The initial concentration of a solution of NaOH is 5.0 M. What volume of the concentrated stock solution is needed to make 200 mL of .02 M solution? (YOU MUST INCLUDE UNITS IN YOUR ANSWER) *

Answers

Answer 1

Answer:

0.8 mL

Explanation:

Use the formula M1V1 = M2V2.

Plug the values in.

5(V1) = 0.02(200)

5V1 = 4

V1 = 0.8 mL

Hope this is right, correct me if I'm wrong!


Related Questions

Which substance is the best oxidizing agent?

A. NaOH
B. H2O
C. Xe
D. HCI
E. O3

Answers

Answer:

the answer is A.

Explanation:

Elemental fluorine, for example, is the strongest common oxidizing agent.

The heat of combustion per mole for acetylene, C2H2(g), is -1299.5 kJ/mol. Assuming that the combustion products are CO2(g) and H2O(l), and given that the enthalpy of formation is -393.5 kJ/mol for CO2(g) and -285.8 kJ/mol for H2O(l), find the enthalpy of formation of C2H2(g).

Answers

Answer: The heat of combustion per mole for acetylene is 227.7 kJ/mol.

Explanation:

The combustion equation of acetylene is as follows.

[tex]C_{2}H_{2} + \frac{5}{2}O_{2} \rightarrow 2CO_{2} + H_{2}O[/tex]

Formula to calculate enthalpy of formation for a reaction is as follows.

[tex]\Delta H^{o}_{rxn} = \sum \Delta H_{products} - \sum \Delta H_{reactants}\\\Delta H^{o}_{rxn} = [2\Delta H^{o}_{f}(CO_{2}) + \Delta H^{o}_{f} (H_{2}O)] - [\Delta H^{o}_{f}(C_{2}H_{2}) + \frac{5}{2} \Delta H^{o}_{f} O_{2}]\\-1299.5 = 2(-393.5) + (-285.8) - \Delta H^{o}_{f} (C_{2}H_{2})\\\Delta H^{o}_{f} (C_{2}H_{2}) = 227.7 kJ/mol[/tex]

Thus, we can conclude that heat of combustion per mole for acetylene is 227.7 kJ/mol.

By what factor does [OH- ] change when the pH increases by 1.7?

Answers

the values change in factors of ten.

Use the equations below to calculate the enthalpy of formation for propane gas, C3H8, from its elements, hydrogen gas and solid carbon. Please hurry!!

Answers

Answer: I got -4542.9kg/mol

Explanation:

Using the enthalpy relation, the enthalpy of formation of propane gas in the given equation is 4542.9 kJ/mol

[tex] △H_{f} = Product [/tex]

Using the enthalpy value of [tex] CO_{2} [/tex] and[tex] H_{2}0[/tex] given :

Product = [tex] 3CO_{2} + 4H_{2}0[/tex]

Product = 3(-393.5) + 4(-285.8) = - 2323.70

Reactant = [tex] C_{3}H_{8} + 5H_{2}0[/tex]

Water, H20 has △H = 0

Reactant = [tex] C_{3}H_{8} + 0[/tex]

Enthalpy of formation = product - Reactant

2219.2 = -2323.70 - (propane + 0)

2219.2 = - 2323.70 - propane

Propane = - 2323.70 - 2219.2

[tex] C_{3}H_{8} = - 4542.9 [/tex]

Therefore, the entalphy of formation of propane gas is - 4542.9 kJ/mol.

Learn more :https://brainly.com/question/1261360

A 0.150-kg sample of a metal alloy is heated at 540 Celsius an then plunged into a 0.400-kg of water at 10.0 Celsius, which is contained in a 0.200-kg aluminum calorimeter cup. The final temperature of the system is 30.5 Celsius. What is the specific heat of the metal alloy in J/Kg.Celsius

Answers

Answer:

[tex]C_{alloy}=0.497\frac{J}{g\°C}[/tex]

Explanation:

Hello there!

