The ________ is a consortium of organizations that develops web protocols and sets standards.

Answer:

Here is the C++ and Python programs:

C++ program:

#include<iostream>  //to use input output functions

using namespace std;  //to identify objects like cin cout

void swapvalues(int&  userVal1, int& userVal2); //function to swap values

int main() {  //start of main function

  int integer1,integer2;  //declare two integers

  cout<<"Enter first integer: ";  //prompts user to enter the first number

  cin>>integer1;  //reads first number from user

     cout<<"Enter second integer: "; //prompts user to enter the second number

  cin>>integer2;  //reads second number from user

 cout<<"Integers before swapping:\n";  //displays two numbers before swapping

 cout<<integer1<<endl<<integer2;  

  swapvalues(integer1, integer2);  //calls swapvalues method passing two integers to it

  cout << "\nIntegers after swapping:\n"; //displays two numbers after swapping

 cout<<integer1<<endl<<integer2; }

void swapvalues(int&  userVal1, int& userVal2){  //method that takes two int type numbers and swaps these numbers

  int temp;  //temporary variable

  temp = userVal1;  //temp holds the original value of userVal1

  userVal1 = userVal2;  //the value in userVal2 is assigned to userVal1

  userVal2 = temp; } //assigns value of temp(original value of userVal1) to userVal2

The program prompts the user to enter two integers and then calls swapvalues() method by passing the integers by reference. The swapvalues() method modifies the passed parameters by swapping them. The method uses a temp variable to hold the original value of first integer variable and then assigns the value of second integer variable to first. For example if userVal1 = 1 and userVal2 =2. Then these swapping statements work as follows:

temp = userVal1;  

temp = 1

userVal1 = userVal2;  

userVal1 = 2

userVal2 = temp;

userVal2 = 1

Now because of these statements the values of userVal1 and userVal2 are swapped as:

userVal1 = 2

userVal2 = 1

Explanation:

Python program:

def swap_values(user_val1, user_val2):  #method to swap two numbers

   return user_val2,user_val1   #returns the swapped numbers

integer1 = int(input('Enter first integer :')) #prompts user to enter first number

integer2 = int(input('Enter second integer :'))  #prompts user to enter second number

print("Numbers before swapping") #displays numbers before swapping

print(integer1,integer2)

print("Numbers after swapping") #displays numbers after swapping

integer1,integer2 = swap_values(integer1,integer2) #calls method passing integer1 and integer2 to swap their values

print(integer1,integer2) #displays the swapped numbers

The screenshot of programs and outputs is attached.

The program that swaps variables will return the reverse of the users input.  The second integer input will be printed first followed by the first integer input.

def swap_variables(first_input, second_input):

    return second_input, first_input

first_input = input("input the first integer: ")

second_input = input("input the second integer: ")

print(f"numbers before swapping are {first_input} and {second_input}")

print(f"numbers after swapping are {second_input} and {first_input}")

Code explanation

The code is written in python.

learn more on python variables here: https://brainly.com/question/14039335

Answer:

hello your question is incomplete attached below is the complete question and answer

answer ; attached below

Explanation:

To prove this identity combination the right hand side has to be equal to the left hand side attached below is the prove showing that the right hand side is equal to the left hand side

Answer:

Hierarchical inheritance

Explanation:

It is the  Hierarchical inheritance when one continuously, is similar to a tree structure. The  Hierarchical inheritance derives more than one class from the main class. And it is done continuously and subsequently. Thus, resulting a shape of tree tree of classes being linked.

Answer:

Home Location Register

Explanation:

Home Location Register is a mobile network database that serves as storage for various information of different individuals or people referred to as customers or subscribers.

The information it stores includes the following:

1. Subscriber's service profile

2. Subscriber's current location information

3. Subscriber's activity status

Hence, the correct answer is HOME LOCATION REGISTER.

Answer:

The use of VPNs and network demarcation zones mitigates the risk of an attack from an external source while constant briefing of network attack prevention guidelines to employees and access control is adviced.

