Answer:
the objects have very large masses or an object in circular orbit. This has motion but its always being to pulled to earth by gravity.
Greater gravitational forces will be used to attract heavier things, since the gravitational force is directly proportional to the mass of both interacting objects. Two objects are attracted to one another by gravity as their respective masses increase. Thus, option B is correct.
What is the role of large masses in gravitation force?The gravitational pull between two objects changes inversely with their squared distance and directly with their large masses.
As a result, the gravitational force between the two items would decrease to one-fourth of its initial strength when the large masses of both objects are halved without affecting their distance.
Therefore, The objects are either in a circular orbit or have extremely large masses. Although something is moving, gravity is always bringing it dangerously close to the ground.
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In Drosophila, the genes for eye color, wing shape, and wing length are located on chromosome II. Purple eyes (pr), arc bent wings (a), and vestigial wings (vg) are the mutant forms of the wild type traits red eyes, straight wings, and long wings, respectively. You've discovered some data in your genetics laboratory which indicates that the distance between vg and pr is 12.5 m.u., the distance between a and pr is 44.7 m.u., and the distance between a and vg is 32.2 m.u. what is the chance of a double crossover between these three genes
Answer:
The expected double recombinant frequency = 0.0402 = 4.02%
Explanation:
Available data:
genes for eye color, wing shape, and wing length are located on the same chromosomePurple eyes (pr) is the mutant form of the wild type traits red eyes (pr+)Arc bent wings (a) is the mutant form of the straight wings (a+)Vestigial wings (vg) are the mutant forms of the long wings (vg+)the distance between vg and pr is 12.5 m.uthe distance between a and pr is 44.7 m.uthe distance between a and vg is 32.2 m.u→ Two genes that are very close will have a few recombination events and are strongly bounded.
→ The map unit is the distance between the pair of genes for which every 100 meiotic products, one of them results in a recombinant one.
1) First, we need to know their order in the chromosome, and to do so, we need to compare the distances between them.
The most distant pair is a-pr
----a---------------------------------------------pr---
║-------------------44,7 MU-------------║
From gene a to vg there are 32.2 MU
----a-----------------------------vg--------------pr---
║-------------------44,7 MU-------------║
║----------32.2 MU------║
Finally, de distance from vg to pr is 12.5 MU
----a-----------------------------vg--------------pr---
║-------------------44,7 MU---------------║
║----------32.2 MU------║--12.5 MU--║
We can name region I to the distance between a-vg, and region II to the distance between vg-pr.
2) To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cM. And that the maximum recombination frequency is always 50%.
1 MU -----------1% of recombination
32.2 MU -----X = 32.2 % of recombination
12.5 MU-------X = 12.5 % of recombination
3) The expected double recombinant frequency = recombination frequency in region I x recombination frequency in region II.
The expected d. recombinant frequency = 32.2% x 12.5% = 0.322 x 0.125
The expected double recombinant frequency = 0.0402 = 4.02%
what is the cause of down syndrome
Answer:
there is multiple causes is this an acual question??????
Explanation:
Where are diploid cells found ?
A. only in reproductive organs
B. only in twin siblings
C. through out the body
D. only in the lungs
Answer:
c
Explanation:
diploid cells are cell that have 2 genetic alleles, one from your mom and one from dad, so all your cells are diploid, except haploid cells in the rep system.
Granite has only recently been exposed at a location on Earth’s surface. What will need to happen first in order for granite to become sedimentary rock?
Answer:
Granite has only recently been exposed at a location on Earth's surface. What will need to happen first in order for granite to become sedimentary rock? A thick layer of humus must form on top of the granite. The granite must be broken into smaller pieces by weathering processes.