In this case, according to this calorimetry problem on equilibrium temperature, it is possible for us to infer that the heat released by the metal allow is absorbed by the water for us to write:

[tex]Q_{allow}=-(Q_{water}+Q_{Al})[/tex]

Thus, by writing the aforementioned in terms of mass, specific heat and temperature, we have:

[tex]m_{alloy}C_{alloy}(T_{eq}-T_{alloy})=-(m_{water}C_{water}(T_{eq}-T_{water})+m_{Al}C_{Al}(T_{eq}-T_{Al})[/tex]

Then, we solve for specific heat of the metallic alloy to obtain:

[tex]C_{alloy}=\frac{-(m_{water}C_{water}(T_{eq}-T_{water})+m_{Al}C_{Al}(T_{eq}-T_{Al})}{m_{alloy}(T_{eq}-T_{alloy})}[/tex]

Thereby, we plug in the given data to obtain:

[tex]C_{alloy}=\frac{-(400g*4.184\frac{J}{g\°C} (30.5\°C-10.0\°C)+200g*0.900\frac{J}{g\°C}(30.5\°C-10.0\°C)}{150g(30.5\°C-540\°C)} \\\\C_{alloy}=0.497\frac{J}{g\°C}[/tex]

Regards!

The enthalpy of formation of water is -285.8 kJ/mol. What can be inferred from this statement? O The enthalpy of the products is equal to the enthalpy of the reactants. O Heat is absorbed during the process. O Heat is released during the process. The enthalpy of the products is more than the enthalpy of the reactants.​

Answers

Answer:

the answer is c

Explanation:

i did the test

The enthalpy of the formation of water is -285.8 kJ/mol. The information that can be made by the statement is heat is released during the process. The correct option is C.

What is enthalpy?

Enthalpy is the volume times the pressure times the internal energy of the system. It is an entity of thermodynamics. It is the measurement of the energy in a thermodynamic system. The enthalpy totals the internal energy plus pressure and volume.

The statement that is given here is given that enthalpy is -285.8 kJ/mol. The value is negative, so the energy is released here. When energy is gained the energy will be positive and when the energy is released it is negative.

Thus, the correct option is C, heat is released during the process regarding the given statement of enthalpy.

To learn more about enthalpy, refer to the link:

https://brainly.com/question/24136717

#SPJ6

What would the products be for the reaction between Na3PO4 + MgSO4?

Answers

MgSO4 + Na3PO4 = Na2SO4 + Mg3(PO4)2

Answer: The products of Na3PO4 + MgSO4 are Na2SO4 + Mg3(PO4)2

Explanation:

Purification of copper can be achieved by electrorefining copper from an impure copper anode onto a pure copper cathode in an electrolytic cell. How many hours will it take to plate 19.5 kg of copper onto the cathode if the current passed through the cell is held constant at 38.5 A

Answers

Answer: It will take 425 hours to plate 19.5 kg of copper onto the cathode if the current passed through the cell is held constant at 38.5 A.

Explanation:

The half-reaction equation is as follows.

[tex]Cu^{2+} + 2e^{-} \rightarrow Cu[/tex]

According to the standard values, 1 mole of an electron carries 96500 C. Therefore, charge carried by 2 moles of electrons is [tex]2 \times 96500 C[/tex].

Also, atomic mass of Cu is 63.5 g. According to the equation 2 moles of electrons are depositing 63.5 g of Cu.

Hence, charge required to deposit 19.5 kg (1 kg = 1000 g) or 19500 g of Cu is calculated as follows.

[tex]19500 g Cu \times \frac{2 \times 96500 C}{63.5 g Cu}\\= 5.92 \times 10^{7} C[/tex]

Formula used to calculate time is as follows.

[tex]Q = I \times t[/tex]

where,

Q = charge

I = current

t = time

Substitute the values into above formula as follows.

[tex]5.92 \times 10^{7} C = 38.5 \times t\\t = \frac{5.92 \times 10^{7} C}{38.5}\\= 1.53 \times 10^{6} sec[/tex]

As 1 hour contains 3600 seconds. So, converting seconds into hours as follows.