Explanation:

The use of visualisation tools like the VMware is used to represent, maintain and analyse network performance is very important for network data flow and security and to alert for important scheduled task to be implemented daily.

Answer:

This would be a classroom discussion, But here ill try I guess,

Maybe  None since Ms. Frederick doesn't accept late work  because I dont know her

Answer:

Input is the answer

Answer:

im pretty sure its input..

Explanation:

Answer:

Time machine.

Explanation:

An OS X backup utility that automatically backs up files to a dedicated drive that is always available when the computer is turned on is called a time machine.

OS X was released in 2001 and it's Apple's version ten (10) of the operating system that runs on its Macintosh computers.

A time machine is a software tool built into the Mac operating system and it is primarily designed to automatically backup user files or data onto a dedicated drive such as an external hard drive disk through a wired connection, by using a Thunderbolt or universal serial bus (USB) cable. The automatic backup can as well be done wirelessly through a network connection.

Explanation:

calculators work by processing information in binary form. We're used to thinking of numbers in our normal base-ten system, in which there are ten digits to work with: 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9. The binary number system is a base-two system, which means there are only two digits to work with: 0 and 1. Thus, when you input numbers into a calculator, the integrated circuit converts those numbers to binary strings of 0s and 1s.

The integrated circuits then use those strings of 0s and 1s to turn transistors on and off with electricity to perform the desired calculations. Since there are only two options in a binary system (0 or 1), these can easily be represented by turning transistors on and off, since on and off easily represent the binary option

Once a calculation has been completed, the answer in binary form is then converted back to our normal base-ten system and displayed on the calculator's display screen.

Answer:

1. Brush

2. Bucket

3. Pencil

4. Color Picker

5. Air Brush

Oh man, that's all i think.

Answer:

HTML

Explanation:

yeah i just took test

Answer:

web 2.0 internet

Explanation:

Explanation:

Tim O Reilly in 2004 changed the web with his web 2.0 concept which according to him at the time would allow enable the user to generate content.​

Answer:

"Pattern Matching" is the correct choice.

Explanation:

The other choices don't apply to the specified instance. So that the choice above seems to be the right one.

Answer:

nijit

Explanation:

small nano bytes desind to kill a computers cellular compunds

Answer:

Here is the C++ program.

#include <iostream>  //to use input output functions

using namespace std;  // to access objects like cin cout

void chessboard(int N){  // function that takes a number N as parameter generates corresponding board

   int i, j;  

   string black = "B";  // B for black squares

   string white = "W"; // W for white squares

   for(i=1;i<=N;i++){  //iterates through each column of the board

       for(j=1;j<=N;j++){  //iterates through each row of the board

           if((i+j)%2==0)  // if sum of i and j is completely divisible by 2

               cout<<black<<" ";  //displays B when above if condition is true

           else  //if (i+j)%2 is not equal to 0

           cout<<white<<" ";  }  // displays W when above if condition is false

      cout<<endl;    }    }  //prints the new line

int main(){    //start of the main function

   int num;  //declares an integer num

   cout << "Enter an integer representing the size of the chessboard: ";  //prompts user to enter size of chess board

   cin >> num;  //reads value of num from user

   chessboard(num); } //calls chessboard function to display N lines consist of N space-separated characters representing the chessboard pattern

Explanation:

The function works as follows:

Lets say that N = 2

two string variables black and white are declared. The value of black is set to "B" and value of white is set to "W" to return a chessboard pattern in B and W squares.

The outer loop for(i=1;i<=N;i++) iterates through each column of the chess board. The inner loop  for(j=1;j<=N;j++) iterates through each row of chess board.

At first iteration of outer loop:

N = 2

outer loop:

i=1

i<=N is true because i=1 and 1<=2

So the program enters the body of the outer for loop. It has an inner for loop:

for(j=1;j<=N;j++)

At first iteration of inner loop:

j = 1

j<=N is true because j=1 and 1<=2

So the program enters the body of the inner for loop. It has an if statement:

if((i+j)%2==0) this statement works as:

if(1+1) % 2 == 0

(1+1 )% 2 takes the mod of 1+1 with 2 which gives the remainder of the division.

