The graph of f(x) - 3* -6 is shown below. g() is a transformation of f(x).
How would you write the equation for the function g(x)?
15
10
5+
g(x)
is 2015 16
f(x) = 13*-6 -10
5
10
15 20 25
5
15+
O
A. g(x) - 3* +2
B. g(x) =
Ο Ο
2--13*-6
c. g(x)=13* +3
D. g(x)= - 4*+3
o

Answer:

Capacity of cube in liter = 15.625 liter

Step-by-step explanation:

Given:

Side of cube = 25 cm

Find:

Capacity of cube in liter

Computation:

Volume of cube = Side³

Volume of cube = 25³

Volume of cube = 15,625 cm³

We know that

1 cm³ = 0.001 liter

Capacity of cube in liter = Volume of cube in cubic cm x 0.001

So,

Capacity of cube in liter = 15,625 x 0.001

Capacity of cube in liter = 15.625 liter

Answer:

m∠J = 32°

m∠G = 78°

Step-by-step explanation:

ΔHJI ≈ ΔGEF respectively means;

∠H ≅ ∠G

∠I ≅ ∠E

∠J ≅ ∠F

Therefore;

Since  ∠F = 32°, then ∠J = 32°

Since ∠H = 78°, then ∠G = 78°

Hope this helps!

Answer:

the answer is 8,000.

Step-by-step explanation:

Answer:

hope it helps uh

9514 1404 393

Answer:

  a = 6, b = 12, c = 6, d = 6√3

Step-by-step explanation:

The two triangles are the "special" triangles.

The 45-45-90 triangle has side lengths in the ratios 1 : 1 : √2.

The 30-60-90 triangle has side lengths in the ratios 1 : √3 : 2.

Then ...

  c : a : 6√2 = 1 : 1 : √2   ⇒   c = a = 6

and ...

  a : d : b = 1 : √3 : 2   ⇒   d = 6√3 and b = 12 . . . (since a=6)

The lengths are ...

  a = 6, b = 12, c = 6, d = 6√3

We know that ,

[tex]\pi rad = 180^o[/tex]

Using Unitary Method ,

[tex]\implies 1 \ rad = \dfrac{180^o}{\pi } [/tex]

Therefore ,

[tex]\implies \dfrac{10\pi}{6} rad = \dfrac{10\pi}{6} * \dfrac{180^o}{\pi } [/tex]

[tex]= \boxed{\red{ 300^o }}[/tex]

Required answer !

Answer:

62 degrees since there are supplementary angles

Step-by-step explanation:

∠PQO= 180 degrees - 118 degrees

∠PQO= 62 degrees is the answer.

∠PQO= 180°-∠RQO -------(Supplementary Angles)

∠PQO= 180° - 118°

∠PQO= 62° answer.

Answer:

A) 91

Step-by-step explanation:

Supplementary angels are 2 angels whos sum is 180

To find the supplement of angle 89, substract 89 from 180

180-89 = x

91 = x

y = -49

multiply 7 on both sides

-7*7 = y/7*7

-49 = y

Answer:

y = -49

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Step-by-step explanation:

Step 1: Define

Identify

-7 = y/7

Step 2: Solve for y

Answer:

y = mx + b

m =(-2--4)/(-6--7)

m = 2

-2 = 2(-6) +b

b = 10

y= 2x + 10

Answer:

A. 8100

Step-by-step explanation:

85 x 86

To estimate, we multiply 85*100, which is the easiest multiplication, as a multiplication by 100 is the same as placing two zeros at the end of the number.

85*100 = 8500

Since 86 < 100, 85*86 < 8500. Thus, the correct estimate is given by option A.

Answer: c

Step-by-step explanation: because yes

Answer:

d po answer

yan po sinagot ko

hehe

Answer:

a) The null hypothesis is [tex]H_0: \mu = 310[/tex] and the alternative hypothesis is [tex]H_1: \mu < 310[/tex].

b) The test statistic is [tex]t = -1.54[/tex]. The critical value is [tex]t_c = -2.473[/tex].

c) The test statistic is [tex]t = -1.54 < t_c = -2.473[/tex], which means that there is not enough evidence to reject the null hypothesis that the mean transaction time is of 310 times, so no evidence to conclude that the mean transaction time is less than 310 seconds.

Step-by-step explanation:

Question a:

Costco is interested in finding out whether the mean transaction time is less than 310 seconds.