Explanation: hope this helps dude
Environmental scientists calculating pollutant half-lives often define a transport rate constant that is analogous to a reaction rate constant and describes how a pollutant moves out of an ecosystem. In a study of the gasoline additive MTBE in Donner Lake, California, scientists from the University of California, Davis, found that in the summer the half-life of MTBE in the lake was 26.01 days. Assume that the transport process is first order. What was the transport rate constant of MTBE out of Donner Lake during the study
Answer:
k ≈ [tex]2.7 *10^{-2} d^{-1}[/tex]
Explanation:
For a first order reaction
Half life ( [tex]t_{1/2}[/tex] ) = 0.693 / k
k = rate constant
[tex]t_{1/2}[/tex] = 26.01
hence k = 0.693 / ( 26.01)
k ≈ 2.7 * 10^-2 d^-1
This is a detailed simple solution as required
BIOLOGY CIRCULATORY SYSTEM!! WILL NAME BRAINLIEST IF YOU ANSWER CORRECTLY!!
Answer:
C, G, F, I, H, D, A, E, B
They are in order from top to bottom
How are eukaryotic cell walls different from bacterial cell walls?
What is fermentation? Select all that apply.
process that breaks down larger molecules
into smaller molecules
process that uses oxygen to create usable
energy for the body
process that does not rely on the presence of
oxygen
process that creates waste products
Answer:
Option One
Option Three
Option Four
Explanation:
Fermentation is the process of breaking down substances different types of bacteria or microorganisms will producing heat, this process can also be completed without the usage of oxygen. Finally, fermentation is used to create alcohol like wine or beer which is considered wastes to the body. Therefore options one, three, and four are your answers or "process that breaks down larger molecules into smaller molecules, energy for the body process that does not rely on the presence of oxygen, and process that creates waste products."
Hope this helps.
17. When a person looks up into the sky
during new moon, what fraction of the
bright surface of the moon do we see?
Answer:
i dont really know why and how im here but im here
Explanation:
Which unhealthy condition30 point would most likely result from a person eating too much food for many years?
Answer:
Conditions such as obesity, stroke, high blood pressure, heart disease, and diabetes can occur to someone who eats too much unhealthy food for many years.
what do you call a soft ,heated mass of crushed leaves and other substances that spread over the skin to treat swelling or pain ?
a.bandage
b.ointment
c.poultice
d.solution
The skin cells of an organism are analyzed and cells identified in G1 and have an average of 12 picograms of DNA. In the same organism a cell from gonadal tissues is identified and that single cell contains 6 picograms of DNA. Given this information, which of the following is true about the single gonadal tissue cell with 6pg of DNA?
1. The cell is at the beginning of Prophase I.
2. The cell has already completed meiosis.
3. The cell is not dividing (is in interphase).
4. The cell contains unduplicated chromosomes.
Answer:
El Rasho Macuin
Explanation:
The statement which is true about the single gonadal tissue cell with 6 picograms of DNA is that the cell has already completed meiosis. So, the correct option is B.
What do you mean by DNA?It is a complex molecule that contains all the information necessary to build and maintain an organism. It stands for Deoxyribonucleic acid. It is considered the genetic material in most organisms.
The skin cells in the G1 phase have an average of 12 picograms of DNA. As the amount of DNA in the G1 phase is 2C, hence 2C = 12 pg of DNA.
Now in the same organism, a cell from gonadal tissue is identified and that single cell contains 6 pg of DNA, which means, the amount of DNA is 6 pg that is C. Therefore, after the completion of meiosis, the cell contains half the amount of DNA as compared to the parent cell in G1.
So, Amount of DNA = C = 6 pg.
Therefore, the statement which is true about the single gonadal tissue cell with 6 picograms of DNA is that the cell has already completed meiosis.
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Using this illustration as a guide, indicate the level one would need to drill to gain a sample containing the highest ratio of parent rock in comparison with organic material.
horizon C
horizon A
horizon B
horizon O
Answer:
horizon C
Explanation:
The horizon C has the highest ratio of parent rock as compared to organic matter. This horizon starts after horizon B and present above the bed rock. This horizon consists of weathered and partially decomposed rocks. It is the actual layer of soil of that place whereas the other horizon A and B comes with the passage of time when the wind bring the soil particles and these particles deposits on this layer of the soil making horizon A and B.