2%2 As 2 is completely divisible by 2 so 2%2 == 0

Hence the if condition evaluates to true. So the statement in if part executes:

cout<<black<<" ";

This prints B on the output screen with a space.

B

The value of j is incremented to 1.

j = 2

At second iteration of inner loop:

j = 2

j<=N is true because j=2 and 2=2

So the program enters the body of the inner for loop. It has an if statement:

if((i+j)%2==0) this statement works as:

if(1+2) % 2 == 0

(1+2 )% 2 takes the mod of 1+2 with 2 which gives the remainder of the division.

3%2 As 3 is not completely divisible by 2

Hence the if condition evaluates to false. So the statement in else part executes:

cout<<white<<" ";

This prints W on the output screen with a space.

B W

The value of j is incremented to 1.

j = 3

Now  

j<=N is false because j=3 and 3>2

So the loop breaks and program moves to the outer loop to iterate through the next row.

At second iteration of outer loop:

N = 2

outer loop:

i=2

i<=N is true because i=2 and 2 = 2

So the program enters the body of the outer for loop. It has an inner for loop:

for(j=1;j<=N;j++)

At first iteration of inner loop:

j = 1

j<=N is true because j=1 and 1<=2

So the program enters the body of the inner for loop. It has an if statement:

if((i+j)%2==0) this statement works as:

if(2+1) % 2 == 0

(2+1 )% 2 takes the mod of 2+1 with 2 which gives the remainder of the division.

3%2 As 3 is not completely divisible by 2

Hence the if condition evaluates to false. So the statement in else part executes:

cout<<white<<" ";

This prints W on the output screen with a space.

B W

W

The value of j is incremented to 1.

j = 2

At second iteration of inner loop:

j = 2

j<=N is true because j=2 and 2=2

So the program enters the body of the inner for loop. It has an if statement:

if((i+j)%2==0) this statement works as:

if(2+2) % 2 == 0

(2+2 )% 2 takes the mod of 2+2 with 2 which gives the remainder of the division.

4%2 As 4 is completely divisible by 2 so 4%2 == 0

Hence the if condition evaluates to false. So the statement in if part executes:

cout<<black<<" ";

This prints B on the output screen with a space.

B W

W B

The value of j is incremented to 1.

j = 3

Now  

j<=N is false because j=3 and 3>2

So the loop breaks and program moves to the outer loop. The value of outer loop variable i is incremented to 1 so i = 3

N = 2

outer loop:

i=3

i<=N is false because i=3 and 3>2

So this outer loop ends.

Now the output of this program is:

B W

W B

Screenshot of this program along with its output is attached.

This would be the Tab key

Answer:

Explanation: malware

Answer:

The function written in python is as follows;

def main():

      user_input = int(input("Input: "))

      mylist = []

      while not user_input == 0:

             mylist.append(user_input)

             user_input = int(input("Input: "))

      print(mylist)

if __name__ == "__main__":

      main()

Explanation:

This line declares a main function with no arguments

def main():

This line prompts user for input

      user_input = int(input("Input: "))

This line declares an empty list

      mylist = []

The following iteration checks if user input is not 0; If yes, the user input is appended to the list; otherwise, the iteration ends

      while not user_input == 0:

             mylist.append(user_input)

             user_input = int(input("Input: "))

This liine prints the list in the order which it was inputted

      print(mylist)

The following lines call the main function

if __name__ == "__main__":

      main()

Answer:  

Here is the C++ program to find the largest of three integers.

