The length of a guys wire supporting a cell tower is 120 meters. The guy wire is anchored to the ground at a distance of 80 meters from the base of the tower . To the nearest hundredth of a meter , how tall is the tower ?

Answers

Answer 1

Answer: 89.4427

Step-by-step explanation: I apologize if I am wrong; I used Pythagorean Thyreom, and I used the formula a=√c^2-b^2 since we are solving for side a.

a=√120^2−80^2

a=√14400−6400

a=√8000

a=89.4427

I hope this is what you are looking for :)

Answer 2

Pythagoras is the sum of the square of two sides is equal to the square of the longest side. Then the height of the tower is 89.44 m.

What is a right-angle triangle?

It is a type of triangle in which one angle is 90 degrees and it follows the Pythagoras theorem and we can use the trigonometry function.

The length of a guy's wire supporting a cell tower is 120 meters.

The guy wire is anchored to the ground at a distance of 80 meters from the base of the tower.

We know that the Pythagoras theorem.

[tex]\rm H^2 = P^2 + B^2[/tex]

We have

H = 120 m

B = 80 m

Then by the Pythagoras theorem, we have

[tex]\rm P = \sqrt{H^2 - B^2}\\\\P = \sqrt{120^2 - 80^2}\\\\P = \sqrt{14400 - 6400}\\\\P = \sqrt{8000} = 89.44[/tex]

Thus, the height of the tower is 89.44 m.

More about the right-angle triangle link is given below.

https://brainly.com/question/3770177


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