22) During durg adminsteration not necesary tell
to the patient
A) Prupase of durg
B) Side effect of durg
C) Route of mrdication
In a flower, the anther is attached to filament. What advantage does the filament provide to the anther?
A. The filament elevates the anther to allow for easier transport of pollen by wind or insects.
B. The filament provides the anther with nutrients to produce pollen grains.
C. The filament protects the anther from harsh sunlight and insects.
D. The filament produces a sticky surface to allow the anther to capture pollen.
The correct answer is A. The filament elevates the anther to allow for easier transport of pollen by wind or insects.
Explanation
The filament of a flower is the sterile part of the stamen (male organ of the flower) that is located just below the anther. Its function is structural to hold the sling so that it is accessible to insects. The filament is usually cylindrical and fine. Therefore, the correct answer is A. The filament elevates the anther to allow for easier transport of pollen by wind or insects.
What part of meiosis involves the splitting of 2 cells to make 4 total cells
Answer:
Meiosis II
Explanation:
During Meiosis II, the 2 cells were split into 4 cells, each with 23 chromosomes.
give the correct biological term for the following programme where members of the community help patients take their medicines regularly
Answer:
Explanation:
Supervised treatment
Evergreen broadleaf trees, along with abundant rain, warm temperatures, and consistent day length, characterize the _ biome.
Answer:
Rainforest biome (tropical rainforest)
Explanation:
The characteristics of the tropical rainforest biome are:
Located in humid and warm regions of equatorial climate.Medium temperature among 18 and 30 ºCAnnual precipitation is around 1000 and 8000 millimeters. Precipitation levels are never inferior to 1500 mm. There is no dry season, or if there is, it is too short. There is no hydric deficit. Fanerophic species dominate in this biome. Evergreen tall trees might reach up to 50 meters in height. They develop dense foliation and branches, becoming a refuge and source of food for many species. Vegetation does not need to develop strategies for surviving the dry season. Instead, they need to develop strategies for competing for light and nutrients. We can find different species of plants such as epiphytes, lianas, stranglers, aerial-rooted pants, tabular-rooted plants, among other vegetation forms. Tropical and subtropical rainforests might differentiate from each other in latitude and seasonality. Tropical rainforests might be found in latitudes of the Capricorn and Cancer tropics. From cero to ten degrees latitude. They are in America, Africa, and Asia continents. It is the biome with the greatest biodiversity on the planet. Rainforests have an extraordinary richness of animals and plants.
The combination of fibers and ground substance in fluid connective tissue is known as
A) ground substance
B) fat
C) cytosol
D) plasma
When two parents join to form a new individual-
Offspring will NOT be identical to one parent.
It will have traits from both parents
Both A and C
Offspring will be identical to one parent.
Help please!!
Answer:
"B"
Explanation:
It will have both traits from both parents.
Drag the tiles to the correct boxes to complete the pairs.
Identify the types of inheritance based on the expression of alleles in the organism.
Answer:
Presence of many alleles for the trait to be expressed --> Multiple
Presence of two alleles for the trait to be expressed --> recessive
Presence of a single allele for the trait to be expressed --> dominant
Answer:
Presence of two alleles for the trait to be expressed: recessive
Presence of many alleles for the trait to be expressed: multiple
Presence of a single allele for the trait to be expressed: dominant
Explanation:
Edmentum
How does the process of binary fission work in the asexual reproduction of bacteria?
A. Two cells join to become one larger cell
B. One cell splits into two cells with identical DNA.
O. DNA material from the environment is added to the cell.
D. Bacteria can only reproduce via sexual reproduction, not asexual reproduction,
The process of binary fission work as 'one cell splits into two cells with identical DNA. in the asexual reproduction of bacteria'.
So, option B is correct one.
What is binary fission?The simplest meaning of binary fission is division into two. The binary fission is the most common methods of asexual reproduction.In biological , division of single entity into two or more parts and regenerates of these parts again and each parts have potential to grow to the size of the original cell.Binary fission occurs in Amoeba which is unicellular organismThe binary fission is type of asexual reproduction.What is asexual reproduction of bacteria
The bacteria is prokaryotic organisms that reproduce asexually and bacteria is mainly reproduce by binary fission in which single cell divides into two .