#include <iostream> //to use input output functions

using namespace std; //to identify objects like cin cout

int main(){ //start of main function

int integer1, integer2, integer3;  // declare three integers

   cin>>integer1>>integer2>>integer3;  //reads values of three integers variables from user

   if (integer1 >= integer2 && integer1 >= integer3) //if value of integer1 variable is greater than or equal to both integer2 and integers3 values

       cout<<integer1;   //then largest number is integer1 and it is displayed

   else if (integer2 >= integer1 && integer2 >= integer3) //if value of integer2 variable is greater than or equal to both integer1 and integers3 values

       cout<<integer2;  //then largest number is integer2 and it is displayed

   else //in case value of integer3 variable is greater than or equal to both integer1 and integers2 values

       cout<<integer3; } //then largest number is integer3 and it is displayed

Here is the JAVA program to find the largest of three integers.

import java.util.Scanner; //to take input from user

public class Main{

public static void main(String[] args) {//start of main function

Scanner input= new Scanner(System.in); //a standard input stream.

int integer1= input.nextInt();//declare and read value of first integer

int integer2= input.nextInt();//declare and read value of second integer

int integer3= input.nextInt();//declare and read value of third integer

   if (integer1 >= integer2 && integer1 >= integer3) //if value of integer1 variable is greater than or equal to both integer2 and integers3 values

       System.out.println(integer1);   //then largest number is integer1 and it is displayed

   else if (integer2 >= integer1 && integer2 >= integer3) //if value of integer2 variable is greater than or equal to both integer1 and integers3 values

       System.out.println(integer2); //then largest number is integer2 and it is displayed

   else //when value of integer3 variable is greater than or equal to both integer1 and integers2 values

               System.out.println(integer3);  } } //then largest number is integer3 and it is displayed

Explanation:

The program is well explained in the comments attached with each statement of the program. I will explain the program with the help of an examples. Suppose

integer1 = 7

integer2 = 15

integer3 = 3

first if condition  if (integer1 >= integer2 && integer1 >= integer3) checks if value of integer1 variable is greater than or equal to both integer2 and integers3 values. Since integer1 = 7 so it is greater than integer3 = 3 but less than integer2. So this statement evaluates to false because in && ( AND logical operator) both of the conditions i.e integer1 >= integer2 and integer1 >= integer3 should be true. So the program moves to the else if part.

The else if condition else if (integer2 >= integer1 && integer2 >= integer3) checks if value of integer2 variable is greater than or equal to both integer1 and integer3 values. Since integer2 = 15 so it is greater than integer1 = 7 and also greater than integer3 = 3. So this statement evaluates to true as both parts of the else if condition holds true. So the else if part executes which has the statement: cout<<integer2; which prints the value of integer2 i.e. 15 on output screen.

Output:

15

Answer:

#include <stdio.h>

int main(void) {

 int num1;

 int num2;

 int num3;

 printf("Enter three integers: ");

 scanf("%d", &num1);

 scanf("%d", &num2);

 scanf("%d", &num3);

 if (num1 == 0 || num2 == 0 || num3 == 0)

 {

   printf("please input a number greater than zero :)\n");

 }

 if (num1 <= num2 && num1 <= num3)

 {

   printf("%i is the smallest number!\n", num1);

 }

 else if (num2 <= num1 && num2 <= num3)

 {

   printf("%i is the smallest number!\n", num2);

 }

 else

 {

   printf("%i is the smallest number!\n", num3);

 }

 return 0;

}

Explanation:

Alright so let's start with the requirements of the question:

So we needed to create 3 variables to hold each integer that was going to be passed into our script.

By using scanf("%i", &variableName) we were able to take in user input and  store it inside of num1, num2, and num3.

Since you mentioned you were new to the C programming language, I threw in the first if statement as an example of how they can be used, use it as a guide for future reference, sometimes it's better to understand your code visually.