At the null hypothesis, we test if the mean is of 310 seconds, that is:

[tex]H_0: \mu = 310[/tex]

At the alternative hypothesis, we test if the mean is of less than 310 seconds, that is:

[tex]H_1: \mu < 310[/tex]

b) Find the test statistic and the critical value at 1% significance level.

Test if the mean is less than a value, sample of 28, and standard deviation for the sample. Thus, we have a left-tailed t-test with 28 - 1 = 27 degrees of freedom and a 0.01 significance level, and the critical value is [tex]t_c = -2.473[/tex].

The test statistic is:

[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, s is the standard deviation pf the sample and n is the size of the sample.

310 is tested at the null hypothesis:

This means that [tex]\mu = 310[/tex].

A sample of 28 sales transactions at Costco shows a mean transaction time of 296 seconds with a standard deviation of 48 seconds.

This means that [tex]n = 28, X = 296, s = 48[/tex].

Value of the test statistic:

[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]

[tex]t = \frac{296 - 310}{\frac{48}{\sqrt{28}}}[/tex]

[tex]t = -1.54[/tex]

The test statistic is [tex]t = -1.54[/tex].

c) At 1% level of significance, what is your conclusion

The test statistic is [tex]t = -1.54 < t_c = -2.473[/tex], which means that there is not enough evidence to reject the null hypothesis that the mean transaction time is of 310 times, so no evidence to conclude that the mean transaction time is less than 310 seconds.

Answer: C 22.5 ft2!

Step-by-step explanation:

i took the test, have a great day:) <3

Answer:

right

Step-by-step explanation:

Answer:

Quesiton is not clear. here is the asnswer basing on our understand

Step-by-step explanation:

(8-32)3 = (-24*3) = =72

Answer:

2 is the probability

Step-by-step explanation:

Answer:

w=-1+[tex]\sqrt{2}[/tex], w=-1-[tex]\sqrt{2}[/tex]

Step-by-step explanation:

Answer:

(x-4)(x+4)

Step-by-step explanation:

x^2 - 64 = x^2 - 4^2 = (x-4)(x+4)

Answer:

7kg

Step-by-step explanation:

258 / 36 = 7.16

the nearest ten, 7.20

Mark me brianest

Answer:

Step-by-step explanation:

11 no

46+4x=90 degree(being perpendicular)

4x=90-46

x=44/4

x=11

12 no

They are complementary angles

6 no

angle B+27=180 degree(being straight line)

angle B=180-27

angle B=153

10 no

angle 38 +angle DFE=180 degree(being supplementary)

angle DFE=180-38

angle DFE=142 degree

5 no

They are vertically opposite angles.

7 no

angle AGF and angle CGD (because they have common arm and vertex)

Answer:

Solution given:

11.4x+46=90[being right angle]

4x=90-46

x=44/4

x=11

12.

Complementary angles

5.

vertical

6.

<ABD+27=180°[linear pair]

<ABD=180-27

<ABD=153° degree

10.

<DFE+38=180[being supplementary]

<DFE=180-38

<DFE=142 degrees.

7.

angle DGE and angle DGC

8.

<AGB and <AGE

Answer:

8 days

Step-by-step explanation:

1 ton=2,000 pounds and If you divide 2,000÷250=8 days. It will talk 8 days for the baby whale to weigh his first ton.

Answer:

[tex]y = \frac{-1}{5}x -4[/tex]

Step-by-step explanation:

[tex]x + 5y = -20\\\\5y = -x - 20\\\\y = \frac{-1}{5}x - 4[/tex]

Answer:

Step-by-step explanation:

1). If two right triangles are congruent by HL property of congruence,

   Their corresponding sides will be congruent.

   By this property,

   x - 4 = y + 3

   x - y = 7 -----(1)

   x = 2y ------(2)

   By substituting x = 2y in equation (1),

   2y - y = 7

    y = 7

    From equation (1)

    x - 7 = 7

    x = 15

2). If both the right triangles are congruent by HL property of congruence,

    Their height and and hypotenuse will be congruent.

    y + x = x + 7

    y = 7

    y + 5 = 2y - x

    y - 2y + 5 = -x

    -y + 5 = -x

    x = y - 5

    By substituting y = 7 in the equation,

    x = 7 - 5

    x = 2

Answer:

2

35

6

Step-by-step explanation:

14/7=2

5*7=35

42/7=6

refer to the attachment

Answer:

the equation is 11+1.2d= h      so the height after 9 days would be 21.8cm

Step-by-step explanation:

Answer:

f(h) = 11 + 1.2h

f(9) = 21.8 cm

Step-by-step explanation:

let 'h' = height

f(h) = 11 + 1.2h

height after 9 days:

f(9) = 11 + 1.2(9)

= 11 + 10.8

= 21.8 cm

Answer:

20000000000000000000000000000

Answer:

[tex]A + B + E = 32[/tex]

Step-by-step explanation:

Given

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{1}{64}e^{-4x}[Ax^2 + Bx + E]C[/tex]

Required

Find [tex]A +B + E[/tex]

We have:

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{1}{64}e^{-4x}[Ax^2 + Bx + E]C[/tex]

Using integration by parts

[tex]\int {u} \, dv = uv - \int vdu[/tex]

Where

[tex]u = x^2[/tex] and [tex]dv = e^{-4x}dx[/tex]

Solve for du (differentiate u)

[tex]du = 2x\ dx[/tex]

Solve for v (integrate dv)

[tex]v = -\frac{1}{4}e^{-4x}[/tex]

So, we have:

[tex]\int {u} \, dv = uv - \int vdu[/tex]

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = x^2 *-\frac{1}{4}e^{-4x} - \int -\frac{1}{4}e^{-4x} 2xdx[/tex]

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} - \int -\frac{1}{2}e^{-4x} xdx[/tex]

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} +\frac{1}{2} \int xe^{-4x} dx[/tex]

-----------------------------------------------------------------------

Solving

[tex]\int xe^{-4x} dx[/tex]

Integration by parts

[tex]u = x[/tex] ---- [tex]du = dx[/tex]

[tex]dv = e^{-4x}dx[/tex] ---------- [tex]v = -\frac{1}{4}e^{-4x}[/tex]

So:

[tex]\int xe^{-4x} dx = -\frac{x}{4}e^{-4x} - \int -\frac{1}{4}e^{-4x}\ dx[/tex]

[tex]\int xe^{-4x} dx = -\frac{x}{4}e^{-4x} + \int e^{-4x}\ dx[/tex]

[tex]\int xe^{-4x} dx = -\frac{x}{4}e^{-4x} -\frac{1}{4}e^{-4x}[/tex]

So, we have:

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} +\frac{1}{2} \int xe^{-4x} dx[/tex]

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} +\frac{1}{2} [ -\frac{x}{4}e^{-4x} -\frac{1}{4}e^{-4x}][/tex]

Open bracket

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} -\frac{x}{8}e^{-4x} -\frac{1}{8}e^{-4x}[/tex]

Factor out [tex]e^{-4x}[/tex]

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = [-\frac{x^2}{4} -\frac{x}{8} -\frac{1}{8}]e^{-4x}[/tex]

Rewrite as:

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = [-\frac{1}{4}x^2 -\frac{1}{8}x -\frac{1}{8}]e^{-4x}[/tex]

Recall that:

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{1}{64}e^{-4x}[Ax^2 + Bx + E]C[/tex]

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = [-\frac{1}{64}Ax^2 -\frac{1}{64} Bx -\frac{1}{64} E]Ce^{-4x}[/tex]

By comparison:

[tex]-\frac{1}{4}x^2 = -\frac{1}{64}Ax^2[/tex]

[tex]-\frac{1}{8}x = -\frac{1}{64}Bx[/tex]

[tex]-\frac{1}{8} = -\frac{1}{64}E[/tex]

Solve A, B and C

[tex]-\frac{1}{4}x^2 = -\frac{1}{64}Ax^2[/tex]

Divide by [tex]-x^2[/tex]

[tex]\frac{1}{4} = \frac{1}{64}A[/tex]

Multiply by 64

[tex]64 * \frac{1}{4} = A[/tex]

[tex]A =16[/tex]

[tex]-\frac{1}{8}x = -\frac{1}{64}Bx[/tex]

Divide by [tex]-x[/tex]

[tex]\frac{1}{8} = \frac{1}{64}B[/tex]

Multiply by 64

[tex]64 * \frac{1}{8} = \frac{1}{64}B*64[/tex]

[tex]B = 8[/tex]

[tex]-\frac{1}{8} = -\frac{1}{64}E[/tex]

Multiply by -64

[tex]-64 * -\frac{1}{8} = -\frac{1}{64}E * -64[/tex]

[tex]E = 8[/tex]

So:

[tex]A + B + E = 16 +8+8[/tex]

[tex]A + B + E = 32[/tex]