HELPP!!! ALMOST OUT OF TIME
Answer:
option 2 is correct
Step-by-step explanation:
Another 2 btc please
Solve for r.
K=4r-7s
r=
Answer:
[tex]r=\frac{k+7s}{4}[/tex]
Step-by-step explanation:
HELP! PLEASEE I’ve been stuck!! I WILL GIVE BRAINLY,,, THANK YOU SM
Answer:
$119
Step-by-step explanation:
08:00 - 12:15 = 4hrs 15mins
13:00 - 17:15 = 4hrs 15mins
Total hours worked = 8hrs 30 mins
$14/hr
14 × 8 = 112
30 mins is half of an hour so 14/2 = 7
$7 for 30 mins
112 + 7 = 119
$119
hope this helps ^^
100 POINTS !!!! Let f(x)=√3x and g(x)=x-6 What's the smallest number that is in the domain of fog?
Answer:
6
Step-by-step explanation:
fog(x) = √3(x-6)
Domain => 3(x-6) ≥ 0
<=> x-6≥ 0
=> x ≥ 6
so, the smallest number is 6
As
(fog)(x)=f(g(x))
g(x)=x-6f(g(x))
f(x-6)√3(x-6)So
x-6≥0x≥6Smallest no is 6
Rewrite the expression using exponents.
7 • 4 • 4 • 4
(Type whole numbers.)
Answer: 7×4³
Step-by-step explanation:
Answer:
7 x 4³
Step-by-step explanation:
using exponents to my understanding,
the answer vis supposed to be;
7 x 4³
Which equation is true?
Answer:
The third option
Step-by-step explanation:
[tex]\frac{-56}{8} = -7[/tex]
A. G(X) > -6
B. All real numbers
C. G(X) < 0
D. G(X) < 10
Answer:
can't explain how but i'm confident the answer is:
A. G(X) > -6
Factor the polynomial
x^3-3x^2+x
Answer:
Solution given:
x³-3x²+x
taking common
x(x²-3x+1)
is a required answer.
The first day of a water polo tournament the total value of tickets sold was $1540. One-day passes sold for $10
and tournament passes sold for $20. The number of tournament passes sold was 23 more than the number of day
passes sold. How many day passes and tournament passes were sold?
Answer:
59 tournament passes and 36 one-day passes were sold.
Step-by-step explanation:
Since the first day of a water polo tournament the total value of tickets sold was $ 1540, and one-day passes sold for $ 10 and tournament passes sold for $ 20, and the number of tournament passes sold was 23 more than the number of day passes. sold, to determine how many day passes and tournament passes were sold, the following calculation must be performed:
20 x 33 + 10 x 10 = 760
20 x 63 + 10 x 40 = 1,660
20 x 58 + 10 x 35 = 1,510
20 x 59 + 10 x 36 = 1,540
Thus, 59 tournament passes and 36 one-day passes were sold.
Resuelve el siguiente ejercicios de porcentaje:
¿32 representa el 64% de qué número?
Answer:
50
Step-by-step explanation:
32/0.64 = 50
In desperate need. for answer 11 and 12.
Question 11 has to have an answer with explanation and
Question 12 has 3 parts. I need answers to all three with explanations for all three.
Solve the system of equations using substitution or graphing.
y= -x2 + 4x + 5
y= x + 1
OA) (-1,0) and (6,7)
OB) (-1,0) and (4,5)
C) (1, 2) and (4,5)
D) (1, 2) and (6,7)
What is the value of x?
Answer:
Hello! answer: x = 15
Step-by-step explanation:
Here is a visual i created of what the complementary angle would look like!
Which of the following statements best describes the difference between net income and gross profit? a. Gross profit considers operating expenses while net income does not. b. Net income considers operating expenses while gross profit does not. c. Gross profit deducts taxes while net income does not. d. Net income deducts taxes while gross profit does not. Please select the best answer from the choices provided A B C D
Answer:
its b
Step-by-step explanation:
edg 20/21
g if we want to calculate a confidence interval of the difference of two proportions what is the standard error (do not pool for this answer)
Answer:
The standard error is [tex]s = \sqrt{\frac{\pi_1(1-\pi_1)}{n_1}+\frac{\pi_2(1-\pi_2)}{n_2}}[/tex], in which [tex]p_1,p_2[/tex] are the proportions and [tex]n_1,n_2[/tex] are the sample sizes.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].
