The function f(x) =5x coverts x nickels to pennies. Find a function that converts X Pennys to Nichols then convert 50 pennies to Nichols. 

Answer:

[tex]t \ge h[/tex] and [tex]t + 0.5h \le 12.0[/tex]

Step-by-step explanation:

Given

[tex]t= thickness[/tex]

[tex]h =height[/tex]

From the first statement, we have that:

[tex]t\ mm \ge 0.1 * h\ cm[/tex]

Convert mm to cm

[tex]t\ * 0.1*cm \ge 0.1 * h\ cm[/tex]

[tex]t\ *0.1 \ge 0.1 * h[/tex]

Divide both sides by 0.1

[tex]t \ge h[/tex]

From the second statement, we have that:

[tex]Cost \le 12.2[/tex]

Substitute 0.2 + t + 0.5h for Cost

[tex]0.2 + t + 0.5h \le 12.2[/tex]

Collect Like Terms:

[tex]t + 0.5h \le 12.2-0.2[/tex]

[tex]t + 0.5h \le 12.0[/tex]

So, the inequalities are:

[tex]t \ge h[/tex] and [tex]t + 0.5h \le 12.0[/tex]

Answer: it's a, the answer

Step-by-step explanation:

Answer:

750 is the answer. Hope it helps!

It would be B)no.

Hope This Helps!

Answer:

Image attached

Step-by-step explanation:

Just wandering, no hate, you can post answers on brainly but can't read an analog clock.

BTW I've got one in my house

Answer:

Step-by-step explanation:

x+y = 8

y = 8-x

xy = 17

x(8-x)  = 17

8x - x² = 17

x² - 8x + 17 = 0

Quadratic formula

x = [8 ± √(8² – 4·1·17)] / [2·1]

 = [8 ± √(-4)] / 2

 = [8 ± 2i] /2

 = 4±i

x = 4+i

y = 4-i

A quadratic equation is written in the form of ax²+bx+c. The two numbers whose sum is 8 and whose product is 17​ are (4+i) and (4-i).

A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers. It is written in the form of ax²+bx+c.

Let the first number be 'a' and the second number be 'b'. Therefore, the sum of the two numbers is,

a+b=8

The product of the two numbers is,

ab=17

b=17/a

now, the equation can be written as,

a+b=8

a+(17/a)=8

a² + 17 = 8a

a²-8a+17=0

a = 4±i

Hence, the two numbers whose sum is 8 and whose product is 17​ are (4+i) and (4-i).

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Answer:

He bought 2 cans of paint

Step-by-step explanation:

If he put ⅖ in each, and ⅘ total, he would have had 2 cans

Quantity of special paint additive Ernest bought = [tex] \tt \frac{4}{5} \: of \: a \: litre [/tex]

Quantity of additive he put in each can = [tex] \tt \frac{2}{5} \: of \: a \: litre [/tex]

Number of cans of paint he bought :

[tex] =\tt \frac{4}{5} \div \frac{2}{5} [/tex]

[tex] = \tt\frac{4}{5} \times \frac{5}{2} [/tex]

[tex] = \tt\frac{4 \times 5}{5 \times 2} [/tex]

[tex] =\tt \frac{20}{10} [/tex]

[tex]\color{plum} = \tt2 \: paint \: cans[/tex]

▪︎Therefore, Ernest bought 2 paint cans.

Answer:

4

Step-by-step explanation:

subtract negative 4 by negative 8

After plotting the above equation on the coordinate plane, we can see the graph of the function.

A parametric equation in mathematics specifies a set of numbers as functions of one or more independent variables known as parameters.

We have two parametric equations:

x = 1 – t² and

y = 2t

t = y/2  and

0 ≤ t² ≤ 5

1 ≤ 1 - t²≤ 4

1 ≤ x≤ 4

Plug the above value in x = 1 – t²

x = 1- (y/2)²

x = 1 - y²/4

4x = 4 - y²

y² = 4(1 - x)

Thus, after plotting the above equation on the coordinate plane, we can see the graph of the function.

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Answer:

56

Step-by-step explanation: Use the values of a, b, and c to find the discriminant.

Answer:

[tex]\Delta =56[/tex]

Step-by-step explanation:

We are given:

[tex]y = x^2 - 8x + 2[/tex][tex]y=x^2-8x+2[/tex]

So, a = 1, b = -8, and c = 2.

The discriminant (symbolized by Δ) is given by:

[tex]\Delta =b^2-4ac[/tex]

So, our discriminant in this case will be:

[tex]\Delta=(-8)^2-4(1)(2)=64-8=56[/tex]

Since our discriminant is a positive value, our equation has two real roots.

Answer:

4) x=14

Step-by-step explanation:

multiply the area by 2 to get 140then devide by 10 to find x

Answer:

=[tex](x-1)(x+6)[/tex]

Step-by-step explanation:

Answer:

[tex]x^{2} +5x-6=(x-1)(x+6)[/tex]

Step-by-step explanation:

Answer:

1742 hours

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Single light:

Mean of 1700 hours and standard deviation of 400 hours, which means that [tex]\mu = 1700, \sigma = 400[/tex]

Sample of 64:

This means that [tex]n = 64, s = \frac{400}{\sqrt{64}} = 50[/tex]

The probability is 0.20 that the sample mean lifetime is more than how many hours?

