Answer:
This is decay. The exponent has a negative sign. The reciprocal of 2 is 0.5. So N(t) can be rewritten as 0.5^(t/8). The base is fraction less than 1, which is decay.
Step-by-step explanation:
sample response on edgen 2022
In a standard deck of cards, what is the probability of drawing a face card followed by drawing a non-face card
Answer:
0.1771
Step-by-step explanation:
total number of cards in a deck : 52
number of face card per suite : 3
total number of suites : 4 (hearts, clubs, diamonds, spades)
3 * 4 = total number of face cards
12/52 = 0.23 = probability of drawing a face card
remaining card are non face cards
52-12 = 40
40 non face cards
40/52 = 0.77 = probability of drawing a non face card
probability of drawing a face card followed by a non face card
multiply probabilities together to find combined probability
probability of drawing a face card * probability of drawing a non face card
= 0.23 * 0.77
= 0.1771
PLS ANWER ASAP!! person with correct answer will be marked brainliest
Answer:
62 degrees since there are supplementary angles
Step-by-step explanation:
∠PQO= 180 degrees - 118 degrees
∠PQO= 62 degrees is the answer.
∠PQO= 180°-∠RQO -------(Supplementary Angles)
∠PQO= 180° - 118°
∠PQO= 62° answer.
A snail can travel 390 inches in 5 hours.
How far does it travel in 1 hour?
Answer:
78 inches
Step-by-step explanation:
5 hours = 390 inches
1 hour = 390 / 5
1 hour = 78 inches
Therefore the snail travels 78 inches in 1 hour.
Hope this helps!
Find (−5x−9)−(−6x−1)
POSSIBLE POINTS 50
Mr Franklin needs to pay for his three kids to go to college. He figured out that college will cost an average of
$50,000 per year per child when they are ready to go to college. To pay for this, Mr. Franklin bought a cylindrical
gas truck, The truck is 40 feet long and the radius of the base is 60 inches, Gas has a density of five pounds per
cubic foot. Mr. Franklin makes $2.50 per pound of gas when he sends a delivery. How many trips of full tanks of
gas will Mr. Franklin have to send to pay for his three kids to go to four years of college each?
Be sure to label each step and show all work. Don't forget units.
a) Find the volume of the cylinder
b) Find the mass of the gas in one truckload by using the density formula
c) Find the amount of money one truckload will generate.
d) Find the amount of money four years of college will cost for Mr. Franklin's three children.
e) Find the amount of trips it will take Mr. Franklin to make enough money to pay for college,
5
x Clear
Und
Answer:
2500
Step-by-step explanation:
pls pls i need the answer and A REALLY GOOD EXPLANATION pls pls
Answer:
15/50 will be your answer 30%
Step-by-step explanation:
First add them all up.
Then you want to make a simple equation
15/50
Answer:
30%
Step-by-step explanation:
15+10+2+20+3 = 50
therefore 15 is 30% of 50
Find the length of side y.
y=_ft
Answer:
y = 5.66388 feet, (round that to whatever you need to round to)
Step-by-step explanation:
cos (51) = y/9
cos(51)*9=
y = 5.66388 feet
You answered 85% of the questions on the quiz correctly. What fraction of
the questions did you answer correctly?
Answer:
A percentage is out of 100.
85/100
in lowest terms this is
17/20
Hope this helps :)
Step-by-step explanation:
Mrs. Smith decides to buy three sweaters and a pair of Jeans. She has $129 in her wallet.
If the price of the Jeans Is $40.05, what is the highest possible price of a sweater, each sweater is the
same price?
Variable:
Equation:
Solution:
Answer:
Step-by-step explanation:Herely/3fcEdSx's li[tex]^{}[/tex]nk to the answer:
bit.[tex]^{}[/tex]
23
A university administered a survey to all incoming students regarding living arrangements for the upcoming school year. The results of the survey are displayed in the following two-way relative frequency table.
University Living Arrangements
On-Campus Off-Campus Total
Freshmen 0.44 0.28 0.72
Transfer Students 0.21 0.07 0.28
Total 0.65 0.35 1
What percentage of incoming freshmen plan to live on-campus?
A.
61.11%
B.
67.69%
C.
56%
D.
44%
The probability of incoming freshmen who plan to live on-campus in percentage will be 61.11%. Then the correct option is A.
What is probability?Its basic premise is that something will almost certainly happen. The percentage of favorable events to the total number of occurrences.
A university administered a survey to all incoming students regarding living arrangements for the upcoming school year.
The results of the survey are displayed in the following two-way relative frequency table.