[tex]1.53 \times 10^{6} sec = 1.53 \times 10^{6} sec \times \frac{1 hr}{3600 sec}\\= 425 hr[/tex]

Thus, we can conclude that it will take 425 hours to plate 19.5 kg of copper onto the cathode if the current passed through the cell is held constant at 38.5 A.

Explain what matter is, and all of the states it can have.

Answers

Answer:

matter is anything that occupies space

states of matter : solid,liquid, gas,plasma

Answer:

matter can be anything, tables chairs, literally anything. it has volume and takes up space.

Explanation:

Solids, liquids, gases, plasmas, and Bose-Einstein condensates (BEC)

Information normally shown as a continuous wave is analog or digital. Examples include music cds and smartphones is it analog or digital. Takes up a lot of space and degrades over time is it analog or digital. Examples include dimmer light switches and cameras that use film is it analog or digital. Purer data is more accurate and has more details is it analog or digital. Please help

Answers

Answer:

Music CDs and smartphones are digital.

Explanation:

Music CDs and smartphones are digital. Analogue takes up a lot of space and degrades with the [passage of time while on the other hand, digital takes less space and degrades in large piece of time. Dimmer light switches and cameras that use film is it analog not digital. The major difference between both signals is that the analog signals have continuous electronic signals, while digital signals have non-continuous electronic signals.

For each of the following compounds, decide whether the compound's solubility in aqueous solution changes with pH. If the solubility does change, pick the pH at which you'd expect the highest solubility. You'll find Ksp data in the ALEKS Data tab. compound Does solubility change with pH

Answers

Answer: Hello attached below is the complete question and using data from ALEKS data tab

answer:

PbCl₂ :  Yes , PH = 3

CaC0₃ : Yes, PH = 3

AgCn : Yes , PH = 3 .

Explanation:

For PbCl₂  

PbCl₂ solubility will change ( decrease )  with increase in PH, and the PH at which PbCl₂ will be most soluble is at PH = 3

For CaC0₃

Addition of -ions which increases the PH level will cause a decrease in the solubility of  CaC0₃ hence the PH at which it will be most soluble in an aqueous solution is PH = 3

For AgCn

Increase in the PH level there would be a decrease in the solubility of AgCn hence the PH at which AgCn is most soluble ( highest solubility ) = 3

The ability of a solute to be able to dissolve is called solubility. Yes, at pH 3, the solubility of lead chloride, calcium carbonate, and silver cyanide.

What is solubility?

The ability of the solute to get dissolved in a solvent to form a saturated solution is called solubility.

For lead chloride, the solubility will decrease as the pH will increase and is most soluble at a pH of 3.

For calcium carbonate, the addition of ions increases the pH will result in a decreased solubility, and will be most soluble at pH 3.

For silver cyanide increased pH decreases the solubility and is most soluble at a pH of three.

Therefore, solubility decrease with an increase in pH due to the concentration factor.

Learn more about solubility here:

https://brainly.com/question/22985530

Why is a wire used to connect the electrodes in an electrochemical cell?
O A. To provide the metal that is the oxidizing agent
B. To prevent the flow of protons from electrodes
C. So ions can flow from one electrode to another
D. So electrons can flow from one electrode to another

Answers

Answer:

D. So electrons can flow from one electrode to another

Explanation:

An electrochemical cell is any cell in which electricity is produced by reason of a chemical change.

An electrochemical cell consists of two electrodes, these two electrodes are connected using a wire.

Usually, electrons flow from one electrode to another via this wire thereby enabling the electrochemical processes of oxidation and reduction in the cell to proceed effectively.

1) For the following molecules: - Draw the Lewis structures/dots - Determine the polarity (polar or non-polar). - List all intermolecular forces. a) CF4 b) CH2Br2 c) H2CO3 d) N2 e) PCl3 f) XeF2 g) NH4

Answers

Answer:

ed

Explanation:

ed

omg posting takes away point WHAT.

Answers

Answer:

yep

Explanation:

that why I have someone else post questions for me. But its a good incentive to help others to help you to help me to you to help others.