Basically what this if statement does is, it checks to see if any of the integers that came in from user input was the number zero, it told the user it does not accept that number, please input a number greater than zero.

if (num1 == 0 || num2 == 0 || num3 == 0)

 {

   printf("please input a number greater than zero :)\n");

 }

I used this methodology and implemented the heart of the question,

whichever number is smaller, print it out on the shell (output).

if (num1 <= num2 && num1 <= num3)

^^ here we're checking if the first variable we created is smaller than the second variable and the third ^^

 {

   printf("%i is the smallest number!\n", num1);

   ^^ if it is smaller, then print integer and then print a new line so the next line looks neat ^^

   ( incase if your wondering what "\n" is, its a special character that allows you so print a new line on the terminal, kind of like hitting the return or enter key )

 }

else if (num2 <= num1 && num2 <= num3)

^^ else if is used when your checking for more than one thing, and so for the second variable we checked to see if it was smaller than the first and third variable we created ^^

 {

   printf("%i is the smallest number!\n", num2); < -- and we print if it's smaller

 }

Last but not least:

else

^^ if it isn't num1 or num2, then it must be num3 ^^

 {

   printf("%i is the smallest number!\n", num3);

  we checked the first two options, if its neither of those then we have only one variable left, and thats num3.

 }

I hope that helps !!

Good luck on your coding journey :) ‍

Answer:

a) the Statement is Invalid

b) the Statement is Invalid

Explanation:

a)

lets Consider, s: student of my class

A(x): Getting an A

Let b: john

I have a student in my class who is getting ab A: Зs, A(s)

John need not be the student i.e b ≠ s could be true

Hence ¬A(b) could be true and the given statement is invalid

b)

Lets Consider G: girl scout

C: selling 50 boxes of cookies

P: getting prize

s: Suzy

Now every girl scout who sells at least 50 boxes of cookies will get a prize: ∀x ∈ G, C(x) -> P(x)

Suzy, a girl scout, got a prize: s ∈ G, P(s)

since P(s) is true, C(s) need not be true

Main Reason: false → true is also true

Therefore the Statement is Invalid

The argument that is valid is B. Every girl scout who sells at least 50 boxes of cookies will get a prize. Suzy, a girl scout, got a prize. Therefore Suzy sold 50 boxes of cookies.

It should be noted that a valid argument simply means the argument that's the conclusion can be derived from the premise given.

In this case, the argument that is valid is that every girl scout who sells at least 50 boxes of cookies will get a prize. Suzy, a girl scout, got a prize. Therefore Suzy sold 50 boxes of cookies.

Learn more about arguments on:

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Answer:

I'll answer this question using Python

print("  ^ ^")

print("( o o )")

print("   v")

Explanation:

To answer this question, you have to follow the hint as it is in the question

The hint says you should copy each line into a print statement and that's exactly what I did when answering this question;

In other words;

^ ^  becomes print("  ^ ^")

( o o )   becomes print("( o o )")

v becomes print("   v")

for x in range(7):

   if (x == 3 or x==6):

       continue

   print(x, end=' ')

print("\n")

>> 0 1 2 4 5

The code above has been written in Python. The following explains each line of the code.

Line 1: for x in range(7):

The built-in function range(7)  generates integers between 0 and 7. 0 is included but not 7. i.e 0 - 6.

The for loop then iterates over the sequence of number being generated by the range() function. At each iteration, the value of x equals the number at that iteration. i.e

For the first iteration, x = 0

For the second iteration, x = 1

For the third iteration, x = 2 and so on up to x = 6 (since the last number, 7, is not included).

Line 2: if (x == 3 or x == 6):

This line checks for the value of x at each iteration. if the value of x is 3 or 6, then the next line, line 3 is executed.

Line 3: continue

The continue keyword is used to skip an iteration in a loop. In other words, when the continue statement is encountered in a loop, the loop skips to the next iteration without executing expressions that follow the continue statement in that iteration. In this case, the print(x, end=' ')  in line 4 will not be executed when x is 3 or 6. That means 3 and 6 will not be printed.

Line 4: print(x, end=' ')

This line prints the value of x at each iteration(loop) and then followed by a single space. i.e 0 1 2 ... will be printed. Bear in mind that 3 and 6 will not be printed though.

Line 5: print("\n")

This line will be printed after the loop has finished execution. This line prints a new line character.

The program is an illustration of loops.

Loops are used to perform repetitive operations.