The standard error is:
[tex]s = \sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
For the difference of proportions:
For proportion 1, the standard error is:
[tex]s_1 = \sqrt{\frac{\pi_1(1-\pi_1)}{n_1}}[/tex]
For proportion 2, the standard error is:
[tex]s_2 = \sqrt{\frac{\pi_2(1-\pi_2)}{n_2}}[/tex]
For the difference:
The standard error is the square root of the sum of the squares of each separate standard error. So
[tex]s = \sqrt{(\sqrt{\frac{\pi_1(1-\pi_1)}{n_1}})+(\sqrt{\frac{\pi_2(1-\pi_2)}{n_2}})^2} = \sqrt{\frac{\pi_1(1-\pi_1)}{n_1}+\frac{\pi_2(1-\pi_2)}{n_2}}[/tex]
The standard error is [tex]s = \sqrt{\frac{\pi_1(1-\pi_1)}{n_1}+\frac{\pi_2(1-\pi_2)}{n_2}}[/tex], in which [tex]p_1,p_2[/tex] are the proportions and [tex]n_1,n_2[/tex] are the sample sizes.
18. If an apprentice can do a piece of work in 24 days, and the apprentice and
instructor together can do it in 6 days, how long would it take the instructor to do
the work alone?
18. If an apprentice can do a piece of work in 24 days, and the apprentice and
instructor together can do it in 6 days, how long would it take the instructor to do
the work alone?
Answer:
the number of days when instructor do the work alone is 8 days
Step-by-step explanation:
Given that
The apprentice can do the work in 24 days
And, the apprentice and instructor together can do it in 6 days
We need to find out the number of days when instructor do the work alone
So,
[tex]= \frac{1}{6} - \frac{1}{24} \\\\= \frac{4 - 1}{24} \\\\= \frac{3}{24} \\\\= \frac{1}{8} \\\\= 8[/tex]
hence, the number of days when instructor do the work alone is 8 days
Evaluate the following complex expression. (4+ i) 2= + i (-4 i)(3 i)= i 3(9- i)= - i (5+2 i)(3-7 i)= - i (8+5 i)+2(3 i-4)= i (4+6 i)-(-4- i)= + i
Answer:
Operations on Complex Numbers (page 2 of 3) ... Simplify (2 – i)(3 + 4i). (2 – i)(3 + 4i) = (2)(3) + (2)(4i) + (–i)(3) + (–i)(4i). = 6 + 8i – 3i – 4i2 = 6 + 5i – 4(–1) ... exact same techniques for simplifying complex-number expressions as you do for polynomial ... Suppose you have the following exercise:
Step-by-step explanation:
Find the 12th term of the geometric sequence 5, 20, 80, ...5,20,80
Answer:
a₁₂ = 20971520
Step-by-step explanation:
The nth term of a geometric sequence is
[tex]a_{n}[/tex] = a₁[tex](r)^{n-1}[/tex]
where a₁ is the first term and r the common ratio
Here a₁ = 5 and r = a₂ ÷ a₁ = 20 ÷ 5 = 4 , then
a₁₂ = 5 × [tex]4^{11}[/tex] = 5 × 4194304 = 20971520
What is 787,452 rounded to the nearest ten thousand?
Answer:
790000
Step-by-step explanation:
Answer:
790,000
Step-by-step explanation:
What clockwise rotation is equivalent to a 90° counterclockwise rotation?
Answer: 270°
Step-by-step explanation:
A full rotation is 360° so to find out the clockwise equivalent of a 90° counterclockwise rotation, deduct the counterclockwise rotation from 360°:
= 360 - 90
= 270°
If you rotated 90° counterclockwise, you would get to the same point as if you rotated 270° clockwise.
Express ( 3/2x-2)^2
as a trinomial in simplest form.
Answer:
9/4x^2 - 6x +4
Step-by-step explanation:
( 3/2x-2)^2
(3/2x-2)(3/2x-2)
9/4x^2 - 3x - 3x +4
9/4x^2 - 6x +4
3/2 x 2 = 6/2 = 3
Step-by-step explanation:
( 3/2x-2)² = 9/4 x²- 6x +4
HELPPP
PLLS
DUE RN
WILL
GIVE BRAINLIST
X
X
X
X
Answer:
33% of the people preferred onions
can i get brainliest now lol
how many 1/8 cups are in 4/4
Answer:8
is the answer
Can anyone help me ASAP please
The x-intercept is the point on the x-axis where the line crosses it. The
y-coordinate of the line's x-intercept is always zero. The x-coordinate of the
x-intercept is the number where it crosses the x-axis. A line with an x-
intercept of (5,0) crosses the x-axis at the number 5. A line with an x-
intercept of (-5,0) crosses the x-axis at -5.
Which of these coordinates could be a line's x-intercept?