This is the 100 - 20 = 80th percentile, which is X when Z has a pvalue of 0.8. So X when Z = 0.84

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]0.84 = \frac{X - 1700}{50}[/tex]

[tex]X - 1700 = 50*0.84[/tex]

[tex]X = 1700 + 50*0.84[/tex]

[tex]X = 1742[/tex]

Answer:

16 is the answer

I hope this answer help you

Answer:

Subtract 4 1st

Step-by-step explanation:

Subtract 4 of the cars since he gave them to his brother then divide between 4

Answer: If you divide 202/4=50.5 or 50 1/2

Step-by-step explanation:

Answer:

its b

Step-by-step explanation:

Answer:

[tex]P(X > 11) = 0.368[/tex]

[tex]P(X > 22) = 0.135[/tex]

[tex]P(X > 33) = 0.050[/tex]

[tex]x = 33[/tex]

Step-by-step explanation:

Given

[tex]E(x) = 11[/tex] --- Mean

Required (Missing from  the question)

[tex](a)\ P(X>11)[/tex]

[tex](b)\ P(X>22)[/tex]

[tex](c)\ P(X>33)[/tex]

(d) x such that [tex]P(X <x)=0.95[/tex]

In an exponential distribution:

[tex]f(x) = \lambda e^{-\lambda x}, x \ge 0[/tex] --- the pdf

[tex]F(x) = 1 - e^{-\lambda x}, x \ge 0[/tex] --- the cdf

[tex]P(X > x) = 1 - F(x)[/tex]

In the above equations:

[tex]\lambda = \frac{1}{E(x)}[/tex]

Substitute 11 for E(x)

[tex]\lambda = \frac{1}{11}[/tex]

Now, we solve (a) to (d) as follows:

Solving (a): P(X>11)

[tex]P(X > 11) = 1 - F(11)[/tex]

Substitute 11 for x in [tex]F(x) = 1 - e^{-\lambda x}[/tex]

[tex]P(X > 11) = 1 - (1 - e^{-\frac{1}{11}* 11})[/tex]

[tex]P(X > 11) = 1 - (1 - e^{-\frac{11}{11}})[/tex]

[tex]P(X > 11) = 1 - (1 - e^{-1})[/tex]

Remove bracket

[tex]P(X > 11) = 1 - 1 + e^{-1}[/tex]

[tex]P(X > 11) = e^{-1}[/tex]

[tex]P(X > 11) = 0.368[/tex]

Solving (b): P(X>22)

[tex]P(X > 22) = 1 - F(22)[/tex]

Substitute 22 for x in [tex]F(x) = 1 - e^{-\lambda x}[/tex]

[tex]P(X > 22) = 1 - (1 - e^{-\frac{1}{11}* 22})[/tex]

[tex]P(X > 22) = 1 - (1 - e^{-\frac{22}{11}})[/tex]

[tex]P(X > 22) = 1 - (1 - e^{-2})[/tex]

Remove bracket

[tex]P(X > 22) = 1 - 1 + e^{-2}[/tex]

[tex]P(X > 22) = e^{-2}[/tex]

[tex]P(X > 22) = 0.135[/tex]

Solving (c): P(X>33)

[tex]P(X > 33) = 1 - F(33)[/tex]

Substitute 33 for x in [tex]F(x) = 1 - e^{-\lambda x}[/tex]

[tex]P(X > 33) = 1 - (1 - e^{-\frac{1}{11}* 33})[/tex]

[tex]P(X > 33) = 1 - (1 - e^{-\frac{33}{11}})[/tex]

[tex]P(X > 33) = 1 - (1 - e^{-3})[/tex]

Remove bracket

[tex]P(X > 33) = 1 - 1 + e^{-3}[/tex]

[tex]P(X > 33) = e^{-3}[/tex]

[tex]P(X > 33) = 0.050[/tex]

Solving (d): x when [tex]P(X <x)=0.95[/tex]

Here, we make use of:

[tex]P(X<x) = F(x)[/tex]

Substitute [tex]F(x) = 1 - e^{-\lambda x}[/tex]

[tex]P(X<x) = 1 - e^{-\lambda x}[/tex]

So, we have:

[tex]0.95 = 1 - e^{-\lambda x}[/tex]

Subtract 1 from both sides

[tex]0.95 -1= 1-1 - e^{-\lambda x}[/tex]

[tex]-0.05=- e^{-\lambda x}[/tex]

Reorder the equation

[tex]e^{-\lambda x} = 0.05[/tex]

Substitute 1/11 for [tex]\lambda[/tex]

[tex]e^{-\frac{1}{11} x} = 0.05[/tex]

Solve for x:

[tex]x = -\frac{1}{1/11}\ ln(0.05)[/tex]

[tex]x = -11\ ln(0.05)[/tex]

[tex]x = 32.9530550091[/tex]

[tex]x = 33[/tex] --- approximated

Answer:

(f o h)(-5)=-33

Step-by-step explanation:

Let f(x) = 4x - 1, h(x) = - X-3.