The program in Python,  where comments are used to explain each line is as follows:

#This iterates from 0 to 6

for i in range(7):

   #This checks if the current number is not 3 or 6

   if not i==3 and not i == 6:

       #If yes, the current number is printed

       print(i,end=" ")

Read more about similar programs at:

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Answer:

Set args = Wscript.Arguments

If (WScript.Arguments.Count <> 1) Then

 Wscript.Echo "Specify the folder name as a command line argument."

Else

   objStartFolder = args.Item(0)

   Set objFSO = CreateObject("Scripting.FileSystemObject")

   if (Not objFSO.FolderExists(objStartFolder)) Then

       Wscript.Echo "Folder "&objStartFolder&" does not exist"

   Else

       Set objFolder = objFSO.GetFolder(objStartFolder)

       Set colFiles = objFolder.Files

       For Each objFile in colFiles

           Wscript.Echo objFile.Name, objFile.Size, objFile.DateCreated

       Next

   End If

End If

Explanation:

Here's some code to get you started.

Answer:

ISO standards

Explanation:

ISO / IEC 14443 is the ISO standard that covers RFID usage by devices.

EPCglobal - Electronics Product Code Global Incorporated is also another international standard that covers RFID. These two standards work together to standardize RFID products produced by manufacturers so that these products can be the same across different markets and manufacturers. Example I can purchase a tag from one manufacturer and a transceiver from another and they would function well together. There are also other standards for RFID but the above two are the biggest and most popular with ISO being the oldest.

Answer:

Explanation:

Data is collected is to make the decisions that will positively impact the success of a company, improve its practices and increase revenue. It is also essential that the way in which data are collected, assembled and published respects Indigenous sensitivities, not least so as to ensure that Indigenous people understand the purposes for which the data is being collected and willingly provide accurate answers to data collectors.

Hope this helped you!

Answer:

timely

Explanation:A student who sets a date to finish a goal is using which SMART goal

Answer: D.) Timely

Explanation: Setting a date to finish a goal is using time.

Answer:

Correct

Explanation:

Indeed, the world application is a word processing software used by many professionals and students alike.

Read a document: To do this, the user should go to the document area  found at the top left corner of the tool bar.

Find the name of the document: By looking at the Title bar.

Change the way a document is viewed: The Ribbon area is located at the top right section of the screen near the minimize icon.

Find help to do a certain activity on word: Close to the Ribbon area there is a dialog box having the image of a bulb.

Go up and down to different parts of a document: By going to the scroll bar which found at the extreme right hand side (margin) of the page.

Determine the page number of the document: By going to the Status bar found at the bottom right of the page.

The part of the Word application window where the information van be found is illustrated thus:

Read a document: The user should go to the document area that can be found at the top left corner of the tool bar.

Find the name of the document: This can be seen by looking at the Title bar.

Change the way a document is viewed: This is located at the top right section of the screen near the minimize icon.

Find help to do a certain activity on word: This can be found close to the Ribbon area.

Go up and down to different parts of a document: This can be found on the scroll bar.

Determine the page number of the document: This can be found on the Status bar.

Learn more about word applications on;

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Answer:

Internet Key Exchange

Explanation:

The first phase, setting up an IPsec tunnel, is called IKE phase 1. There are two types of setting up an IPsec tunnel.

Phase 1 and Phase 2 of VPN discussions are separate stages. Phase 1's primary goal is to establish a safe, encrypted channel for Phase 2 negotiations between the two peers. When Phase 1 is successfully completed, the peers immediately begin Phase 2 negotiations.

When two dedicated routers are deployed in IPsec tunnel mode, each router serves as one end of a fictitious "tunnel" over a public network. In IPsec tunnel mode, in addition to the packet content, the original IP header containing the packet's final destination is also encrypted.

Therefore, the first phase, setting up an IPsec tunnel, is called IKE phase 1.

To learn more about IPsec tunnel, refer to the link:

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#SPJ5

Answer: LAN

Explanation: