Y-connected load is 660 V. The load impedance is 240-j70 Ω/Φ. The load is fed from a line that has an impedance of 0.5 + j4 Ω/Φ.
A) What is the magnitude of the line current?
B) What is the magnitude of the line voltage at the source?

Answer:

well its 31.4226804124

Explanation:

Answer:

The amount of phase shift between input and output signal is important when measuring a common emitter amplifier circuit​.

Explanation:

the amount of phase shift between input and output signal is important when measuring a common emitter amplifier circuit​

In signal processing, phase distortion is change in the shape of the waveform, that occurs when the phase shift introduced by a circuit is not directly proportional to frequency.

In a common emitter amplifier circuit​ there is an 180-degree phase shift between the input and output waveforms.

Answer:

First, there are 4 atoms in the FCC unit cell.

The unit volume of the unit can be calculated based on the atomic radii, in which case the hypotenuse of the cube of the unit cell would be 4 X 0.1278  

Next, find the weight of one atom by taking (63.55g / mol) X (mols / 6.0221415 x 10 ^ 23 atoms)

So now you have all the numbers you need. Take the weight of the atom X 4 divided by the cube volume taken from the hypotenuse.

Explanation:

Answer:

Finding stuff you need ( D )

Explanation:

Once an idea is narrowed down and divided into categories, The next line of action would be to create smaller groups that will be brainstorm solutions towards resolving the problem/ implement the idea faced by the team.

The phase of the design process that the smaller teams created will be focused on is to model and build a prototype ( finding stuff you need ) that would help implement the ideas

Answer:

5318.346

Explanation:

From the question we have

M = 6kg/s

P = 15kpa

h1 = 3248.4kj

x = 0.9

H2 is unknown

From the steam table

hf = 225.85

hg = 2599.36

H2 = HF + x(hg -hf)

h2= 225.85+0.9(2599.36 - 225.85)

= 225.85 + 0.9(2373.51)

= 225.85 + 2136.159

= 2362.009

To find The power generated by this turbine:

We insert all the parameters into the equation below:

m(h1 - h2)

= 6(3248.4 - 2362.009)

= 6 x 886.391

= 5318.346KW

Answer:

Is

Explanation:

Answer:

D. All the above

Explanation:

A is correct. The theory of formation of concrete is based on this phenomenon of formation of voids because, a coarse aggregate aggregate on its own, contain voids. When a fine aggregate like sand is added, it occupies these voids. Further, when finely powdered cement is added to the mixture, it further occupies the voids between the sand particles.

B is correct. The bulking of sand should be taken into account when volumetric proportioning of the aggregates is adopted. Otherwise, less quantity of concrete per bag of cement will be produced, which naturally will increase the cost of concrete. This is because sand particles when left on their own, do not pack properly near each other due to sand buckling, leaving too many void spaces between the sand particles.

C is correct . The dry sand and the sand completely flooded with water have practically the same volume. This is due to the bulking of sand. When water is added to the sand, up to complete flooding, the sand particles pack near each other and the amount of bulking of sand is decreased. The addition of the volume of water, leads to a decrease in the volume of the sand due to the extra voids. These cancels out to practically leave the dry sand and the flooded sand with the same volume.

Answer: It is power stroke

Answer:  1804.61 lbs

Explanation:

Given, diameter of concrete column = 390 mm

= 0.390 m  [ 1 mm =0.001 m]

⇒ Radius = [tex]\dfrac{0.390}{2}=0.195\ m[/tex]

also, Length = 2.8 m

Volume of column  (cylindrical)= [tex]\pi r^2l[/tex]

[tex]=(3.14)(0.195)^2(2.8)[/tex]

[tex]=0.3343158\ m^3[/tex]

Density  [tex]=\dfrac{Mass }{Volume}=2.45\ Mg/m^3[/tex]  

⇒ Mass = 2.45 x (Volume)

= 2.45 (0.3343158) Mg

= 0.81907371 Mg

⇒ Mass = 819.07271 kg  [1 Mg =1000 kg]

Weight = [tex]{mass}\times{gravity}={819.07271}\times{9.8}=8026.91\ N[/tex]

1 N= 0.22482 lb

Then, Weight = [tex]0.22482\times 8026.91=1804.61\ lb[/tex]

Weight of the column in pounds.= 1804.61 lbs (approx)

Weight of the column is 1804.61 lbs.

Given that,

According to the given data, calculation are as follows,

Diameter = 0.39m

So, radius (r) = 0.39 [tex]\div[/tex] 2 = 0.195m

Volume of column = [tex]\pi r^{2}l [/tex]

By putting the value, we get

Volume = [ (3.14)[tex]\times[/tex] [tex](0.195)^{2} [/tex] [tex]\times[/tex] 2.8m ]

= [tex]0.3343158m^{3} [/tex]

Now, as we know that,

Density = Mass [tex]\div[/tex] Volume

Or, Mass (M) = Density [tex]\times[/tex] Volume

= 2.45 [tex]\times[/tex] 0.3343158

= 819.07271 kg

Now Weight = (M [tex]\times[/tex] Gravity )         Value of gravity is 9.8.

Weight = 819.07271 kg [tex]\times[/tex] 9.8

= 8026.91N

Where, 1N = 0.22482 lbs

So, Weight of the column = 1804.61 lbs

Learn more : https://brainly.com/question/21667661

Answer:

Bluray

DVD

CD

Explanation:

Blu ray can hold 25gb per layer

Dvd can hold 4.7GB on a single layer

Cd can hold around 737 mb

Also, dvds can go up to 2 layers

Blu ray can go up to 4

Answer:

CD

 ↓

DVD

  ↓

Blu-ray

Explanation:

Answer:

Qsp > ksp

Explanation:

given data

Ag2CrO4 = 9.0 × [tex]10^{-12}[/tex]

solution

new [[tex]Ag^+[/tex]] = [tex]\frac{0.005 \times 200}{200+300}[/tex] = 0.002 M     .................1

and

new [[tex]CrO^{2-}_4[/tex]] = [tex]\frac{0.002 \times 300}{200+300}[/tex]  = 0.0012M    ..............2

so here solubility equation will be as

[tex]Ag_2CrO_4(s)[/tex] ⇄  2[tex]Ag^+[/tex] (aq) + [tex]CrO^{2-}_4[/tex] (aq)    ......................3

so

Qsp = [tex][Ag^+]^2[/tex] [ [tex]CrO^{2-}_4[/tex]]

put here value

Qsp = (0.002)² × (0.0012)

Qsp = 4.80 × [tex]10^{-9}[/tex]  

so that we can say that Qsp > ksp

Answer:

At the middle of the DC load

Explanation:

For the Q point of an amplifier to have the Largest linear output. the Q plant has to be biased at the middle of the DC load line, this is because when the input voltage is low the transistor will be in the cutoff region while when the input voltage is very high the transistor will be in the saturation, hence when the Q point is biased at the middle it is will be higher linearly in relation to the active region

Answer:

A. Loose concrete

Explanation:

Concrete is a solid composite structural material.It is the most used component in setting up a structure. Concrete is known for its very good ability to bear load, but can sometimes fail, or can be damaged. To rehabilitate or repair a concrete, the loose concrete must first be removed, so that the surface can be cleaned and well set before the material used for repair is applied on it.

Answer:

Kindly check explanation

Explanation:

(a) μMN, (b) N/μm, (c) MN/ks2, and (d) kN/ms.

(a) μMN = (10^-6 * 10^6) = 10^(-6 + 6) = 10^0 = N

b) N/μm = N / 10^-6 m = 10^6 * N/m = MN/m

(c) MN/ks2 = 10^6N / (10^3 s)^2

10^6 N / 10^6s^2 = 10^6 * 10^-6 N /s^2 = N/s^2

D) kN/ms = 10^3N / 10^-3 s = 10^3 * 10^3 * N/s = 10^6N / s = MN/s

2)

a) 0.000431kg = 431 × 10^6 kg = 431 * 10^9g = 431Gg

b) 35.3 × 10^3 N

10^3 = kilo(K)

35.3 KN

C) 0.00532km = 5.32 * 10^3 km = 5.32 * 10^3 * 10^3 = 5.32 * 10^6 = 5.32Mm

3) Represent each of the following combinations of units in the correct SI form: (a) Mg/ms, (b) N/nm, and (c) mN/(kg⋅μs).

a) Mg/ms = 10^6g / 10^-3s = 10^6 * 10^3 g/s = 10^9 g/s = Gg/s

b) N/nm = N / 10^-9 m = 10^9 N/m = GN/m

c) mN/(kg⋅μs) = 10^6N / kg(10^-6s) = 10^12N/(kg.s)

= TN/(kg.s)

Answer:

B) 5.05

Explanation:

The wall thickness of a pipe is the difference between the diameter of outer wall and the diameter of inner wall divided by 2. It is given by:

Thickness of pipe = (Outer wall diameter - Inner wall diameter) / 2

Given that:

Inner diameter = ID = 25 ± 0.05, Outer diameter = OD = 35 ± 0.05

Maximum outer diameter = 35 + 0.05 = 35.05

Minimum inner diameter = 25 - 0.05 = 24.95

Thickness of pipe = (maximum outer wall diameter - minimum inner wall diameter) / 2 = (35.05 - 24.95) / 2 = 5.05

or

Thickness = (35 - 25) / 2 + 0.05 = 10/2 + 0.05 = 5 + 0.05 = 5.05

Therefore the LMC wall thickness is 5.05

Answer:

Their purpose is to invent, design, analyze, build and test machines, complex systems, structures, gadgets and materials to fulfill functional objectives and requirements while considering the limitations imposed by practicality, regulation, safety and cost.

Answer:

To make things

Explanation:

Answer:

The answer is false, I hope this helps. :3

Answer:

False

Explanation:

I took the quiz and it was correct

John Smeatom, U.K. 18th century, was the first self-proclaimed, civil engineer in the 18th century and IS considered “the father of modern, civil engineering”.

hoped this helped! :)

Answer:

Sir Mokshagundam Visvesvaraya

Answer:

see below

Explanation:

10 per hour

example: 37.5 hours in a week

10 x 37.5 hours per week x 52 weeks in a year

19,500 per year.

you can use the above calculation depending on how much you want to work per week.

Answer:

(a) km/s

(b) mm

(c) Gs/kg

(d) mmN

Explanation:

(a) Given:

m / ms => the proper SI unit should be m/s

So let's convert to m/s

m / ms = [tex]\frac{m}{ms}[/tex]

The denominator is ms which means milliseconds.

But milli = 10⁻³

∴ [tex]\frac{m}{ms}[/tex] = [tex]\frac{m}{10^{-3}s}[/tex] = [tex]\frac{10^3m}{s}[/tex]

Also 10³ = kilo (k)

[tex]\frac{10^3m}{s}[/tex] = [tex]\frac{km}{s}[/tex]

∴ m / ms = [tex]\frac{km}{s}[/tex] =  km/s

(b) Given:

μkm => the proper SI unit should be m

So let's convert to m

μkm = 10⁻⁶ km [since μ = 10⁻⁶]

=> μkm = 10⁻⁶ x 10³ m [since k = 10³]

=> μkm = 10⁻³ m

But 10⁻³ = milli (m)

=> μkm = 10⁻³ m = mm

∴ μkm = mm

(c) Given:

ks/mg => the proper SI unit should be s/kg

So let's convert to s/kg

ks/mg = 10³s / mg [since k = 10³]

=> ks/mg = 10³s / 10⁻³g [since m = 10⁻³]

=> ks/mg = 10³ x 10³ s / g

=> ks/mg = 10⁶ s / g

=> ks/mg = [tex]\frac{10^6 s}{g}[/tex]

Multiply the numerator and denominator by 10³

=> ks/mg = [tex]\frac{10^6 X 10^3s}{10^3 X g}[/tex]

=> ks/mg = [tex]\frac{10^9s}{10^3 X g}[/tex]

=> ks/mg = [tex]\frac{Gs}{10^3 X g}[/tex]  [since 10⁹ = Giga (G) ]

=> ks/mg = [tex]\frac{Gs}{kg}[/tex]  [since 10³ = Kilo (k) ]

∴ ks/mg = [tex]\frac{Gs}{kg}[/tex]  = Gs/kg

(d) Given:

km.μN => the proper SI unit should be mN or Nm

So let's convert to km.μN

km.μN = 10³m.μN                 [since k = 10³]

=> km.μN = 10³m.10⁻⁶N        [since μ = 10⁻⁶]

=> km.μN = 10⁻³ mN

=> km.μN = mmN             [since m = milli = 10⁻³]

∴ km.μN = mmN

Answer:

1) Visual Communication involves the use of images ans symbolism for the exchange of ideas from a source to the intended audience.

