The half-life of the radioactive isotope polonium-218 is 3.05 minutes.

How long will it take for the activity of a sample of polonium-218 to decrease from 2.81E4 Ci to 3.52E3 Ci?

Answers

Answer 1

Answer: It will take 9.13 minutes for the sample.

Explanation:

Expression for rate law for first order kinetics is given by:

[tex]t=\frac{2.303}{k}\log\frac{a}{a-x}[/tex]

where,

k = rate constant  

t = age of sample

a = initial amount of the reactant = [tex]2.81\times 10^4[/tex]

a - x = amount left after decay process = [tex]3.52\times 10^3[/tex]

a) for completion of half life:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

[tex]t_{\frac{1}{2}}=\frac{0.693}{k}[/tex]

[tex]k=\frac{0.693}{3.05min}=0.227min^{-1}[/tex]

b) for activity to decrease from 2.81E4 Ci to 3.52E3 Ci:

[tex]t=\frac{2.303}{0.227}\log\frac{2.81\times 10^4}{3.52\times 10^3}[/tex]

[tex]t=9.13min[/tex]

Thus it will take 9.13 minutes for the sample.

[tex]t_{99.9}=40min[/tex]

The time after which 99.9% reactions gets completed is 40 minutes


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Answers

Answer:

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Answers

Answer:

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Explanation:

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