The _________ law of Newton’s Laws of Motion helps us add intensity to any activity.

A.
third

B.
first

C.
second

D.
second and third

Answer:

Creo que es D pero no tan segura

Explanation:

Answer:

it's expanding from is 15

Answer:

Explanation:

3( 2+5 )

3. ( 7 )

3 . 7= 21

Answer:

Boil the water until it evaporates

Explanation:

If the water evaporates the sugar will no longer bond to it and then percipitate at the bottom of the beaker.

Answer: Because not all stars are in patterns

Answer:

Because the stars do not come out when the temperature rises on Earth

Explanation:

By using combined gas law , volume will be 1.88 [tex]dm^{3}[/tex].

The combined gas law contains the laws of Charles, Boyle, and Gay-Lussac. When you know the pressure, volume, and temperature of a system and need to modify one of these, you can apply this law to compute the resulting unknown.

Combined gas law is expressed as:

[tex]$\frac{P_{1} V_{1}}{T_{1}}=\frac{P_{2} V_{2}}{T_{2}}$[/tex]

Calculation of volume by using combined gas law

It is given that, [tex]V_{1}[/tex] = 254[tex]dm^{3}[/tex], at STP P = 101.3 kPa and T = 273 K

Now, put the value of given data in above equation.

[tex]V_{2}[/tex] = (254[tex]dm^{3}[/tex]) (101.3 kPa) (26+273) /(150 kPa) (273)

[tex]V_{2}[/tex] = 1.88 [tex]dm^{3}[/tex].

By using combined gas law  volume will be 1.88 [tex]dm^{3}[/tex].

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Answer:

2.3 * 10^-5

Explanation:

Recall that the solubility of a solute is the amount of solute that dissolves in 1 dm^3 or 1000cm^3 of solution.

Hence;

Amount of calcium oxalate = 154 * 10^-3/128.097 g/mol = 1.2 * 10^-3 mols

From the question;

1.2 * 10^-3 mols dissolves in 250 mL

x moles dissolves in 1000mL

x = 1.2 * 10^-3 mols * 1000/250

x= 4.8 * 10^-3 moldm^-3

CaC2O4(s) ------->Ca^2+(aq) + C2O4^2-(aq)

Hence Ksp = [Ca^2+] [C2O4^2-]

Where;

[Ca^2+] = [C2O4^2-] = 4.8 * 10^-3 moldm^-3

Ksp = (4.8 * 10^-3)^2

Ksp = 2.3 * 10^-5

Answer:Al2s3

Explanation:

Just took quiz

Answer:

Subbituminous coal can form at temperatures as low as 35 to 80 °C (95 to 176 °F) while anthracite requires a temperature of at least 180 to 245 °C (356 to 473 °F).

Sub-types: Cannel coal

Child material class: Lignite

Explanation:

Answer: (a) Mole fraction of [tex]H_{2}[/tex] is 0.66.

Mole fraction of [tex]N_{2}[/tex] is 0.33

(b) The partial pressure of [tex]H_{2}[/tex] is 1.98 atm.

The partial pressure of [tex]N_{2}[/tex] is 0.99 atm.

(c) The total pressure is 3.0 atm

Explanation:

Given: Volume = [tex]22.4 dm^{3}[/tex]  (1 [tex]dm^{3}[/tex] = 1 L) = 22.4 L

Moles of [tex]H_{2}[/tex] = 2.0 mol

Moles of [tex]N_{2}[/tex] = 1.0 mol

Total moles = (2.0 + 1.0) mol = 3.0 mol

Temperature = 273.15 K

[tex]PV = nRT\\[/tex]

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

[tex]PV = nRT\\P \times 22.4 L = 3.0 mol \times 0.0821 L atm/mol K \times 273.15 K\\P = 3.0 atm[/tex]

The mole fraction of [tex]H_{2}[/tex] is calculated as follows.

[tex]Mole fraction = \frac{moles of H_{2}}{moles of H_{2} + moles of N_{2}}\\= \frac{2.0 mol}{(2.0 + 1.0) mol}\\= 0.66[/tex]

The mole fraction of [tex]N_{2}[/tex] is as follows.