10 ml of a 0.25M solution is diluted to make exactly 250 ml of solution. What's the concentration of the diluted solution?

Answers

Answer:

0.01 M

Explanation:

As this problem deals with a dilution process, we can solve it by using the following formula:

C₁V₁=C₂V₂

Where subscript 1 stands for the initial concentration and volume, while 2 stands for the final conditions.

That means that in this case:

C₁ = 0.25 MV₁ = 10 mLC₂ = ?V₂ = 250 mL

We input the given data:

0.25 M * 10 mL = C₂ * 250 mLC₂ = 0.01 M

How much water, in grams, can be made from 1.84 × 1024 hydrogen molecules?

Answers

Answer:

55.0g water can be made

Explanation:

To solve this question, we must convert the molecules of H2 to moles using Avogadro's constant. With the moles, and the reaction:

H2 + 1/2O2 → H2O

We can find the moles of H2O = Moles H2 and its mass of using molar mass of water -H2O = 18.01g/mol-

Moles H2 = Moles H2O:

1.84x10²⁴ molecules * (1mol / 6.022x10²³ molecules) = 3.055 moles H2O

Mass:

3.055 moles H2O * (18.01g / mol) = 55.0g water can be made

A student reads a barometer in the laboratory and finds the prevailing atmospheric pressure to be 736 mmHg. Express this pressure in torr and in atmospheres.

Answers

Answer:

736 mmHg = 0.97 atm (Approx.)

736 mmHg = 736 Torr

Explanation:

Given barometer in the laboratory atmospheric pressure data:

Atmospheric pressure in mmHg = 736 mmHg

Find:

Change given data into Torr

Change given data in atm (atmospheric pressure)

Computation:

We know that;

1 atm = 760 mmHg

So,

736 mmHg = 736 / 760

736 mmHg = 0.97 atm (Approx.)

We know that;

760 mmHg = 760 Torr

So,

736 mmHg = 736 Torr

Hl Weakly dissociates in water according to the chemical equation below. H20+ Hl <-> H3O^+ + l- What is a conjugate acid-base pair in this reaction?

Answers

Answer:

https://www.clutchprep.com/chemistry/practice-problems/70217/hi-aq-h2o-l-h3o-aq-i-aq-identify-each-as-either-a-bronsted-lowry-acid-bronsted-l

Explanation:

https://www.clutchprep.com/chemistry/practice-problems/70217/hi-aq-h2o-l-h3o-aq-i-aq-identify-each-as-either-a-bronsted-lowry-acid-bronsted-l

A car traveling at 30 m/s comes to a stop in 5 seconds. What is the acceleration of this car?

Answers

Answer:

6m/s brainliest?

Explanation:

Answer:

6 m/s

Explanation:

A sample of gas at 90 degrees Celsius occupies 15.5 L. This gas is heated to occupy a new volume of 20.3L. What is the new temperature of the gas?

Answers

Answer:

202 °C

Explanation:

From the question given above, the following data were obtained:

Initial temperature (T₁) = 90 °C

Initial volume (V₁) = 15.5 L

Final volume (V₂) = 20.3 L

Final temperature (T₂) =?

Next, we shall convert 90 °C to Kelvin temperature. This is illustrated below:

T(K) = T(°C) + 273

Initial temperature (T₁) = 90 °C

Initial temperature (T₁) = 90 °C + 273

Initial temperature (T₁) = 363 K

Next, we shall determine the final temperature.

Initial temperature (T₁) = 363 K

Initial volume (V₁) = 15.5 L

Final volume (V₂) = 20.3 L

Final temperature (T₂) =?

V₁ / T₁ = V₂ / T₂

15.5 / 363 = 20.3 / T₂

Cross multiply

15.5 × T₂ = 363 × 20.3

15.5 × T₂ = 7368.9

Divide both side by 15.5

T₂ = 7368.9 / 15.5

T₂ ≈ 475 K

Finally, we shall convert 475 K to celsius temperature. This is illustrated below:

T(°C) = T(K) – 273

T₂ = 475 – 273

T₂ = 202 °C

Thus, the new temperature of the gas is 202 °C

200.0g of a 3.0% NaF solution, how much distilled water do we weigh out?

197g of distilled water
194g of distilled water
140g of distilled water
170g of distilled water

Answers

Answer:

194g of distilled water.

Explanation:

Hello there!

In this case, according to the given information for this problem, it turns out possible for us to use the given mass of the solution and the percent by mass of NaF to firstly calculate the grams of this solute as shown below:

[tex]\%m=\frac{m_{solute}}{m_{solution}} *100\%\\\\m_{solute}=\frac{\%m*m_{solution}}{100\%} \\\\m_{solute}=\frac{3.0\%*200.0g}{100\%} \\\\m_{solute}=6g[/tex]

And finally, since the mass of solution is calculated by adding mass of solute and mass of solvent we obtain the mass of water (solvent) as follows:

[tex]m_w=200g-6g=194g[/tex]

Therefore, the answer is 194g of distilled water

Regards!

Which of the following would result in being able to dissolve a greater amount of gas in a solution? ​

Answers

Answer:

Lower the temperature of the solution

How are solutions and compounds similar?

Answers

Answer:

hope you liked it!!!!!!

A compound is a pure substance that is composed of elements chemically bonded in definite proportions. A compound can be broken down into simpler substances only by chemical reactions, such as electrolysis.

A solution is a homogeneous mixture, meaning that it is the same throughout. A solution is composed of one or more solutes dissolved in a solvent. The proportions of the solute(s) can vary, as the components of a solution are not chemically bonded. The components of a mixture can be separated by physical means, such as filtration and distillation

Spread your smarts while you wait.

Answers

Answer:

lol ok 1+1=2 2 x 2=4

have a good day :)

Explanation:

Answer:  oke

Explanation: have a goood day!

12. An electrolysis reaction is
A. hydrophobic.
B. spontaneous.
C. exothermic.
D. non-spontaneous.

Answers

Answer: D.) non-spontaneous.

Explanation:

How many molecules are present in 4.5
moles of H2O?

Answers

Answer:

Mole of the H2O = 4.5

Number of molecules =4.5 multipled by avogadro's number.

If the fan and power source are not connected to anything else, the amount of electrical energy is the same as the amount of mechanical energy. What is this rule known as?

1. transference of energy
2. conversion of energy
3. adaptation of energy
4. conservation of energy

Answers

Answer:

not B

Explanation:

my friend got it wrong

What is one movement that liquid water CANNOT do while on or at the Earth's surface? (GIVE RIGHT ANSWER OR I DELETE 100 POINTS)

Answers

Answer:

One movement that i can't do is float in mid air

Explanation:

1. Which individuals are most likely to die before reproducing, those with adaptive traits or
nonadaptive traits? Why? (Hint: You may use the newt population as an example in your
explanation.)

Answers

Nonadaptive traits .

130 cm of a gas at 20°C exerts a pressure of
750 mm Hg. Calculate its pressure if its volume
is increased to 150 cm3 at 35 °C.​

Answers

Answer: The pressure is 1137.5 mm Hg its pressure if its volume is increased to 150 [tex]cm^{3}[/tex] at 35 °C

Explanation:

Given: [tex]P_{1}[/tex] = 750 mm Hg,    [tex]V_{1} = 130 cm^{3}[/tex],     [tex]T_{1} = 20^{o}C[/tex]

[tex]P_{2}[/tex] = ?,          [tex]V_{2} = 150 cm^{3}[/tex],            [tex]T_{2} = 35^{o}C[/tex]

Formula used to calculate the new pressure is as follows.

[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}[/tex]

Substitute the values into above formula as follows.

[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{750 mm Hg \times 130 cm^{3}}{20^{o}C} = \frac{P_{2} \times 150 cm^{3}}{35^{o}C}\\P_{2} = 1137.5 mm Hg[/tex]

Thus, we can conclude that the pressure is 1137.5 mm Hg its pressure if its volume is increased to 150 [tex]cm^{3}[/tex] at 35 °C.

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