Visual Communication can help enhance the message conveyed by the speaker when the message being conveyed is new to the audience, such as instructional or educational presentation by enable the audience to more quickly understand the the point of view of the speaker

2) A particular situation where it is best to use visual communication is in a communication that involves giving of traffic and way finding details to a tourist

Explanation:

Visual communication can improve the message that is transmitted with the speaker through the transmission of additional concepts to the message, such as gestures, body expressions or communicative looks, which add meanings to the words emitted.

Today, visual communication is extremely developed and is designed to perform several tasks at once. Communication through visual images is progressing thanks to the development of new technologies. Visual communication is one of the key components of modern media and social media.

Learn more in https://brainly.com/question/6753854

Answer:

More Drag on the down going wing and More Lift on the up going wing

Explanation:

The autorotation spins of blades used in airborne wind energy technology sectors help drive and move the winds and water propeller-type turbines or shafts of generators to produce electricity at altitude and transmit the electricity to earth through conductive tethers.

Sometimes autorotation takes place in rotating parachutes, kite tails. Etc.

As a result, more Drag usually induces the autorotation spin characteristics of a straight-wing aircraft on the downgoing wing and More Lift on the up-going wing.

Answer: The Government.

Explanation: Highways are usually a roads where people travel on. They are usually owned mainly by the government some are owned by private entities. Of the above options the most possible employer of Trevor is the government as majority of the highways are usually owned by the government.

The government provide several services on the highways such as roads maintenance, security, accidents and emergency cares etc

Answer: I think it's C, I hope this helps ;)

Answer: Tech B

Explanation:

From the question above, tech B saying the automotive industry offers numerous career choices is the correct answer. Pursuing a career in automotive industry is challenging and rewarding as one works with both vehicles and technology.

Examples of career choices in the automotive industry are car detailer, tire technician, car rental agent, auto mecahnic, vehicle inspector, auto electrician, auto engineer etc.

Answer:

The transistor goes into cutoff ( A )

Explanation:

In a voltage-divider biased npn transistor, if the upper voltage-divider resistor (the one connected to VCC) opens the transistor goes into cutoff

Voltage-divider biased npn transistor is a transistor that consists of some resistors and this resistors help to divide and distribute the voltage entering the transistor into its correct levels ( this is the most popular means of biasing a BJT transistor )

Answer:

A. 0.66 Amps

Explanation:

Using ohms law, we can say that Voltage is equivalent to Current times Resistance.  We are given the voltage and the resistance of the circuit, so we simply need to find the current.

V = IR

Solve for I, where V = 2volts and R = 3ohms.

V = IR

V * 1/R = I * R * 1/R

I = V/R

I = 2/3 Amps

Hence, we should choose option A, 0.66 Amps for the current in this simple circuit.

Cheers.

Answer:

a) 4.51 lbf-s^2/ft

b) 65.8 kg

c) 645 N

d) 23.8 lb

e) 65.8 kg

Explanation:

Weight of the man on Earth = 145 lb

a) Mass in slug is...

32.174 pound = 1 slug

145 pound = [tex]x[/tex] slug

[tex]x[/tex] = 145/32.174 = 4.51 lbf-s^2/ft

b) Mass in kg is...

2.205 pounds = 1 kg

145 pounds = [tex]x[/tex] kg

[tex]x[/tex] = 145/2.205 = 65.8 kg

c) Weight in Newton = mg

where

m is mass in kg

g is acceleration due to gravity on Earth = 9.81 m/s^2

Weight in Newton = 65.8 x 9.81 = 645 N

d) If on the moon with acceleration due to gravity of 5.30 ft/s^2,

1 m/s^2 = 3.2808 ft/s^2

[tex]x[/tex] m/s^2 = 5.30 ft/s^2

[tex]x[/tex] = 5.30/3.2808 = 1.6155 m/s^2

weight in Newton = mg = 65.8 x 1.6155 = 106

weight in pounds = 106/4.448 = 23.8 lb

e) The mass of the man does not change on the moon. It will therefore have the same value as his mass here on Earth

mass on the moon = 65.8 kg