[tex]Mole fraction = \frac{moles of N_{2}}{moles of H_{2} + moles of N_{2}}\\= \frac{1.0 mol}{(2.0 + 1.0) mol}\\= 0.33[/tex]

Partial pressure of [tex]H_{2}[/tex] are as follows.

[tex]P_{H_{2}} = P_{total} \times mole fraction of H_{2}\\= 3.0 atm \times 0.66\\= 1.98 atm[/tex]

Partial pressure of [tex]N_{2}[/tex] are as follows.

[tex]P_{N_{2}} = P_{total} \times mola fraction of N_{2}\\= 3.0 atm \times 0.33\\= 0.99 atm[/tex]

Answer:

155.1 L

Explanation:

Step 1: Given data

Mass of CO₃: 415.4 g

Step 2: Calculate the moles corresponding to 415.4 g of CO₃

The molar mass of CO₃ is 60.01 g/mol.

415.4 g × 1 mol/60.01 g = 6.922 mol

Step 3: Calculate the volume occupied by 6.922 moles of CO₃

The volume of a gas depends on conditions such as Temperature and Pressure. Since the conditions are not specified, we may assume that the gas is at Standard Pressure and Temperature (1 atm and 273.15 K). At STP, 1 mole of a gas occupies 22.41 L.

6.922 mol × 22.41 L/1 mol = 155.1 L

Answer:

1.73 M

Explanation:

Molarity is moles per liter, so we need to divide 7.47 moles by 4.31 liters to get the molarity of the solution.

7.47/4.31 ≈ 1.73 M

Answer:

Aneroid barometer and mercury barometer are such two types. The main difference between aneroid and mercury barometer is that aneroid barometer measures the atmospheric pressure using the expansion of a metal whereas mercury barometer measures the atmospheric pressure by adjusting the height of mercury inside a tube.

Explanation:

Answer:

the order of vibrational frequency is:

C ≡ N > C=N > C=S > S-C

Explanation:

The bond's vibration frequency is determined using the following equation:

[tex]\zeta = \dfrac{1}{2 \pi c}\sqrt{\dfrac{k}{\mu}}[/tex]

where;

reduced mass[tex]\mu = \dfrac{m_1m_2}{m_1+m_2}[/tex]

velcoity of light = c

force constant = k

The frequency of vibration, on the other hand, is inversely proportional to the atom's mass, because the heavier the atom, the lower the frequency.

In addition, the value of a bond's stretching frequency rises as the bond's intensity rises. As a result, the frequency is as follows:

triple > double > single

The reduced mass [tex](\mu)[/tex] of C-N bond.

[tex]\mu = \dfrac{m_1m_2}{m_1+m_2}[/tex]

[tex]\mu = \dfrac{12*14}{12+14} \\ \\ \mu = 6.46[/tex]

The reduced mass of C-S bond;

[tex]\mu = \dfrac{m_1m_2}{m_1+m_2}[/tex]

[tex]\mu = \dfrac{12\times 32}{12+32} \\ \\ \mu = 8.72[/tex]

Thus, the order of vibrational frequency is:

C ≡ N > C=N > C=S > S-C

Answer:

[tex]296.05\ \text{K}[/tex]

Explanation:

[tex]m_w[/tex] = Mass of water = 100 g

[tex]c_w[/tex] = Specific heat of water = [tex]4.184\ \text{J/g K}[/tex]

[tex]m_c[/tex] = Mass of copper = 20 g

[tex]c_c[/tex] = Specific heat of copper = [tex]0.385\ \text{J/g K}[/tex]

[tex]\Delta T_w[/tex] = Temperature change in water = [tex](T-295)[/tex]

[tex]\Delta T_c[/tex] = Temperature change in cooper = [tex](353-T)[/tex]

T = Final temperature of the system

The heat balance of the system is given by

[tex]m_wc_w\Delta T_w=m_cc_c\Delta T_c\\\Rightarrow 100\times 4.184\times (T-295)=20\times 0.385\times (353-T)\\\Rightarrow 418400\left(T-295\right)=7700\left(353-T\right)\\\Rightarrow 418400T-123428000=2718100-7700T\\\Rightarrow T=\frac{1261461}{4261}\\\Rightarrow T=296.05\ \text{K}[/tex]

The final temperature of the water is [tex]296.05\ \text{K}[/tex].

The final temperature of the water when placed in a calorimeter is 296.05K

HOW TO CALCULATE FINAL TEMPERATURE:

Where;

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Answer:

dog 2 because it is running 1m faster a second than dog 1. Dog 2 can run 1 meter farther in a second than the other dog.

Answer:

With Br2 - Bromobenzene

With Cl2 - Chlorobenzene

With HNO3- Nitrobenzene

With H2SO4 - Benzenesulphonic acid

With HCOCl - Benzoyl chloride

With 1-chloro-2,2-dimethylpropane - 2,2dimethyl-1-phenyl propane

Explanation:

All the reactions listed above are electrophillic reactions. They are electrophillic reactions because the attacking agents in each reagent is an electrophile. An electrophile means any specie that is electron deficient and attacks regions of high electron density in molecules.

The benzene molecule has rich electron density. Substituents that are electron pushing increases the tendency of benzene to undergo electrophillic substitution reactions while electron withdrawing substituents decrease the the tendency of benzene to undergo electrophillic substitution reactions.

The names of the compounds formed when benzene undergoes electrophillic reaction with different attacking agents have been listed in the answer section.

Answer:

Trees could go extinct and people could die.

Explanation:

Answer:

A. it allows results to be reviewed and reproduced by other scientists.

Sorry, I won't understand your words.

Answer:

1. Volume of stock required = 15 mL

Volume of water required = 485 mL

2. Volume of stock required = 5 mL

Volume of water required = 495 mL

3. Volume of stock required = 5.30 mL

Volume of water required = 494.70 mL

4. Volume of stock required = 50 mL

Volume of water required = 450 mL

Explanation:

Using the dilution formula C₁V₁ = C₂V₂

Where C₁ = initial concentration; C₂ = final concentration; V₁ = initial volume; V₂ = final volume

1. C₁ = 5 M NaCl, C₂ = 150 mM NaCl = 0.15 M NaCl

V₁ = ?; V₂ = 500 mL

V₁ = C₂V₂/C₁

V₁ = 0.15 × 500/ 5 = 15 mL

Volume of stock required = 15 mL

Volume of water required = 500 mL - 15 mL

Volume of water required = 485 mL

2. C₁ = 1 M Tris-HCl, C₂ = 50 mM Tris-HCl = 0.05 M Tris-HCl

V₁ = ?; V₂ = 500 mL

V₁ = C₂V₂/C₁

V₁ = 0.05 × 500/ 5 = 5 mL

Volume of stock required = 5 mL

Volume of water required = 500 mL - 5 mL

Volume of water required = 495 mL

3. C₁ = 95% NP-40, C₂ = 1% NP-40

V₁ = ?; V₂ = 500 mL

V₁ = C₂V₂/C₁

V₁ = 1 × 500/ 95 = 5.30 mL

Volume of stock required = 5.30 mL

Volume of water required = 500 mL - 5.30 mL

Volume of water required = 494.70 mL

4. C₁ = 1% SDS, C₂ = 10% SDS

V₁ = ?; V₂ = 500 mL

V₁ = C₂V₂/C₁

V₁ = 1 × 500/ 10 = 50 mL

Volume of stock required = 50 mL

Volume of water required = 500 mL - 50 mL

Volume of water required = 450 mL

Answer:

1. iodide ion into neutral iodine

2. blue-black

3. neutral iodine into iodide ion

4. clear

Explanation:

The function of hypochlorite in iodine titration is to oxidize the iodide ion into iodine molecule as shown below;

ClO-(aq) + 2H+(aq) + 2I-(aq) ---------> 6 I2(l) + Cl- (aq)+ H2O(l)

The addition of starch to iodine leads to the formation of a starch iodide complex which has a blue black colour.

the titrant, thiosulfate, reduces neutral iodine into iodide ion as shown below;

I2  +  2S2O32-  → 2I- + S4O62-

At end point, the solution becomes clear again.

Answer: behavior that is simple, untaught, and born knowing

Have a nice dam day!!

The term that describes innate behavior is:

D. behavior that is untaught but very complex

Intr-insic or "intuitive" ways of behaving are innate and don't need learning or related knowledge to be performed. Models incorporate romance and ways of behaving, departure and guarded moves, and hostility. Movement and Migration Innate or ins-tinctual behaviors rely on response to sti-muli.

Thus, option D is correct.

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Answer:

Its 12.6M

Explanation:

It came to the conclusion and got these answers

2.22

20.5

10

12.6

12.6 is the correct answer

The correct option is :

=》It has a high magnitude.

the damage caused by an earthquake is proportional to its magnitude, as much the magnitude is, that much damage will be caused by it.

The term used to indicate and earthquake that causes major damage to buildings in an area is called a high magnitude earthquake. Hence, option a is correct.

The most typical way to gauge an earthquake's size is by its magnitude. No matter where you are or how violent the shaking is, it is the same number since it represents the size of the earthquake's source.

The USGS no longer uses the outmoded Richter scale to determine the magnitude of major, teleseismic earthquakes. Several magnitude scales measure various aspects of the earthquake, but the Richter scale measures the biggest wobble (amplitude) on the recording.

Currently, the USGS uses the Moment Magnitude scale to report earthquake magnitudes, however many different magnitudes can be calculated for comparison and research. Therefore, option a is correct.

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Answer:

Volume is reduced to half

Explanation:

Acid base titration are commonly used reactions in a lab, and are ofter used to get pH or different kind of solutions.

The neutralization of an acid base reaction is reached, when the solution (having added an indicator previously) changes its original color. chemically speaking, this occurs when the number of moles of the acid and the base are balanced and equal. In other words the following:

n₁ = n₂   (1)

This expression can also be expressed in function of concentration and volume:

M₁V₁ = M₂V₂   (2)

From here, solving for V₁:

V₁ = M₂V₂  / M₁

Now, this expression is true only when we have the same kind of substance that can lose or gain the same number of hydrogens.

Lets suppose that we have as base NaOH (Monoprotic base) and HCl (monoprotic acid), the titration reaction would be:

NaOH + HCl --------> NaCl + H₂O

As both of the species are monoprotic, the number of moles are the same  when they reach the equilibrium, so, expression  (2) can be used, and calculate volume or concentrations.

However, in this case, a partner made a mistake and use a diprotic acid, in this case, H₂SO₄, In this case, things chance because H₂SO₄ is diprotic, meaning that we need to dissociate two hydrogens in equilibrium, therefore, expression (2) would be something like this.

Acid: 1; Base: 2

H₂SO₄ + 2NaOH ------> Na₂SO₄ + H₂O

nH₂SO₄ = n₁ = 1

nNaOH = n₂ = 2

n₁/n₂ = 1/2

2n₁ = n₂   (3)

Writting this, in function of concentration and volume, it would be:

2M₁V₁ = M₂V₂   (4)

From here, if we solve for the volume of the acid (V₁):

V₁ = M₂V₂ / 2M₁

Therefore, according to this expression, we can see that the volume required of the acid would be half the volume required of the monoprotic acid. For example, if we need 50 mL of Chloridic acid to reach the equivalence point with NaOH, then, with H₂SO₄ it will only need 25 mL. This, of course, assuming that concentrations are the same, and volume of the base used, the same.

Hope this helps

Answer:

The answer is in the problem

Explanation:

As general rule of number of oxygen is -2:

O → -2

Alkali metals (Li, Na, K) are always +1

Na → +1

Alkali earth methals (Be, Mg, Ca...) are always +2

Ca → +2

The halogen group (F, Cl, Br...) is always -1

F → -1

The oxidation number of Si (+/- 4)

Aluminium is, usually +3

And to complete the octet rule in nitrogen, 3 electrons are required. That means:

N → -3