There are some bacteria which divides in every 10 to 15 minutes .
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A scientist is studying metabolic rate in a Giant Hummingbird in Peru. The scientist assumes a captured individual has been feeding on nectar (glucose) recently, but in fact the individual has not fed in the last hour and is currently metabolizing fat (palmitic acid). 3. Calculate the measurement error the scientist would introduce based on their faulty assumption if the scientist were measuring CO2 production. Will the scientist over- or underestimate metabolic rate
Answer:
Yes.
Explanation:
Yes, the scientist underestimate the metabolic rate of Giant Hummingbird. The scientist experience the measurement error due to non-feeding of Giant Hummingbird that leads to faulty assumption when the scientist were measuring CO2 production because the Giant Hummingbird breakdown the fats of the body for the release of energy instead of glucose. There is difference in the production of carbondioxide rate due to difference in the composition of fats and glucose.
A cleft chin in humans is coded by the dominant allele C. A chin without a cleft is coded by the recessive allele c. A man with a cc allele combination for the trait produces a zygote with a woman with a Cc allele combination for the trait. Which allele combinations could occur in the zygote?
Answer:
The allele combinations are: Cc, cc, Cc, cc
Phenotypically there is a 50% chance that the child will be born with or without the cleft
The allele combinations that could occur in the zygote is Cc or cc.
What is an allele combination?An identification of the specific alleles found at each of the relevant mouse loci on the two homologous chromosomes (i.e., all allele pairs of a genotype). One or more allele pairs can make up an allele combination.
Genetic linkage is the capacity of a chromosome to transmit alleles that are near to one another as a whole unit through meiosis. Inheritance of traits is also understood by this principle. It is useful in locating the genes that are in charge of characteristics and diseases.
The person is homozygous for the allele if the two alleles are the same. The person is heterozygous if the alleles are different.
Therefore, the zygote may include the allele combinations Cc or cc.
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Which has the highest density?
A. water at 0°C
B. water at 4°C
C. water at 6°C
D. water at 8°C
what is a false scorpion
Answer:
huh im not prcicley undertsa
Answer:
A pseudoscorpion, also known as a false scorpion or book scorpion, is an arachnid belonging to the order Pseudoscorpiones, also known as Pseudoscorpionida or Chelonethida. Despite their appearance to true scorpions and ticks, they are NOT harmful to people. Physical removal is the only necessary control.
Explanation:
Which argument is BEST supported by the
information given?
A. The earthworm and lizard evolved at the same
time because of the absence of legs and hair.
B. The lizard and humans share a common
ancestor because of the presence of a
backbone and legs.
C. The trout and humans share a common
ancestor because of the presence of a
backbone.
D. Earthworms were the most recent to evolve
because of the absence of the derived
characteristics.
Answer:
B
Explanation:
It tells us a lot about why the argument is correct.
In fruit flies, curved wings (w) are recessive to the dominant straight wings (W), and ebony body (b) is recessive to the dominant gray body (B). A fly that has curved wings and ebony body is crossed with a fly that has straight wings and gray body. Of the offspring there were approximately equal numbers of straight gray, straight ebony, curved gray, curved ebony. What are the genotypes of the parents and offspring
Answer:
The correct answer =
parents : WwBb x wwbb
offspring :
WwBb, Wwbb, wwBb, and wwbb
Explanation:
It is given that the straight wings (W) is dominant over curved wings (w) and the ebony body (b) is recessive to the dominant gray body (B) and there is a cross between curved wings and ebony body and straight wings and gray body is made. The phenotypic ratio is: 1:1:1:1 for the four different phenotypes straight gray, straight ebony, curved gray, curved ebony.
It is not given the genotype of parents, however, for the curved and ebony fly, it is clear that both alleles are recessive as recessive alleles only appear in absence of the dominant allele of the trait.
