The graph below shows the solution to which system of inequalities?
Someone please help me I would appreciate the help

Answer:

[tex]\dfrac{1213}{9999}[/tex]

Step-by-step explanation:

We are required to express [tex]0.\overline{1}+0.\overline{01}+0.\overline{0001}[/tex] as a common fraction.

The bar on top of the decimal part indicates the decimal number is a repeating decimal.

Therefore:

[tex]0.\overline{1}=\dfrac{1}{10-1}= \dfrac{1}{9}\\\\0.\overline{01}=\dfrac{1}{100-1}= \dfrac{1}{99}\\\\0.\overline{0001}=\dfrac{1}{10000-1}= \dfrac{1}{9999}\\\\\\$Therefore$:\\0.\overline{1}+0.\overline{01}+0.\overline{0001} \\=\dfrac{1}{9}+\dfrac{1}{99}+\dfrac{1}{9999}\\\\=\dfrac{1213}{9999}[/tex]

Answer:

i think it might be A. 0.2

Step-by-step explanation:

Answer:

V = 18125 in^3

Step-by-step explanation:

Surface Area of Rectangular Prism:

V = 18125 in^3

Step-by-step explanation:

Surface Area of Rectangular Prism:

S = 2(lw + lh + wh)

length l = 25 in

width w = 25 in

height h = 29 in

diagonal d = 45.7274535 in

total surface area S_tot = 4150 in^2

lateral surface area S_lat = 2900 in^2

top surface area S_top = 625 in^2

bottom surface area S_bot = 625 in^2

volume V = 18125 in^3

Group of answer choices:

A) 0.56 to 0.68

B) 0.52 to 0.72

C) 0.53 to 0.71

D) 0.55 to 0.69

Answer:

Option  B) 0.52 to 0.72

Step-by-step explanation:

This is a very trivial exercise. A very good point that is required to solve this question is that the wider the Confidence level, the wider the Confidence Interval.

Let us consider the options one after the other for the width of interval:

Option A) 0.56 to 0.68

Width of Interval = 0.68 - 0.56 = 0.12

Option  B) 0.52 to 0.72

Width of Interval = 0.72 - 0.52 = 0.20

Option  C) 0.53 to 0.71

Width of Interval = 0.71 - 0.53 = 0.18

Option D) 0.55 to 0.69

Width of Interval = 0.69 - 0.55 = 0.14

Assigning the confidence level based on the width of the confidence intervals:

Option A) 0.56 to 0.68 = 90%

Option D) 0.55 to 0.69 = 95%

Option  C) 0.53 to 0.71  = 98%

Option  B) 0.52 to 0.72  = 99%

Answer:

4

Step-by-step explanation:

C1= 2π*8= 16π

C2= 2π*2= 4π

C1/C2= 16π/4π= 4

Answer:

4

Step-by-step explanation:

The circumference is pi*d.

pi*16/pi*4

Cancel pi.

16/4

= 4

Hi

500 *1.025^10 ≈ 640.04

Answer: x = 15, y = 12.5

Step-by-step explanation:

The sum of the three angle measures of a triangle equals 180ᴼ

Since these triangles are vertical, the measures are congruent.

45 + 60 = 105

180 - 105 = 75

So now we know that 5x = 75ᴼ and 6y = 75ᴼ.

To find x, divide 75 by 5

75 / 5 = 15

x = 15

To find y, divide 75 by 6

75 / 6 = 12.5

y = 12.5

Answer:

5/7

Step-by-step explanation:

4/7 < x < 6/7

Let x be the middle value of 4/7 and 6/7.

(4/7 + 6/7)/2

(10/7)/2

10/14 = 5/7

4/7 < 5/7 < 6/7

Answer:

The option with “at most” and “no more than”

Step-by-step explanation:

These two phrases mean “greater than or equal to”

1. The sum of 1.5 and the product of 6.5 and a number is no greater than 21.

2. The product of 6.5 and a number, when increased by 1.5, is at most 21.

In which mathematical expression both sides are not equal, i.e. one side is greater or less or greater equal or less equal than other side, is called inequality.

Example : 4x+5>3x-2

The given inequality is [tex]6.5x+1.5\leq 21[/tex]

Firstly, The sum of 1.5 and the product of 6.5 and a number (say x) is 6.5x+1.5,  which is no greater than 21, i.e. [tex]6.5x+1.5\leq 21[/tex]

Again, The product of 6.5 and a number (say x) is 6.5x, when increased by 1.5, it will be 6.5x+1.5 which is at most 21, i.e. [tex]6.5x+1.5\leq 21[/tex]

Hence, the correct options are,

1. The sum of 1.5 and the product of 6.5 and a number is no greater than 21.

2. The product of 6.5 and a number, when increased by 1.5, is at most 21.

Learn more about inequality here :

https://brainly.com/question/11613554

#SPJ2

Answer:

W = (18,0)

Step-by-step explanation:

I found the slope of the line from point M to point V. The slope is -3.875. I continued this slope starting with point V to find the coordinates of point W. The coordinates of point W are (18,0).

I graphed the coordinates and the line of VW on the graph below.

Answer:

Option D

Step-by-step explanation:

A sample can be described as a small part or potion that is intended to describe what the whole population is like.

In this study, the sample is a group of the children taking skiing or snowboarding lessons: this group is taken out of the whole population of children taking skiing or snowboarding lessons.

Answer:

  30 miles

Step-by-step explanation:

Jose's charges are ...

  j = 5 + 0.30m . . . . . for m miles

Kathy's charges are ...

  k = 8 +0.20m . . . . . for m miles

The charges are the same when ...

 j = k

  5 +0.30m = 8 + 0.20m

  0.30m = 3 + 0.20m . . . . subtract 5

  0.10m = 3 . . . . . . . . . . . . subtract 0.20m

  m = 30 . . . . . . . . . . . . . . . multiply by 10

The charges will be the same for a distance of 30 miles.

Answer:

A = {CBA, CAB, BCA, ACB}

Step-by-step explanation:

Answer: A. {CBA, CAB, BCA, ACB}

Step-by-step explanation: Id appreciate it if anyone else could explain why that is the answer. (?)

Answer:

104 degrees

Step-by-step explanation:

The angle of the whole set of lines is 140 degrees. In addition, the partial angle of it is also given--which is 36 degrees. In order to solve for the remaining part, Subtract 36 degrees from 140 degrees to get 104 degrees.

Answer:

inside, 120

Step-by-step explanation:

Answer:

1. Inside

2. 120

did on edge

Answer:

  x² = 32² +35² -2·32·35·cos(120°)

Step-by-step explanation:

The equation of choice is the one that makes use of the law of cosines. If x represents the unknown side, then you would want to solve ...

  x² = 32² +35² -2·32·35·cos(120°)

_____

The solution is ...

  x² = 3369

  x = √3369 ≈ 58.043

_____

Comment on the question

Usually, when the question asks, "Which ...", there will be a selection of answer choices. Those will give a clue as to what variables are used, how far the equation is simplified, and whether the equation is for x² or for x. That information is not provided here, so we have shown the equation we would use to solve the problem.

Answer:

The guy above me is right.

Step-by-step explanation:

I took the test.

Answer:

a) 100 $

b) 566,66 $

c) 566,66 $

Step-by-step explanation:

Mak 85,000 $ /per year, means 85000/12 per month that is 7083,33

8% of 7083,33 is  566,66 $ . Then

a) 200 < 566,33 then my company will contribute with 0,5*200 = 100 $

b) If I contribute with 830 $  ( 830 > 566,66 ) then my company will contribute with 566,66 $ the biggest amount

c) 566,66 s the maximm amount of money

Answer:

Step-by-step explanation:

In an isosceles triangle, the base angles are equal. This also means that the length of two sides of the triangle are equal. Looking at triangle ABC, to prove that it is an isosceles triangle, then

Angle CAB = angle CBA

For the second question, to determine how it is known that QS is equivalent to YT, we would recall that the diameter of a circle passes through the center and from one side of the circle to the other side. Assuming R is the center of the circle, then QS and YT are the diameters of the circle and also the diagonals of the rectangle. Thus, the correct option is

The diameters act as diagonals

Answer:

The phrase "95% confident" means that there is a 95% confidence that the true mean parking time of students from within the various college on campus is included in the interval (9.1944, 11.738).

Step-by-step explanation:

The (1 - α)% confidence interval for population parameter implies that there is a (1 - α) probability that the true value of the parameter is included in the interval.

Or, the (1 - α)% confidence interval for the parameter implies that there is (1 - α)% confidence or certainty that the true parameter value is contained in the interval.

From the provided data the 95% confidence interval for the population mean parking time of students from within the various college on campus is:

CI = (9.1944, 11.738)

This 95% confidence interval implies that the true mean parking time of students from within the various college on campus is included in the interval (9.1944, 11.738) with a specific probability or confidence of 95%.

Thus, the phrase "95% confident" means that there is a 95% confidence that the true mean parking time of students from within the various college on campus is included in the interval (9.1944, 11.738).

Answer:

a. The null and alternative hypothesis can be written as:

[tex]H_0: \mu=3173\\\\H_a:\mu< 3173[/tex]

b. A Type I error is made when a true null hypothesis is rejected. In this case, it would happen if it is concluded that the actual mean outstanding credit card debt of college undergraduate is significantly less than $3173, when in fact it does not.

A Type II error is made when a false null hypothesis is failed to be rejected. In this case, the actual mean outstanding credit card debt of college undergraduate is in fact less than $3173, but the test concludes there is no enough evidence to claim that.

Step-by-step explanation:

We have a prior study of the mean outstanding credit card debt of college undergraduate that states that it was $3173 in 2010.

A researcher believes that this amount has decreased since then.

Then, he has to perform a hypothesis test where the null hypothesis states that the mean is still $3173 and an alternative hypothesis that states that the actual credit card debt is significantly smaller than $3173.

The null and alternative hypothesis can be written as:

[tex]H_0: \mu=3173\\\\H_a:\mu< 3173[/tex]

Answer:

Step-by-step explanation:

Given that:

[tex]E( \hat \theta _1) = \theta \ \ \ \ E( \hat \theta _2) = \theta \ \ \ \ V( \hat \theta _1) = \sigma_1^2 \ \ \ \ V(\hat \theta_2) = \sigma_2^2[/tex]

If we are to consider the estimator [tex]\hat \theta _3 = a \hat \theta_1 + (1-a) \hat \theta_2[/tex]

a. Then, for  [tex]\hat \theta_3[/tex] to be an unbiased estimator ; Then:

[tex]E ( \hat \theta_3) = E ( a \hat \theta_1+ (1-a) \hat \theta_2)[/tex]

[tex]E ( \hat \theta_3) = aE ( \theta_1) + (1-a) E ( \hat \theta_2)[/tex]

[tex]E ( \hat \theta_3) = a \theta + (1-a) \theta = \theta[/tex]

b) If [tex]\hat \theta _1 \ \ and \ \ \hat \theta_2[/tex] are independent

[tex]V(\hat \theta _3) = V (a \hat \theta_1+ (1-a) \hat \theta_2)[/tex]

[tex]V(\hat \theta _3) = a ^2 V ( \hat \theta_1) + (1-a)^2 V ( \hat \theta_2)[/tex]

Thus; in order to minimize the variance of [tex]\hat \theta_3[/tex] ; then constant a can be determined as :

[tex]V( \hat \theta_3) = a^2 \sigma_1^2 + (1-a)^2 \sigma^2_2[/tex]

Using differentiation:

[tex]\dfrac{d}{da}(V \ \hat \theta_3) = 0 \implies 2a \ \sigma_1^2 + 2(1-a)(-1) \sigma_2^2 = 0[/tex]

⇒

[tex]a (\sigma_1^2 + \sigma_2^2) = \sigma^2_2[/tex]

[tex]\hat a = \dfrac{\sigma^2_2}{\sigma^2_1+\sigma^2_2}[/tex]

This implies that

[tex]\dfrac{d}{da}(V \ \hat \theta_3)|_{a = \hat a} = 2 \ \sigma_1^2 + 2 \ \sigma_2^2 > 0[/tex]

So, [tex]V( \hat \theta_3)[/tex] is minimum when [tex]\hat a = \dfrac{\sigma_2^2}{\sigma_1^2+\sigma_2^2}[/tex]

As such; [tex]a = \dfrac{1}{2}[/tex]       if   [tex]\sigma_1^2 \ \ = \ \ \sigma_2^2[/tex]

Answer:

(B) 25%

Step-by-step explanation:

Answer:

The factors are 7 and 3

Step-by-step explanation:

The factors of a multiplication sentence are the numbers that are being multiplied for the product (or answer).

Answer:

10 rows with 6 passengers per row

Step-by-step explanation:

Let x be the number of rows and y the number of passengers per row.

Then we can interpret the story as the following two equations:

xy=60

(x+2)(y-1)=60

Solving these two equations:

y=60/x

(x+2)(60/x-1)=60     (substitute y)

60 - x + 120/x - 2 = 60 (multiply by -x)

x² + 2x - 120 = 0     (factor)

(x-10)(x+12) = 0

x = 10

y = 60/10 = 6

and indeed 10 * 6 = 60 and also 12 * 5 = 60

Correct question:

The vector matrix [ [tex] \left[\begin{array}{ccc}2\\7\end{array}\right] [/tex] is dilated by a factor of 1.5 and then reflected across the x axis. If the resulting matrix is [a/b] then a=??? and b=???

Answer:

a = 3

b = 10.5

Step-by-step explanation:

Given:

Vector matrix = [tex] \left[\begin{array}{ccc}2\\7\end{array}\right] [/tex]

Dilation factor = 1.5

Since the vector matrix is dilated by 1.5, we have:

[tex] \left[\begin{array}{ccc}1.5 * 2\\1.5 * 7\end{array}\right] [/tex]

= [tex] \left[\begin{array}{ccc}3\\10.5\end{array}\right] [/tex]

Here, we are told the vector is reflected on the x axis.

Therefore,

a = 3

b = 10.5

Answer:

a = 3

b = -10.5

Step-by-step explanation:

got a 100% on PLATO

Answer:

A margin of error of +/- 3%

Step-by-step explanation:

Strenght of surveys:

The lesser the margin of error, the more precise, stronger, the confidence interval is.

The margin of error depends of the number of people surveyed. The more people are surveyed, lower the margin of error is, giving a stronger interval.

In this question:

We want the smaller margin of error, which is given by:

A margin of error of +/- 3%

Step-by-step explanation:

[tex] (\frac{5}{6} \times \frac{3}{4} ) \times \frac{8}{7} \times 1 \\ = \frac{5}{8} \times \frac{8}{7} \\ = \frac{5}{7} [/tex]

[tex]( \frac{3}{2} \times \frac{3}{4} ) \times \frac{2}{8} \\ = \frac{9}{8} \times \frac{2}{8 } \\ = \frac{9}{32} [/tex]

Answer:

[tex] y = -6x^2 -17 x -12[/tex]

And since the higher exponent for the x term is 2 we can classify the equation  as quadratic

Quadratic term: -6

Linear term: -17

Constant term: -12

Step-by-step explanation:

For this problem we have the following equation:

[tex] y = (3x+4)(-2x-3)[/tex]

And we can distribute the terms and we got:

[tex] y = -6x^2 -9x -8x -12[/tex]

And solving we got:

[tex] y = -6x^2 -17 x -12[/tex]

And since the higher exponent for the x term is 2 we can classify the equation  as quadratic

Quadratic term: -6

Linear term: -17

Constant term: -12

Answer:

81/4

Step-by-step explanation:

From the given information; we are to use Lagrange multipliers to find the volume of the largest rectangular box

The coordinate planes and the vertex given in the plane is x + 9y + 4z = 27.

By applying Lagrange multipliers, we have;

[tex]fx = \lambda gx[/tex]

where;

[tex]f: V = xyz[/tex]

[tex]g : x + 9y + 4z = 27[/tex]

From; [tex]fx = \lambda gx[/tex]

[tex]yz = \lambda[/tex]    --------- equation (1)

From; [tex]fy = \lambda gy[/tex]

[tex]xz = 9 \lambda[/tex]  --------- equation (2)

From; [tex]fz = \lambda gz[/tex]

[tex]xy = 4 \lambda[/tex] --------- equation (3)

Comparing and solving equation (1),(2) and (3);

[tex]\lambda x = 9 \lambda y = 4 \lambda z[/tex]

divide through by [tex]\lambda[/tex]

x = 9 y = 4z

3x = 27

x = 27/3

x = 9

From x = 9y

9 = 9 y

y = 9/9

y = 1

From

x = 4z

9 = 4 z

z = 9/4

Thus; the Volume of the largest rectangular box = 9 × 1  × 9/4

= 81/4

Answer:

The curvature is modelled by [tex]\kappa = \frac{e^{-t}}{6\sqrt{2}}[/tex].

Step-by-step explanation:

The equation of the curvature is:

[tex]\kappa = \frac{|\dot {x}\cdot \ddot {y}-\dot{y}\cdot \ddot{x}|}{[\dot{x}^{2}+\dot{y}^{2}]^{\frac{3}{2} }}[/tex]

The parametric componentes of the curve are:

[tex]x = 6\cdot e^{t} \cdot \cos t[/tex] and [tex]y = 6\cdot e^{t}\cdot \sin t[/tex]

The first and second derivative associated to each component are determined by differentiation rules:

First derivative

[tex]\dot{x} = 6\cdot e^{t}\cdot \cos t - 6\cdot e^{t}\cdot \sin t[/tex] and [tex]\dot {y} = 6\cdot e^{t}\cdot \sin t + 6\cdot e^{t} \cdot \cos t[/tex]

[tex]\dot x = 6\cdot e^{t} \cdot (\cos t - \sin t)[/tex] and [tex]\dot {y} = 6\cdot e^{t}\cdot (\sin t + \cos t)[/tex]

Second derivative

[tex]\ddot{x} = 6\cdot e^{t}\cdot (\cos t-\sin t)+6\cdot e^{t} \cdot (-\sin t -\cos t)[/tex]

[tex]\ddot x = -12\cdot e^{t}\cdot \sin t[/tex]

[tex]\ddot {y} = 6\cdot e^{t}\cdot (\sin t + \cos t) + 6\cdot e^{t}\cdot (\cos t - \sin t)[/tex]

[tex]\ddot{y} = 12\cdot e^{t}\cdot \cos t[/tex]

Now, each term is replaced in the the curvature equation:

[tex]\kappa = \frac{|6\cdot e^{t}\cdot (\cos t - \sin t)\cdot 12\cdot e^{t}\cdot \cos t-6\cdot e^{t}\cdot (\sin t + \cos t)\cdot (-12\cdot e^{t}\cdot \sin t)|}{\left\{\left[6\cdot e^{t}\cdot (\cos t - \sin t)\right]^{2}+\right[6\cdot e^{t}\cdot (\sin t + \cos t)\left]^{2}\right\}^{\frac{3}{2}}} }[/tex]

And the resulting expression is simplified by algebraic and trigonometric means:

[tex]\kappa = \frac{72\cdot e^{2\cdot t}\cdot \cos^{2}t-72\cdot e^{2\cdot t}\cdot \sin t\cdot \cos t + 72\cdot e^{2\cdot t}\cdot \sin^{2}t+72\cdot e^{2\cdot t}\cdot \sin t \cdot \cos t}{[36\cdot e^{2\cdot t}\cdot (\cos^{2}t -2\cdot \cos t \cdot \sin t +\sin^{2}t)+36\cdot e^{2\cdot t}\cdot (\sin^{2}t+2\cdot \cos t \cdot \sin t +\cos^{2} t)]^{\frac{3}{2} }}[/tex]

[tex]\kappa = \frac{72\cdot e^{2\cdot t}}{[72\cdot e^{2\cdot t}]^{\frac{3}{2} } }[/tex]

[tex]\kappa = [72\cdot e^{2\cdot t}]^{-\frac{1}{2} }[/tex]

[tex]\kappa = 72^{-\frac{1}{2} }\cdot e^{-t}[/tex]

[tex]\kappa = \frac{e^{-t}}{6\sqrt{2}}[/tex]

The curvature is modelled by [tex]\kappa = \frac{e^{-t}}{6\sqrt{2}}[/tex].