On-Campus Off-Campus Total
Freshmen 0.44 0.28 0.72
Transfer Students 0.21 0.07 0.28
Total 0.65 0.35 1
Then the probability of incoming freshmen who plan to live on-campus in percentage will be
P = (0.44 / 0.72) x 100
P = 0.6111 x 100
P = 61.11%
The probability of incoming freshmen who plan to live on-campus in percentage will be 61.11%.
Then the correct option is A.
More about the probability link is given below.
https://brainly.com/question/795909
#SPJ5
Only please help #2,3,5, and 6
Answer:
3.$0.9
5.9:3 =3:1
Step-by-step explanation:
3.$5.40÷6=$0.9
A radioactive substance decays to 30% of its original mass in 15 months. Determine the half-life of this radioactive substance to the nearest tenth. Show your work.
please help
Answer:
The half-life of this radioactive substance is of 8.6 months.
Step-by-step explanation:
Exponential decay of an amount:
The equation that models an amount after t units of time, subject to exponential decay, is given by:
[tex]A(t) = A(0)(1-r)^t[/tex]
In which A(0) is the initial amount and r is the decay rate, as a decimal.
A radioactive substance decays to 30% of its original mass in 15 months.
This means that [tex]A(15) = 0.3A(0)[/tex]. We use this to find 1 - r.
[tex]A(t) = A(0)(1-r)^t[/tex]
[tex]0.3A(0) = A(0)(1-r)^{15}[/tex]
[tex](1-r)^{15} = 0.3[/tex]
[tex]\sqrt[15]{(1-r)^{15}} = \sqrt[15]{0.3}[/tex]
[tex]1 - r = (0.3)^{\frac{1}{15}}[/tex]
[tex]1 - r = 0.9229[/tex]
So
[tex]A(t) = A(0)(0.9229)^t[/tex]
Determine the half-life of this radioactive substance to the nearest tenth.
This is t for which A(t) = 0.5A(0). So
[tex]A(t) = A(0)(0.9229)^t[/tex]
[tex]0.5A(0) = A(0)(0.9229)^t[/tex]
[tex](0.9229)^t = 0.5[/tex]
[tex]\log{(0.9229)^t} = \log{0.5}[/tex]
[tex]t\log{0.9229} = \log{0.5}[/tex]
[tex]t = \frac{\log{0.5}}{\log{0.9229}}[/tex]
[tex]t = 8.6[/tex]
The half-life of this radioactive substance is of 8.6 months.
How can you rewrite -8 − 10 as an addition problem?
A
-8 + (-10)
B
-8 + 10
C
-8 + 18
D
-8 + (-18)
Answer:
A
Step-by-step explanation:
-8 + (-10) = -8 -10
Need help quick with full work
Answer:
(x + 5) and (x -1)
Step-by-step explanation:
Given
The attached graph
Required
The [tex]factors[/tex] of the graph
The x [tex]values[/tex] are where the [tex]curve[/tex] [tex]touches[/tex] the x-axis
The first is at:
[tex]x = -5[/tex]
Add 5 to both sides
[tex]x +5= -5+5[/tex]
[tex]x +5= 0[/tex]
This implies that the first factor is: (x + 5)
The second is at:
[tex]x =1[/tex]
Subtract 1 from both sides
[tex]x - 1 = 1 - 1[/tex]
[tex]x - 1 = 0[/tex]
This implies that the other factor is: (x - 1)
GUYS PLEASE HELP ALMOST DUE
Answer:
1/5
Step-by-step explanation:
y = 12
12 = 1/5 x 60
12= 12
y = 9
9 = 1/5 x 45
9 = 9
and so on and it always results to one fifth
Use the Empirical Rule. The mean speed of a sample of vehicles along a stretch of highway is miles per hour, with a standard deviation of miles per hour. Estimate the percent of vehicles whose speeds are between miles per hour and miles per hour. (Assume the data set has a bell-shaped distribution.)
Approximately % of vehicles travel between 61 miles per hour and 71 miles per hour.
Answer:
68%
Step-by-step explanation:
We observe that the mean of the sample is (61+71)/2 = 66 mph which means the standard deviation of the sample is 5 because 66-5=61 and 66+5=71. The Empirical Rule states that for data observed in a normal distribution, 68% of data will fall within one standard deviation of the mean. Therefore, approximately 68% of vehicles travel between 61 miles per hour and 71 miles per hour.
At the neighborhood block party, Hassan served 3 gallons of hot chocolate and 1/2 of a gallon of apple cider. How much more hot chocolate than apple cider did Hassan serve?
Write your answer as a fraction or as a whole or mixed number.
Answer:
2 gallons and 1/2
Step-by-step explanation:
You just have to subtract 1/2 from 3.
3 - 1/2 = 2 1/2
or
3 - .5 = 2.5
And 2 1/2 is how much more he served.
Answer: 5 times more hot chocolate
Step-by-step explanation:
Which numbers are irrational? Select all that apply.
Answer:
I believe Option 1, 2 and 4 are all irrational numbers Hope this helps
Step-by-step explanation:
A coach collected data for his runners for 2 weeks. Week 1: Mean = 14.5 miles/ MAD = 1.15 Week 2: Mean = 16 miles/ MAD = 1.5. Which statement correctly compares the variability from Week 1 to Week 2? *
30 ft.
6 ft.
4 ft.
20 ft.
?
25 ft.
PLEASE HELP QUICK
Answer:
5 ft
Step-by-step explanation:
30/6 = 5
20/4 = 5
25/x = 5
25/5 = 5
x = 5
Answer:
5 feet
Step-by-step explanation:
the triangles are scaled by the factor of 5
The measure of an angle is 89. Find the measure of its supplementent
a. 91
b. 89
c.90
d. 80
Answer:
A) 91
Step-by-step explanation:
Supplementary angels are 2 angels whos sum is 180
To find the supplement of angle 89, substract 89 from 180
180-89 = x
91 = x
8. True or False. The correlation coefficient is a measure of the strength of an
association between two variables.
HELPPPPPPPPPPPPPPPPPPPPP
Answer:
2
35
6
Step-by-step explanation:
14/7=2
5*7=35
42/7=6
What is the measure of angle c?
Answer:
c=29°
Step-by-step explanation:
angle b=97°{ vertically opposite angle}
now,
97°+54°+c=180°{ sum of angle of triangle}
x=180-151x=29°stay safe healthy and happy.Answer: I'm pretty sure it's 29 degrees.
Step-by-step explanation:
Angle b is directly opposite of 97, and is the same. So b is equal to 97. Every triangle is 180 degrees, so all you have to do is 180 - 54 - 97, which is 29. I hope that helps!!
7 x [(26 - 5) - (5 + 6)]
Answer:70x
Step-by-step explanation: FIND BY OWN
B Reading Choose the best estimate for the multiplication problem below. 85 x 86
A. 8100
B. 10,400
C. 12,200
Answer:
A. 8100
Step-by-step explanation:
85 x 86
To estimate, we multiply 85*100, which is the easiest multiplication, as a multiplication by 100 is the same as placing two zeros at the end of the number.
85*100 = 8500
Since 86 < 100, 85*86 < 8500. Thus, the correct estimate is given by option A.
If the integral of the product of x squared and e raised to the negative 4 times x power, dx equals the product of negative 1 over 64 times e raised to the negative 4 times x power and the quantity A times x squared plus B times x plus E, plus C , then the value of A B E is
Answer:
[tex]A + B + E = 32[/tex]
Step-by-step explanation:
Given
[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{1}{64}e^{-4x}[Ax^2 + Bx + E]C[/tex]
Required
Find [tex]A +B + E[/tex]
We have:
[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{1}{64}e^{-4x}[Ax^2 + Bx + E]C[/tex]
Using integration by parts
[tex]\int {u} \, dv = uv - \int vdu[/tex]
Where
[tex]u = x^2[/tex] and [tex]dv = e^{-4x}dx[/tex]
Solve for du (differentiate u)
[tex]du = 2x\ dx[/tex]
Solve for v (integrate dv)
[tex]v = -\frac{1}{4}e^{-4x}[/tex]
So, we have:
[tex]\int {u} \, dv = uv - \int vdu[/tex]
[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = x^2 *-\frac{1}{4}e^{-4x} - \int -\frac{1}{4}e^{-4x} 2xdx[/tex]
[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} - \int -\frac{1}{2}e^{-4x} xdx[/tex]
[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} +\frac{1}{2} \int xe^{-4x} dx[/tex]
-----------------------------------------------------------------------
Solving
[tex]\int xe^{-4x} dx[/tex]
Integration by parts
[tex]u = x[/tex] ---- [tex]du = dx[/tex]
[tex]dv = e^{-4x}dx[/tex] ---------- [tex]v = -\frac{1}{4}e^{-4x}[/tex]
So:
[tex]\int xe^{-4x} dx = -\frac{x}{4}e^{-4x} - \int -\frac{1}{4}e^{-4x}\ dx[/tex]
[tex]\int xe^{-4x} dx = -\frac{x}{4}e^{-4x} + \int e^{-4x}\ dx[/tex]
[tex]\int xe^{-4x} dx = -\frac{x}{4}e^{-4x} -\frac{1}{4}e^{-4x}[/tex]
So, we have:
[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} +\frac{1}{2} \int xe^{-4x} dx[/tex]
[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} +\frac{1}{2} [ -\frac{x}{4}e^{-4x} -\frac{1}{4}e^{-4x}][/tex]
Open bracket
[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} -\frac{x}{8}e^{-4x} -\frac{1}{8}e^{-4x}[/tex]
Factor out [tex]e^{-4x}[/tex]
[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = [-\frac{x^2}{4} -\frac{x}{8} -\frac{1}{8}]e^{-4x}[/tex]
Rewrite as:
[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = [-\frac{1}{4}x^2 -\frac{1}{8}x -\frac{1}{8}]e^{-4x}[/tex]
Recall that:
[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{1}{64}e^{-4x}[Ax^2 + Bx + E]C[/tex]
[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = [-\frac{1}{64}Ax^2 -\frac{1}{64} Bx -\frac{1}{64} E]Ce^{-4x}[/tex]
By comparison:
[tex]-\frac{1}{4}x^2 = -\frac{1}{64}Ax^2[/tex]
[tex]-\frac{1}{8}x = -\frac{1}{64}Bx[/tex]
[tex]-\frac{1}{8} = -\frac{1}{64}E[/tex]
Solve A, B and C
[tex]-\frac{1}{4}x^2 = -\frac{1}{64}Ax^2[/tex]
Divide by [tex]-x^2[/tex]
[tex]\frac{1}{4} = \frac{1}{64}A[/tex]
Multiply by 64
[tex]64 * \frac{1}{4} = A[/tex]
[tex]A =16[/tex]
[tex]-\frac{1}{8}x = -\frac{1}{64}Bx[/tex]
Divide by [tex]-x[/tex]
[tex]\frac{1}{8} = \frac{1}{64}B[/tex]
Multiply by 64
[tex]64 * \frac{1}{8} = \frac{1}{64}B*64[/tex]
[tex]B = 8[/tex]
[tex]-\frac{1}{8} = -\frac{1}{64}E[/tex]
Multiply by -64
[tex]-64 * -\frac{1}{8} = -\frac{1}{64}E * -64[/tex]
[tex]E = 8[/tex]
So:
[tex]A + B + E = 16 +8+8[/tex]
[tex]A + B + E = 32[/tex]
PLEASE ANSWER THIS
PLEASE URGENT WORK
I M CRYING
Answer:
b=69(alternate angle)
b=37(alternate angle)
50 PTS AND BRAINLIEST FOR CORRECT ANSWER
Answer: I asked my teacher, she said it is c
Step-by-step explanation:
Answer:
yes it's c
have a great day
Suppose you are investigating the relationship between two variables, traffic flow and expected lead content, where traffic flow is a predictor of lead content. You find the 95% CI for expected lead content when traffic flow is 15, based on a sample of n= 10 observations, is (461.7, 598.1).
Required:
What parameter is this interval estimating?
Answer:
The answers is " Option B".
Step-by-step explanation:
[tex]CI=\hat{Y}\pm t_{Critical}\times S_{e}[/tex]
Where,
[tex]\hat{Y}=[/tex] predicted value of lead content when traffic flow is 15.
[tex]\to df=n-1=8-1=7[/tex]
[tex]95\% \ CI\ is\ (463.5, 596.3) \\\\\hat{Y}=\frac{(463.5+596.3)}{2}\\\\[/tex]
[tex]=\frac{1059.8}{2}\\\\=529.9[/tex]
Calculating thet-critical value[tex]t_{ \{\frac{\alpha}{2},\ df \}}=-2.365[/tex]
The lower predicted value [tex]=529.9-2.365(Se)[/tex]
[tex]463.5=529.9-2.365(Se)\\\\529.9-463.5=2.365(Se)\\\\66.4=2.365(Se)\\\\Se=\frac{66.4}{2.365} \\\\Se=28.076[/tex]
When [tex]99\%[/tex] of CI use as the expected lead content: [tex]\to 529.9\pm t_{0.005,7}\times 28.076 \\\\=(529.9 \pm 3.499 \times 28.076)\\\\=(529.9 \pm 98.238)\\\\=(529.9-98.238, 529.9+98.238)\\\\=(431.662, 628.138)\\\\=(431.6, 628.1)[/tex]