For another parent, the possible genotypes can be WWBB or WwBb, however in the case of WWBB the phenotypic ratio would not be equal therefore,
crossing WwBb x wwbb
This can be represented in the form of a punnett square as below:
wb wb wb wb
WB WwBb WwBb WwBb WwBb Straight wing, Gray body
Wb Wwbb Wwbb Wwbb Wwbb Straight wing, Ebony body
wB wwBb wwBb wwBb wwBb Curved wing, Gray body
wb wwbb wwbb wwbb wwbb Curved wing, Ebony Body
The phenotypic ratio is: 1:1:1:1 for the four different phenotypes
Your friend runs out of gas and you have to help push his car. Discuss the sequence of bones and joints that convey the forces passing from your hand, through your upper limb and your pectoral girdle, and to your axial skeleton.?
Answer: The sequence of bones and joints that convey the forces include: From metacarpal bones --> carpal bones --> midcarpal and radiocarpal joints --> radius and ulna bones --> elbow joint --> humerus --> glenohumeral joint --> scapula --> acromioclavicular joint --> clavicle --> sternoclavicular joint --> sternum.
Note: the sign (-->) represents "into the".
Explanation:
The skeletal system is made up of bones of the skeleton, their joints and the skeletal muscles which acts together to bring about different movements in the body. The skeleton of a vertebrate had the following basic plan:
--> The axial skeleton: this forms the main central axis. This is made up of the skull,vertebral column, breastbone (sternum), and ribs.
--> The appendicular skeleton: this consists of parts that articulates with the axial skeleton. This is made up of the forelimbs, hindlimbs, pelvic and pectoral girdles.
From the question given, in an attempt to help push the friend's car, the sequence of bones and joints that convey the forces will pass from METACARPAL BONES of your hand into the CARPAL BONES at the base of your hand. Forces will then pass through the MIDCARPAL and RADIOCARPAL JOINTS into the RADIUS and ULNA bones of the forearm. These will pass the force through the ELBOW JOINT into the HUMERUS of the arm, and then through the GLENOHUMERAL JOINT into the SCAPULA. The force will travel through the ACROMIOCLAVICULAR JOINT into the CLAVICLE, and then through the STERNOCLAVICULAR joint into the STERNUM, which is part of the axial skeleton.
As one pushes against the car, the forces will pass in a sequential manner from the bones of the hand to the bones that are part of the axial skeleton.
• Forces will pass from the metacarpal bones of the hand into the carpal bones at the base of the hand, when one pushes against the car.
• After that the forces will then mediate via the radiocarpal and midcarpal joints into the ulna and the radius bones of the forearm.
• Then the force will move via the arm's humerus, and then via the glenohumeral joint into the scapula.
• The force then will mediate via the acromioclavicular joint into the clavicle, and then via the sternoclavicular joint into the sternum, that is, the part of the axial skeleton.
Thus, in the given case, force gets mediated through the bones of the hand and towards the bones of the axial skeleton in a sequential manner.
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You are studying a new gene "X" that you think controls skin color in Bearded Dragons. In order to determine what gene X does you need lots of gene X DNA to work with. So, you decide to amplify it through the process known as PCR. You have a forward and a reverse primer that have been designed to gene Xf – a gene in frogs that is similar to the one found in the Bearded Dragon. You are pretty sure that these two primers will work in Bearded Dragons, so you decide to go ahead with the PCR. In frogs, the Forward Xf primer binds gene Xf between nucleotides 32 and 47. The Reverse Xf primer binds between nucleotides 1110 and 1135. What size PCR product would these two primers create if they amplified the frog gene Xfp
Answer:
The correct answer is - 1103 bp.
Explanation:
PCR or polymerase chain reaction is a process that uses a primer to amplifying the desired segments of DNA molecules. It is a technique that can amplify a million copies of the DNA segment.
given:
forward primer binds from - 32 to 47
reverse primer binds from - 1135 to 1110
PCR product would be between - 32 to 1135
So, product size would = 1135-32 = 1103.
Thus, the correct answer is - 1103.