A
(3,1)
B
(0,-12)
С
(-5,4)
(-7,0)
Answer:
D
Step-by-step explanation:
Cab 1 charges $1 per kilometer. Cab 2 charges $0.50 per kilometer and a $4 base charge. Solve for the value of k(kilometers ) that the 2 cab companies would cost the same.
Answer:
k=8
Step-by-step explanation:
Cab 1 : 1/km
Cab2: 0.5 /km with Base charge =4
x=0.5 x+4
x-0.5x=4
0.5x=4
4/0.5=x
x=8
Assume x=k
k=8
if it is correct i will mark as brainlist or i will report
Answer:
The number of non-positive integral values of [tex]k[/tex] are contained in the following set:
[tex]S_{k} = \{-1, 0\}[/tex]
Step-by-step explanation:
Let be the following second order polynomial:
[tex]x^{2}-(k + 1)\cdot x + (k^{2}+k -8) = 0[/tex], [tex]k \le 0[/tex] (1)
Whose roots can be found by the Quadratic Formula:
[tex]x_{1,2} =\frac{k + 1\pm \sqrt{k^{2}+2\cdot k +1 - 4\cdot k^{2}-4\cdot k +32 }}{2}[/tex]
[tex]x_{1,2} = \frac{k+1}{2} \pm \frac{\sqrt{33-2\cdot k -3\cdot k^{2}}}{2}[/tex]
Based on the statement, we have the following system of inequations:
[tex]\frac{k+1}{2} + \frac{\sqrt{33 - 2\cdot k -3\cdot k^{2}}}{2} > 2[/tex] (2)
[tex]\frac{k+1}{2} - \frac{\sqrt{33 - 2\cdot k -3\cdot k^{2}}}{2} < 2[/tex] (3)
By (2) we have:
[tex]k + 1 + \sqrt{33-2\cdot k -3\cdot k^{2}} > 4[/tex]
[tex]\sqrt{33 -2\cdot k - 3\cdot k^{2}} > 4 - (k + 1)[/tex]
[tex]33 - 2\cdot k -3\cdot k^{2} > [4 - (k+ 1)]^{2}[/tex]
[tex]33 - 2\cdot k -3\cdot k^{2} > 16 -8\cdot (k+1)+(k+1)^{2}[/tex]
[tex]33 - 2\cdot k - 3\cdot k^{2} > 16-8\cdot k -8 + k^{2}+2\cdot k + 1[/tex]
[tex]33 - 2\cdot k -3\cdot k^{2} > 9 -6\cdot k + k^{2}[/tex]
[tex]0 > 4\cdot k^{2}-4\cdot k -24[/tex]
[tex]4\cdot k^{2}-4\cdot k -24< 0[/tex]
[tex]4\cdot (k^{2}-k-6) < 0[/tex]
[tex]k^{2}-k - 6 < 0[/tex]
[tex](k -3)\cdot (k+2) < 0[/tex]
The solution is:
[tex]k \in (-2, 3)[/tex]
Likewise, we get the following expression from (3):
[tex]k^{2}-k - 6 > 0[/tex]
[tex](k -3)\cdot (k + 2) > 0[/tex]
The solution is:
[tex]k \in (-\infty, -2)\,\cup\,(3, +\infty)[/tex]
The number of non-positive integral values of [tex]k[/tex] are contained in the following set:
[tex]S_{k} = \{-1, 0\}[/tex]
Write the equation in either slope-intercept or point-slope form for the
line that goes through (1,1) and (3,-5). *
Answer:
y = mx + b
m = (-5-1)/(3-1)
m = -3
1=(-3)1 + b
b= 4
y= -3x + 4
Help on this pls ?????????
Answer:
8u =32 this is the equation
Answer and Step-by-step explanation:
8u = 32 is the answer.
This is because there are eight U's, and it is equal to 32.
#teamtrees #PAW (Plant And Water)
If cose < 0 and cote > 0, then the terminal point determined by e is in:
A. quadrant 4.
B. quadrant 1.
C. quadrant 3.
D. quadrant 2.
If cos < 0 and cot > 0, then the terminal point is determined by
C. quadrant 3.
What are reference angles according to quadrats?We have I, II, III, IV quadrants.In quadrant I the referece angle Ф is Ф.
In quadrant II the referece angle Ф is (π - Ф).
In quadrant III the referece angle Ф is (π + Ф).
In quadrant IV the referece angle Ф is (2π - Ф).
We know, cos is -ve on III and IV quadrants, and cot = 1/tan is +ve on I and III quadrant.
Therefore, The combined condition cos < 0 and cot > 0 satisfies on the II quadrant.
learn more about quadrants here :
https://brainly.com/question/7196312
#SPJ7