The lines graphed below are perpendicular. The slop of the red line is -1/3. What is the slope of the green line

Answer:

Symmetry is the property of an object to retain its shape even if it is turned or turned.

The three corporate logos are McDonald, Shell, Snapcaht

McDonald company logo is symmetrical and it is a reflective symmetry.

Shell logo is symmetrical and it is also reflective symmetry.

Snaphcat logo is symmetrical and it is also reflective symmetry.

Answer:

explanation

Step-by-step explanation:

the reason for your statement is just your explanation of why you think that.

Answer:

6/35

Step-by-step explanation:

add ¹/7+¹/5 =12/35

divide 12/35 by 2

=6/35

Answer:

Slope is -0.4 or 2/5

Step-by-step explanation:

x , y   x^2,y^2

(-1,4)   (14,-2)

y^2-y^1/x^2-x^1

-2-4/14-(-1)

-6/15

=-2/5 or -0.4.

Hope this helps. If right pls give me brainliest thank you.

Answer:

it is -2/5

Step-by-step explanation:

Answer:

Step-by-step explanation:

Question (1). An alloy contains zinc and copper in the ratio of 7 : 9.

If the weight of an alloy = x kgs

Then weight of copper = [tex]\frac{9}{7+9}\times (x)[/tex]

                                      = [tex]\frac{9}{16}\times (x)[/tex]

And the weight of zinc = [tex]\frac{7}{7+9}\times (x)[/tex]

                                      = [tex]\frac{7}{16}\times (x)[/tex]

If the weight of zinc = 31.5 kg

31.5 = [tex]\frac{7}{16}\times (x)[/tex]

x = [tex]\frac{16\times 31.5}{7}[/tex]

x = 72 kgs

Therefore, weight of copper = [tex]\frac{9}{16}\times (72)[/tex]

                                               = 40.5 kgs

2). i). 2 : 3 = [tex]\frac{2}{3}[/tex]

        4 : 5 = [tex]\frac{4}{5}[/tex]

Now we will equalize the denominators of each fraction to compare the ratios.

[tex]\frac{2}{3}\times \frac{5}{5}[/tex] = [tex]\frac{10}{15}[/tex]

[tex]\frac{4}{5}\times \frac{3}{3}=\frac{12}{15}[/tex]

Since, [tex]\frac{12}{15}>\frac{10}{15}[/tex]

Therefore, 4 : 5 > 2 : 3

ii). 11 : 19 = [tex]\frac{11}{19}[/tex]

    19 : 21 = [tex]\frac{19}{21}[/tex]

By equalizing denominators of the given fractions,

[tex]\frac{11}{19}\times \frac{21}{21}=\frac{231}{399}[/tex]

And [tex]\frac{19}{21}\times \frac{19}{19}=\frac{361}{399}[/tex]

Since, [tex]\frac{361}{399}>\frac{231}{399}[/tex]

Therefore, 19 : 21 > 11 : 19

iii). [tex]\frac{1}{2}:\frac{1}{3}=\frac{1}{2}\times \frac{3}{1}[/tex]

             [tex]=\frac{3}{2}[/tex]

     [tex]\frac{1}{3}:\frac{1}{4}=\frac{1}{3}\times \frac{4}{1}[/tex]

              = [tex]\frac{4}{3}[/tex]

Now we equalize the denominators of the fractions,

[tex]\frac{3}{2}\times \frac{3}{3}=\frac{9}{6}[/tex]

And [tex]\frac{4}{3}\times \frac{2}{2}=\frac{8}{6}[/tex]

Since [tex]\frac{9}{6}>\frac{8}{6}[/tex]

Therefore, [tex]\frac{1}{2}:\frac{1}{3}>\frac{1}{3}:\frac{1}{4}[/tex] will be the answer.

IV). [tex]1\frac{1}{5}:1\frac{1}{3}=\frac{6}{5}:\frac{4}{3}[/tex]

                  [tex]=\frac{6}{5}\times \frac{3}{4}[/tex]

                  [tex]=\frac{18}{20}[/tex]

                  [tex]=\frac{9}{10}[/tex]

Similarly, [tex]\frac{2}{5}:\frac{3}{2}=\frac{2}{5}\times \frac{2}{3}[/tex]

                       [tex]=\frac{4}{15}[/tex]                  

By equalizing the denominators,

[tex]\frac{9}{10}\times \frac{30}{30}=\frac{270}{300}[/tex]

Similarly, [tex]\frac{4}{15}\times \frac{20}{20}=\frac{80}{300}[/tex]

Since [tex]\frac{270}{300}>\frac{80}{300}[/tex]

Therefore, [tex]1\frac{1}{5}:1\frac{1}{3}>\frac{2}{5}:\frac{3}{2}[/tex]

V). If a : b = 6 : 5

     [tex]\frac{a}{b}=\frac{6}{5}[/tex]

        [tex]=\frac{6}{5}\times \frac{2}{2}[/tex]

        [tex]=\frac{12}{10}[/tex]

  And b : c = 10 : 9

  [tex]\frac{b}{c}=\frac{10}{9}[/tex]

 Since a : b = 12 : 10

 And b : c = 10 : 9

 Since b = 10 is common in both the ratios,

 Therefore, combined form of the ratios will be,

 a : b : c = 12 : 10 : 9

Answer:

C

Step-by-step explanation:

1:draw a very simple Cartesian plane for the graph

2:label the quadrants 1-4 from top right round to bottom right as 4

3:then apply x>0 (1,2) is top right and y<0 is bottom right (-1,-2)

Answer:

Step-by-step explanation:

The values ​​of the cosine function are represented by the axis OX of the goniometric circumference (circumference centered at the origin and of radius 1). Therefore the cosine is zero for the 90º and 270º angles.

Answer:

[tex]\boxed{x=7, \: x=-13}[/tex]

Step-by-step explanation:

[tex]|3x+9|= 30[/tex]

Solve for absolute value.

There are two possibilities.

One possibility:

[tex]3x+9=30\\3x=21\\x=7[/tex]

Second possibility:

[tex]3x+9=-30\\3x=-39\\x=-13[/tex]

Answer: $466

Step-by-step explanation:

Answer:

b.$466

Step-by-step explanation:

Answer:

144 codes are possible

Step-by-step explanation:

Okay for the first digit, we shall be selecting one out of 3,4,5,6.

Meaning we are selecting one out of four choices

The number of ways this can be done is 4C1 ways = 4 ways

For the second digit, we have 5,6,7 or 8, we are still selecting 1 out of 4 selections and the number of ways we can do this is also 4 ways

And lastly , we can choose any digit for the last number expect 5 , so from 0 to 9, we are removing 1 which means we are left with 9 choices

So the number of different area codes possible are ; 9 * 4 * 4 = 144 codes

Answer:

49

Step-by-step explanation:

[tex]3x^2+5x-2 = 0[/tex]

Apply discriminant formula : [tex]D = b^2- 4ac[/tex]

[tex]D=discriminant\\b=5\\a=3\\c=-2[/tex]

[tex]D = b^2- 4ac[/tex]

Plug in the values for a, b, and c.

[tex]D = 5^2- 4(3)(-2)[/tex]

Evaluate.

[tex]D = 25- 12(-2)[/tex]

[tex]D = 25- - 24[/tex]

[tex]D=25+24[/tex]

[tex]D=49[/tex]

Answer:

49

Step-by-step explanation:

3x²+5x-2 = 0

This is in the form

ax^2 + bx + c=0

a=3  b=5  c = -2

The discriminant is

b^2 -4ac

5^2 -4(3) (-2)

25 + 24

49

The discriminant is 49

Answer:

The answer would be zero. This is due to the fact that the tangent is a line on a point around the circle. These two circles share no common tangents.

Step-by-step explanation:

The number of the common tangent to the concentric circles is zero. Option D is correct.

Two concentric circles are given in the figure, and common tangents to the circles are to be determined.

The circle is the locus of a point whose distance from a fixed point is constant i.e center ( h, k ). The equation of the circle is given by[tex](x-h)^2 + (y-k)^ = r^2[/tex]. where h, k is the coordinate of the center of the circle on the coordinate plane and r is the radius of the circle.

Since the line passes through the circumference of the circle is known as a tangent to the circle and the common tangent of the concentric circle is not possible because the tangent to the inner circle results secant to the outer circle.

Thus, the number of the common tangent to the circles is zero. Option D is correct.

Learn more about circle here:

brainly.com/question/11833983

#SPJ5

Answer:

17

Step-by-step explanation:

3m-(m + 5)

Distribute the minus sign

3m -m -5

Combine like terms

2m -5

Let m =11

2*11 -5

22-5

17

Answer:

[tex]17[/tex]

Step-by-step explanation:

[tex]3m-(m + 5)[/tex]

[tex]m= 11[/tex]

Plug m as 11 in the expression.

[tex]3(11)-(11+5)[/tex]

Evaluate.

[tex]33-16[/tex]

[tex]=17[/tex]

Answer:

x = -7/9; y = 4/3.

Step-by-step explanation:

I will assume that the top equation is 6x + 2y = -2, and the bottom one is 3x - 2y = -5.

If you add the two...

(6x + 3x) + (2y + (-2y)) = (-2 + (-5))

9x + 0 = -7

9x = -7

x = -7/9

6(-7/9) + 2y = -2

-42/9 + 2y = -18/9

2y = 24/9

y = 24/18

y = 12/9

y = 4/3

Hope this helps!

Answer: 15 teams

Step-by-step explanation:

Total number of games played in the tournament = 105

Number of participating teams = p

Each team plays against every other team , then the total number of games played by each team = (p - 1) , since a team can't play itself

To obtain total number of games played =

(Number of teams × number of games played) [p × (p-1)]

However, the teams played against each other only once :

Therefore, total number of games played:

[p × (p-1)] / 2

Since we've been given the total number of games played :

[p × (p-1)] / 2 = 105

p × (p-1) = 105 × 2

p × (p-1) = 210

p^2 - p = 210

p^2 - p - 210 = 0

p^2 - 15p + 14p - 210 = 0

p(p - 15) +14(p-15) = 0

(p - 15) = 0 or (p + 14) = 0

p = 15 or p = - 14

Number of teams can't be negative

Therefore p = 15

Number of teams = 15

Answer:

x = 66°

Step-by-step explanation:

Hello,

This question involves use of rules or theorems of angles in a right angled triangle

<DAB + <BAC = 180°

Sum of angles on a straight line = 180°

98° + <BAC = 180°

<BAC = 180° - 98°

<BAC = 82°

Now, we can use <BAC to find x because some of angles in a triangle is equal to 180°

32° + 82° + x = 180°

Sum of angles in a triangle = 180°

114° + x = 180°

x = 180° - 114°

x = 66°

Angle x = 66°

Answer:

72

Step-by-step explanation:

First find the discount

10% of 80

.10 * 80

8

Subtract this amount from the bill

80 -8 = 72

The customer will pay 72

Answer:

69

Step-by-step explanation:

A triangle has a 180 degree angle so you do 180-111=69

Answer: x=24

Step-by-step explanation:

lets say 94 is ∠ a

41 is ∠ b

___ ∠  c

111∠ d

x ∠ e

so with that you will figure out that ∠  c is to find X

108-94-41= 45

so ∠ c is 45

now you can ∠a ∠ b∠ c

with that yo take

108-111-45=24

So X=24

Answer:

The number is 3

Step-by-step explanation:

The fraction is 11/36

let

x = no. added to the numerator

2x = no. added to denominator

We have,

x+11/2x+36=1/3

Cross multiply

3(x+11) = (2x + 36)

3x + 33 = 2x + 36

Collect like terms

3x - 2x = 36 - 33

x=3

The number is 3

Check:

3+11/6+36=1/3

14/42=1/3

Answer:

Step-by-step explanation:

Use BODMAS rule:

B = Bracket

O = Of

D = Division

M = Multiplication

A = Addition

S = Subtraction

Now, let's Solve,

[tex]52 + 2 \times (9) + 6[/tex]

First, we have to multiply the numbers:

[tex] = 52 + 18 + 6[/tex]

Add the numbers:

[tex] = 76[/tex]

Hope this helps...

Good luck on your assignment...

Answer:

6c1;   [tex]Area = 81.12m^2[/tex]

6cii:  See Explanation

Step-by-step explanation:

Given

[tex]A = 3p^2[/tex]

[tex]0 \leq p \leq 6[/tex]

Where A represents Area and P represents Width

Required

Solve 6c

Please note that because you only need 6c, I'll solve using calculations;

Solving 6ci:

Area of the cage, when width is 5.2m

Substitute 5.2m for p in[tex]A = 3p^2[/tex]

[tex]A = 3 * 5.2m^2[/tex]

[tex]A = 3 * 27.04m^2[/tex]

[tex]A = 81.12m^2[/tex]

Hence, the area of the cage is 81.12m²

Solving 6cii:

Area of the cage, when width is 40m

From the range of value of p:   [tex]0 \leq p \leq 6[/tex], 40m is out of range of the values of p

However, if the range is extended; the value of Area is as follows;

Substitute 40m for p

[tex]A = 3 * 40m^2[/tex]

[tex]A = 3 * 1600m^2[/tex]

[tex]A = 4,800m^2[/tex]

Answer:

A=3244.8 dollars

Step-by-step explanation:

A=p(1+r)^t

A=3000(1+0.04)^2

A=3244.8 dollars

Answer:

Step-by-step explanation:

[tex]6\: km\: in \:10\: minutes\\First\:lets\:convert\:10\:min\:to\:seconds\\\\1\:minute \:\:\:\:=60\:seconds\\\\10\:minutes = x \:seconds\\\\x = 60\times 10\\x = 600seconds\\\\6km\: = 600\:seconds\\x\:km = 1 \:second\\\\Cross\:Multiply\\600x =6\\\frac{600x}{600} =\frac{6}{600} \\\\x = 1/100\\\\ =0.01km[/tex]

Answer:

? = 26 in

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

?² = 24² + 10² = 576 + 100 = 676 ( take the square root of both sides )

? = [tex]\sqrt{676}[/tex] = 26

Answer:

26 inch

Step-by-step explanation:

unknown side can be found using Pythagorean theorem

a*a+b*b=c*c

24*24+10*10=c*c

576+100=c*c

√676=c

c=26inche

Answer:

366.6 mm²

Step-by-step explanation:

Step 1: find XY using the Law of sines.

Thus,

[tex] \frac{XY}{sin(W)} = \frac{WY}{sin(X)} [/tex]

m < W = 180 - (70+43) (sum of angles in a triangle)

W = 180 - 113 = 67°

WY = 24 mm

X = 43°

XY = ?

[tex] \frac{XY}{sin(67)} = \frac{24}{sin(43)} [/tex]

Cross multiply:

[tex] XY*sin(43) = 24*sin(67) [/tex]

[tex] XY*0.68 = 24*0.92 [/tex]

Divide both sides by 0.68 to solve for XY

[tex] \frac{XY*0.68}{0.68} = \frac{24*0.92}{0.68} [/tex]

[tex] XY = 32.47 [/tex]

XY ≈ 32.5 mm

Step 2: find the area using the formula, ½*XY*WY*sin(Y).

Area = ½*32.5*24*sin(70)

Area = ½*32.5*24*0.94

= 32.5*12*0.94

Area = 366.6 mm² (nearest tenth)

Answer:

rectangular prism

Step-by-step explanation:

check by rotating the shape in images

Answer:

4 liters

Step-by-step explanation:

Let's assume that the side lengths of the cubical block are 2 inches.

This means that one of the sides area is 4 in².

Multiplying this by 6 (for there are 6 sides) gets us 24 in².

So one liter of paint covers 24 in².

Now if the side lengths (edge) of the second block is doubled, that means that the side lengths are [tex]2\cdot2 = 4[/tex] inches.

So the area of one side is 16 in².

Multiplying this by 6 (as there are 6 sides) gets us 96 in².

To find how many liters of paint this will take, we divide 96 by 24.

[tex]96\div24=4[/tex]

So 4 liters of paint will be needed for the second cubical block.

Hope this helped!

the answer is (A) you cant have 11 it should be 1.1 x 10^22

The correlation coefficient r is always between -1 and 1, inclusive of both endpoints. We can write [tex]-1 \le r \le 1[/tex]

If r = 0, then we have no linear correlation at all. If r = 1, then we have perfect positive correlation. If r = -1, then we have perfect negative correlation.

We see that r = 0.9 is close to r = 1, so we have strong positive linear correlation going on here.

Answer:

[tex]y\geq 0\\y\geq \frac{3}{2}x-3\\ y\leq -x+3[/tex]

Step-by-step explanation:

The region R is surrounded by 4 lines, the first one is y=x+1, the second one is y=0 or the axis x, and the third and fourth one need to be calcualted.

To find the equation of a line through the points (x1,y1) and (x2, y2) we can use the following equation:

[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

Then, our third line is going to be the line that passes through the points (2,0) and (4,3), so the equation is:

[tex]y=\frac{3-0}{4-2}(x-2)\\y=\frac{3}{2}x-3[/tex]

Our fourth line is the line that passes through the points (3,0) and (0,3), so the equation is:

[tex]y=\frac{3-0}{0-3}(x-3)\\y=-x+3[/tex]

Then we can say that the other three inequalities are:

[tex]y\geq 0\\y\geq \frac{3}{2}x-3\\ y\leq -x+3[/tex]