(f o h)=4(-x-3)-1

(f o h)=-4x-12-1

(f o h)=-4x-13

(f o h)(-5)=-4(-(-5))-13

(f o h)(-5)=-20-13

(f o h)(-5)=-33

Answer:

3.75

Step-by-step explanation:

To make it a fraction form answer, you multiply the dividend numerator by the divisor denominator to make a new numerator.

Furthermore, you multiply the dividend denominator by the divisor numerator to make a new denominator:

To make the answer to 3/4 divided by 1/5 in decimal form, you simply divide the numerator by the denominator from the fraction answer above:

15/4 = 3.75

The answer is rounded to the nearest four decimal points if necessary.

15/4 is an improper fraction and should be written as 3 3/4.

Answer:

3.75

Step-by-step explanation:

Answer:

L=8.062 feet

Step-by-step explanation:

wall=7

distance=4

Pythagorean theorem

7^2+4^2=L^2

49+16=L^2

65=L^2

L=8.062 feet

The required length of the ladder is given as 8.06 feet.

In a right-angled triangle, its sides, such as hypotenuse, perpendicular, and base are Pythagorean triplets.

here,
As mentioned in the question,
perpendicular length = 7, base length = 4 feet,
Let the length of the ladder be x,
Following the Pythagoras theorem,
x² = 7 ² + 4²
x ² = 49 + 16
x² = 65
x = √65
x = 8.06

Thus, the required length of the ladder is given as 8.06 feet.

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Given:

The statement is " a is the fourth root of 16".

To find:

The true statement for the given statement.

Solution:

The given statement is

a is the fourth root of 16.

Mathematically, it can be written as

[tex]a=\sqrt[4]{16}[/tex]

Taking power 4 on both sides.

[tex]a^4=(\sqrt[4]{16})^4[/tex]

[tex]a\times a\times a\times a=16[/tex]

Therefore, the correct option is A.

A true statement ,  if a is the fourth root of 16 is

a x a x a x a = 16

Important Information :

'a' is the fourth root of 16 can be written as

[tex]a=\sqrt[4]{16}[/tex]

To remove fourth root, we take exponent 4 on both sides

[tex]a=\sqrt[4]{16}\\(a)^4=(\sqrt[4]{16})^4[/tex]

Exponent 4  and fourth root will get cancelled

[tex]a^4=16\\a \cdot a\cdot a \cdot a=16[/tex]

a x a x a x a = 16

A true statement ,  if a is the fourth root of 16 is

a x a x a x a = 16

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Answer:

i think 25.09 weighs more

Step-by-step explanation: well simply 25.018 has more decimal places down therefore making it a smaller number

sorry if you get it wrong :c

Answer:

9

Step-by-step explanation:

Answer:

The difference between the greatest and smallest rational number   [tex]=\frac{3}{20}[/tex]              

Step-by-step explanation:

Step(i):-

Given that the rational numbers

[tex]\frac{7}{15} , \frac{11}{20} ,\frac{2}{5} ,\frac{12}{25}[/tex]

we have to find that the difference between the greatest and the smallest rational numbers

solution:-

The greatest rational number  =  [tex]\frac{11}{20}[/tex]

Convert into decimal = 0.55

The smallest rational number = [tex]\frac{2}{5}[/tex]

Convert into decimal = 0.4

The difference between the greatest and smallest rational number

                     [tex]= \frac{11}{20} - \frac{2}{5}[/tex]

                     = [tex]\frac{11-8}{20}[/tex]

                    [tex]=\frac{3}{20}[/tex]

Final answer:-

The difference between the greatest and smallest rational number     [tex]=\frac{3}{20}[/tex]

Answer:

P(A, B or C) = 6/7 or 0.8571

Step-by-step explanation:

From the image, we have the frequency for each grade as;

Grade A = 5

Grade B = 10

Grade C = 15

Grade D = 3

Grade F = 2

We want to find the probability that a student earns a grade of A, B or C.

Total frequency for A, B & C = 5 + 10 + 15 = 30

There are a total of 35 students overall for the geometry course.

Thus;

P(A, B or C) = 30/35

P(A, B or C) = 6/7 or 0.8571

Answer:

Step-by-step explanation:

Total frequency for A, B & C = 5 + 10 + 15 = 30

There are a total of 35 students overall for the geometry course.

P(A, B or C) = 30/35

P(A, B or C) = 6/7 or 0.8571

now we round to the hundredths place

0.8571 ⇒ 0.86

Answer:

r = -4

Step-by-step explanation:

-2 - 5r = 18

+2         +2

––––––––

-5r = 20

/5     /5

––––––

-r = 4

/-1  /-1

–––––

r = -4